Technical Mathematics Grade 10 Paper 1 North West June 2019 Memo

Downloaded from hlayiso.com PROVINCIAL ASSESSMENT GRADE 10 TECHNICAL MATHEMATICS P1 JUNE 2019 MEMORANDUM MARKS: 75 This memorandum consists of 6 pages. Demo NW/JUNE/TEC-MATH/ EMIS/6*******

Downloaded from hlayiso.com Technical Mathematics/P1 2 NW/June 2019 Memorandum – Grade 10 QUESTION/VRAAG 1 1.1.1 27  one mark /een punt (1) 1.1.2  27 answer/antwoord (1) 1.1.3 3  27 answer/antwoord (1) 1.2 Let/laat x  0,2 3 ------------1 equating to x/stel gelyk aan x 100x  23,2 3 ----------2 multiply by 100/vermenigvuldig 100x  x  23 met100 99x  23 23 x 99 answer/antwoord (3) 1.3 5 and/en 6 OR/OF both values/beide waardes (2) 5  27  6 1.4 55 10 = 32 + 16 +4+2+1 method/metode = 2 2 2 2 2 5 4 2 1 0 = 2  1  2  1  2  0  2  1  2  1  2  1 5 4 3 2 1 0 answer/antwoord (2) = 110111 2 OR/OF 2 55 1 2 27 1 2 13 1 2 6 0 2 3 1 2 1 1 55 10 = 110111 2 1.5.1 10110 101 10 110 first row 10110/eerste ry 10110 1011000 2nd row 1011000/tweede ry 1011000 1101110 answer/antwoord (3) 1.5.2 1 1 0 1 1 1 0 = 26  1  25  1  24  0  23  1  22  1  21  1  20  0 method/metode = 64+32+8+4+2 Demo NW/JUNE/TEC-MATH/ EMIS/6*******

Downloaded from hlayiso.com Technical Mathematics/P1 3 NW/June 2019 Memorandum – Grade 10 = 110 answer/antwoord (2) 1.6 A  b a 1  a b 1 substitution/substitusie  3  2  2 1 31 simplify/vereenvoudig  3  16 answer/antwoord  A  19 (3) 1.7 1  10 6  0,000001 answer/antwoord (1) [19] QUESTION 2/VRAAG 2 2.1.1 5 x  1x  2  2  5x 2  9 x  2  2 expanding/uitbreiding  5x 2  9 x  4 final answer/finale antwoord (2) 2.1.2  7 x x  4  2 expanding  7 xx 2  8 x  16 brackets/uitmaal van hakies  7 x 3  56x 2  112x answer/antwoord (3) 2.2 x  32  x 2  6 x  9  x 2  6x  9  x 2  x  9    x 2  6x  9 subtracition/aftrekking  x 2  6x  9  x 2  x  9  7x answer/antwoord or/of 7x answer only/antwoord alleenlik (3) 2.3.1 4 x  12x  16x 3 2  4 xx 2  3x  4 4x as common factor/4x as gemeenskaplike factor  4 xx  4x  1 both brackets/beide hakies (3) 2.3.2 a 3  3a 2  4a  12 grouping/groepering  a 2 a  3  4a  3 common   a  3 a 2  4  factor/gemeenskaplike factor  a  3a  2a  2 difference of squares/verskil van vierkante (4) Demo NW/JUNE/TEC-MATH/ EMIS/6*******

Downloaded from hlayiso.com Technical Mathematics/P1 4 NW/June 2019 Memorandum – Grade 10 2.4 x 2  x  12 2 x  8 3x  9   x2  9 3x  9 2x  8 factors numerator and x  x  12 3x  9 2   denominator in1st x2  9 2x  8 fraction/faktore teller en  x  4x  3  3x  3 noemer in eerste breuk x  3x  3 2x  4 one mark second fraction 3 factors/een punt tweede breuk  faktore 2 answer/antwoord (5) 2.5 x  2 xy  y  2 2  x  y  2  x  y  2 answer/antwoord x y (2) [22] QUESTION 3/VRAAG 3 3.1  2 a 2b3  2 raising power/magsverheffing   2 a  4 b 6  2 numerator/teller  4 6 a b denominator/noemer (3) 3.2 5a(2a ) 3 2  25a 4  5a 4 numerator/teller 20a 7 denominator/noemer   20a 4  a 3 answer/antwoord (3) 3.3 3 216x 3  16x  6x  6 x  16 x answer/antwoord (2)  10x 3.4 8 x 1 4 2 x 2 prime bases/priem  2  3 x 1 grondtalle 2  2 2 x2 2 3 x 3  4 x4 simplify/vereenvoudig 2  2 7 x answer/antwoord (4) [12] Demo NW/JUNE/TEC-MATH/ EMIS/6*******

Downloaded from hlayiso.com Technical Mathematics/P1 5 NW/June 2019 Memorandum – Grade 10 QUESTION 4/VRAAG 4 4.1.1 5.2 x  160 2 x  32 ÷ 5 2 x  25 prime bases/priem x  5 grontalle answer/antwoord (3) 4.1.2 x2  4x  0 x x  4   0 factors/faktore x  0 or / of x4 both answers/beide antwoorde (2) 4.1.3 x7 1  4 2 x72 multiply with LCM 4/vermenigvuldig met KGV x  5 4 answer/antwoord (2) 4.1.4 x  2x  3  6 x2  x  6  6 standard form/standard x 2  x  12  0 vorm x  4x  3  0 factors/faktore x  4 or / of 1x each answer/1x elke x  3 antwoord (4) Demo NW/JUNE/TEC-MATH/ EMIS/6*******

Downloaded from hlayiso.com Technical Mathematics/P1 6 NW/June 2019 Memorandum – Grade 10 4.2.1  3  2x  5  7  3  5  2x  7  5 -5 on all sides/aan alle kante  8  2x  2 ÷ 2  4  x  1 each endpoint/elke eindpunt (4) 4.2.2 ○ ● • • 2 marks/2 punte -4 1 (2) 4.3 V  u  at V  u  at subtract u/aftrekking van u V u ÷ 𝑡 a (2) t 4.4 x  y  7     1 subract 1 from 2/trek 1 van 2 x  y  11    2 2 af/or substitution/ of 2 1: vervanging x  4 x value/x waarde y 3 y value/y waarde (3) or/of x  y  1         1 2 x  y  11       2 From/vanuit 1: y  7  x    3 Substitute/stel 3 in 2: 2 x  (7  x)  11 x  4 y 3 [22] TOTAL/TOTAAL:75 Demo NW/JUNE/TEC-MATH/ EMIS/6*******