Skip to content

Physical Sciences Grade 11 Paper 1 KZN November 2024 Memo

MemorandumPhysical SciencesGrade 11202425 pages

Grade 11 Physical Sciences Paper 1 memorandum from the KZN November Exam 2024, 25 pages. Read online or download the free PDF.

Free to read online, no sign-up needed

Loading document…

Loading document…

Document textSearch extracted text and jump to a page.
Downloaded from Stanmorephysics.com KWAZULU-NATAL PROVINCE EDUCATION REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE 150 TIME : 3hours This question paper consists of 12 pages and 3 data sheets. Copyright Reserved Please turn over
2 Physical Soweshaaded from Stanmexapdaysics.com November 2024 INSTRUCTIONS AND INFORMATION il Write your NAME in the appropriate spaces on the ANSWER BOOK. 2 This question paper consists of 8 questions. Answer ALL the questions in the ANSWER BOOK. Ks Start EACH question on a NEW page in the ANSWER BOOK. 4. Number the answers correctly according to the numbering system used in this question paper. 5. Leave ONE line between two sub questions, for example between QUESTION 2.1 and QUESTION 2.2. 6. You may use a non-programmable calculator. te You may use appropriate mathematical instruments. 8. Show ALL formulae and substitutions in ALL calculations. 9. Round off your final numerical answers to a minimum of TWO decimal places. 10. Give brief motivations, discussions et cetera where required. Tt You are advised to use the attached DATA SHEETS. 12. Write neatly and legibly. Copyright Reserved Please turn over
Physical scRewnloaded from Stannergphygics.com November 2024 QUESTION 1: MULTIPLE CHOICE QUESTIONS Four options are provided as possible answers to the following questions. Each question has only ONE correct answer. Write only the letter (A — D) next to the question number (1.1 — 1.10) in the ANSWER BOOK. 1.1. Which ONE of the following pairs can be classified as scalar quantities? A Mass and inertia B Inertia and weight Cc Weight and frictional force D __ Frictional force and mass (2) 1.2. The vertical component of a force acting on an object moving horizontally... A accelerates the object horizontally. B accelerates the object vertically. c has a tendency to move the object vertically. D has a tendency to move thesobjectyh (2) 1.3 Acrate is moved, fr ; horizontal surface by a force F. Which O} f the fo! ents about the kinetic frictional force acting on t The kinetic onal force is ... A greater than the maximum static frictional force and less than F. B greater than the maximum static frictional force and greater than F. Cc less than the maximum static frictional force and greater than.F.. D less than the maximum static frictional force and less than F. (2) 1.4 Consider the following statements related to Newton's third law: When a force acts on an object, (i) the reaction to this force acts on the same object. (ii) the reaction to this force acts on a different object. (iii) the time for which the force acts is greater than the time for which the reaction to this force acts. (iv) _ the force and the reaction to this force are in opposite directions. Which of the above statements is/are true? A (i) and (iv) only. B (ii) and (iv) only. Cc (i), (iii) and (iv) only. D (ii), (iii) and (iv) only. (2) Copyright Reserved Please turn over
Physical 1.5 wnloaded from Stanmoreph ics.com ciences P1 NSC Grade 11 November 2024 The acceleration versus resultant force graphs for the motion of objects X and Y are shown below. Which ONE of the following statements is true? A Object X has a greater mass than object Y. B Object Y has a greater mass than object X. Cc If both objects experience the same acceleration, the resultant force on object X is greater than that on object Y. D For the same resultant force, object X has a smaller acceleration than object Y. 1.6 The magnitude of the gravitational acceleration on Earth is g. What will the value of the gravitational acceleration be on planet X, which has the SAME mass as Earth, but HALF the radius of Earth? A “wg B 4g Cc ’Ag D 29 1.7 Asmall test charge, q, is placed exactly halfway between two fixed identical charged spheres, X and Y, each carrying a charge of +Q, as shown in the diagram below. xX ¥' > O< eo ; *@ +Q +Q The net electrostatic force experienced by the test charge will be... A towards X. B towards Y. Cc zero. D greater than zero. Copyright Reserved (2) (2) (2) Please turn over
Downloaded from Stanmorephysics.com Physical Sciences P1 November 2024 1.8 The minimum resistance that can be obtained by connecting two 4 Q resistors in a circuit is ... A 8a B 40 Cc 3Q D 20 (2) 1.9 The two resistors in CIRCUIT 1 below are identical. They are connected to a cell with emf V and negligible internal resistance. The power dissipated by each resistor is P. i |! CIRCUIT 1 The same resistors are now GéAhed parallel, as shown in CIRCUIT 2. What is the power dissipated by each resistor in CIRCUIT 2? A 2P B 4P Cc 8P D 16P (2) 1.10 Abar magnet is moved into and out of a solenoid. Which ONE of the following changes will result in a LARGER induced emf in the solenoid? A Using a weaker magnet. B Using a solenoid with fewer turns. [e} Using a solenoid with a smaller diameter. D Moving the magnet faster into and out of the solenoid. (2) [20] Copyright Reserved Please turn over
Downloaded from Stanmorephysics.com Physical Sciences P1 NSC Grade 11 November 2024 QUESTION 2 : (Start on a new page) Three co-planar forces, F1, F2 and Fs of magnitude 6 N, 3 N and 4 N respectively act on an object. The sketch below, not drawn to scale, shows the directions of the forces. 2.1 2:2 Define resultant force. (2) Calculate the: 2.2.1 Magnitude of the resultant force acting on the object (8) 2.2.2 Direction of the resultant force (3) [13] QUESTION 3: (Start on a new page) 3.1 3.2 3.3 Define inertia. (2) A passenger is seated in a fast-moving taxi when the taxi driver suddenly slams on the brakes. Use your knowledge of Newton's laws to explain why the passenger moves forward when the brakes are applied. (3) Explain why wearing a seat belt is a safety measure for the occupants of a vehicle. (2) Copyright Reserved Please turn over
Physical wnlogded from Stanmorephys om November 2024 3.4. Acrate of mass 80 kg lies on a rough plane inclined at 25° to the horizontal. The crate begins to slip when the angle of inclination exceeds 25°. Refer to the diagram below. 3.4.1 Define the term static friction. (2) 3.4.2 Draw a free-body diagram showing all the forces acting on the crate. (3) 3.4.3 Define the term normal force. (2) 3.4.4 Calculate the magnitude of the normal force. (3) 3.4.5 Calculate the magnitude of the maximum static frictional force acting on the crate. (3) 3.4.6 Calculate the coefficient of static friction between the crate and the plane. (3) 3.4.7 _ If the mass of the crate is increased, will the crate begin to slide? Choose from YES or NO. Explain the answer. (3) 3.4.8 If the angle of inclination is changed from 25° to 20°, how would this change affect the static frictional force acting on the crate? Choose from INCREASES, DECREASES, or REMAINS THE SAME. Explain the answer. (3) [29] Copyright Reserved Please turn over
Downloaded from Stanmeréphysics.com —a" Physical QUESTION 4: (Start on a new page) Two blocks of masses 1 kg and 3 kg are connected by a light, inextensible string. The blocks are initially at rest on a smooth horizontal surface. A force F of magnitude 9 N is applied to the 3 kg block, as shown in the diagram below. 4.1 State Newton's Se in in words. (2) 4.2 Drawa free-body di showing all the forces acting on the 3 kg block. (4) 4.3 By applying news eenane aw to each block separately, calculate the: 4.3.1 Magnitude of the acceleration of the blocks (5) 4.3.2 Tension in the string (2) 4.4 The 1 kg block is replaced by a block with a bigger mass, while the force applied on the 3 kg block remains unchanged. State whether the tension calculated in Question 4.3.2 will INCREASE, DECREASE or STAY THE SAME. Give a reason for the answer. (3) QUESTION 5: (Start on a new page) = 5.1. State Newton's Law of universal gravitation in words. (2) 5.2 Differentiate between the MASS and the WEIGHT of an object. (2) 5.3. A70kg mountain climber reaches the top of Mount Everest, 8,85 km above sea level. Take the surface of Earth to be sea level. At the top of Mount Everest, determine the: 5.3.1 Acceleration due to gravity (4) 5.3.2 Mountain climber’s weight (3) 5.4 Alearner makes the following statement: “An astronaut orbiting Earth experiences weightlessness because he or she is beyond the pull of Earth’s gravity’. 5.4.1. Define weightlessness. (2) 5.4.2 Is the statement correct? Choose from YES or NO. Explain the answer. (3) [16] Copyright Reserved Please turn over
Physicaleganenlagded from StanmareRnys (¢s.com November 2024 QUESTION 6: (Start on a new page) The diagram below shows two identical spheres, A and B on insulated stands, carrying charges of -4yC and +4C respectively. The distance between the centres of the spheres is 0,40 m. 0,40 m -4uC (8 )+4uc 6.1. State Coulomb's Law in words. (2) 6.2 Calculate the electrostatic force that sphere A exerts on sphere B. (4) 6.3 Draw the electric field pattern due to the two spheres. (3) sphere, sphere C, carrying a charge of ining the centres of the spheres, as 6.4. Define electric field at a point. (2) 6.5 _ If the net electric field at point P is zero, calculate the distance between point P and the centre of sphere A. (6) [17] Copyright Reserved Please turn over
physicals aleqded from Stanmecephys i¢ S.com November 2024 QUESTION 7: (Start on a new page) The battery inthe circuit diagram below has an internal resistance r. The ammeters and connecting wires have negligible resistance. © Si oly Both switches S: and Sz are initially closed. The reading on voltmeter V2 is 18 V and the power dissipated by resistor R is 12 W. 7.1 Calculate the: 7.1.1 Resistance of resistor R (3) 7.1.2 Reading on the ammeter (5) 7.1.3 Potential difference across the 10 Q resistor (3) 7.2 When switch Si is opened the reading on voltmeter Vi changes to 41,9 V. Calculate the internal resistance of the battery. (4) 7.3 Switch S2 is now opened while S: is closed. Will the reading on the ammeter INCREASE, DECREASE or REMAIN THE SAME? Give a reason for the answer. (2) Copyright Reserved Please turn over
Downloaded from Stanmorephysics.com Physical Sciences P1 NSC Grade 11 November 2024 7.4 Alearner sets up the circuit shown below to investigate Ohm's Law for each of two resistors X and Y. Ignore the internal resistance of the battery. 12V Si @) We XorY fw) ay, The following graphs were obtained from the results of the investigation. 12 10 = s 3) 8 =e6 $ 4 2 01 02 03 04 05 06 07 08 0,9 rh Current(A) Yr 7.4.1. State Ohm’s Law in words. (2) 7.4.2 Use the graph to determine the resistance of resistor Y. (4) 7.4.3 Resistors X and Y are connected in series to a battery in a circuit. Which resistor, X or ¥ will be more suitable to boil the same mass of water at a faster rate in an electric kettle? Give a reason for the answer. (3) [26] Copyright Reserved Please turn over
Downloaded from Stanmorephysi Sics.com — ljovember Physical Sciences P1 QUESTION 8: (Start on a new page) In the diagram below the north pole of a bar magnet is being pushed into a coil. The emf induced in the coil is recorded by a galvanometer. 8.1 When the bar magnet moves in and out o} magnet exert a force on each other | S ELECTROSTATIC or MAGNETIC? (1) 8.2 State the direction of the induced current through the galvanometer. Choose A to B or B to A (2) 8.3. Write down the reading on the galvanometer when the bar magnet is at rest inside the coil. (1) 8.4 Acoilis made up of 100 turns of insulated copper wire, each having a circular area of 4,8 x 10% m2. The coil is placed in a uniform magnetic fi eld of 3,9 x 10 T in such a way that the angle between the magnetic field and the normal to the circular plane of the coil is 30°. The coil is then rotated so that the angle changes to 70° in 0,2 s. 8.4.1 State Faraday's law of electromagnetic induction in words. (2) 8.4.2 Calculate the magnitude of the emf induced in the coil. (4) 8.4.3 Calculate the current induced in the coil if it has an effective resistance of 2 Q. (3) [13] TOTAL: 150 Copyright Reserved Pisane turnover
Downloaded from Stanmorephysics.com DATA FOR PHYSICAL SCIENCES GRADE 11 PAPER 1 (PHYSICS) GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 11 VRAESTEL 1 (FISIKA) TABLE 1: PHYSICAL CONSTANTS / TABEL 1: FISIESE KONSTANTES Radius van Aarde NAME / NAAM SYMBOL / SIMBOOL VALUE / WAARDE Acceleration due to gravity 9,8 m-s? Swaartekragversnelling Universal gravitational constant fey 6,67 x 10° N-m?-kg? Universele gravitasiekonstante Speed of light in a vacuum c 3,0 x 10° m-s* Spoed van lig in 'n vakuum Planck’s constant h 6,63 x 10% J-s Planck se konstante Coulomb's constant k 9,0 x 109N-m2-C2 Coulomb se konstante Charge on electron e -1,6 x 10°79C Lading op electron Electron mass Me 9,11 x 10°31 kg Elektronmassa Mass of Earth M 5,98 « 104 kg Massa van Aarde Radius of Earth Re 6,38 x 10®m Copyright Reserved Please turn over
Downloaded from Stanmorephysics.com TABLE 2: FORMULAE / TABEL 2: FORMULES MOTION / BEWEGING VE =v +aAt Ax =v, At + tadt? or/of Ay = v,At + taat? v2 =Vv\2-+2aAxorlofv,” =v,’ + 2aAy Ax = (4 Jae orlof Ay = (“sts Jas FORCE / KRAG Fret =a fs(™* = sN fk = UkN w=mg F= Gm, M2 x Gm 2 ee ELECTROSTATICS / ELEKTROSTATIKA kQ4Q2 kQ F=—t2 Ex r2 r@ fet e-F q q n=2 ORIOF n=2 e Ge ELECTRIC CIRCUITS / ELEKTRIESE STROOMBANE R Vv emf (€) =1(R+r) “aT R, =R, +R, + a q-tet R, R, R, Copyright Reserved Please turn over
Downloaded from Stanmorephysics.com W=Vq pW W=VIAt At ‘ P=VI W=FRAt P=?R _ V2At ” We R R ELECTRODYNAMICS A@ e=-N>- @ = BACos 0 Copyright Reserved
Downloaded from Stanmorephysics.com NA) KWAZULU-NATAL PROVINCE EDUCATION REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE GRADE 11 MARKS: 150 These marking guidelines consist of 10 pages. Copyright Reserved Please turn over
Physica] Sciences P1 2 . November 2024 Term 4 Test wnloaded from Stanmorephysics.com QUESTION 1 1.1. Avv 12 Cvv' 1.3. Dvv 14 BYY 15 ByYv 16 ByYy 17 Cv¥¥ 18 Dvv 19 BYv 1.10 Dvv QUESTION 2 2:4 Marking criteria If any of the underlined key words/phrases in the correct context is omitted deduct 1 mark Resultant force is the vector sum of two or more forces acting togetherY OR That single force having the same effectv as two or more forces acting together. v 2.2.1 (2) (2) (2) (2) (2) (2) (2) (2) (2) (2) [20] (2) Vector Resultant x-component 5,83 N v (to the right) y-component 3,17 N v¥ (Upwards) NOTE: If the 0 N is implied for the x—cot y—component of F2, award the marks indicated by the rin R2= Rx? + Ry a R? = 5,832 + 3,172¥ R =6,64NV 2.2.2 POSITIVE MARKING FROM Q 2.2.1 Ry NOTE: Award the formula mark H to the substitution if formula is R not given. 1 1 8 R Rx = tan 8= ad 237 tan 0= SB 6 = 28,53° North of East ¥ OR 6 = 61,47° East of North / Bearing. (8) (3) [13] Copyright Reserved Please turn over
Physica] Sciences P1 November 2024 Term 4 Test wnloaded from Stanmorephysics. com QUESTION 3 3.1 Inertia is the resistance of an object to any changes in its state of motion. vv (2OR0). (2) 3.2 e Passenger and taxi move with the same velocity before brakes are applied. v e When brakes are applied, the net force acts on the taxiv (and not the passenger). «Due to inertia the passenger continues to move forward.” (3) 3.3. The occupant moving forward exerts a force on the seat belt. By Newton’s third law, the seat belt exerts an equal force in the opposite direction” to prevent the occupant from moving forward.” (2) 3.4.1 | Marking criteria If any of the underlined key words/phrases in the correct context is omitted deduct 1 mark Static frictional force is the force that opposes the tendency of motion of a stationary object relative to a surface. Vv (2) 3.4.2 W | Fg/Fw/Fearth on P/weight /mg /784 N /gravitational force f | Fr/fs/(static) friction N | Fn/Normal /Fnormal Notes: Mark awarded for label and arrow. Do not penalise for length of arrows since drawing is not to scale. e Any other additional force(s): Max 2/5 e If everything correct, but no arrows: Max 2/5 e If force(s) do not make contact with the dot: Max 2/5 (3) Copyright Reserved Please turn over
Q3.4.7 Correct answer is : NO.✔Both the parallel component of the gravitational force and the maximum static frictional force increase✔ by the same magnitude.✔
Physical Sciences P1 wnloaded from Stanmorephysics.com QUESTION 4 November 2024 Term 4 Test Marking criteria If any of the underlined key words/phrases in the correct context is omitted deduct 1 mark 41 4.2 When a resultant/net for the force at ania object will accelerate in the direction of fo the force” and inversely proportional (2) Accepted labels W | Fg/Fw/Fearth on P/weight /mg /88,2 N /gravitational force T | Fr/Fstring /Ft/tension. F | Fapplied/ Fapp / 9 N N | Fn/Normal /Frormat Notes: Mark awarded for label and arrow. e Do not penalise for length of arrows since drawing is not to scale. e Any other additional force(s): Max 3 A e If everything correct, but no arrows: Max x e If force(s) do not make contact with the dot: Max % (4) Copyright Reserved Please turn over
Physical Sciences P1 November 2024 Term 4 Test ownloaded from Stanmorephysics. com 4.3.1. MARKING CRITERIA e Fhet = ma (for either block)¥ e Substitution of T and mass for 1 kg blockY e Substitution on the left-hand side for the 3 kg block.” e Substitute 3 kg on the right-hand side for the 3 kg block. e Answer. ¥ For the 1 kg block Fret = ma ¥ T = 1av -----------------------------------eqn. 1 For the 3 kg block Fret = ma Fx-T=ma (9 cos25° - T)v= BAW aaccnccsesicceasances eqn. 2 Therefore a = 2,04 m:s?v 4.3.2 POSITIVE MARKING FROM Q 4.3 OPTION 1: OPTION 2: T=1a Fapp- T=ma T = 1(2,04) (9 cos25° - T) = 3 (2,04)v T = 2,04 NVY T = 2,04 NY 44 IncreaseY The increased mass of the smaller block increases the load, “ requiring a bigger force to pull it.v OR T = Fcos25 — 3a. Y Acceleration decreases, VY hence T increases. QUESTION 5 Marking criteria niverse attracts every other particle with a gravitational force that is | to the product of their masses and inversely proportional to the f matter contained in the body. Weight is the force with which the y-v NOTE: If candidate states: Mass is a scalar quantity, while weight it is a vector quantity, award 1 mark only. (2) (3) [16] (2) (2) Copyright Reserved Please turn over
Physical Sciences P1 November 2024 Term 4 Test 5.3.1 5.3.2 5.4.1 5.4.2 ownloaded from Stanmorephysics. com g> Slt _ 6a x10" x 5,98 x10%v (6,38%10°+ 8850)” = 9,77 m:s?v downwards / towards the Earth’s centre OPTION 1 OPTION 2 POSITIVE MARKING FROM Q 5.3.1 Fg= = Smim amg sereio" ga UL Se ee Fo= (6,38%10° 8850)" " = Ze |, 38x + acini w = 684,04 Nv The sensation experienced when all contact forces are removed / in free fall. vv (2 OR 0). No.¥ The gravitational force exerted by Earth still exists in orbit. ~ Astronauts experience weightlessness because the only force acting on them is the gravitational force. ¥ QUESTION 6 6.1 Marking criteria 6.2 Copyright Reserved If any of the underlined key words/phrases in the correct context is omitted deduct 1 mark The magnitude of the (electrostatic) force exerted by one point charge (Q1) on another point charge (Qz2) is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance (r) between them. Vv Fe= 910° x4 x10%x 4 x10%) y (0,4)? = 0,9 NY towards A/ to the leftY k Q4Q) 2 v NOTE: Direction must be marked independent of answer. (4) (3) (2) (3) [16] (2) (4) Please turn over
Physica] Sciences P1 November 2024 Term 4 Test ownloaded from Stanmorephysics. com 6.3 . 3) Marking Criteria: e Correct direction of field — from positive to negative charge. v e Field lines not touching each other and starting from / touching the surfaces of the spheres. W e Correct shape. ¥ 6.4 | Marking criteria If any of the underlined key words/phrases in the correct context is omitted deduct 1 mark The electric field at a point is the electrostatic force experienced per unit positive charge placed at that point. vv (2) 6.5 | Marking Criteria: Ea + Ec =0 Any one v Ea = Ec e Correct vector equation equating Ea and Es.v kKQa , _ _kQp ¢ Correct formula to calculate electric field. v 2” 4-12 ° Substitution to calculate Ea. ¥ 4x 10° 9x10 8v ¢ Substitution to calculate Es. vv 2 ys oa ney e Final answer (r = 0,16 m). “ (0,4 - 1) r=0,16 mv (6) [17] Copyright Reserved Please turn over
Physical Sciences P1 November 2024 Term 4 Test 9 ownloaded from Stanmorephysics.com QUESTION 7 711 5_¥ p= tv _ 18? 12=2v R= 2704 7.1.2 | OPTION 1: OPTION 2: POSITIVE MARKING FROM Q7.1.1: lIr= vy 1 if 1 = —=—+—v¥ OR =Ri*Roy P =Viv OR Rp Ry Re Ro Re Rp 12 = 18 IRV = By | 1 1 27 Bae = 2M2, Ir =0,67A Reesgiq0 l= Bv V2 18 lp = Rp” lyo= aa” 18. ly2=1,5A 331 ing= +15 =2,17AV = 2,17 AV -. ammeter reading is 2,17 A Arinety teading “0.87 + 15° 2.178 7.1.3 POSITIVE MARKING FROM Q7.1.2: V=IRVY V =2,17 x 10¥ V=21,7 V¥ 7.2 | OPTION 1: OPTION 2: POSITIVE MARKING FROM Q7.1.2 & Q7.1.3 POSITIVE MARKING FROM Q7.1.2 ~ Viost ="44,9 = (21,7 +18) V E=\(R+nv haul 220, 41,9Y = 2,17((8,31+10) +r) ¥ Most = Irv aa r= 1,00 QV 2,20 = 2,17rv OR €= Vext +Ir ¥ Wy =40inv 41,9Y = (21,7418) + 2,171 7.3. Decrease.v Rrot increases. V 7.4.1 | Marking criteria If any of the underlined key words/phrases in the correct context is omitted deduct 1 mark The potential difference across a conductor is directly proportional to the current in the conductor at constant temperature. Vv va a NOTES: “-& Gradient = rid Any ordered pair, correctly read from the graph = 120) "= 43339 can be used. ; a (0,9-0) W y The fourth mark is for clearly indicating that the Therefore, the resistance of Y is 13,33 Qv |_aradient is the resistance. 7.4.3 Y. ¥ The higher the resistance the higher the power output / P « Rv (I is constant) thus more energy dissipated in the resistor per unit time / per second / in a given time. ¥ Copyright Reserved (3) (4) (2) (4) (3) [26] Please turn over
Physical Sciences P1 November 2024 Term 4 Test ownloaded from Stanmorephysics. com QUESTION 8 8.1 Magnetic force. v (1) 8.2 AtoBYY (2) 8.3 Zero. (1) 8.4.1 | Marking criteria 8.4.2 8.4.3 If any of the underlined key words/phrases in the correct context is omitted deduct 1 mark The magnitude of the induced emf across the ends of a conductor is directly proportional to the rate of change in the magnetic flux linked with the conductor. vv (2) A 7 ne Ve -D 39°) g= sa a ny one ¥ (BACos 70 - BACos30) = -NQ At (3,9x10“x4,8 x 10% Cos 70¥ - 3,9x10% x 4,8x10% Cos30v) € =-100 0,2 & =4,90 x 105 vv (4) POSITIVE MARKING FROM Q8.4.2 e€=IR/V=IRY 4,90 x 105 = (2) v | =2,45x 10° Av (3) [13] TOTAL: 150 Copyright Reserved Please turn over

Study this subject

More from Grade 11 Physical Sciences

View all