Physical Sciences Grade 11 Limpopo Prelim 2025 Paper & Memo

Downloaded from Stanmorephysics.com LIMPOPO PROVINCIAL GOVERNMENT REPUBLIC OF SOUTH AFRICA DEPARTMENT OF EDUCATION NATIONAL SENIOR CERTIFICATE MARKS: 100 TIME: 2 hours This question paper consists of 10 pages, 4 data sheets and 1 graph paper. Copyright reserved Please turn over eee ee ene eee ee

Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 Limpopo DoE/September 2025 NSC INSTRUCTIONS AND INFORMATION 1J Write your name and other applicable information in the appropriate spaces on the ANSWER BOOK. - The question paper consists of SEVEN questions. Answer ALL the questions in the ANSWER BOOK, except question 7.2.2 which should be answered on the provided graph paper on page 15. 3: Start EACH question on a NEW page in the ANSWER BOOK. 4. Number the answers correctly according to the numbering system used in this question paper. 5; Leave ONE line between two sub-questions, for example between QUESTION 3.1 and QUESTION 3.2. 6. You may use a non-progrs pocket calculator. Ps You may use app atical instruments. 8. Show ALL formulae: tions in ALL calculations. 9. Round off your FINAL swers to a maximum of THREE decimal places 10. Give brief motivations, discussions, etc. where required. 11. | You are advised to use the attached DATA SHEETS. 12. Write neatly and legibly. Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 Limpopo DoE/September 2025 NSC QUESTION 1: MULTIPLE-CHOICE QUESTIONS Four options are provided as possible answers to the following questions. Each question has only ONE correct answer. Choose the answer and write only the letter (A — D) next to the question number (1.1 — 1.5) in the ANSWER BOOK, e.g. 1.6 A. 1.1 The activation energy for the forward reaction of the reaction below is 230 kJ.mol™ A2 + B2 > 2C AH = + 150 kJ.mol™ What is the enthalpy change for this reaction? A. 380 B. 230 Cc. 150 D. 80 (2) 1.2 ONE mole of wate ole of carbon dioxide (CO2z) will have the same... sual A. molar mass. B. mass. C. density. D. number of molecules. (2) 1.3. Which of the following represents a neutralization reaction? A. HCl+ Zn — ZnCte B. H2NOs +. Cu — Cu(NOs)2= c. 5 a2SO D. ai (2) 14 the name of the salt formed in this reaction? q) > CHsCOONa (aq) + H20 (/) A. iur B. sodiur C. sodium methanoate D. sodium acetate (2) Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 Limpopo DoE/September 2025 NSC 1.5 The pressure of a gas is 200 kPa when its volume is 3 000 cm‘. If the gas is compressed to 2 000 cm* at constant temperature, what is its new pressure? A. 250 kPa B. 300 kPa C. 350 kPa D. 400kPa (2) [10] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com | Physical Sciences/Gr 11 5: Limpopo DoE/September 2025 NSC QUESTION 2 (Start on a new page) The following reaction between Ammonia and Oxygen takes place at constant pressure and temperature: 2.1 Define the term acti Prgy (2) 2.2 Give a reason why t stion ic. (1) 2.3 Redraw the graph and a dotted line the effect of a catalyst on the activation energy. (1) 2.4 Write down the values for the: 2.4.1 Energy of the products (1) 2.4.2 Energy of the reactants (1) 2.4.3 Activation energy for the reverse reaction (1) 2.4.4 Activation energy for the forward reaction. (1) 2.5 Calculate the heat of reaction,(AH), for the reverse reaction. (2) 2.6 What effect will the addition of the catalyst have on: (Choose from INCREASES, DECREASES or REMAINS THE SAME) 2.6.1 The energy of the products? (1) 2.6.2 The heat of reaction? (1) 2.6.3 The activation energy for the reverse reaction? (1) [13] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 Limpopo DoE/September 2025 NSC QUESTION 3 (Start on a new page) 3.1 itric acid with ampholyte X to form the reaction below. Study the flow 5 that follow. + | NOs (2) 3.1.2 Write a chemical equation for the reaction above. (3) pholyte X. (2) 3.2 base in the reaction below. (2) 3:3 i e a ator. (2) 3.4 . is reaction and identify the acid and the base required to prepare potassium chloride. (3) [14] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 Limpopo DoE/September 2025 NSC QUESTION 4 (Start on a new page) A solution of calcium carbonate (CaCOs) was prepared by dissolving 20 g of powdered CaCOs in 500 cm of water. a ial This solution was then added to 500 cm? s concentration of 0.25 mol.dm* as in the set u — - / aas ium natte ition 0,26 J cs 4.1 Define the term limiting agent. (2) 4.2 Write a balanced equation for the reaction in the set up above. (3) 4.3 Calculate the initial concentration of the CaCOs solution. (4) 4.4 Which substance is the limiting reagent? Show by means of a suitable calculation. (4) 4.5 Calculate the percentage purity of the excess reagent. 3 (5) [18] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 Limpopo DoE/September 2025 NSC QUESTION 5 (Start on a new page) 5.1 Define the term molar mass in words. (2) 5.2 An organic acid was analysed and found that it has the following chemical composition: 76.6%carbon(C) 12.05%Hydrogen (H) 11.35%oxygen(O) The reaction of this acid with alcohols produces a compound that has a fruity smell. During combustion, 0.01272g of this acid was used and it produced 0.01863g of carbon dioxide (COz) and 0.0075 g of water, according to the following reaction: + $02(g)—»CO2 (g)+ H20(t) 5.2.1 Calculatelt ass of H2O (2) 5.2.2 Given the pere , determine the empirical formula for the acid. (7) 5.3 Calculate the number of mo f carbon dioxide produced (3) [14] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 9 Limpopo DoE/September 2025 NSC QUESTION 6 (Start on a new page) When sulphuric acid reacts with water, it ionises in two steps, as shown in the two balanced equations below: 6.1 6.2 6.3 6.4 O(t) — Hs0*(aq) + HSO; (aq) O(t) + Hs0*(aq) + SO%-(aq) Define an acid < Bronsted theory. Is the solution forme i ACIDIC or BASIC (ALKALINE)? Give a reason for your answer. Write down a conjugate base of H30* A few drops of bromothymol blue indicator are added to a potassium hydroxide solution in a beaker,Adilute sulphuric acid solution is now gradually added to this solution until the ¢o dieator changes. Write down the: 6.4.1 Type of rea 6.4.2 Balanced ct 6.4.3. Colour for the reaction that takes place. r. Choose from the following: to blue OR Blue to purple 6.4.4 Write down a reason why bromothymol blue is the most suitable indicator for this reaction. (2) (2) (2) (2) (3) (2) (1) [14] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 Limpopo DoE/September 2025 NSC QUESTION 7 (Start on a new page) (2) occupies a volume of 5.0 L at a pressure of decreased to 150 kPa at constant temperature, the final volume? (4) provided to draw a pressure vs volume graph cale) and show by means of point X on the rz the initial and the final value of the volume. (4) TT A gas sample has a mass of 16 g and occupies a volume of 11.2 dcm*® at standard temperature and pressure (STP). Determine, b e ula of the gas. (5) 74 A bicycle ti temperature rem inside the tire? E reducing its volume by half. If the at happens to the pressure of the air (2) [17] TOTAL: [100] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com _ Physical Sciences/Gr 11 11 LimpopoDoE/September 2025 NSC TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES NAME/NAAM SYMBOL/SIMBOOL VALUE/WAARDE siete konstants Na 6,02 x 10 mot pers x anion R 8,31 J:K*-molt Sneoune p° 1,013 x 108 Pa Molers gasvolume by STD Vi 22,4 dm?-mot" Socereiener e 273 K TABLE 2: FORMULAE/TABEL 2: FORMULES P1V1 = P2V2 (oa OR/OF c= Vv Copyright reserved Please turn over

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Downloaded from Stanmore Physical Sciences/Gr 11 physics. com NSC TABLE 4A: STANDARD REDUCTION POTENTIALS - SiakeomailetiaT Falta | é D- TENSIALE Half-reactions / Halfreaksies EP w Increasing strength of oxidising agents / Toenemende sterkte van oksideermiddels F2(g) + 2e- Co** + e- H2Oz + 2H* +2e- MnO] + 8H* + 5e~ Cla(g) + 2e- CrO2- + 14H* + 6e- O2(g) + 4H* + 4e- MnO2 + 4H* + 2e- PI?* + 2e- Bra(t) + 207 NO} + 4H’ + 3e- Hg?* + 2e- Ag* +o- Cu?* +e Sn** + 2e- S + 2H* + 2e~ 2H* + 20- Fe* + 3e- Pb?* + 2e- Sn?* + 2e- Ni?* + 2e- Co** + 2e- Cd?" + 2e~ cr? +e- Fe** + 2e- Cre* + 3e- Zn?" + 2e- 2H20 + 2e- Cr** + 2e- Mn?* + 2e- Al + 3e7 Mg?* + 2e— Na* + e~ Ca?* + 2e- Sr?* + 2e- Ba?* + 2e- Cs*+e K* +e- Lit + e- PASE EE EEE CEE SE EEL ERE EP ECE ET ERED 2F- Co** 2H20 Mn?" + 4420 2ce- 2Cr* + 7H20 2H20 Mn?" + 2H20 Pt 28r NO(g) + 2H20 Hot) Ag NO2(g) + HzO Fe** H20O2 2I- Cu S+2H20 SO2(g) + 2H20 Cur Sn?- HeS(g) H2(9) Fe Pb Sn Ni H2(g) + 2OH- Cr Mn At + 2,87 + 1,81 +1,77 + 1,51 + 1,36 + 1,33 +1,23 +1,23 + 1,20 + 1,07 + 0,96 + 0,85 + 0,80 + 0,80 +0,77 + 0,68 + 0,54 + 0,52 +045 +0,40 + 0,34 +0,17 +0,16 +0,15 + 0,14 0,00 — 0.06 — 0,13 —0,14 —0,27 —0,28 —0,40 —0,41 —0,44 —0,74 —0,76 — 0,83 —0,91 =41,18 — 1,66 —2,36 —2,71 — 2,87 — 2.89 —2,90 -2,92 — 2,93 — 3,05 Copyright reserved Please turn over LimpopoDoE/September 2025 Increasing strength of reducing agents / Toenemende sterkte van reduseermiddels

Downloaded from Stanmore Physical Sciences/Gr 11 TABLE 4B T physics.com : STANDARD Ri NSC Half-reactions / Halfreaksies Increasing strength of oxidising agents / Toenemende sterkfe van oksideermiddels litte = Li —3,05 K'+e = K —2,93 Cs*+e- = Cs -—2,92 Ba?*+2e = Ba — 2,90 Sr*+2e- = Sr —2,89 Ca**+2e- = Ca — 2,87 Na’*+e- = Na —2.71 Mg**+2e- = Mg —2,36 AC+3e-— = AC — 1,66 Mn?* + 2e- = Mn —1,18 Cree+2e- = Cr —0,91 2H2O0+2e- = H2(g) + 20H- — 0,83 Zn?*+2e- = Zn —0,76 Cr*+3e5 .—= Cr —0,74 — Fe —0,44 = cr —0,41 = Cd —0,40 = Co —0,28 - Ni -0,27 i= Sn —0,14 = Pb —0,13 - ‘Fe — 0,06 2H*+2e = H2(g) 0,00 S+2H*+2e- = H2S(g) +0,14 Sn**+2e7 = Sn? +0,15 Cu?*+e- = Cur +0,16 SO? +4H*+2e- = SO2x(g)+2H20] +0,17 Cu?*+2e- = Cu + 0.34 2H20 + O2+4e- = 40H + 0,40 SO2+4H*+4e- = S+2H20 + 0,45 curx+e- = Cu + 0,52 fa+2e- = 2k +0,54 O2x(g) + 2H*+2e- = H2O2 +0,68 Fe**+e- = Fe* +0,77 NO; +2H*+e- = NO2(g)+ HzO +0,80 Ag*+e- = Ag +0,80 Hg** + 2e- = Halt) +0,85 NO} +4H*+3e- = NO(g) + 2H20 + 0,96 Br(t)+2e- = 2Br- + 1,07 Pre+2e- =— Pt +1,20 MnO2z2+ 4H* + 2e- = Mn** + 2H2O + 1,23 O2x9)+4H*+4e- = 2H2O + 1,23 cro” +14H++60e- = 2Cr* + 7H20 + 1,33 C&(g)+2e- = 20% + 1,36 MnO, + 8H*+5e-— = Mn?* + 4H20 + 1,51 H202+2H*+2e- =— 2H20 +1,77 Co*+e- <= Co + 1,81 F2(9)+2e- = 2F- + 2,87 LimpopoDoE/September 2025 EDUCTION POTENTIALS J Increasing strength of reducing agents / Toenemende sterkte van reduseermiddels Copyright reserved Please turn over

LimpopoDoE/September 2025 15 NSC Physical Sciences/Gr 11 Downloaded from Stanmorephysics.com SUBMIT THIS SHEET WITH THE ANSWER SHEET QUESTION 7.2.2 =e eee es Paes = 71 : oe = Parse Fe es ee ee = a am - om r tt ae pepe -& BISIZIE! Cll ee Ee GEES LER EEE whe pe he Pr paGapafadetedeade de dede EEERE. “os tod > - T e a i> i i> A 7 7 7 e ege - T in ” 4 4 SEPTETT t SEES Leese Pere eee TTTTT Banana 4 sss pete tte eee + + + +t a2 rl pan r 4 glete gtate ma rae 7 ; ; us Di i Eis 7) i aes rs es rere a -a fe pe 4 er ree ee ee eee ees eee eee ——— + ite t ; t ttt aan mas tT ri a ttt : 7 cit be & are Trt sae es ri =a ioe: 4 rrtre a aes TT TT a a ; " iin 2 name : Ere a3 = ae a1 3 r T ra el —> + : z

Downloaded from Stanmorephysics.com grea. LIMPOPO oe PROVINCIAL GOVERNMENT REPUBLIC OF SOUTH AFRICA DEPARTMENT OF EDUCATION NATIONAL SENIOR CERTIFICATE | oRabeicbaao 11 : PHYSICAL SCIENCES: CONTROLLED TEST 2 ; FISIESE WETENSKAPPE: KONTROLE TOETS 2 : AMENDED MARKING GUIDELINE/AANGEPASTE r NASIENRIGL YNE : . SEPTEMBER 2025 J MARKS/PUNTE: 100 This marking guideline consists of 11 pages/Hierdie nasienriglyne bestaan uit 11 bladsye Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from Stanmorephysics. com Physical Sciences/Gr 11 Limpopo DoE/September 2025 NSCINSS Marking Guidelines/Nasienriglyne QUESTION 1/VRAAG 1 1.14. Cvv (2) 12 Dvv (2) 13 Cvv (2) 14 Dvv (2) 15 Byv (2) [10] QUESTION 2/VRAAG 2 2.1. The minimum energy needed for a reaction to take place. ¥v/ Die minimum energie wat be 'n'réaksie om plaas te vind ased than absorbed. v ¥ rd vrygestel as geabsorbeer (2) The potential energy of the product is lower than that of the reactants. “/ Die potensiéle energie van die produk is laer as dié van die reaktante. (1) 2.2 2.3 Ep (kJ.mol’) = & i) iw eaction/Verloop van reaksie Marking criteria/Nasienriglyne e A dotted line under the activated complexv/ ‘n Stippellyn onder die geaktiveerde kompleks (1) Copyright reserved Please turn over

Downloaded from Stanmorephysics. com Physical Sciences/Gr 11 Limpopo DoE/September 2025 NSCINSS Marking Guidelines/Nasienriglyne 2.4 2.4.1, 183,3 kJ.mol" ¥ (1) 2.4.2 400 kJ.mol™ ¥ (1) 2.4.3. 2487.6 kJ.mol" v (1) 2.4.4 2670 kJ.mol" v (1) 2.5 AH = Energy of products - Energy of reactants/ AH = Energie van produkte — energie van reaktante = 400 - 183.3 V = 216.7 kJ.mol” ¥ (2) 2.6 2.6.1 (1) 2.6.2 (1) 2.6.3 (1) [13] Copyright reserved Please turn over

Downloaded from Stanmorephysics. com Physical Sciences/Gr 11 Limpopo DoE/September 2025 NSCINSS Marking Guidelines/Nasienriglyne QUESTION 3/VRAAG 3 3.4 3.1.1. A base is a substance that produces hydroxide ions (OH") when it dissolves in water. v/'n Basis is 'n stof wat hidroksiedione (OH) produseer wanneer dit in water oplos. (2) 3.1.2--HNOs (aq) ¥+H2O0(t) ¥—> H30*(aq) + NOs (aq)¥ (3) Notes/notas: e Reactants ¥ V/reaktante « Products “/produkte e Ignore phases/ignoreer fases e Ignore double arrows/ignoreer dubbel pyle (2) 3.2 Water/H20(2) identi a base in the reaction because it accepts a Hydrogen ion/prote idrochloric acid HC£(aq) to form H3 O*(aq).¥“// Water/H t eras 'n basis in die reaksie omdat dit 'n waterstofioon/proi soutsuur HCf(aq) aanvaar om H30 “aq) te vorm. (2) or the OH" ion concentration in a solution indikator is 'n swak suur, of 'n swak basis, waarvan “ioonkonsentrasie of die OH -ioonkonsentrasie in (2) p(s) + H20(f)v’ (3) Reactants v V/reaktante Products Y/produkte Ignore phases/igoneer fases Ignore double arrows/ignoreer dubbel pyle [14] Copyright reserved Please turn over

Downloaded from Stanmorephysics. com Physical Sciences/Gr 11 NSCINSS Marking Guidelines/Nasienriglyne QUESTION 4/VRAAG 4 Limpopo DoE/September 2025 4.1 Areagent that gets used up completely in a chemical reactiony “/ 'n Reagens wat volledig in 'n chemiese reaksie opgebruik word 4.2 CaCOs(s) + H2SOa (aq) Y— CaSOa(aq) + H20(2) + CO2(g)” Balv Notes/Notas: e Reactantsv /reaktante Products ¥/produkte Balancing “/balansering e Ignore phases/ignoreer fases e Ignore double arrows/ignoreer dubbel pyle OPTION 2/OPSIE 2 (100) (0,5)v = 0.4 mol.dm=v n(CaCOs) = “~ v M 4.4 POSITIVE MARKING FROM 4.3/POSITIEWE NASIEN VANAF 4.3 OPTION 1/OPSIE 1 0.2mol n(CaCOs) x 0.1mol HzO 0.2mol (CaCO3) = 0.1 mol H2O produced by CaCOs ¥ = 20. (100) n(H2SOs) = CV =0.2 mol.dm=v = (0.25) (0.5) ¥ = = n(H2SO4) = CV 0.125 mol = (0.25) (0.5) ¥ = 0.125 mol OPTION 2/OPSIE 2 n(CaCOs) = “— v M Copyright reserved Please turn over (2) (3) (4)

Downloaded from Stanmorephysics. com Physical Sciences/Gr 11 Limpopo DoE/September 2025 NSCINSS Marking Guidelines/Nasienriglyne 0.425mol (H2SO4) x_0.1mol H20 0.125mol (H2SOs) = 0.1 mol H2O produced by H2SO ¥ Ratio/ Verhouding CaCOs: H2SO4 44 0.2mol : 0.125 mol Since you will need 1mol of CaCO3 to react with 1mol H2SO4, to produce 0.1mol H2O. H2S04 is less and it will Ratio/verhouding CaCOs3: H2SO4 31 0.2 mol : 0.125 mol Since you will need 1mol of CaCOs to react with 1mol H2SO4, to produce 0.1mol HzO. H2SOs is less and it will run out first. ./ Aangesien jy 1 mol CaCO3 benodig om met 1 mol H2SO4 run out first./ Aangesien j' yy 1 mol oI CaCOs te reageer om 0.1 mol H20 te (4) benodig om te) produseer, is H2SO4 minder en dit sal reageer om 0.1 ni eerste opraak. is H2SO4 mind opraak. H2SOsis a limiting agent v / H2SOz HeSOais a limitinc is 'n beperkende middel 'n beperkende middel~ 4.5 POSITIVE MARKING FROM 4.3 and 4.4/POSITIEWE NASIEN VANAF 4.3 EN 4.4 Mol ratio 1:1 only 0.125 mol CaCOscan react./ Molverhouding 1:1, slegs 0.125 mol CaCO3 kan reageer. CaCOs : H2SO4 Suiwerheid = Sulwer stof onsuiwer stof _ 125 100 v 20 = 62.5 %v (5) [18] Copyright reserved Please turn over

Downloaded from Stanmorephysics. com Physical Sciences/Gr 11 Limpopo DoE/September 2025 NSCINSS Marking Guidelines/Nasienriglyne QUESTION 5/VRAAG 5 5.1 The mass of one mole of a substance measured in g:mol™.v “/ Die massa van een mol van 'n stof gemeet in g:‘mol™ (2) 2 5.2.1 M (H2O) = 1(2) + 16% = 18 g.mol'"v (2) 5.2.2 Percentage composition in mass/ Persentasie samestelling in massa Element | Percentage Divide all mole ition i | values with 0.709/ Deel alle molwaardes met 0.709 6.383/0.709 = Ov H 12.05% 12.05/1 12.05/0/709 = 12.05V =17vV fe} 11.35% 11,35/16 = 0.709/0.709 = 0.709 ¥ =1v The empirical formula is/Die empiriese formule is: Co3H170Y (7) 5.3 Calculate the number of moles of carbon dioxide produced/ Bereken die aantal mol koolstofdioksied wat geproduseer word m n=-—v M _ 0.01863 44 v = 0.0004 mol¥ (3) [14] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 8 Limpopo DoE/September 2025 NSC/NSS Marking Guidelines/Nasienriglyne . Vv I 'n Suur is 'n proton skenker. (2 orlof 0) (2) ed in water.”/ Hidroniumione word in water gevorm. (2) (2) (2) (3) (2) 6.4.4 _ It’s areaction between strong acid and strong base /neutralisation occurs at almost pH = 7 ¥ / Dit is 'n reaksie tussen 'n sterk suur en 'n sterk basis / neutralisasie vind plaas by amper pH = 7. (1) [14] Copyright reserved Please turn over

Downloaded from Stanmorephysics. com Physical Sciences/Gr 11 Limpopo DoE/September 2025 NSCINSS Marking Guidelines/Nasienriglyne QUESTION 7/VRAAG 7 7.1. The pressure of an enclosed gas is inversely proportional to the volume it occupies at constant temperature. v “/ Die druk van 'n ingeslote gas is omgekeerd eweredig aan die volume wat dit by konstante temperatuur beslaan 7.2 7.2.1 PiV1= P2V2¥ (200) (5.0) “= (150) V2 ¥ V2=6,67L vv E22 eal gas at constant temperature./ Druk ale gas by konstante temperatuur Notes/Notas X and Y axis labelled “/X en Y as byskrifte Curved linew’/geboé lyn Initial volume on graph/ Aanvanklike volume op grafiek e Point marked x on graph (200:5)“/ Punt gemerk met x op grafiek (200:5) Final volume on graph/Finale volume op grafiek e Point marked x on graph (140 -160: 6-7) (Any reasonable range point) Punt gemerk x op grafiek (140 -160: 6-7) (Enige punt met redelike bereik) Copyright reserved Please turn over (2) (4) (4)

Downloaded from Stanmorephysics. com Physical Sciences/Gr 11 Limpopo DoE/September 2025 NSCINSS Marking Guidelines/Nasienriglyne 13 Vy Vin = 12 22,4 = 0,5 mol m n=— M 0,5=16v/M =32,0 g. mol’ ¥ Molar mass of apps ly $2,0)g. mol correspond to that of O2/Oxygen ¥ / Molére massa V g. mol™ stem ooreen met dié van O2/suurstof (5) 7.4 The pressure doub @ same number of molecules are now confined to a smalle ding to more frequent collisions with the tire.v/ Die druk verdubbel omdat dieselfde aantal molekules nou tot 'n kleiner volume beperk is, wat lei tot meer gereelde botsings met die band. (2) [17] TOTAL/ITOTAAL [100] Copyright reserved Please turn over