joule cycle ansswers

POUVVER WAUGHINES NO a 22:3 s2 _ 0,0107 0,013 4 =79,851% V¥ x100% V¥ 2.2.4 (1 Weta -1-4a(, \e) 1 z s2 is (5) 0,798 51=1-—2—_| (433) -1] ¥ 0,013 4 V.,=0,001 45m’ / cycle ¥ 225 V,=V,,+V,, =0,00145+0,0134 v =0,014 85m’ /cycle ¥ 2.3 7: pee wet (74) a] v n- f ( 0,32) ~ 2213? 76 5 0,287%294| (a) 1] vv 0,32 =111,223kW ¥ QUESTION 3 3.1 nen(2} P [kPa] (2) (3) (2) (4) [20] 2 3 ; ie -an( 2) Dg 490 =307,361K ¥ 4 4 V [rm] 3.2 T,=T.+AT = 307,361+420 ¥ -”7361§éwnloaded from hlayiso.com Copyright reserved (3) (2) Please turn over

MARKING GUIDELINE -5- a POWER MACHINES N6 3.3 Q;-5 =mC,(T,-7,) ef =1x1,005(727,361~471) v = 257, 643k) /kg Vv (3) s (2 P. 54a) 3 3.4 110 . = 727,361{ 2 v 490 =474,655K Vv (3) 3.5 Q,_, = mC, (7, -T,) MG = 1x1,005(307,361- 474,655) v =-168,13k /kg v (3) 3.6 1,4 =0,718k/ /kg.K ¥ (2) Oy eee ee =1,005-0,718 ¥ =0,287kI /kg.K ¥ (2) Bs Gea0 Q @ eae y ye" 100% 7 =1-<-% 100% nni-{2) : ree rec. 0,4 _ 257,643 -168,13 ogy ¥ oR 7 =1-—19823_x100% OR eee 257,643 257,643 490 =34,743% Vv = 34,743% = 34,743% (2) [20] Downloaded from hlayiso.com