Mathematical Literacy Grade 12 P2 2024 Memo (Eng)

NATIONAL SENIOR CERTIFICATE GRADE 12 SEPTEMBER 2024 MATHEMATICAL LITERACY P2 MARKING GUIDELINES MARKS: 150 Symbol Explanation M Method MA Method with accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification RT Reading from a table/graph/diagram SF Correct substitution in a formula O Opinion/Explanation/Reasoning P Penalty, e.g. for no units, incorrect rounding off etc. R Rounding Off/Reason NPR No penalty for correct rounding minimum two decimal places AO Answer only MCA Method with consistent accuracy RCA Rounding with consistent accuracy This marking guidelines consist of 12 pages. Hosted by www.ecexams.co.za.

2 MATHEMATICAL LITERACY P2 (EC/SEPTEMBER 2024) MARKING GUIDELINES NOTE: • If a candidate answers a question TWICE, only mark the FIRST attempt. • If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled) version. • Consistent Accuracy (CA) applies in ALL aspects of the marking guidelines; however, it stops at the second calculation error. • If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalise for every extra incorrect item presented. LET WEL: • As ʼn kandidaat ʼn vraag TWEE keer beantwoord, merk slegs die EERSTE poging. • As ʼn kandidaat ʼn antwoord van ʼn vraag doodtrek (kanseleer) en nie oordoen nie, merk die doodgetrekte (gekanseleerde) poging. • Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyne toegepas, maar dit hou by die tweede berekeningsfout op. • Wanneer ʼn kandidaat aflees van ʼn grafiek, tabel, uitlegplan, en kaart en ekstra antwoorde gee, penaliseer vir elke ekstra verkeerde item. Copyright reserved Please turn over Hosted by www.ecexams.co.za.

(EC/SEPTEMBER 2024) MATHEMATICAL LITERACY P2 3 KEY TO TOPIC SYMBOL: F = Finance; M = Measurement; MP = Maps, Plans and Other representations; P = Probability QUESTION 1 [28 MARKS] ANSWER ONLY FULL MARKS Ques. Solution Explanation Level 1.1.1 125 1M divide by 1000 M Volume of heavy whipping cream = 1 000 M 1A answer L1 = 0,125 litres A (2) 1.1.2 50 Grams of cocoa powder needed for 12 people = 4 × 12 ✓MA 1MA divide by 4 M and multiply by 12 L1 = 150 g A 1A answer OR 12 OR Grams of cocoa powder needed for 12 people = 4 ×50 ✓MA 1MA divide by 4 = 150 g A and multiply by 50 1A answer (2) 1.1.3 Total time = (15 min + 6 min) 1MA adding time M = 21 min × 2 MA and multiply by 2 L1 = 42 minutes A 1A answer (2) 1.1.4 Time = 12:05 1M subtracting M = 0:21 (prep. and cooking) both times L1 = 1:00 (chilling) M 1A correct time = 10:44 A (2) 1.2.1 A OR Word Scale A AND 1A first scale MP C OR Ratio ScaleA 1A second scale L1 (2) 1.2.2 Winburg ✓A 2A correct town MP (2) L1 1.2.3 4 national roads ✓RT 2RT number of MP national roads L1 (2) 1.2.4 Edenburg ✓RT 2RT correct town MP (2) L1 1.3.1 Radius = 132 ÷ 2 M 1M divide by 2 M = 66 cm A 1A correct radius L1 (2) Copyright reserved Please turn over Hosted by www.ecexams.co.za.

4 MATHEMATICAL LITERACY P2 (EC/SEPTEMBER 2024) 1.3.2 Total number of tanks = 920 × 2 MA 1MA multiply correct M = 1 840 A values L1 1A number of tanks (2) 1.3.3 B ✓A OR cubic metres ✓A 2A correct unit M L1 (2) 1.3.4 The diameter is the distance from one side of the circle to the 2A definition M other side of the circle, through the centre of the circle. ✓A (2) L1 1.4.1 Number of days = 5 ✓A 2A correct number of M (Accept 4 days = 1 Mark) days L1 (2) 1.4.2 Year born = 2024 – 57 M 1M subtracting 57 from M = 1967 ✓A 2024 L1 1A correct year (2) [28] Copyright reserved Please turn over Hosted by www.ecexams.co.za.

(EC/SEPTEMBER 2024) MATHEMATICAL LITERACY P2 5 QUESTION 2 [34 MARKS] Ques. Solution Explanation Level 2.1.1 National Roads ✓A 2A correct road MP (2) L1 2.1.2 Northeast OR NE ✓A 2A correct direction MP (2) L1 2.1.3 Eastern Cape 2A correct province MP (2) L2 ✓A 2.1.4 Speed = Distance MP Time L3 614,6 km SF 1SF substitution 120 km/h = Time 614,6 km 1MA change subject Time = MA 120 km/h and answer = 5,121666667 hours 0,12166… × 60 = 7,3 minutes C 1C hours to minutes Time taken to reach Vryheid = 5 hours and 7,3 minutesCA 1CA total time (Accept 5 hours and 7 minutes) (4) 2.2.1 • From the Free State, drive on the N3 till she reaches 1O N3 MP Pietermaritzburg. O 1O left on N2 and L4 • Pass Pietermaritzburg and turn left onto the N2. passing Richard’s Bay Continue driving on the N2 till she passes Richard’s and Empangeni Bay, turn left and pass Empangeni. O 1O continue to Eshowe • Continue on the road from Empangeni until she reaches from Empangeni Eshowe. O (Accept any other relevant explanation.) (3) 2.2.2 5,9 1MA dividing correct Number of litres of petrol = × 614,9 l MA 100 values and multiply by = 36,2614 × 2 M 614,9 = 72,5228 1M multiply by 2 CA ≈ 72,523 litres 1CA number of litres (Accept 72,5 OR 72,52) NPR (3) 2.2.3 Petrol cost = 72,523 litres × R24,45 MCA CA from 2.2.2 F = R1 773,18735 1MCA multiply by L1 ≈ R1 773,19 CA R24,45 1CA answer (2) Copyright reserved Please turn over Hosted by www.ecexams.co.za.

6 MATHEMATICAL LITERACY P2 (EC/SEPTEMBER 2024) 2.3.1 One unit on the map represents 350 units in reality. ✓A 2A explanation MP L1 OR ✓A One unit on the map equals 350 units on the floor. (2) 2.3.2 Elevator ✓A OR Stairs ✓A 2A one correct feature MP (2) L1 2.3.3 Hata Street entrance ✓A 2A correct entrance MP (2) L1 2.3.4 Number of restrooms = 4 ✓A 2A correct number of MP restrooms L2 (2) 2.3.5 Impossible OR None OR 0 OR 0% ✓A 2A answer P (2) L2 2.3.6 34 mm ✓A 2A correct length in mm MP (Accept 33 – 35 mm) (2) L1 2.3.7 Actual length = 34 × 350 CA from 2.3.6 MP = 11 900 mm MCA 1MCA multiply with L2 11 900 correct scale and answer ⸫ = 1 000 C 1C divide by 1000 = 11,9 m ✓MCA 1MCA answer = 12 m R 1R rounding (Accept 11,55 m – 12,25 m) and (12 m) (4) [34] Copyright reserved Please turn over Hosted by www.ecexams.co.za.

(EC/SEPTEMBER 2024) MATHEMATICAL LITERACY P2 7 QUESTION 3 [30 MARKS] Ques. Solution Explanation Level 3.1.1 Area of rectangular school hall = length × width M = 18 m × 12 m SF 1SF substitution L3 = 216 m2 A 1A area Area of stage = length × width = 10 m × 5,5 m = 55 m2 A 1A area Area of floor to be tiled = 216 m2 – 55 m2 MCA 1MCA subtracting areas = 161 m2CA 1CA answer (5) 3.1.2 Area of tile = 60 cm × 60 cm M 1M calculating area M (a) = 3 600 cm2 1C conversion L2 3 600 = 100 × 100 C 1CA area in m2 = 0,36 m2 CA OR 1C conversion OR C 1M calculating area Area of tile = 0,6 m × 0,6 m M 1CA area in m2 = 0,36 m2 CA (3) 3.1.2 161 CA from 3.1.1 and M Number of tiles needed = MCA (b) 0,36 3.1.2(a) L2 = 447,22… × 1,1 M 1MCA dividing correct = 491,94 … values ≈ 492 tiles CA 1M multiply by 10% 1CA number of tiles (3) 3.1.2 Cutting OR breakages OR wastage ✓O 2O reason M (c) (2) L4 Copyright reserved Please turn over Hosted by www.ecexams.co.za.

8 MATHEMATICAL LITERACY P2 (EC/SEPTEMBER 2024) 3.1.3 Scale = 60 mm : 18 m M 1M correct ratio M = 60 : 18 000 C 1C converting 18m to mm L3 S C 1S unit ratio = 1: 300 OR OR M Scale = 60 mm: 18 m 1M correct ratio = 0,06: 18 C 1C converting 6 mm to m = 1 : 300 S 1S unit ratio (3) 3.2.1 Diameter = 8 cm × 2 M 1M multiplying by 2 M = 16 cm × 10 1C diameter in mm L2 = 160 mm C OR OR C Diameter: 8 cm × 10 = 80 mm 1C diameter in mm M 1M multiplying by 2 ⸫ 80 mm × 2 = 160 mm (2) 3.2.2 Dimensions of unshaded part: M Length = 28,5 cm – 2,5 cm – 2,5 cm M 1M subtracting 2,5 twice L3 = 23,5 cm CA from length 1CA length Width = 22 cm – 2,5 cm – 2,5 cm 1CA width = 17 cm CA (3) 3.2.3 Perimeter = 2 (length + width) CA from 3.2.2 M = 2 (23,5 cm + 17 cm) SF 1SF correct length and L1 = 81 cm CA width 1CA perimeter (2) 3.2.4 Area of certificate without border and (circle included) CA from 3.2.2 M = length × width L4 = 23,5 cm × 17 cm SF 1SF correct dimensions = 399,5 cm2 MCA 1MCA area Area of circle = 3,142 × radius2 = 3,142 × 82 SF 1SF substitution = 201,088 cm2 CA 1CA area of circle ⸫ Area of unshaded part (excluding border and circle): = 399,5 cm2 – 201,088 cm2 MCA 1MCA subtracting areas = 198,412 cm2 1CA unshaded area ≈ 198 cm2 CA 1O opinion ⸫ Her statement is valid O (7) [30] Copyright reserved Please turn over Hosted by www.ecexams.co.za.

(EC/SEPTEMBER 2024) MATHEMATICAL LITERACY P2 9 QUESTION 4 [35 MARKS] Ques. Solution Explanation Level 4.1.1 Dimensions in mm = 17 inch × 25,4 1C converting M = 431,8 mm C dimension L2 ⸫ Volume = length × width × height 1SF substitution = 431,8 mm × 431,8 mm × 431,8 mm SF 1CA volume = 80 509 645,43 mm3 CA (3) 4.1.2 Total surface area: M = 2 (l × w) + 2 (l × h) + 2 (w × h) L4 = 2 (431,8 × 431,8) + 2 (431,8 × 431,8) + 2 (431,8 × 431,8) SF 1SF substitution = 372 902,48 + 372 902,48 + 372 902,48 M 1M multiply by 2 2 = 1 118 707,44 mm 1 118 707,44 1C conversion ⸫ TSA = C 1 000 000 1CA surface area = 1,12 m2CA (Accept 1,119 m2) 1O opinion ⸫ His statement is invalid O OR OR Total surface area: = 2 (l × w) + 2 (l × h) + 2 (w × h) 1C conversion = 2 (0,4318 × 0,4318 ) + 2 (0,4318 × 0,4318 ) + 2 (0,4318 × 1SF substitution 0,4318) C SF 1M multiply by 2 = 0,37290248 + 0,37290248 + 0,37290248 M 1CA surface area = 1,12 m2CA (Accept 1,119 m2) 1O opinion ⸫ His statement is invalid O NPR (5) 4.1.3 2,2 1M dividing correct MP Number of boxes in length = M 0,4318 values L3 = 5,094… 1A number of boxes = 5 boxes A 1,5 Number of boxes in width = 0,4318 1A correct number = 3,473… of boxes = 3 boxes A 1,6 Number of boxes in height = 0,4318 1A correct number = 3,705… of boxes = 3 boxes A 1MCA Total number of boxes =5×3×3 multiplication and = 45 boxes MCA total number of boxes (5) Copyright reserved Please turn over Hosted by www.ecexams.co.za.

10 MATHEMATICAL LITERACY P2 (EC/SEPTEMBER 2024) 4.2.1 Distance = Speed × Time 18h48min = 18,8 hrs C 1C converting time MP 1 268 = Speed × 18,8 h SF 1SF substitution L3 1 268 1M changing subject ⸫ Speed = M 18,8 1CA speed = 67,45 miles/h CA NPR (Accept 67 OR 67,447 OR 67,5 miles/h) (4) 4.2.2 1 157 miles = 1 862 km MP 1 862 1M dividing by 1 157 L2 1 mile = M 1 157 1CA answer = 1,609334… CA 1R rounding ≈ 1,609 km R (3) 4.3.1 Number of arches needed = 11 × 5 MA 1MA multiply correct M = 55 arches A values L2 1A number of arches (2) 4.3.2 Number of poles needed = 20 M 1M dividing by 5 M 5 1CA number of poles L2 = 4 poles CA (2) 4.3.3 Number of steel rods needed = 11 arches × 5 pegs M 1M multiply correct M = 55 steel rods CA values L4 The statement is valid O 1CA simplification 1O opinion (3) 4.3.4 Volume of a rectangular prism = length × width × height M C 1C conversion L3 = 1,2 × 1 × 1,4 SF 1SF substitution = 1,68 m3CA 1CA simplification = 1,68 kl C 1C total kilolitres (4) 4.3.5 Mask is for protection when spraying fertilisers. ✓O 2O opinion M (2) L4 4.3.6 Rainwater ✓A 2A answer M OR L4 Underground water ✓A OR Borehole ✓A (Accept any relevant answer.) (2) [35] Copyright reserved Please turn over Hosted by www.ecexams.co.za.

(EC/SEPTEMBER 2024) MATHEMATICAL LITERACY P2 11 QUESTION 5 [23 MARKS] Ques. Solution Explanation Level 5.1.1 Probability = 2 A 1A numerator P × 100% 6 A 1A denominator L2 = 33,33% CA 1CA % (NPR) (Accept 33,3% OR 33,333%) (3) 5.1.2 Actual distance = 815,6 km – 144,9 km M 1M subtract correct values MP = 670,7 km 1C conversion L2 ⸫ 670,7 × 1 000 C 1CA answer = 670 700 m CA (3) 5.1.3 81 560 000 1MA dividing correct values MP Map distance = MA 9 600 000 1CA answer L2 = 8,4958… CA 1R one decimal place ≈ 8,5 cm R (3) 5.1.4 Distance MP Speed = Time SF 1SF substitution L3 80 km/h = 815,6 km ÷ Time 815,6 km M Time = 1M changing subject 80 km/h = 10,195h 1CA time in hours and minutes = 10 hours 11 minutes 42 seconds CA 1A Total time for stopovers (1h ⸫ Time bus travelled = 10:11:42 45 min) A 1M subtract time M = 01:45:00 1CA time bus travelled = 08:26:42 NPR = 8 hours 26 minutes 42 seconds CA (Accept 8h 26 min OR 8h 27 min) (6) 5.2.1 The space left allow for movement of the fluid 2O opinion M during temperature change or transportation of the L4 bottles. ✓O (Accept any other relevant response.) (2) 5.2.2 3 Number of rectangular bottles in box = × 75 MA 1MA multiply correct fraction P 5 with 75 L2 = 45 A 1A number of rectangular bottles 45 ⸫ Probability = CA 1CA correct probability 75 (3) Copyright reserved Please turn over Hosted by www.ecexams.co.za.

12 MATHEMATICAL LITERACY P2 (EC/SEPTEMBER 2024) 5.2.3 Volume = 3,142 × radius2 × height 1SF substitution M = 3,142 × 42 × 5 SF L4 = 251,36 m3 ≈ 251 m3 CA 1CA volume ⸫ Pam’s statement is invalid O 1O opinion (3) [23] TOTAL: 150 Copyright reserved Please turn over Hosted by www.ecexams.co.za.