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WESTERN CAPE EDUCATION
DEPARTMENT
NATIONAL
SENIOR CERTIFICATE
GRADE 12
MATHEMATICS
PAPER 2
SEPTEMBER 2015
MARKS: 150
TIME: 3 hours
This question paper consists of 14 pages, 1 information sheet and an ANSWER BOOK
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Mathematics Grade 12 P2 Western Cape Mock 2015 QP
Grade 12 Mathematics Paper 2 question paper from the Western Cape Mock Exam 2015, 15 pages. Read online or download the free PDF.
Mathematics · Grade 12 · Western Cape Mock Exam · 2015. Question paper, 15 pages. Read online or download the PDF.
- Subject
- Mathematics
- Grade
- Grade 12
- Document type
- Question paper
- Year
- 2015
- Exam period
- Western Cape Mock Exam
- Paper
- 2
- Curriculum
- CAPS
- Pages
- 15
- File size
- 776.8 KB
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Grade 12 Mathematics P2 2 WCED/September 2015
INSTRUCTIONS AND INFORMATION
Read the following instructions carefully before answering the questions.
1. This question paper consists of 11 questions.
2. Answer ALL the questions in the ANSWER BOOK provided.
3. Clearly show ALL calculations, diagrams, graphs, et cetera which you
have used in determining the answers.
4. Answers only will NOT necessarily be awarded full marks.
5. You may use an approved scientific calculator (non-programmable and
non-graphical), unless stated otherwise.
6. If necessary, round off answers to TWO decimal places, unless stated
otherwise.
7. Write neatly and legibly.
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Grade 12 Mathematics P2 3 WCED/September 2015
QUESTION 1
The data in the table below represents the score in percentage of 12 Mathematics
learners in their Grade 12 trial examination and their corresponding final examination.
Trial
76 64 90 68 70 79 52 64 61 71 84 70
Exam
Final
82 69 94 75 80 88 56 81 76 78 90 76
Exam
1.1 Determine the equation of the least squares regression line for this set of data. (3)
1.2 Hence, predict the final percentage for a learner obtaining 73% in the trial
examination. Give your answer to the nearest percentage. (2)
1.3 Calculate the correlation coefficient for the above data. (2)
1.4 Do you think that by using the least squares regression line one can accurately
predict a learner’s final percentage? Provide Mathematical justification for your
answer. (2)
[9]
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Grade 12 Mathematics P2 4 WCED/September 2015
QUESTION 2
The time taken (to the nearest minute) for a certain task to be completed was recorded
on 48 occasions and the following data was obtained:
Time Cumulative
(in minutes) Frequency
11 t < 15 6
15 t < 19 15
19 t < 23 28
23 t < 27 40
27 t < 31 48
2.1 Write down the modal class. (1)
2.2 Draw an ogive (cumulative frequency curve) for the given data. (4)
2.3 Determine, using the ogive, the interquartile range for the data. (3)
2.4 Use your graph to estimate in how many of the 48 occasions was this task
completed in more than 20 minutes? (2)
[10]
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Grade 12 Mathematics P2 5 WCED/September 2015
QUESTION 3
In the diagram, ABCD is a trapezium with AD | | BC and vertices A(x ; 7), B(–5 ; 0),
C( 1 ; –8) and D. DE BC with E on BC such that BE = EC. The inclination of AD
with the positive x-axis is θ and AD cuts the y-axis in F.
A(x ; 7)
y
F
x
B(–5 ; 0) O
D
E
C(1; –8)
3.1 Calculate the gradient of BC. (2)
3.2 Calculate the coordinates of E. (2)
3.3 Determine the equation of DE in the form y mx c . (3)
3.4 Calculate the size of . (3)
3.5 Calculate the size of OF̂D . (2)
3.6 Calculate the value of x if the length of AB 5 2 . (5)
3.7 Determine the equation of the circle with diameter BC in the form
( x a) 2 ( y b) 2 r 2 . (3)
[20]
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Grade 12 Mathematics P2 6 WCED/September 2015
QUESTION 4
In the diagram, the circle with centre M and equation x 2 y 2 4x 4 y 12 0 is
drawn. C is the x-intercept of the circle. The tangent AB touches the circle at A(–6 ; 4)
and cuts the x-axis at B.
y
A(–6 ; 4)
M
B
O C x
4.1 Calculate the
4.1.1 coordinates of M. (2)
4.1.2 coordinates of C. (3)
4.2 Determine, giving reasons, the equation of the tangent AB in the form y = mx + c
1
if it is given that the gradient of MC is .
2 (4)
4.3 Calculate the area of ∆ABC. (5)
4.4 Determine for which values of k the line y 2 x k will intersect the circle at two
points. (5)
[19]
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Grade 12 Mathematics P2 7 WCED/September 2015
QUESTION 5
5.1 If sin 31° = p, determine the following, without using a calculator, in terms of p:
5.1.1 sin 149° (2)
5.1.2 cos (–59°) (2)
5.1.3 cos 62° (2)
5.2 Simplify the following expression to a single trigonometric ratio:
tan(180 ).sin 2 (90 ) cos( 180).sin (6)
sin 2 x sin x
5.3 Consider: tan x
cos 2 x cos x 1
5.3.1 Prove the identity. (5)
5.3.2 Determine the values of x, where x [180° ; 360°], for which the above
identity will be invalid/undefined. (2)
[19]
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Grade 12 Mathematics P2 8 WCED/September 2015
QUESTION 6
6.1 Determine the general solution of : sin (x + 30°) = cos 3x. (6)
6.2 In the diagram below, the graph of f (x) = sin (x + 30°) is drawn for the interval
x [–30° ; 150°].
y
1
f
x
–30° 0° 30° 60° 90° 120° 150°
–1
6.2.1 On the same system of axes sketch the graph of g, where g(x) = cos 3x, for
the interval x [–30° ; 150°]. (3)
6.2.2 Write down the period of g. (1)
6.2.3 For which values of x will f ( x) g ( x) in the interval x (–30° ; 150°)? (3)
[13]
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Grade 12 Mathematics P2 9 WCED/September 2015
QUESTION 7
In the diagram below, A, B and C are in the same horizontal plane. P is a point
vertically above A. The angle of elevation from B to P is .
AĈB β , AB̂C θ and BC = 20 units.
P
A
B
C
20
7.1 Write AP in terms of AB and . (2)
20 sin β tan α
7.2 Prove that AP (3)
sin (θ β)
7.3 Given that AB = AC, determine AP in terms of and in its simplest form. (3)
[8]
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Grade 12 Mathematics P2 10 WCED/September 2015
PROVIDE REASONS FOR ALL YOUR STATEMENTS AND CALCULATIONS IN
QUESTION 8, 9 10 AND 11.
QUESTION 8
In the diagram, O is the centre of the circle. A, B, C and D are points on the
circumference of the circle. Diameter BD bisects chord AC at E. Chords AB, CD and
AD are drawn. Ĉ 43 .
C
B
43°
O E
1
2
1 D
A
8.1 Give a reason for DE AC. (1)
8.2 Calculate, giving reasons, the size of B̂ . (2)
8.3 Prove that Ê1 BÂD . (2)
8.4 The length of the diameter of the circle is 28 units. Calculate the length of AB. (2)
[7]
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Grade 12 Mathematics P2 11 WCED/September 2015
QUESTION 9
In the diagram, O is the centre of the circle. A, B, C and D are points on the
circumference of the circle and CB is the diameter of the circle. Chord CA intersect
radius OD at E. AB is drawn. CD | | OA and  2 x .
A
D
1
2
x
E
1 2
B
1 2
O
1 2
C
9.1 Give reasons why
9.1.1 Ĉ1 x (1)
9.1.2 Ĉ 2 x (1)
9.2 Determine, giving reasons, the size of the following angles in terms of x.
9.2.1 Â1 (3)
9.2.2 Ô1 (2)
9.2.3 Ô 2 (2)
9.3 For which value of x will ABOE be a cyclic quadrilateral? (3)
[12]
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Grade 12 Mathematics P2 12 WCED/September 2015
QUESTION 10
10.1 Complete the following statement of the theorem in the ANSWER BOOK:
If two triangles are equiangular, then the corresponding sides are … (1)
10.2 In the diagram, DGFC is a cyclic quadrilateral and AB is a tangent to the circle at
B. Chords DB and BC are drawn. DG and CF produced meet at E and DC is
produced to A. EA | | GF.
E
1 2
G
2
1
1
2 F
2
D
1 2
1 2
C A
1
2 1
B
10.2.1 Give a reason why B̂1 D̂1 . (1)
10.2.2 Prove ABC | | | ADB . (3)
10.2.3 Prove Ê 2 D̂ 2 . (4)
2
10.2.4 Prove AE AD AC . (4)
10.2.5 Hence, deduct that AE = AB. (3)
[16]
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Grade 12 Mathematics P2 13 WCED/September 2015
QUESTION 11
11.1 In ABC below, D and E are points on AB and AC respectively such that
AD AE
DE | | BC. Prove the theorem that states that .
DB EC (6)
A
D E
B C
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Grade 12 Mathematics P2 14 WCED/September 2015
11.2 In the diagram below, P is the midpoint of AC in ABC. R is a point on AB such
AR 3
that RS | | BP and . RC cuts BP in T.
AB 5
A
S
P
R
T
B
C
Determine, giving reasons, the following ratios:
AS
11.2.1 (4)
SC
RT
11.2.2 (3)
TC
Area of ΔTPC
11.2.3 (4)
Area of ΔRSC
[17]
TOTAL : 150
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Grade 12 Mathematics P2 15 WCED/September 2015
INFORMATION SHEET
b b 2 4ac
x
2a
A P(1 ni) A P(1 ni) A P(1 i) n A P(1 i) n
Tn a (n 1)d Sn
n
2a (n 1)d
2
Tn ar n 1
Sn
a r n 1 ;r 1 S
a
; 1 r 1
r 1 1 r
F
x 1 i n 1 P
x 1 1 i n
i i
f ( x h) f ( x )
f ' ( x) lim
h 0 h
x x y y2
d ( x2 x1 ) 2 ( y 2 y1 ) 2 M 1 2 ; 1
2 2
y 2 y1
y mx c y y1 m( x x1 ) m m tan
x 2 x1
x a 2 y b2 r 2
a b c
In ABC: a 2 b 2 c 2 2bc. cos A
sin A sin B sin C
1
area ΔABC ab. sin C
2
sinα β sin α.cos β cos α.sin β sinα β sin α.cos β cos α.sin β
cosα β cos α.cos β sin α.sin β cosα β cos α.cos β sin α.sin β
cos2 sin 2
cos 2 1 2 sin 2 sin 2 2 sin . cos
2 cos2 1
n
fx (x x) i
2
x 2 i 1
n n
n( A )
P(A) P(A or B) = P(A) + P(B) – P(A and B)
n(S)
x x (y y)
yˆ a bx b
2
(x x)
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