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GRADE 10
MATHEMATICS PAPER2
MID – YEAR EXAMINATION 2018
MEMORANDUM
MARKS: 75
This memorandum consists of 7 pages
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Mathematics Grade 10 Paper 2 North West June 2018 Memo
Grade 10 Mathematics Paper 2 memorandum from the North West June 2018, 7 pages. Read online or get the free PDF download, question paper linked when available.
Mathematics · Grade 10 · North West June · 2018. Memorandum, 7 pages. Read online or download the PDF.
- Subject
- Mathematics
- Grade
- Grade 10
- Document type
- Memorandum
- Year
- 2018
- Exam period
- North West June
- Paper
- 2
- Curriculum
- CAPS
- Pages
- 7
- File size
- 701.6 KB
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North West June 2018
- Paper 1Question paperMemo
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Mathematics memo/P2 2 NW/June 2018
Grade10
QUESTION 1
1.1 sin sec
sin 47,5 sec 50,3
substitution
1
sin 47,5
cos 50,3 1
2.30
cos50,3
ANSWER ONLY: Full marks
answer
(3)
1.2.1 2 sin x 2
sin x 1 division by 2
answer
x 90 (2)
1.2.2 cos ( x 11) 1 1,79
cos ( x 11) 0,79 transposing
x 11 37,8144 simplification
answer
x 48,81
(3)
1.3.1 24 tan 45
2
1
24 1 answer
5 (2)
1.3.2
sin 60 .sec 60 . cot 30
sin 45
3
3 2
. 2. 3 2
2
2 3
2 1 2
or
6 2 2
3 answer
(5)
[15]
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Mathematics memo/P2 3 NW/June 2018
Grade10
QUESTION 2
2.1
13
12
θ
-5 correct quad
r = 13
5
13
cos sin 12
5 12 13
13 13
17
answer
13
(5)
2.2 Q
P
36
S
R
2.2.1 PS
cos 36 answer
PQ
answer
PQ
cos 36 (2)
PR
2.2.2 QS
tan 36 ratio
PS
QS subs of 9,5
tan 36
9 .5
simplification
QS 9,5 tan 36
QS 6,9cm answer
(4)
2.2.3 SP answer
sin 54 (1)
QP
[12]
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Mathematics memo/P2 4 NW/June 2018
Grade10
QUESTION 3
3.1 opp
sin ratio
hyp
Substitution
122
sin
1200 Answer
6
Answer only: full marks (3)
3.2.1 QT
cos 15 substitution into
72
Q T 72 cos15 the correct ratio
simplification
QT 69,55cm
answer
(3)
3.2.2 QT substitution into
cos35
TR the correct ratio
69,55 simplification
TR answer
cos35
TR 84,90 cm (3)
[9]
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Mathematics memo/P2 5 NW/June 2018
Grade10
QUESTION 4
4.1
f
y – intercept
x – intercept
shape
g
y – intercept
x – intercept
shape
6
4.2 0 0 x 3600 notation
end points
2
4.3 y 0; 2 notation
end points
OR
0 y 2 2
[10]
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Mathematics memo/P2 6 NW/June 2018
Grade10
QUESTION 5
5.1 Lˆ Mˆ (s opp sides) R
SR
Lˆ Mˆ 2 x 1800 ( of s of a Δ)
2M 2 x 180 0
Mˆ 900 x value of M̂
6 x 900 x 1800 (co int s PQ KM ) SR
5 x 900
x 180 answer
(7)
5.2
5.2.1 EGˆ F x (s opp sides / EF EG) S R
(2)
5.2.2 GEˆ D GDˆ E 2 x (Ext of a ∆ FEˆ G ) value of FEˆ G
Fˆ Dˆ DGˆ H (Ext of a ∆ DGˆ F ) SR
x 2 x 75 substitution
x 25
answer (5) [14]
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Mathematics memo/P2 7 NW/June 2018
Grade10
QUESTION 6
6.1
6.1.1 DOC and BOA
OC OA (given) S/R
SR
DCˆO BXˆO (alter...s) S/R
DOˆ C BOˆ A (vert....opp) S/R
DOC BOA ( AAS ) conclusion
AB DC (6)
6.1.2 OD = OB ( DOC BOA) S R
Diagonals bisect each other (2)
7.2 PQ 2 PT 2 QT 2 Pythagoras
substitution
10 8 QT
2 2 2
QT 2 100 64
QT 36 QT 6
QT 6
TS 21 6 TS 15
TS 15
PS 2 TS 2 PT 2
PS 2 152 82 PS 17
PS 289 substitution
PS 17
Perimeter 2(10) 2(17)
answer (7)
[15]
54cm
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