KZN-Physical-Sciences-Grade-11-September-2025-QP-and-Memo.pdf

Downloaded from Stanmorephysics.com PATA NATAL PROVINCE EDUCATION REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE GRADE 11 MARKS: 100 TIME: 2 hours This question paper consists of 8 pages and 2 data sheets. Please Turn Over Copyright Reserved

Povsieeeaesaded from Stanmoreiifysics.com September 2025 Test INSTRUCTIONS AND INFORMATION 2. 3. 4. 5 7 Show ALL formul: s ‘ew ns in ALL calculations. 8. Round off your fii eri ers to a minimum of TWO decimal places. 9 Give brief motivation o... t cetera where required. 10. Write neatly and leg} y afimoreph com Copyright reserved

PhysicaleaaKedasded from Stanmorgphysics.com September 2025 Test QUESTION 1: MULTIPLE-CHOICE QUESTIONS Four options are provided as possible answers to the following questions. Each question has only ONE correct answer. Choose the correct answer and write only the letter (A-D) next to the question number (1.1—1.8) in the ANSWER BOOK, for example 1.9 E. 14 A certain chloride is formed when 0,5 moles of element X combines with 1,5 moles of chlorine. Which ONE of the following is the correct empirical formula for this chloride? A xXCe B XCh C XC D X2Cts | (2) » & a | 1.2 What is the volume occupied by1 gof hydrogen gas at STP? A 11,2. dm? F y B 22,4 dm? ep C 33,6 dm? D 44,8 dm (2) 1.3 Which ONE of the reactions below will produce hydrogen gas? A HCl+Mg—> B HNOs + Mg(OH)2 > C —H2SOs + MgCOs D CHsCOOH + MgO ~ (2) Copyright reserved Please turn over

Physi®iGrntetded from Stanmorephysics.com September 2025 Test 1.4 Which ONE of the following pairs represents the CONJUGATE ACID and CONJUGATE BASE of HPO2? CONJUGATE ACID CONJUGATE BASE A_ | Pos H2PO, B_ | H2PO, HsPO4 C | H3PO« Po D | HPO} POs (2) 1.5 Which ONE of the following processes is exothermic? A __ Melting ice cubes. B Baking bread. C Burning a candle. D Photosynth (2) 1.6 Which ONE of tl for Boyle’s Law? A pax : when te B PXV whelfl el Cc px : when volume is constant. D-—_p« T when volume is constant. (2) 1.7 Which ONE of the following graphs represents the deviation of real gas behaviour (broken line) from ideal gas behaviour (solid line)? (2) [2x7 =14] Copyright reserved Please turn over

Physicalsaumelasded from Stanmorephysics.com September 2025 Test QUESTION 2 (Start on a new page.) 2.1 Methane gas, CHa, of mass 34,5 g is reacted with oxygen gas in a sealed container according to the following balanced chemical equation. CHa(g) + 202(g) + CO2(g) + 2H20(2) The initial volume of the oxygen gas was 69,3 dm® when measured at STP Fa | Define the term limiting reagent. (2) 2A2 Determine the limiting reagent in this reaction. (4) 2.1.3 Determine the total number of moles of gas in the container after the reaction is completed. (4) 2.1.4 Calculate the percentage yield of COz if 58,08 g COz was formed during the reaction: __..) (3) ee | wh ate is highly endothermic. A 200 cm? solution is Ca(NOs)z in water. 2.2 The solubility of éaleium formed by dissolving 11 2.2.1 Define concentration. (2) 222 Calculate the concentration of this solution. (4) 2.2.3 Calculate the number of nitrate (NO3) ions in the solution. (3) 2.2.4 How will the temperature of the final solution be affected? Choose from INCREASES, DECREASES or REMAINS THE SAME. Explain the answer. (3) 23 A 29,05 g sample of a compound contains 11,62 g carbon, 1,94 g hydrogen and 15,49 g oxygen. 2.3.1 Determine the empirical formula of this compound. (5) 2.3.2 The molecular mass of this compound is 90 g-mol. Determine the molecular formula of this compound. (2) [32] Copyright reserved Please turn over

PrysiiGimrerried from Stanmoréphysics.com September 2025 Test QUESTION 3. (Start on a new page.) The following reversible reaction takes place in a closed container. A2 + Be = 2AB The graph below shows the changes in chemical potential energy during the course of the reaction. a of reaction 3.1 Is the forward reactior or exothermic? Give a reason for the answer. (2) 3.2 Calculate AH for t (2) 3.3 Define activation energy. (2) 3.4 What is the activation energy for the reverse reaction? (1) 3.5 How does the strength of the bonds within the reactant molecules compare to the strength of the bonds within the product molecules for the forward reaction? Choose from STRONGER THAN, WEAKER THAN, or OF SIMILAR STRENGTH. Give a reason for the answer. (3) 3.6 Redraw the above graph in your answer book, and label it A. Do not label the axes or show any given values. On the same set of axes, draw the graph that will be obtained if a catalyst is added. Label this as graph B. (2) [12] Copyright reserved Please turn over

Physiicaw ested from Stanmorephysics.com September 2025 Test QUESTION 4 (Start on a new page.) 41 The balanced equation below represents the ionisation of nitric acid (HNOs) in water: HNOs(£) + H2O(t) = H3O0*(aq) + NO3(aq) 4.1.1 Define an acid in terms of the Lowry-Bronsted theory. 4.1.2 Write down the FORMULAE of the TWO bases in the equation above. 4.1.3 Is nitric acid a STRONG or a WEAK acid? Give a reason for the answer. 4.1.4 Define an ampholyte. 4.1.5 Write down the formula of an ampholyte present in the equation 4.2 A learner _ of concentration 0, 4.2.1 above. Define a standard solution. ) > K2SOa(aq) + 2H20(2) _a standard potassium hydroxide solution Iphuric acid of unknown concentration. ion is: The titration is done three times (Runs 1, 2 and 3) using the same indicator. The volumes of the acid and the base solutions used for each run are indicated in the table below. 4.2.2 4.2.3 Copyright reserved RUN 1 2 3 Using the above data, determine solution. The following is a list of possible indicators that can be used. Indicator | Methyl orange re Phenolphthalein pH range 4-6 6-8 8-10 Which indicator is most suitable for this titration? Give a reason for the answer Please turn over (2) (2) (2) (2) (1) (2) (5) (2)

Physical Seimprmmeded from Stanmorephysics.com September 2025 Test 4.3 A solution is formed by adding m> of HCE of concentration 0,15 mol-dm? to 20 cm? ition 0,1 mol-dm’’, according to the following balanced ec CaCl + 2H20 Determine the final pH of the si i (8) ae E [26] QUESTION 5 (Start on a new page.) 5.1 A gas is contained in Chamber A, which has a volume of 5,3 dm®, and is sealed off from Chamber B, which has a volume of 3.2 dm*. Initially, only Chamber A contains gas at a pressure of 135,2 kPa, while Chamber B is a vacuum (contains no gas). The chambers are then connected by opening a valve between them, and. thi allowed to expand freely. The temperature rem O gas escapes. §.1.1 State Boyle’s Law in words. (2) 612 Explain, in terms of Boyle’s Law, what happens to the pressure of the gas after the valve is opened. (2) §.13 Calculate the final pressure of th (4) 5.2 Sketch a graph that shows the relationship betwes ) and volume (x-axis) for a fixed amount of gas at cons (2) 5.3 State the conditions of temperature and presst behaves as an ideal gas. (2) 5.4 Which real gas behaves the closest to an ideal gas? Explain the answer. (4) [16] TOTAL: 100 Copyright reserved Please turn over

Physiaicwleaded from Stanmorephysics.com PAPER 2 (CHEMISTRY) VRAESTEL 2 (CHEMIE) September 2025 Test DATA FOR PHYSICAL SCIENCES GRADE 11 GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 11 TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES NAME/NAAM SYMBOL/SIMBOOL VALUE/WAARDE Avogadro's constant . Avogadro-konstante Na 6,02 x 107 mor Molar gas constant 1, = Molére gaskonstante R 8,31 J-K mor Standard pressure ‘ Standaarddruk Pp 1,013 x 10° Pa Molar gas volume at STP 3, ; Molére gasvolume by STD Vm 22,4 dm*-mor Standard temperature Standaardtemperatuur 7 273K ei iL 2: FORMULES | PH = -log [Hs0*] na N, c=2 OROF c= N. MV Copyright reserved Please turn over

peniesal yyBsAdo, Downloaded from Stanmorephysics.com TABLE 3: THE PERIOD! STABLE OF ELEMENTS/TABEL 3: DIE PERIODIEKE TABEL VAN ELEMENTE 1 2 cK}! 7 ani ° 7 8 9 10 8611 12 13 14 #+15 146 #417 18 ® qm ‘ S (ys (iV) (v) (vi) (vith (VI) 1 E — Atomic number 2 SH ay SLEUTEL Atoomgeta!l He 1 ; 4 3 4 a 29 5 6 7 8 9 10 J Electronegativity Symbol @ Li |$ Be Elektronegatiwitei’ >| & CY }—simboo! S$ B/S C|FN/G 0/9 F| Ne 7 9 63,5 1] 12| 14| 16] #19| 2 1 12 13) 14) 15| 16| #«7| ‘18 ¢ Na/? Mg Approximate relative atomic mass ZaAele Sila P |8 S |4%Ce| Ar 23 24 Benaderde relatiewe atoommassa 27 28 31 32 35,5 40 19 20 21] 22] 23] 24| 25| 26[ 27; 28] 29] 30| 31| 32| 33| 34| 35/ 36 S$ K |2 Cal? Sc [2 Ti |2 V |S Cr|2Mn{S Fe [2 Co|S Ni |2 Cu/ Zn |2 Ga |% Ge |§ As |& Se |S Br| Kr 39 40 45| 48| 51| 52| 55| 56| 59| 59| 63,5| 65| 70] 73| 75/| 79| 80/ 84 37 38 39 | 40| 41| +42| 43| 44/ 45| 46| 47| +48] 49| Sol 51| S2| 53 | 5a $ Rb|? Sr|t Y |% Zr| Nb/% Molt Tc |t Ru | Rh|s Pd |2 Ag|> Cd | In |2 Sn|? Sb /% Te |S | Xe 86 88 s9 | 91] 92| 96 101| 103} 106] 108| 112] 115| 119] 122| 128| 127| 131 55 56 57 | 72| 73| 74| 75| 76| | 78) 79| 80| 81| 82| 83| 84| 85 | 86 Ss Cs |3 Ba La|2 Hf}; Ta| W]| Re/| Os| Ir Pt| Au| Hg/% Te |2 Pb|% Bi |8 Po|§ At} Rn 133| 137] 139| 179| 181| 184| 186| 190| 192] 195| 197| 201| 204| 207/ 209 87 88 89 S 3 Fr | te Ac se | 59] 60 | 61 | 62 | 6 | 64 | 6 | eo | er | 8 | 6 | 70] 71 Ce | Pr | Nd | Pm| Sm| Eu | Gd| Tb | Dy | Ho| Er | Tm| Yb | Lu 140 | 141 | 144 150 | 152 | 157 | 159 | 163 | 165 | 167 | 169 | 173 | 175 90 | 91 | 92 | 93 | 94 | 95 | 96 | 97 | 98 | 99 | 100 | 101 | 102 | 103 Th | Pa | U | Np| Pu | Am|Cm| Bk | Cf | Es | Fm | Md | No| Lr 232 238 S@OUGIDS |BdISKYq OSN 1881 Sz0z Jaquie}das

Downloaded from Stanmorephysics.com KWAZULU-NATAL PROVINCE EDUCATION REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE MARKS: 100 These marking guidelines consist of 8 pages. Hierdie nasienriglyne bestaan uit 8 bladsye.

PhysicdDaseuetoaziat sf meen siaba amore physics.com September 2025 Test Marking Guidelines/Nasienriglyne (2) (2) (2) 1 out of 12, and convert to 14 using table below. (2) 1.6 Avy (2) 17. Bvv (2) [2x7 =14] CONVERSION TABLE btaine: Converted mark ww 0 2 z= 5 fahmorep..Veles.com 7 9 10 12 12 14 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

PhysicdDesenelsaziat sf memnsieba umorephysics.com Marking Guidelines/Nasienriglyne QUESTION 2/VRAAG 2 241A Limiting reagent is the reactant that is consumed completely in a reaction. vv OR the substance that determines the amount of products formed. (2 or 0) September 2025 Test Beperkte reagens is die reagens wat volledig opgebruik word in a reaksie. (2) NOTE ee 2.1.2 iz m i= ve M Vin 16 1224 n= 2,16 mol CHa n = 3,09 mol O2 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 OPTION 3/OPSIE 3 CHa : CH4 : O2 3,09 +2<2,16+1v 1:2 4 2,16 : 4, 1,55 : 3,09 mol v ly/ O2 is the limiting reagent. Vv (4) 2.1.3 } ‘med./Bereken aantal mol COz gevorm. Calculate number ot ‘unreacted./Bereken aantal mol CH, wat nie reageer het nie. e Addition of two different gases./Bymekaartel van twee verskillende gasse. e Correct answer./Korrekte antwoo! dd. e: 2,156 — 2,160 : OPTION 2/OPSIE 2 CHa : COz 1:4 1,55 : 1,55 mol v 555 ¥ (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

PhysicdDesenelsaziatsmamnsiaba umorephysics.com September 2025 Test Marking Guidelines/Nasienriglyne 2.1.4 POSITIVE MARKING FROM QUESTION 2.1.2 POSITIEWE NASIEN VANAF VRAAG 2.1.2 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 m m uM eM m 58,08 =—Vv a a 1,55 u ri v m= 68,29 = 1,32 mol % yield = Actual yield 100 v ever © Theoretical yield * 1:32 :_— v 1,55 x 100 = 85,16 % v (4) 7 2.2.1 The amount of solute/dissolved substance/mole per litre/dm® of solution. vv The hoeveelheid opgelos é/molper liter/dm’ van die oplossing. (2) 222 OPTION 2/OPSIE 2 m or = -(105:6) v _ 105.6 | ~ (164)(0,2) vo ~ 164 c= 3,22 mol-dm? v. n= 0,64 moles n =v ov = 0,2 = 3,2 mol-dm? v (4) 2.2.3 CRITERIA: _N © Substitution into formula OR/OF n= Na e Apply ratio (2:1) N F 0,64 = ——s VY e Final answer 6,02 x 1072 N N = 3,85 x 1079 Ca(NOs)2 n=— Na N Number of NO3 ions = 2 x (3,85 x 102%) v (0,64 x 2) ¥= ———5y V = 7,71 X 10 v 6,02 x 10 N=7,71 X 10% v (3) 2.2.4 Decreases. Vv (Net) absorption of energy.” Energy of surrounding/solution/water decreases. ¥ (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

PhysicdDeseneloaziatsmemnsieba umorephysics.com September 2025 Test Marking Guidelines/Nasienriglyne 2.3.1 at mM _ 15,49 | 46 ole H = 0,97 mole O ot shown, award 2 marks for answer) 2.3.2. | Mr(CH20) = 30 g-mol" 90 —=3v 30 8 Molecular formula = CsH6O3 ~ QUESTION 3/VRAAG 3) _ 3.41 Exothermic. ¥ There is a net rele ore energy is released than absorbed./ AH< 0/AH is negative yroducts is less than energy of reactants.” Eksotermies Meer energie is vrygestel as geabsorbeer./AH< O/AH is negatief./Energie van reaktante is minder as energie van produkte. ~ 3:2 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 AH = Eproducts — Ereactants AH = Eabsorbed — Ereleased = 37- 81v = 34-— 78v = —44 kJ-mol" v = —44 kJ-mol v 3.8 The minimum energy needed for a reaction to take place. vv OR The minimum energy required to break the bonds in the reactants. Die minimum energie benodig vir die reaksie om plaas te vind. 3.4 Ea = 78 kJ-molt v 3.5 Weaker than.v Az + Ba. More energy is released when the bonds in the products are formed than when the bonds in the reactants are broken.v OR The products are more stable than the reactants because they have less energy than that of the reactants. OR The activation energy for the forward reaction is less than the activation energy for the reverse reaction. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief (5) (2) [32] (2) (2) (2) (1) (3)

PhysicdDesenelsaziat sé memnsieba amore ph ics.com Marking Guidelines/Nasienriglyne 3.6 September 2025 Test ing criteri jen righ e Eawith catalyst is less than Ea without./Ea met katalisator is minder as Ea sonder. ¥ e Energy of reactants and products remain the same./Energie van reaktante en produkte bly dieselfde. v QUESTION 4/VRAAG 4 4.1.1. Aacid is proton donory v ‘n Suur is 'n protonontskenker. 4.1.2 H20 v and/en NO3 v 4.1.3. Strong v It ionize Sterk. Dit ionise 4.1.4 Asubstance that c reaction VV (2 OR 41.5 HOv 4.2.1 A solution of known concentration./ ‘n Oplossing met bekende konsentrasie. Vv (2 or 0) ‘oduce a high concentration of H3O* ions v d in one reaction and a base in another 4.2.2 OPTION 1/OPSIE 1 CaVa _ | ACA WA yy CgVe np Ca (21,08)v_ 1, (0,1)(25) v2 Ca = 0,06 mol-dm? v cA ery _ 0,00125 °* "0.0211 n= 0,06 mol-dm? v Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief (2) [12] (2) (2) (2) (2) (1) (2) (5)

PhysicdDeseneloaziatsmemnsieba umorephysics.com September 2025 Test 4.2.3 4.3 Marking Guidelines/Nasienriglyne Bromothymol blue/Broomtimolblou” Bromothymol blue changes colour in the range of the endpoint of the titrationY ORA strong acid is reacting with a strong base. Broomtimolblou verander kleur in die gebied van die eindpunt. Marking criteria/Nasienriglyne e_ Calculate the initial mol of Ca(OH)2./Bereken aantal mol Ca(OH)2 gebruik. ¥ Calculate the initial mol of HCI./Bereken aantal mol HCI gebruik. Vv Correctly apply the ratio of Ca(OH)2: HCI (2: 1). v Calculate correct amount of HCI unreacted./Bereken hoeveelheid mol HCI wat nie reageer het nie. V ¢ Correct substitution to calculate concentration of HCl after titration./Korrekte invervanging om konsentrasie HCI te bepaal na titrasie. V Correct formula for pH./Korrekte formule vir pH. ¥ Correct substitution to calculate pH./ Korrekte invervanging om pH te bereken. ¥ Correct answer/Korrekte antwoord V Amount of HCI needed to neutralise Ca(OH)z: Ca(OH)2 : HCI 2x 103: 4x 10° mol HCI ¥ Amount of HCI left unreacted= 4,5 x 103-4 x 103 v =5x 10% mol Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief (2) (8) [25]

PhysicdDesenelsaziatsmemnsieba umorephysics.com September 2025 Test Marking Guidelines/Nasienriglyne QUESTION 5/VRAAG 5 ixed amount / constant mass of gas is inversely (2) provided the temperature remains constant.v Vv eelheid gas is omgekeerd eweredig aan die =mperatuur konstant bly. olume increases./Wanneer die klep oop gedraai According to Boyle’s Law, as volume increases, pressure decreasesv ./Volgens Boyle se Wet sal die druk afneem indien die volume (2) toeneem. §:1.3 (4) 512 Marking criteria/Nasien riglyne Correct shape./Korrekte vorm. Vv ¥ (2) 5.3 Low pressure Y and high temperatures. “/Lae druk en hoé temperature. (2) 5.4 Helium v Helium has the smallest volume/molecular mass,” with no forces of attraction between molecules.” /Helium het die kleinste volume/molekulére massa. Ideal gas molecules do not contribute to the volume of the gas.“ /Ideale gasse se volume dra nie by tot die volume van die houer nie. (4) [16] TOTALITOTAAL: 100 Copyright reserved/Kopiereg voorbehou