Mathematics Grade 12 Paper 1 KZN June 2023 Paper & Memo

Downloaded from Stanmorephysics.com KWAZULU-NATAL PROVINCE EDUCATION REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE ete Seba ees eee eeEs Be eeeeee eee eS « “ Ls 1" “ rh “ " " 1" “" " “ " " " " “" 1" " " Lo ” TCTTTITTTTTTTrTe te Ae 7 Pree 2? MARKS: 150 TIME: 3 hours

June 2023 Common Test Mathem§5Wnloaded from Stanmorephiysics.com INSTRUCTIONS AND INFORMATION Read the following instructions carefully before answering the questions. 1, This question-paper consists of 11 questions. Mn Ds Answer A’ ral estions. 1 & Clearly show ALL calculations, diagrams, graphs, et cetera that you have used in determining your answers. 4. Answers only will not necessarily be awarded full marks. 5. An approved scientific calculator (non-programmable and non-graphical) may be used, unless stated otherwise. 6. If necessary, answers should be rounded off to TWO decimal places, unless stated otherwise. 7. Diagrams are NOT necessarily drawn to scale. 8. Number the answers correctly according to the numbering system used in this question paper. Write neatly and legibly. Copyright Reserved Please Turn Over

Mathematics P1 Downloaded from Stanmorephysics.com QUESTION 1 1.1 12 1.3 Solve the following equations. 1.1.1 x=0 1.1.2 =—l1x+3 (give your answer to 2 decimal places) 1.1.3 x7 -2x<8 1.1.4 [2023 5, 9200 y apa pie —xX=x The roots of a quadratic equation are: ae 10+/-m-8 y , for which values of m are the roots non real? A rectangle has a length of (2x+ y) metres and a width of y metres as shown in the diagram. The perimeter of the rectangle is 24 metres and the area is 32m’. 2x+y 1.3.1 Show that the expression for the perimeter is: 24=4x+4y 1.3.2 Show that the expression for the area is : 32 =? +2xy 1.3.3 Determine the dimensions of the rectangle if x> 0. QUESTION 2 T, =—2n? +40n+103 is the general term of a quadratic sequence. 2.1 2.2 23 2.4 Determine 7, the first term of the quadratic sequence. Determine the second difference of this quadratic sequence. Which term of the quadratic sequence has a value of 301? Which term is the largest term in this quadratic sequence? Copyright Reserved June 2023 Common Test (3) (3) (4) (4) (2) ql) () (6) [24] (2) (2) (3) (2) 19] Please Turn Over

Mathematics P1 4 June 2023 Common Test Downloaded from Stanmoreph§Sics.com QUESTION 3 3.1 3.2 3.3 The following sequence is a combination of arithmetic and geometric sequence: 3 Bis Os: 6:5, 15:3 12s swecessses 3.1.1 ite down the next two terms. (2) 3.1.2 termine Ty —T,, (5) The given circle is completely divided into n sectors in such a way that the angles are in arithmetic sequence. If the smallest angle is 8° and the largest angle is 52°, calculate 7 ,the number of sectors. JN (4) George is currently 115 kilograms and his doctor has advised him to take up a healthy eating plan so as to lose some of the weight in order to maintain a healthy body. His new diet will enable him to lose 5 kilograms in the first week, thereafter he would lose : of the previous week’s weight loss each week. 33:1 If he follows the new eating plan, how many kilograms will he lose on the eighth day? Give your answer correct to 3 decimal 1 (2) places. 3.3.2 If he follows the new eating plan indefinitely, write his weight loss in sigma notation. (2) 33:3 If he follows the new eating plan indefinitely, what will his new weight eventually be? @) [18] Copyright Reserved Please Tur Over

Mathematics P1 5 Downloaded from Stanmorephi¥sics.com QUESTION 4 June 2023 Common Test The graph of h(x) = = + p Passes through points (2;-5) and (0;—1). 4.1 Write d € equation of the vertical asymptote of h. (1) 4.2 Write down the domain of h. (2) 4.3. - Determine the values of a and q. (6) 4.4 Draw the graph of h, showing the intercepts with the axes as well as the asymptotes. GB) [12] Copyright Reserved Please Turn Over

Mathematics P1 6 June 2023 Common Test Downloaded from Stanmorephysics.com QUESTION 5 The graphs of f(x)=-2(x-3)(x+1) and g (x) =mx +c are drawn below. Q is the x - intercept_of both graphs and E is the y - intercept of both graphs. D is the turning poi 7 . SP is parallel to the y - axis. x 51 Show that the coordinates of E are (0;6) @ 5.2 Determine the coordinates of D, the turning point of 7 . (4) 53 If h(x) =—f(x +3), determine the coordinates of the turning point of h. (2) 5.4 Write down the coordinates of Q () 5.5 Determine the equation of g . (3) 5.6 Determine the value of x, for which the length of SP between E and Q is a maximum. (3) 5.7 Determine the value of k for which f(x)=k has one negative an positive roots. (1) [15] Copyright Reserved Please Turn Over

Mathematics P1 ‘ June 2023 Common Test Downloaded from Stanmorephiysics.com QUESTION 6 The graph of A(x)=ax’ for x20 is drawn below. Point A (1;3) lies on the graph of h. y h A(1 ; 3) 5 x 6.1 Determine the value of a. (2) 62 Determine the equation of h' the inverse of h in the form y = ....... (2) 6.3 Draw the graph of h”', showing the coordinates of another point. (2) 64 Is A” a function? Motivate your answer. (2) Copynght Reserved Please Turn Over

June 2023 Common Test Mathematics P 1 8 SC. Downloaded from Stanmorephysics.com QUESTION 7 7A Convert a nominal interest rate of 7,12% p.a. compounded quarterly to a yearly effective interest rate. (3) 72 A trans; mpany purchases a new lorry to the value of R 1 250 000. 7.2.1 ulate the trade-in value of the lorry in 6 years’ time if the *s value decreases at 11% p.a. on a reducing balance. (2) 7.2.2 Calculate the value of a new lorry in 3 years’ time if the inflation rate remains at 7,5% over the next 3 years. (2) 7.2.3. | How much money will the company need in order to replace the lorry in 3 years’ time, if the old lorry will be used as a trade-in towards buying the new lorry. (2) 7.2.4 The company decides to save money in a sinking fund. They deposit equal amounts at the beginning of each year starting immediately. The last deposit is made at the end of the third year. Interest is calculated at 9,6% p.a. compounded monthly. (a) | How many deposits will the company make? (1) (b) How much will the company deposit each time? (5) [15] QUESTION 8 8.1 Given: f(x) =3x? +2x 8.1.1 Determine f'(x) from first principles. (5) 8.1.2 Determine the average gradient of f(x) between x =—1 and x=2 GB) 8.2 Determine the following: 8.2.1 g(x) if g(x) =(7x-1)(3-x) (2) ee x vx wx x 4) [14] Copyright Reserved Please Tum Over

Mathematics P1 9 Downloaded from Stanmorephisics.com QUESTION 9 June 2023 Common Test Given: f(x)=(x-3)(x-3)(x+2)=2° —4x? -3x +18 9.1 Write do e Y—intercept of 7 . (ql) 9.2 Write he co-ordinates of the xintercepts of / . (3) 9.3 Determine the co-ordinates of the turning points of / . (4) 9.4 Draw the graph of 7 , clearly indicating the intercepts with the axes and the co-ordinates of the turning points. (3) 9.5 Determine the equation of a tangent to / with a gradient of -3 at the point where x is an integer. (4) [15] QUESTION 10 In 2020, the scientists stated that the number of people infected with the Covid 19 Virus in a certain country was given by the equation N (¢) = -30 +3¢7,, where N(t) was the number of infected people in thousands and ¢ was the number of months. 10.1 How many people were infected at the beginning? (at zero months). (1) 10.2 At what rate was the virus spreading in the second month? (2) 10.3 After how many months did the virus reach its peak? (4) 10.4 How many people were infected when the virus reached its peak? (2) 19] Copyright Reserved Please Turn Over

Mathematics P1 10 Downloaded from Stanmoréphysics.com QUESTION 11 Td A study on June 2023 Common Test favorite cell phone of Grade 11 and Grade 12 learners at Greendale High Sc Ided the following results. IPHONE SAMSUNG TOTAL GRADE 11 a d 50 GRADE 12 b c 100 TOTAL 60 90 150 11.1.1 Are events Samsung and Grade 11 learners mutually exclusive? Motivate your answer. (2) 11.1.2. Ifthe learners’ preference for cell phones is independent of their grade, determine the value of d. (4) 11.2 During a TV Game Show, contestants have to answer randomly generated questions within a fixed time: ° The probability of the first question being answered correctly is 0,8. Whenever a question is answered correctly, the next question is more difficult and the probability of a correct answer is reduced by 0,1. . This means that the probability of getting the second answer correct is 0,7. . Whenever the question is answered incorrectly, the next question is of the same standard and the probability of it being answered correctly remains unchanged. 11.2.1 After how many consecutive correct answers will the probability of getting the next question correct, be zero? 11.2.2 Calculate the probability of getting the second answer corre TOTAL Copynght Reserved (1) (4) (4) Please Turn Over

Mathematics P1 jownloaded from Stanmorepliysics.com June 2023 Common Test INFORMATION SHEET: MATHEMATICS INLIGTING BLADSY _-bt Vb? -4ac 2a A= P(1+ni) = P(l=ni) A=P(1-i)" A=P(1+i)" T, =a+(n- S, =5Qa+(n-Dd) T, =ar"" gy -W' ol) ; r#l Soe"; aler< ee on l-r pastel] pal-a+") i i f(x) = lim S(x+h)- f(x) ho>0 h d= (x, =x)? +0, -y,)? M By 5 FY me 2 2 y=met+c y-y, =m(x-x,) = 22771 m=tanO X%2-% i snB snC sin(a + £) = sin a.cos B + cosa.sin B In AABC: cos(a + 8) =cosa.cos # —sin a.sin B cos* @—sin* a cos2a =41—2sin? a 2cos? a@-1 Copyright Reserved a? =b* +c? —2be.cos A area MABC = > ab.sin C sin(a — £)=sin a.cos 8 —cosa.sin B cos(a — 8) =cosa.cos B +sin a.sin B sin 2a@ = 2sin a.cos @ a 2 X“& -x) of = n P(A or B) = P(A) + P(B) pa e-FY-3) > @-xy" and B)

Downloaded from aah | Canaan FINAL KWAZULU-NATAL PROVINCE E ATION BLIC OF SOUTH AFRICA NATION NIOR CERTIFICATE GRADE 12 MARKS: 150 This memorandum consists of 20 pages. Please Turn Over Powered by @ CamScanner

“""ownloaded from Stanmanaphysics.com June 2023 Common Test 1.1.2 on ee -b+ IC e- 2a rel Van 46-3) 7 25) x=0,25 or-2,45 QUESTION 1 LA x(x-2)=0 AY factors x=0 or x=2 AY x=0 a Av x=2 (3) AY standard form CAY substitution CAY answers () Lis x? -2x-8<0 (x-4)(x+2)<0 4 - 4 ire a + 4 xe[-2;4] OR -2<x<4 OR x? -2x-8<0 (x-4)(x+2)<0 + \ / xe[-2;4] OR -2<x<4 AY’ standard form CAY factors CAV critical values AY correct notation OR AY standard form CAY factors CAV end values AY correct notation (4) 1.14 2 (241) > V3+x7-x=x 2 +X -xX=xX (Se¥=a) <2 3+xX-x=x" AY factors on the numerator CAY simplifying CAY squaring Copyright Reserved Please Turn Over Powered by @% CamScanner

Mathematics 3 r June 2023 Common Test ‘Bownloaded from Stanmanaphysics.com 3-x=0 x=3 CAY answer (4) 12 —m-8<0 AY -8<m AY answer R OR -m-8<0 AY —m<8 m>-8 AY answer (2) 1.3.1 Perimeter = 2/ + 2b 24=(2x+y)+y+(2x+y)+y AY qd) 24=4x+4y 1.3.2 Area = [b 32= y(2x+y) AY a) 32= y?+2xy 133 | 24=4x+4y...........(1) 6=x+y x=6-y (3) AY equation 3 32= y? +2xy... 0.2... (2) 32=2y(6-y)+y" CAY substitution 32=12y-2y?+y? 32=12y-y’ y?-12y+32=0 (y-4)(y-8)=0 CAV factors y=4 or 8 CAY y values y=4only x=6-4=2 CAY x value f «length = 8m and width = 4m CAY answer o [24] Copyright Reserved Please Turn Over Powered by @® CamScanner

“““Bownloaded from Stanmanaphysics.com 7 5 b At turning point n =—— ig point n 2a n= 40. =10 2(-2) ~. 4\9 has the maximum value. OR dT, dn 0=-4n+40 4n= 40 =—4n+40 AY substitution CAY answer OR AY derivative QUESTION 2 2:1 T, = -2(1)° + 40(1) +103 AY substitution T,=141 Av answer @) pars 141 ; 17. IS 5 QS. 5; casease 345 303 26 3 nme AY first difference re AY answer The second difference is —4 OR OR AY 2a = second difference 2-2) =-4 AY answer (2) The second difference is —4 25 301 = —2n* + 40n+103 AY equating 2n? —40n+198=0 AY standard form n? ~20n+99=0 (n-9)(n-11) =0 n=9 or ll CAY answers (3) (conditional if answers are natural numbers) 2.4 The maximum value is at the turning point Copyright Reserved June 2023 Common Test Please Turn Over Powered by @% CamScanner

“""ownloaded from Stanmanaphysics.com _“"" 2023 Common Test . T\) has the maximum value. CAY answer T, =-2n? +40n +103 has a maximum value AY T, =301 and T, =301 T,, =301 T,, =301 af Ti, has imum value. CA answer CAY answer Answer only, full marks (2) (9] Copyright Reserved Please Turn Over Powered by @® CamScanner

“““Bownloaded from Stanmanaphysics.com June QUESTION 3 (DO NOT MARK 3.3.1) CAY answer(on condition, answer is natural) Sid 21; 24 AY AY (2) S12 Ty of origi uence is 7, of GP AY Sub in formula for GP In the GP: 8 ; 12 Tar Ty =3.2? =512 CAY 512 T,, of original sequence is 7,, of AP AY Sub in formula for AP 339 $15 T, =a+(n-l)d T,, =3+(11-6 T,, =63 ‘AY 6. Ty, -Ty, = 512-63 = 449 CANS ¥ CAY answer ©) BZ a= 1=52° 5, = 360° AY Sn = 360" 7” AY values of a and S,==(a+l) 1 2 360 = "(8 +52) 2 CAY substitution 360 = 30n 12=n (4) Copyright Reserved 2023 Common Test Please Turn Over Powered by @% CamScanner

“““Bownloaded from Stanmanaphysics.com June 2023 Common Test VYa= ariel a=5 vm n=8 Ae aie 4 T, =ar" 1 2] 7 T= 5(3} 7g CAY answer (2) 332 « nt 2 23) “ a \4 ml nt @) a avs(3) 4 33:3 2 nl S us-s(3) =11s-, AL a nal 1-2 i-= a 4 CAY subtracting His weight will eventually reach = 95kg CAY answer (3) [18] Copyright Reserved Please Turn Over Powered by @® CamScanner

th ‘ics ° 2023 Cor SI ““"Bownloaded from Stanmanaphysics.com QUESTION 4 (DO NOT MARK QUESTION 4.3 AND 4.4) 4.1 x=3 AY a) i—1 42 |xeR; **3 fan? AY AY (2) vs 43 _5- a 4, AY sub (2;—5) 3-2 SH At Perevcsccesd 1 eeP ) CAY equation 1 -1=—+p AY sub (0;—1) 3-0 —3=a+3p .........(2) CAY equation 2 2H 2p cece (2)-() p=l CAV value of p —5=a+l a=-6 CAV value of a (6) os x-intercept 0 = J +1 3-x 6 4 3-x 6=3-x x=-3 CAY x-intercept y-intercept = Oy jo-1 CAY y-intercept 3-0 , CAY shape G3) h f ee rx 3 sel [12] Copyright Reserved Please Turn Over Powered by @% CamScanner

“““Bownloaded from Stanmanaphysics.com June 2023 Common Test QUESTION 5 5.1 y=-2(0-3K0+1) y =-2(-3\1. y='S E(0;6) AY substitute x =0 1e9) 52 y= —2(x? -2x-3) y= -2x° +4x+6 . . b Turning point x =—— ig point x oF x= =1 2(-2) y=-2(l) +4(1I)+6=8 D(I;8) OR y=-A(x? -2x+1)-3-1] y=-2(x-17 +8 DQ; 8) OR y=-2(x-3)(x+1) x-intercepts = 3 or -1 midpoint is x = 1 y=-2(1-3)(1+1) y=8 D1 ; 8) AY equation CAY substitution CAY x value CAY y value OR AY completing the square CAY simplifying CAY x value CAY y value OR AY x intercepts CAY midpoint value CAY x value CAY y value (4) Copyright Reserved Please Turn Over Powered by @% CamScanner

“""ownloaded from Stanmonaphysics.com SP =-2x7 +6x Maximum SP is at turning point b x=-— 2a OR SP CAY substitution CAY answer OR 53 F(-2;-8) AY x coordinate AY y coordinate (2) 54 0=-20- 3x41) x=3 or -1l AtQ x=3 re w Q(3:0) 5.5 y=mx+e y=mx+6 AVy=mx+6 0=m(3)+6 CAY substitute -6=3m (3:0) -2=m y=-2x+6 CAY answer OR OR =n oh CAY substitute in 0-6 _ -6 gradient formula m=5° 37 a) CAY m=-2 c=6 y=-2x+6 GB) CAY answer 5.6 SP =-2x7 +4x-6-(-2x+6) CAV expression for Copyright Reserved June 2023 Common Test Please Turn Over Powered by @® CamScanner

“"ownloaded from Stanmonaphysics.com June 2023 Common Test SP =-2x +4x-6-(-2x+6) CAV expression for SP SP =-2x7 +6x CAY derivative ie —4x+6 dx 0=-4x+6 4x=6 ia 3 CAY answer Z OR OR SP =-2x7+4x-6-(-2x+6) CAV expression for SP SP =-2x7 +6x SP =-2(x? -3x) CAY completing -3)) (-3yY the square SP =-2|| x°-3x+| —] |-| — a} 1) 3) 9 Pp =-2|| x-=] -= 2 sP --o{s-3) 42 z . _. 3 Maximum SP is at x= 3 CAW answer ) 7 k<6 AY (1) [15] Copyright Reserved Please Turn Over Powered by @® CamScanner

“““Bownloaded from Stanmanaphysics.com June 2023 Common Test QUESTION 6 6.1] 3=a(l)’ AY substitution a=3 ia CAY answer (2) faYey 62) x=3y CAY swapping x and y Mia 3 Re x y= t fo AS CAY answer(+ve) (2) y=, [= 3 6.3 yp AY shape rt AY point (2) 6: fo 6.4 | Yes, any vertical line cuts the graph at only one place. AY answer OR CA explanation (2) Yes, it passes the vertical line test OR Yes, it is a one to one function [8] Copyright Reserved Please Turn Over Powered by @% CamScanner

“““Bownloaded from Stanmanaphysics.com June 2023 Common Test QUESTION 7 7A AY formula (1+) 1+ om = AY substitution CAY answer (3) 721) a= P(1-i)" 3 Aes 2500 000{1-1%) 100 A= R881 211,25 AY substitution into correct formula CAY answer (2) 72.2 | A=P(I+i)" A=1 250 000( 14 7:5) 100 A=R1 552 871,10 AY substitution into correct formula CAY answer (2) 7.2.3 | R1 552 871,10 —R881 211,25 = R671 659,85 CAY subtraction CAY answer (2) 7.2.4 | 4 deposits a). AY answer qd) Copyright Reserved Please Turn Over Powered by @% CamScanner

June 2023 Common Test “““Bownloaded from Stanmanaphysics.com Teak Ty Tt % ty b). f f hi | * x x ¥ 36 AY (1 +28) 1200 4 AY (1 5 eo \ 200 200 9,6)" ig a be av x(14 35 } + 671659,85 = x [1 °5 {1+ 25) {1+ | 1 1200 1200 1200 1200 6 X=R144 650,97 CAM setting up the equation CAY answer 6) 05] Copyright Reserved Please Turn Over Powered by @® CamScanner

“““Bownloaded from Stanmanaphysics.com June 2023 Common Test QUESTION 8 8.1.1 f@= 3x? +2x f (x+h) =3( PRY 2x +h) = 3x7 + 6xh + 3h? +2x+2h f= lim h , 3x? +6xh+3h? +2x+2h-3x -2x fe) = lim P yy yy, OXN+ 3h? +2h £@)=lim—~ —— $1) = tim MOE) S (x) = lim(6x + 3h +2) hoo Av calculating fix +h) CAY substitution into the formula CAY simplification CAY factorising (5) FG) = 6x42 CAV answer 8.1.2 | Average gradient = 6x+3h+2 CAY formula for average gradient x=-l AY value for h h=2-(-]1)=3 CAY answer Ave grad = 6(—1) +3(3)+2=5 OR OR Atx=-l y=X-1?+2(-I=1 Avy values Atx=2 — y=3(2)?+2(2)=16 Ave grad = 2H Hox, Ave grad = 16-1 _15_5 CAY substituting in 2-C) 3 gradient la CAV ans (3) Copyright Reserved Please Turn Over Powered by @% CamScanner

“““Bownloaded from Stanmanaphysics.com June 2023 Common Test 8.2.1 | 9(x)=-7x° +22x-3 AY g(x) =-14x4+22 CAV answer (2) lS. 8.2.2 1 y=Sx+-- 2 AY 1 ce y=5x+—-Ox CAY 2x? 2 3 CAY CAY (two dx (4) [14] Copyright Reserved Please Turn Over Powered by @® CamScanner

“““Bownloaded from Stanmanaphysics.com June 2023 Common Test QUESTION 9 91 y=18 AY a) 9.2 O= (4-3) +2) AY equating to zero x=3 or -2 Av AY (3) 93 Turning points: f (x) =3x° —8x-3 AY derivative 0=3x? —8x-3 CAY equating to zero 0=(3x+1)(x-3) x=3 or -3 CAWx values y=(3-3)3-3)3+2)=0 (3:0) y=(-4-3}(-1-3}/-142]=2-1852 (-1,502) | CAvy values 3 3 3 27 3 27 OR OR Turning points: f (x) =3x* -8x-3 AY derivative 0=3x? -8x-3 CAY equating to 0=(3x+I(x-3) ae x=3 or -5 CAWx values y= (3) -4(3)°-3(3)+18=0 — (3:0) 1y 1y 1 500 { 1 | CAVy values (4) y=(-2) -4{-1) -3(-L)413-2 | -=;—— y=(-3} ~4{-3) (5) a (327 Copyright Reserved Please Turn Over Powered by @% CamScanner

nied ¢: fics own loaded from Stanmanaphysics.com June 2023 Common Test 94 $00 27 Sy (+33 ) 18 (230) fe) GB: 9) AY shape CAV turning points labelled CAV intercepts labelled (3) 9.5 f'(20) = 3x7 -8x-3 —3 = 3x? -8x-3 CAY equating f (x) to -3 O=3x" -8x O= x(3x-8) CAV factors x=0Oor 8 2 . x=0 At x=0 y=18 and m=-3 CAY x=0 (4) assets CAY answer {15} Copyright Reserved Please Turn Over Powered by @ CamScanner

“““Bownloaded from Stanmanaphysics.com June 2023 Common Test QUESTION 10 10.1 | No people were infected AY (1) — 102 | Nw - 3 AY substitution NQ) =-3) 6(2) into the derivative = 6000 people/month CAY answer (2) 10.3 Nw =-3P +6 = Siz O= “af * or CAY equating to zero O=f -12r O=1(t-4 ee 2 CAY factors as CAV both values .. 4 months of t CAV answer (4) 10.4 Virus reached the peak after 4 months 17,3 2 N(A)= (4) +3(4) CAY substitution -. 16 000 people CAY answer (2) [9] Copyright Reserved Please Turn Over Powered by @% CamScanner

“““Bownloaded from Stanmanaphysics.com June 2023 Common Test QUESTION 11 (DO NOT MARK 11.1.1) 11.1.1 AYNo For mutually: sive events P(A and B) =0 Av explanation (2) 11.1.2 P(Grade 11 and Samsung) = <—Z AY 150 P(Grade 11) x P(Samsung) = 0. 0 AY 150 150 P(Grade 11 and Samsung) = P(Grade 11) P(Samsung) 4. 0,0 AY “" 150 150° 150 da ex 9) 150 =30 CAY answer (4) 150 150 11.2.1] 8 AY (dl) 11.2.2 c ve 07, a 0,3~NC cnc 08 og.-© NCC 0.2 Ne a 02\ Ne NCNC P(CC or NCC) =0,8x0,7+0,2x0,8 AY 0,8x0,7 AY 0,2x0,8 AY addition =0,72 CAY, (4) [naar (11) TOTAL MARKS: 150 MARK THE PAPER OUT OF 137 THEN CONVERT TO 150 Copyright Reserved Powered by @® CamScanner