education
Department of
Education
FREE STATE PROVINCE
GRADE 12
LIFE SCIENCES P2
JUNE 2025
TOTAL: 150
MARKING GUIDELINES
These marking guidelines consist of 10 pages.
Copyright reserved Please turn over
Skip to contentAll 2025 papers 


%202024%20Possible%20Answers_hlayiso.com_--056e47d6-2126-48a7-b13d-b4af9641a5a9/v1-d5502c6f8d24b3731b50/card.webp)

%20SEP%202022%20Possible%20Answers_hlayiso.com_--17f73f27-a44f-41f5-b5d9-656090338f3e/v1-4bc05d991a2d9fe7e528/card.webp)
View all





Life Sciences Grade 12 Paper 2 Free State June 2025 Memo
Grade 12 Life Sciences Paper 2 memorandum from the Free State June Exam 2025, 11 pages. Read online or download the free PDF.
Life Sciences · Grade 12 · Free State June Exam · 2025. Memorandum, 11 pages. Read online or download the PDF.
- Subject
- Life Sciences
- Grade
- Grade 12
- Document type
- Memorandum
- Year
- 2025
- Exam period
- Free State June Exam
- Paper
- 2
- Curriculum
- CAPS
- Pages
- 11
- File size
- 959.8 KB
Free to read online, no sign-up needed
Loading document…
Loading document…
1 of 11
This exam
Free State June Exam 2025
- Paper 1Question paperMemo
- Paper 2Question paperMemo
Questions in this paper
- Question 1.1DNA: THE CODE OF LIFE23 marks
- Question 1.2DNA: THE CODE OF LIFE6 marks
- Question 1.4DNA: THE CODE OF LIFE9 marks
- Question 1.5GENETICS AND INHERITANCE6 marks
- Question 1.6MEIOSIS6 marks
- Question 2.1HUMAN REPRODUCTION12 marks
Show all 17 questions
- Question 2.2GENETICS AND INHERITANCE3 marks
- Question 2.3DNA: THE CODE OF LIFE23 marks
- Question 2.4DNA: THE CODE OF LIFE6 marks
- Question 2.5GENETICS AND INHERITANCE13 marks
- Question 2.6GENETICS AND INHERITANCE20 marks
- Question 3.1DNA: THE CODE OF LIFE12 marks
- Question 3.2MEIOSIS5 marks
- Question 3.3MEIOSIS7 marks
- Question 3.4MEIOSIS8 marks
- Question 3.5GENETICS AND INHERITANCE6 marks
- Question 3.6GENETICS AND INHERITANCE16 marks
Document textSearch extracted text and jump to a page.
Life Sciences 2 June 2025
Grade 12 Paper 2 Marking Guidelines
PRINCIPLES RELATED TO MARKING LIFE SCIENCES
abe
10.
14:
12:
13.
14.
If more information than marks allocated is given
Stop marking when maximum marks is reached and put a wavy line and 'max' in
the right-hand margin.
If, for example, three reasons are required and five are given
Mark the first three irrespective of whether all or some are correct/incorrect.
If whole process is given when only a part of it is required
Read all and credit the relevant part.
If comparisons are asked for but descriptions are given
Accept if the differences/similarities are clear.
If tabulation is required, but paragraphs are given
Candidates will lose marks for not tabulating.
If diagrams are given with annotations when descriptions are required
Candidates will lose marks.
If flow charts are given instead of descriptions
Candidates will lose marks.
If sequence is muddled and links do not make sense
Where sequence and links are correct, credit. Where sequence and links are
incorrect, do not credit. If sequence and links become correct again, resume credit.
Non-recognised abbreviations
Accept if first defined in answer. If not defined, do not credit the unrecognised
abbreviation but credit the rest of the answer if correct.
Wrong numbering
If answer fits into the correct sequence of questions but the wrong number is given,
it is acceptable.
If language used changes the intended meaning
Do not accept.
Spelling errors
If recognisable, accept the answer, provided it does not mean something else in
Life Sciences or if it is out of context.
If common names are given in terminology
Accept, provided it was accepted at the memo discussion meeting.
If only the letter is asked for but only the name is given (and vice versa)
Do not credit.
Copyright reserved Please turn over
Life Sciences 3 June 2025
Grade 12 Paper 2 Marking Guidelines
15. If units are not given in measurements
Candidates will lose marks. Memorandum will allocate marks for units separately.
16. Be sensitive to the sense of an answer, which may be stated in a different
way.
17. Caption
All illustrations (diagrams, graphs, tables, etc.) must have a caption.
18. Code-switching of official languages (terms and concepts)
A single word or two that appear(s) in any official language other than the learner's
assessment language used to the greatest extent in his/her answers should be
credited if it is correct. A marker that is proficient in the relevant official language
should be consulted. This is applicable to all official languages.
Copyright reserved Please turn over
Life Sciences 4 June 2025
Grade 12 Paper 2 Marking Guidelines
SECTION A
QUESTION 1
ab 11s Bvv
13152 Bvv
1.1.3 Dvv
1.1.4 C vv
a a a} Cvv
1:1:6 Bvyv
AST Bvv
1.1.8 A vv (8x2) (16)
2 Interphase v
20
12:2 Haemophiliav
1.2.3 DNA profilingY
1.2.4 Centriole / CentrosomeY
1.2.5 (Weak) hydrogen bonds¥
1.2.6 HomozygousY¥
1.2.7 Ribosev (1x7) (7)
1.3 1:31 A only¥v
1.3.2 Nonev v
1.3.3 Bonlyvv (3 x 2) (6)
1.4 1.4.1 a) YY (1)
b) Xv (1)
1.4.2 Double helixy (1)
143 ACTG(VV) (2)
1.4.4 MitochondriaY (2)
ChloroplastY
(1)
1.4.5 Thyminev /(T)
(1)
1.4.6 Fourv/4 (9)
Copyright reserved Please turn over
Life Sciences 5 June 2025
Grade 12 Paper 2 Marking Guidelines
1.5 1:5:1 Dihybrid (crossing) ~ (4).
1.5.2 (a) BBhhy ¥ (2)
(b) bhY/ bh bh bh bh (1)
(c) Brown hair colour and short hairy ¥ (2)
(6)
1.6 16.1 4/Foury (1)
1.6.2 2/1 Two : (1)
1.6.3 - They are the same/ similar size/length.
- They have the same/ similar shape. ¥
- They have genes for the same characteristics. ¥
- They have alleles of a specific gene on the same
locus. ¥
- They have centromeres in the same position. VW (2)
(Mark first TWO only) (Any TWO)
(1)
1.6.4 Centromerev
(1)
1.6.5 Diploid cellv (6)
TOTAL SECTION A: (50)
QUESTION 2
2.1. -It is the arrangement of the (complete set of an individual’s)
4 chromosomesY
-According to the number and shapev of the chromosomes. (2)
Autosomes ¥ (1)
2:1:
2 Femalev ¥ (2)
2.1. | -3 chromosomesv / an extra chromosome
3 - at position number 21 ¥ (2)
(7)
2.1
4 - The factors/alleles that control a characteristic separate Vv
- during meiosis ¥
- so that only one factor/allele is present in each gamete ¥ (3)
2:2
Translation’ (1)
RibosomeY (1)
2.3. a) Peptide Bondy (1)
1 b) tRNAV / transfer RNA (1)
Copyright reserved Please turn over
Life Sciences 6 June 2025
Grade 12 Paper 2 Marking Guidelines
2.3. 3v/three (1)
2
a) Tryptophany (1)
2.3.
3 b) ACCYY (2)
c) 2v (1)
2.3%
4 - The codon on the mRNAY
- will change from UUA to UUGY
2:3: - The anticodon on the tRNA will bring the same amino acid v/
5 Leucine to the ribosome
- The sequence of the amino acids would not change ¥
- Therefore, there will be no effect on the protein formedv/ same
protein will form (5)
(14)
2.4 - The DNA double helix unwindsY and
- (the double strand) unzips/weak hydrogen bonds breakY
- to form two separate strandsY
- One strand is used as a templateY
- To form mRNAY
- Using free RNA nucleotidesv from the nucleoplasm
- The mRNA is complementary to the DNA “/A compliments U,G
compliments C
Any 6 (6)
2.5. Striped fury (1)
- In Breeding pair 1v
2:5: - both parents are spotted fury /none of the parents are striped fur
2 - but striped fur appears in the phenotype of the offspringyY
OR
- In cross 1¥
-The ratio spotted fur to stripe fur is 3:1”
-The smaller portion represents the recessive alle striped fur Vv (3)
A gene mutation is a change in the sequence of nucleotides in a
Copyright reserved Please turn over
Life Sciences a6
Grade 12 Paper 2 Marking Guidelines
gene/ DNAYY
Law of dominancev
P1 Phenotype : Spotted fur x Spotted fury
Genotype Nn x Nnv
Meiosis
G/gametes N x N nv
Fertilization
F1 Genotype NN, Nn, Nn, nn ¥
Phenotype ratio: 3 Spotted: 1 striped *v
P1 and Fiv
June 2025
(2)
(1)
Meiosis and fertilization’ *Compulsory 1 + Any 5
OR
Pi Phenotype Spotted fur x Spotted fur V
Genotype Nn x
Meiosis
G/gametes N, on x
Gametes | N n
Fertilisation N NN Nn
1 Mark tor correct gametes
1 Mark tor correct Genotypes
F; Genotype NN, Nn, Nn, nn
Phenotype 3 Spotted fur: 1 Striped fur v*
Pi and Fi¥
Meiosis and fertilisation V *Compulsory 1 + Any 5
Copyright reserved
(6)
(13)
Please turn over
Life Sciences 8 June 2025
Grade 12 Paper 2 Marking Guidelines
26.1 2v (1)
26.2 5-X®Xv¥v (2)
2.6.3 - Males have only one X chromosomev/ XY sex chromosomes
- If this chromosome carries the recessive allelev/ (X‘)
- the male will suffer from Lesch-Nyhan syndrome ¥
- Females have two X chromosomesv/XX and
- will only suffer from Lesch-Nyhan syndrome when they carry two
recessive alleles on both X chromosomesv /(X' X')
- A dominant allele on one of the X-chromosomes will mask the
effectY
Any 4 (4)
(7)
Total Queston 2 [50]
QUESTION 3
3.1.1 FatherBY (1)
3:12 - Allthe DNA profile bars/bands of the children that do not match
the motherv, match the DNA profile bars/bands of Father BY
OR
- All DNA profile bands of the mother and Father BY
- match all the children’s DNA profile bandsv (2)
3.1.3 Child 1 and 2vv (2)
3.1.4 - Blood groups cannot identify with certainty who is the father v/
3.1.5
blood groups can only eliminate men who are not the father
- Because many males have the same blood group. ¥
- Each person’s DNA profile is unique. ¥ (3)
- To identify organisms/dead people from their remainsv
Copyright reserved Please turn over
Life Sciences
Grade 12 Paper 2
9 June 2025
Marking Guidelines
To test for the presence of specific alleles v for genetic
conditions/Identification of genetic disorders
To establish matching tissues for organ transplantsY
Identification of suspects in a crime ¥
Tracing missing persons ¥
(Mark first two only )
Any 2 (2)
3.1.6 - Mark the samples clearly“ to ensure that the samples are not
mixed upY
- Wear a mask and glovesY ,DNA must not get contaminatedv
- Use new and clean/sterilized apparatusY to ensure no
contamination from previous tests. ¥
- Check the access of persons/Only authorized persons may
have accessv so that no one can tamper with the samples.
(Mark first ONE Only) (Any 1 x 2) (2)
(12)
3.2.1. Anaphase 1 (1)
3.2.2. - Chromosome of (homologous pair) is being pulled to the
opposite poles ¥ (1)
3.2.3 a) CentrioleY (1)
b) Spindle fibery (1)
3.2.4 3v/three (1)
(5)
3.3 Mitosis Meiosis
Mitosis occurs in body | Meiosis occurs in sex cells¥
cellsv
Both karyokinesis and
cytokinesis occurs
once.v
Both karyokinesis and
cytokinesis occurs twice.~
Two daughter cells are
formed.v
Four daughter cell are formed.v
Daughter cells are
genetically identical to
one another and to the
parent cellv¥
Daughter cells are genetically
different from each other and
from the parent cellv
Chromosome number
remains constantv
Chromosome number is
halvedv
Crossing over does not
occurY
Crossing over occursY
(Mark first THREE only )
Copyright reserved
( Any 3X2)
Please turn over
Y for TABLE
(7)
Life Sciences 10 June 2025
Grade 12 Paper 2 Marking Guidelines
3.4.1
3.4.2
3.4.3
3.4.4
3.4.5
3.5.1
3.5.2
3.5.3
3.5.4
3.6.1
3.6.2
What is the effect of temperature on the frequency of meiotic
recombination in barley plants?v Vv (2)
a) Temperaturey (1)
b) Frequency of meiotic recombinationY (1)
- Same amount of waterY
- Same light intensityY
- Same barley plant varietyY
- Same precise method of counting ¥
(Mark first THREE only) ( Any 3) (3)
- Genetic material is exchanged.v (1)
-The production of haploid gametes¥
- It maintains a constant chromosome number from one generation to
the next.v
- Itincreases genetic variation Vv (any 2) (2)
(Mark first TWO only) (10)
Undifferentiated cells that can develop into any other type of cellVv (2)
MitosisY (1)
-It can help to replace and repair damaged cells V after an injury or
infection
- Embryonic stem cells can differentiate into any cell typev
- Some diseases and disorders can also be treated. v/ Leukemia
and Parkinsons can be treated
(Mark first TWO only) (Any 2) (2)
Bone marrow /blood/heart/adipose tissue/brain
(Mark first ONE only) (Any 1) (1)
(6)
- Blood groups/the gene for blood groups is controlled by three
allelesv/ I*, 15, i
- Each person can only inherit two allelesv/One allele from each
parent Vv
- The I and I allele are dominant v
- over the i allele ¥
- The combination I*i and I*I produce blood group AY
- The combination |°i and I°I° produces blood group BY
- The combination II? produces blood group ABY
- The combination ii produces blood group OY (6)
- The Mother is heterozygous for blood group Av / I*i
Copyright reserved Please turn over
Life Sciences 11 June 2025
Grade 12 Paper 2 Marking Guidelines
- Ther father is heterozygous for blood group Bv/ I°i
- The child is homozygous for blood group Ov /ii (4)
- And receive the recessive allelew/i form each parent a
[50]
TOTAL SECTION B: 100
GRAND TOTAL: 150
Study this subject
Recommended for this subject

Memorandum
Life Sciences Grade 12 Paper 2 Mpumalanga Mock 2025 Memo

Question paper
Life Sciences Grade 12 P2 NSC June 2025 Question Paper (Afr)

Memorandum
Life Sciences Grade 12 Free State June 2024 Memo
%202024%20Possible%20Answers_hlayiso.com_--056e47d6-2126-48a7-b13d-b4af9641a5a9/v1-d5502c6f8d24b3731b50/card.webp)
Memorandum
Life Sciences Grade 12 P2 Gauteng Prelim 2024 Memo (English)

Memorandum
Life Sciences Grade 12 P2 Eastern Cape Mock 2022 Memo (Afr)
%20SEP%202022%20Possible%20Answers_hlayiso.com_--17f73f27-a44f-41f5-b5d9-656090338f3e/v1-4bc05d991a2d9fe7e528/card.webp)
Memorandum
Life Sciences Grade 12 P2 Gauteng Mock 2022 Memo (English)
More from Grade 12 Life Sciences

Question paper
Life Sciences Grade 12 Eastern Cape June 2025 QP (Eng)

Question paper
Life Sciences Grade 12 KZN March Test 2025 Question Paper

Question paper
Life Sciences Grade 12 P1 Mpumalanga Mock 2025 QP

Question paper
Life Sciences Grade 12 P1 North West Mock 2025 QP

Memorandum
Life Sciences Grade 12 P1 Eastern Cape Prelim 2024 Memo

Question paper