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PREPARATORY EXAMINATION
2022
MARKING GUIDELINES
LIFE SCIENCES PAPER 2 (10832)
14 pages
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Life Sciences Grade 12 P2 Gauteng Mock 2022 Memo (English)
Grade 12 Life Sciences Paper 2 memorandum from the Gauteng Mock Exam 2022 (English), 14 pages. Read online or download the free PDF.
Life Sciences · Grade 12 · Gauteng Mock Exam · 2022 · English. Memorandum, 14 pages. Read online or download the PDF.
- Subject
- Life Sciences
- Grade
- Grade 12
- Language
- English
- Document type
- Memorandum
- Year
- 2022
- Exam period
- Gauteng Mock Exam
- Paper
- 2
- Curriculum
- CAPS
- Pages
- 14
- File size
- 373.7 KB
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This exam
Gauteng Mock Exam 2022
Questions in this paper
- Question 1.1MEIOSIS16 marks
- Question 1.2RESPONDING TO THE ENVIRONMENT (Humans)7 marks
- Question 1.3GENETICS AND INHERITANCE6 marks
- Question 1.4DNA: THE CODE OF LIFE5 marks
- Question 1.5GENETICS AND INHERITANCE4 marks
- Question 1.6GENETICS AND INHERITANCE6 marks
Show all 18 questions
- Question 1.7EVOLUTION6 marks
- Question 2.1GENETICS AND INHERITANCE4 marks
- Question 2.2GENETICS AND INHERITANCE10 marks
- Question 2.3GENETICS AND INHERITANCE8 marks
- Question 2.4MEIOSIS10 marks
- Question 2.5GENETICS AND INHERITANCE9 marks
- Question 2.6GENETICS AND INHERITANCE9 marks
- Question 3.2EVOLUTION11 marks
- Question 3.3EVOLUTION6 marks
- Question 3.4EVOLUTION3 marks
- Question 3.5EVOLUTION6 marks
- Question 3.6EVOLUTION16 marks
Document textSearch extracted text and jump to a page.
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PRINCIPLES RELATING TO THE MARKING OF LIFE SCIENCES
1. If more information than marks allocated is given
Stop marking when maximum number of marks is reached and place a wavy line
and 'max' in the right-hand margin.
2. If, for example, three reasons are required and five are given
Mark only the first three irrespective of whether all or some are correct/incorrect.
3. If whole process is given when only part of it is required
Read all and credit relevant part.
4. If comparisons are asked for and descriptions are given
Accept if differences/similarities are clear.
5. If tabulation is required but paragraphs are given
Candidates will lose marks for not tabulating.
6. If diagrams are given with annotations when descriptions are required
Candidates will lose marks.
7. If flow charts are given instead of descriptions
Candidates will lose marks.
8. If sequence is muddled and links do not make sense
Where sequence and links are correct, credit. Where sequence and links are
incorrect, do not credit. If sequence and links become correct again, resume credit.
9. Non-recognised abbreviations
Accept if first defined in answer. If not defined, do not credit the unrecognised
abbreviation but credit the rest of answer if correct.
10. Wrong numbering
If answer fits into the correct sequence of questions but the wrong number is given,
it is acceptable.
11. If language used changes the intended meaning
Do not accept.
12. Spelling errors
If recognisable, accept, provided it does not mean something else in Life Sciences
or if it is out of context.
13. If common names are given in terminology
Accept, provided it was accepted at the memo discussion meeting.
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14. If only letter is asked for and only name is given (and vice versa)
No credit.
15. If units are not given in measurements
Candidates will lose marks. Memorandum will allocate marks for units separately.
16. Be sensitive to the sense of an answer, which may be stated in a different way.
17. Caption.
All illustrations (diagrams, graphs, tables, etc.) must have a caption.
18. Code-switching of official languages (terms and concepts)
A single word or two that appears in any official language other than the learners'
assessment language used to the greatest extent in his/her answers should be
credited, if it is correct. A marker that is proficient in the relevant official language
should be consulted. This is applicable to all official languages.
19. Changes to the marking guidelines
No changes must be made to the marking guidelines without consulting the
provincial internal moderator.
3
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SECTION A
QUESTION 1
1.1 1.1.1 B
1.1.2 B
1.1.3 C
1.1.4 D
1.1.5 A
1.1.6 C
1.1.7 A
1.1.8 C (8 x 2) (16)
1.2 1.2.1 Incomplete ✓dominance
1.2.2 Chiasma ✓/chiasmata
1.2.3 Nucleotide ✓
1.2.4 Foramen magnum ✓
1.2.5 Colour-blindness ✓
1.2.6 Homozygous ✓
1.2.7 Karyotype ✓ /Karyogram (7 x 1) (7)
1.3 1.3.1 B only ✓✓ (2)
1.3.2 None ✓✓ (2)
1.3.3 Both A and B ✓✓ (2)
(6)
1.4 1.4.1 Nucleus ✓
Ribosome ✓ (2)
1.4.2 Three✓/3 (1)
1.4.3 Peptide ✓ bond (1)
1.4.4 GGU ✓ (1)
(5)
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1.5 1.5.1 Codominance ✓ (1)
1.5.2 BW ✓ /WB (1)
1.5.3 1 black and white : 1 black
Mark for correct phenotypes (P) ✓
Mark for correct ratio (R) ✓
Do not accept % – ratio asked (2)
(4)
1.6 1.6.1 Dihybrid ✓ (1)
1.6.2 (a) Bbrr ✓✓ (2)
(b) BR and bR ✓✓ / BR, BR, bR, bR (2)
1.6.3 Species-specific courtship behaviour ✓ (1)
(6)
1.7 1.7.1 Cultural ✓evidence (1)
1.7.2 Homo sapiens ✓
(Learners must underline scientific name to get the mark.
Capital ‘H’ for Homo genus and lower case ‘s’ for sapien species) (1)
1.7.3 Homo habilis✓/H. habilis
Homo erectus✓/H. erectus (2)
1.7.4 Acheulian ✓ /Mousterian (1)
1.7.5 Mousterian ✓ (1)
(6)
TOTAL SECTION A: 50
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SECTION B
QUESTION 2
2.1 2.1.1 C and D ✓ (1)
2.1.2 The soldier inherits half of his DNA from his mother and half from his
father. ✓
The DNA bars/black bands/black bars of the dead soldier are a combination
of the DNA bars/black bands/black bars of parents C and D. ✓ (2)
2.1.3 − identification of criminals ✓/forensic evidence
− identification of genetic disorders ✓
− developing cures for genetic disorders ✓
− tissue type for organ transplant ✓
Mark FIRST ONE only.
Candidates may not use identification of dead body OR paternity OR
identification of relatives as these are in the question. (1)
(4)
2.2 2.2.1 Inter ✓ (phase) (1)
2.2.2 (Gene) Mutation ✓ (1)
2.2.3 G-G ✓ (1)
2.2.4 – incorrect nitrogenous base sequence results in different DNA strand ✓/
abnormal strand
– will result in wrong genetic code ✓ for daughter cells formed/
wrong/nonsense/different proteins could be formed (2)
2.2.5 Table showing differences between DNA replication and transcription
DNA replication Transcription
A whole DNA molecule used ✓ A part (gene) of the DNA unwinds
exposing the gene ✓
An (identical) DNA molecule is An mRNA molecule is formed ✓ /
formed ✓ /double strand of DNA single strand of RNA
Important for cell division/mitosis/ Important for protein synthesis ✓
meiosis ✓
Both strands of DNA act as One strand of DNA acts as a
templates ✓ template ✓
DNA nucleotides are used ✓ RNA nucleotides are used ✓
Adenine bonds with thymine ✓ Adenine bonds with uracil ✓
Any TWO comparisons + correct table format (T ✓) (5)
Mark first TWO only
(10)
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2.3 2.3.1 2 – glycine ✓
4 – alanine ✓ (2)
2.3.2 Three ✓/3 OR four/4 (1)
2.3.3 Translation ✓ *
− Each tRNA carries a specific amino acid ✓
− when the anticodon on the tRNA ✓
− matches the codon on the mRNA ✓
− then tRNA brings the required amino acid to the ribosome ✓
− amino acids become attached to each other by peptide bonds ✓
− to form the required protein ✓
1 compulsory* + any 4 (5)
(8)
2.4. 2.4.1 Anaphase ✓ I/1/II /2 (1)
2.4.2 (a) 2✓ (1)
(b) Two ✓/2 (1)
2.4.3 Paternal ✓/father
Maternal ✓/mother (2)
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2.4.4
Diagram of a cell in metaphase II
cell membrane
centrosome/centriole
spindle fibre
chromatid/chromosome
centromere
cytoplasm
Note: The diagram in 2.4.4 must correlate to the learner’s answer in 2.4.1.
If 2.4.1. anaphase I/1 then 2.4.4 diagram of metaphase I/1
If 2.4.1. anaphase II/2 then 2.4.4 diagram of metaphase II/2
Criteria Marks
Caption (C) 1
Correct drawing phase (P) 1
Any TWO labels (L) 2
TOTAL 4 (4)
2.4.5 22 ✓ (1)
(10)
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2.5 2.5.1 (a) Three ✓/3 (1)
(b) One ✓/1 (1)
2.5.2 AB ✓ (1)
2.5.3
Pie chart showing the average percentage of different
blood groups in the world
19,8
120,6
Bloodgroup
blood group A
A
Bloodgroup
blood group B
B
Bloodgroup
blood group O
O
162
Bloodgroup
blood group AB
AB
57,6
Calculations
Total = 100
Blood group A Blood group B Blood group O Blood group AB
= 33,5 x 360 = 16,0 x 360 = 45,0 x 360 = 5,5 x 360
100 100 100 100
= 120,6o = 57,6o = 162o = 19,8o
Rubric for the mark allocation of the pie chart
Heading: (H) Both variables included 1
Type: (T) Circle drawn with a compass and four 1
segments shown by lines from centre to
circumference
Plot: (P) 1 – 2 segments plotted accurately 1
3 - 4 segments plotted accurately 2
Calculations: (C) 1 – 3 calculations correct 1
All calculations correct 2
TOTAL 6
NOTE: If the wrong type of graph is drawn, marks will be lost for
“correct type of graph” as well as for drawing the slices in
correct proportions. (6)
(9)
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2.6 2.6.1 (a) nn ✓ (1)
(b) Nn ✓ (1)
2.6.2 Law of dominance ✓ (1)
2.6.3 P1 Phenotype Spotted fur x striped fur ✓
Genotype Nn x nn ✓
Meiosis
G/gametes N, n x n, n✓
Fertilisation
F1 Genotype Nn Nn nn nn ✓
1 Nn : 1 nn ✓
F1 Phenotype 2 spotted fur : 2 striped fur * ✓ OR
1 spotted fur : 1 striped fur
* Compulsory mark
P1 and F1 ✓
Meiosis and fertilisation ✓
*Compulsory 1 + any 5
OR
P1 Phenotype Spotted fur x striped fur ✓
Genotype Nn x nn ✓
Gametes N n
Meiosis n Nn nn
n Nn nn
Fertilisation
1 mark for correct gametes
1 mark for correct genotypes
F1 Genotype Nn Nn nn nn ✓
1 Nn : 1 nn ✓
F1 Phenotype 2 spotted fur : 2 striped fur * ✓ OR
1 spotted fur : 1 striped fur
* Compulsory mark
P1 and F1 ✓
Meiosis and fertilisation ✓
*Compulsory 1 + Any 5 (6)
(9)
[50]
10
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QUESTION 3
3.1 3.1.1 Most of the family are affected ✓/have Rett syndrome / all females (1,4 and 6)
have Rett syndrome / even the heterozygous are affected. (1)
3.1.2 5 ✓ (1)
3.1.3 To explain the males probability:
− Only have one X-chromosome ✓
− Either have the recessive allele thus unaffected ✓
− Or has dominant allele thus affected ✓
− Only a 50% chance of being affected ✓ Any TWO (2)
To explain the females probability:
− Have two X chromosomes ✓
− Have a 75% chance of being affected ✓
− Whether she is homozygous dominant ✓/XR XR
− or heterozygous ✓/XR Xr Any TWO (2)
3.1.4 (a) 100 ✓ (1)
(b) XRXr ✓ (1)
(8)
3.2 3.2.1 (a) Claw size ✓ (1)
(b) Mating success ✓ (1)
3.2.2 Three investigations ✓were conducted./The investigation was repeated
three times / used large sample size / used 15 crabs (1)
3.2.3 Use the same species/type of crab ✓
Same number of male and female crabs ✓
Same cage ✓
Mark first TWO only. (2)
3.2.4 Wear protective clothing ✓/gloves to protect against nipping from claws ✓
Provide appropriate habitat for crabs with sufficient food ✓/water/ shelter to
ensure crab survival ✓
Mark first ONE only. (2)
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3.2.5 According to the law of use and disuse ✓:
− All the male fiddler crabs had short claws ✓ originally
− The male fiddler crabs frequently waved ✓their claws more,
− To attract females to reproduce ✓
− The claws eventually became bigger ✓
− The bigger claw acquired in this way was then passed on to the next
generation ✓
− Eventually all the male fiddler crabs had a large claw. ✓
Any four (4)
(11)
3.3. 3.3.1 Recessive dwarf mutation ✓ (must be full answer for mark allocation) (1)
3.3.2 (a) The sheep jumped over fences/got lost/ran away/loss of sheep/
loss of revenue (1)
(b) − Less damage to fences ✓ so reduces the need for tall
fences ✓/saves money/spends less on fence repairs.
− Short legs limited the sheep’s ability to run,✓ they were less
active thus reducing the number of lost sheep. ✓
− Less money and time wasted, ✓ less need to locate sheep that
jumped over the fences.
− Sheep are safer, ✓less stock loss to predators.
Cause and effect any ONE (1 x 2 = 2) (2)
3.3.3 The intentional breeding of individuals ✓ by humans in a population to
achieve a desirable phenotype /desirable trait. (2)
Any TWO (6)
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3.4 3.4.1 (a) Longer ✓ jaw (1)
(b) Frog ✓/mice/ small prey (1)
3.4.2 (a) A group of organisms with similar characteristics that can
interbreed ✓ and produce fertile offspring. ✓ (2)
(b) Possibility of how speciation could occur:
− The population of tiger snakes could become separated by the
sea *✓
− the population splits into two ✓
− There will be no gene flow between the two populations. ✓
− Since each population may be exposed to different diets/prey
sizes *✓
− natural selection could occur independently in each of the two
populations ✓
− such that the individual species of the two populations become
very different from each other ✓
− genotypically and phenotypically. ✓
− Even if the two populations were to mix again, ✓
− they will not be able to interbreed. ✓
− The two populations are now different species.
TWO compulsory marks* Any other FIVE points (7)
(11)
3.5 3.5.1 − Evolution takes long periods of time ✓
− where very little ✓/gradual/no change occurs (known as equilibrium).
− This alternates with (is punctuated by) short periods of time ✓
− where rapid change occurs. ✓
− through natural selection ✓*
1 compulsory mark + any 3 points (4)
3.5.2 B to C ✓ (1)
3.5.3 No ✓ (1)
(6)
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3.6 3.6.1 (a) Larger ✓ (temporal muscle attaches to a larger jaw) which increases
the ability to chew harder food✓/bite power (2)
(b) Larger teeth ✓/Canines increase the ability to rip and tear tough raw
food ✓ (2)
3.6.2 (Skull) B ✓ (1)
3.6.3 Large brain ✓
Eyes in front ✓
Binocular vision ✓ /stereoscopic vision
Eyes with cones ✓ / colour vision
Freely rotating arms ✓
Long/er upper arms ✓
Rotation around elbow joints ✓
Five fingers ✓ per hand
Bare fingertips or nails instead of claws ✓
Opposable thumb ✓
Upright posture ✓
Sexual dimorphism ✓
Two mammary glands ✓
Mark FIRST THREE only (3)
(8)
[50]
TOTAL SECTION B: 100
TOTAL: 150
14
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