Mathematical Literacy Grade 11 P2 2026 Memo (Eng)

Mock hlayiso mock exams Practice Series: Grade 11 Exam Preparation WWW.HLAYISO.COM NATIONAL SENIOR CERTIFICATE GRADE 11 MATHEMATICAL LITERACY P2 NOVEMBER EXAMINATION 2026 (MOCK) MARKING GUIDELINES MARKS: 100 These marking guidelines consist of 7 pages. Copyright reserved Please turn over

Mathematical Literacy/P2 2 Hlayiso/Mock 2026 NSC – Marking Guidelines SYMBOL AND EXPLANATION Symbol Explanation Symbol Explanation M Method A Accuracy MA Method with accuracy CA Consistent accuracy C Conversion D Definition F Choosing the correct formula SF Substitution in a formula J Justification O Opinion/Reason/Example P Penalty (e.g. no units, incorrect rounding) R Rounding RT/RM Reading from a table/map S Simplification NPR No penalty for rounding AO Answer only, full marks KEY TO TOPIC AND LEVEL: M = Measurement; MP = Maps, plans and other representations; P = Probability; L1–L4 = cognitive levels 1 to 4 NOTE: • If a candidate answers a question TWICE, only mark the FIRST attempt. • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however, it stops at the second calculation error. • Answers only, without working, are awarded full marks unless stated otherwise. In ”verify” questions the conclusion (J) is only awarded if it is supported by a calculation. QUESTION 1 1.1.1 Sugar = 3 × 15 mℓ ✓C multiplying by 15 = 45 mℓ ✓A answer M L1 (2) 1.1.2 (Cooking/deep-fry/oil) thermometer ✓✓A instrument M L1 (2) 1.1.3 ◦ C = (350 − 32) ÷ 1,8 ✓SF substitution = 318 ÷ 1,8 ✓S simplification = 176,666 . . . ≈ 176,7 ◦ C ✓R answer to 1 decimal place M L2 (3) 1.1.4 Number of recipes = 150 ÷ 24 = 6,25 ✓M dividing by 24 Flour = 6,25 × 1 kg = 6,25 kg ✓CA 6,25 kg flour Bags = 6,25 ÷ 2,5 = 2,5 ✓M dividing by 2,5 ⇒ 3 bags ✓R rounding up to 3 bags (Alternative: flour per vetkoek = 1 000 g ÷ 24 = 41,67 M L3 (4) g; 150 × 41,67 g = 6 250 g) Copyright reserved Please turn over

Mathematical Literacy/P2 3 Hlayiso/Mock 2026 NSC – Marking Guidelines 1.1.5 05:50 + 20 min = 06:10 ✓M adding kneading time 06:10 + 1 h 15 min = 07:25 ✓M adding rising time 07:25 + 1 h 40 min = 09:05 ✓CA finishing time 09:05 09:05 is 5 minutes AFTER the market opens. ✓J conclusion ∴ The claim is NOT valid. M L3 (4) (OR total time = 20 + 75 + 100 = 195 min = 3 h 15 min; 05:50 + 3 h 15 min = 09:05) 1.2.1 650 mℓ ✓✓A reading (Accept 640 mℓ – 660 mℓ) M L1 (2) 1.2.2 650 mℓ − 625 mℓ ✓M subtracting 625 mℓ = 25 mℓ ✓CA answer (CA from 1.2.1) M L2 (2) 1.3.1 Perimeter is the total distance (length) around the ✓✓D definition outside of a shape / figure. M L1 (2) 1.3.2 Diameter = 1,2 × 100 = 120 cm ✓C converting to cm C = 3,142 × 120 cm ✓CA answer = 377,04 cm (Answer in m, 3,77 m: max 1 (Accept 377 cm; NPR) mark) M L1 (2) [23] Copyright reserved Please turn over

Mathematical Literacy/P2 4 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 2 2.1.1 N16 ✓✓RM MP L1 (2) 2.1.2 South-east (SE) ✓✓A direction MP L2 (2) 2.1.3 Map distance = 10,8 cm ✓A measuring map distance (Accept 10,6 cm – 11,0 cm) ✓A measuring bar Bar scale: 4 cm represents 40 km ✓M 1 cm = 10 km ∴ 1 cm represents 10 km ✓M multiplying Actual distance = 10,8 × 10 km ✓CA answer in km = 108 km MP L3 (5) (Accept 106 km – 110 km; otherwise CA from the candidate’s own map and bar measurements, i.e. map cm × 40÷ bar cm) 2.1.4 4 cm : 40 km ✓M bar length and distance = 4 cm : 4 000 000 cm ✓C converting to cm = 1 : 1 000 000 ✓CA simplified scale (Accept 1 : 975 610 – 1 : 1 025 641 (CA) from a MP L3 (3) measured bar of 3,9 cm – 4,1 cm) 2.1.5 Towns on a national road: Lindela, Siyakhula, ✓RM 5 towns Khanyisa, Emthonjeni, Nqabeni = 5 ✓M dividing by 8 5 P = × 100% ✓CA percentage 8 P L2 (3) = 62,5% 150 km 2.2.1 Driving time = = 1,666 . . . h ✓SF substitution 90 km/h = 1 h 40 min ✓C 1 h 40 min Total time = 1 h 40 min + 20 min = 2 h ✓M adding the stop Arrival = 07:50 + 2 h = 09:50 ✓CA arrival time 10:00 − 09:50 = 10 minutes before the start ✓J conclusion 10 min < 15 min ∴ The claim is NOT valid. M L3 (5) Copyright reserved Please turn over

Mathematical Literacy/P2 5 Hlayiso/Mock 2026 NSC – Marking Guidelines 2.2.2 Return distance = 150 × 2 = 300 km ✓M return distance Diesel = 300 ÷ 9,6 = 31,25 ℓ ✓M dividing by 9,6 Cost = 31,25× R21,35 = R667,19 ✓M multiplying by R21,35 Per player = R667,19 ÷15 = R44,48 ✓CA amount per player (Accept R44,47 – R44,48) M L3 (4) [24] QUESTION 3 3.1.1 Volume is the amount of space that a 3-dimensional ✓✓D definition object takes up (occupies). M L1 (2) 3.1.2 Radius = 7 ÷ 2 = 3,5 cm ✓A radius V = 3,142 × (3,5)2 × 12 ✓SF substitution = 461,874 ≈ 461,87 cm3 ✓CA answer (Accept 461,9 cm3 or 462 cm3 ; NPR) M L2 (3) 3.1.3 Mass of 1 candle = 461,874 × 0,9 g = 415,69 g ✓M multiplying by 0,9 Mass for 120 candles = 415,69 × 120 ✓M multiplying by 120 = 49 882,39 g = 49,88 kg ✓C converting to kg Blocks = 49,88 ÷ 5 = 9,98 ✓M dividing by 5 ⇒ 10 blocks ✓R rounding up to 10 M L3 (5) 3.1.4 Length = 3,142 × 7 + 1 = 21,994 + 1 = 22,994 cm ✓M circumference + 1 cm Height = 80% × 12 = 9,6 cm ✓A 9,6 cm Area = 22,994 × 9,6 ✓SF length × width = 220,74 cm2 ✓CA area M L3 (4) 3.1.5 Along 45 cm: 45 ÷ 7 = 6,43 ⇒ 6 candles ✓M✓R along the length Along 30 cm: 30 ÷ 7 = 4,29 ⇒ 4 candles ✓R along the width Candles per layer = 6 × 4 = 24 ✓CA 24 per layer Layers: 26 ÷ 12 = 2,17 ⇒ 2 layers ✓M 2 layers Total = 24 × 2 = 48 candles ✓J 48 and conclusion 48 > 40 ∴ The claim is VALID. (Using volume ratio only, 35 100 ÷ 461,87 = 76: max 2 marks) M L4 (6) Copyright reserved Please turn over

Mathematical Literacy/P2 6 Hlayiso/Mock 2026 NSC – Marking Guidelines 3.1.6 TSA = 2(45 × 30) + 2(45 × 26) + 2(30 × 26) ✓SF substitution = 2 700 + 2 340 + 1 560 ✓S simplification = 6 600 cm2 ✓CA answer M L2 (3) 3.1.7 Diameter = 3,5 × 2,54 = 8,89 cm ✓C converting to cm Radius = 8,89 ÷ 2 = 4,445 cm ✓A radius 1 000 = 3,142 × (4,445)2 × h ✓SF substitution h= 1 000 = 16,108 . . . ✓CA height (1 decimal) 62,08 . . . M L3 (4) ≈ 16,1 cm [27] QUESTION 4 4.1.1 Right-hand side ✓✓RM MP L1 (2) 4.1.2 Rows 1–13: 13 × 4 = 52 seats ✓M 52 seats Minus 2 (middle door) and 2 (toilet): 52 − 4 = 48 ✓M subtracting 4 Plus back row: 48 + 5 = 53 seats ✓CA total 53 (Counting AO: full marks) MP L2 (3) 4.1.3 Window seats: A-column 12 + D-column 12 + 14A ✓RM 26 window seats and 14E = 26 ✓M dividing by 53 26 ✓CA percentage P= × 100% 53 P L2 (3) = 49,06% (CA from 4.1.2) (Accept 24 49 = 48,98% if row 1 is excluded with a stated reason) 4.1.4 Any ONE valid reason, e.g. ✓✓O valid reason - They are close to the driver and the front door. MP L4 (2) - They can see/supervise the learners and talk to the driver. - They can get off first to control learners at stops. Copyright reserved Please turn over

Mathematical Literacy/P2 7 Hlayiso/Mock 2026 NSC – Marking Guidelines 4.1.5 53 seats = learners + teachers ✓M learners + teachers = 53 If 48 learners: teachers needed = 48 ÷ 10 = 4,8 ⇒ 5 ✓M 1 teacher per 10 learners 48 + 5 = 53 (fits) ✓R rounding up teachers If 49 learners: teachers needed = 4,9 ⇒ 5; ✓CA 48 learners 49 + 5 = 54 > 53 (does not fit) MP L4 (4) ∴ Maximum = 48 learners 4.1.6 Cost = 386× R14,50 + R1 200 ✓M multiplying by 14,50 = R5 597 + R1 200 = R6 797 ✓M adding R1 200 Per learner = R6 797 ÷48 = R141,60 ✓CA cost per learner R141,60 > R140 ∴ The claim is NOT valid. ✓J conclusion M L3 (4) 4.2.1 Washers = 12 × 15 ✓RT 12 per chair = 180 washers ✓CA answer MP L2 (2) 4.2.2 4 mm Allen key and 10 mm spanner ✓A Allen key ✓A spanner MP L1 (2) 15 4.3.1 P= × 100% ✓M dividing by 400 400 = 3,75% ✓A percentage P L1 (2) 15 385 4.3.2 P(not win) = 1 − = ✓M 1− P(win) or 385 tickets 400 400 = 0,9625 (accept 0,96) ✓CA decimal P L2 (2) [26] TOTAL: 100 Copyright reserved Please turn over