Mathematics Grade 8 Paper 2 Eastern Cape November 2014 Memo

1 Overberg Education District GRADE 8 MODEL EKSAMEN/EXAM P 2 WISKUNDE/MATHS NOVEMBER 2014 MEMORANDUM

2 Ques/ Calculations/Berekeninge Explanation if necessary/ Vr Verduideliking indien nodig VRAAG/QUESTION 1 1.1 (a) 3 593  RG (2) 2RG read from graph (b) 30-39  RG (1) 1 RG lees vanaf grafiek (c) 3593+7183+3330+1938+555+86  M =16 685  CA (3) (d) Diè onder 50 jr is baie meer/Those below 1A compare (Learners can 50 are many more A also work out the totals, but this is not necessary)/ Many more athletes younger than 50 yrs Vergelyk (Leerders kan ook old are fitter than those over 50/ die totale uitwerk, maar dis Baie meer atlete jonger as 50 jr oud is nie nodig nie) fikser as daardie bokant 50   O (3) 2O Reasons/redes Accept any logical/aaanvaar enige aanvaarbare 1.2.1 Sien Bylae /Annexure A b 1A Label/Naam van grafiek 2 A correct horizontal and vertical axes scales plus labels/

3 Ques/ Calculations/Berekeninge Explanation if necessary/ Vr Verduideliking indien nodig 2 A All 12 points correctly plotted (Deduct a mark for each wrong to a maximum of two marks)/ ALLE punte korrek afgesteek. Trek ‘n punt af vir elke fout, tot ‘n maksimum van twee punte. 1CA join points for a broken line/Verbind punte vir ‘n gebroke lyn. (6) 1.2.2 Winter  RG (2) 2RG read from graph/table Lees vanaf grafiek/tabel [17] VRAAG/QUESTION 2 2.1 b 2 = 152 – 92 [ Pyth. in right ang. Triangle/regh 1A statement plus driehoek] A reason/Bewering plus rede = 225 – 81 = 144 CA 1CA simplification/vereenv ∴ b = 12 CA (3) 1CA square root/vktswortel 2.2.1 L = 2 + 7 = 9m 1 A both L & B B = 2 + 5 = 7m  A correct/beide korrek A=LxB = 9 x 7  SF 1SF subst. from above/Stel in uit bostaande = 63 m2  CA 1CA answer (3) 2.2.2 A=LxB = 7x 5  SF 1SF subst. correct measures/Stel in korrekte = 35 m2  CA dimensies (2) 1 CA simplification 2.2.3 Area path/paadjie

4 Ques/ Calculations/Berekeninge Explanation if necessary/ Vr Verduideliking indien nodig 63 – 35  CA 1CA subtract/trek af = 28 m2  CA 1CA simpl/vereenv. (2) 2.3.1 V = π r2 h  M 1M formula = 3,142 x 442 x 45  SF 1SF subs/stel in = 273 731,04m3  CA 1CA answer (3) 2.3.2 SA = 2 πrh + 2 π r  M 2 1M formula 2 = (2 x 3,142 x 44 x 45) + (2x 3,142 x 44 )  SF 1SF subs/stel in = 24 608,14  CA (3) 1CA answer [16] VRAAG/QUESTION 3 3.1 1(c) Kite/Vlieër: 2 pr adj. sides =/2pr aangr. sye = 2(a) Rhombus/Ruit: All side =, but angles not =/alle sye =, maar hoeke nie = 3(e) Reghoek/rectangle: Opp sides = & all angles = 90 degrees/Teenoorst sye = en al die hoeke =90 grade 4(b) Square/Vierkant: Rect with = sides/Regh met sye = 5(d) Trapezium: Only 1 pr opp sides parallel/ slegs 1 pr teenoorst sye ewewydig 5A = (5) 3.2 p = 56°  [alt angles/verw. hoeke: AD∥ BC]  Any method/approach acceptable/Angles can ∠ B + q = 180° [co-int ang/ko-binne hoeke: AB∥ DC] be calculated in any  order. ∴ q = 61°  Enige aanvaarbare r = q [corr. ooreenk: AD∥ BC]  metode/Hoeke kan in enige orde bereken ∴ r = 61°  word.

5 Ques/ Calculations/Berekeninge Explanation if necessary/ Vr Verduideliking indien nodig s = p + q [ext./buite ∠ ∆ BES]  ∴ s = 56° +61° = 117°  t = r = 61° [alt/verw. : AB∥ E C]  (10) 3.3 a +26° +100° +85° +62° = 360° [ ∠ s quad/vhoek]  ∴ a = 87°  a + b + 110° + 62° = 360° [ ∠ s quad/vhoek]  ∴ b = 360° - (87° +110° + 62°) = 101°  (4) 3.4 x + 4 x +2 x +40° = 180° [sum int /som binne ∠ s ∆ ] 7 x = 140° CA x = 20°  (4) 3.4 ∠ F = 38°  (1) 2.5.1 BC = 17mm[opp sides/teenoorst sye parm] (1) 2.5.2 ∠ B + 140° = 180° [co-int/ko-binne ∠ s/opp sides/teenoorst sye parm parallel]  ∴ ∠ B = 40°  (2) [27] TOTAL 60

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