Gr10 Math P2 (English) June 2018 Possible Answer_hlayiso.com_.pdf

Downloaded from hlayiso.com GAUTENG DEPARTMENT OF EDUCATION PROVINCIAL EXAMINATION JUNE 2018 GRADE 10 MATHEMATICS PAPER 2 MARKING GUIDELINES 6 pages

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (Paper 2) GRADE 10 GAUTENG DEPARTMENT OF EDUCATION PROVINCIAL EXAMINATION MATHEMATICS (Paper 2) MARKING GUIDELINES QUESTION 1 1.1 1.1.1 Pythagoras √ √  (2) 1.1.2   (2) 1.1.3 LHS: sin  . cot  . sec RHS: 1 12 5 13  substitute correct    values 13 12 5 1 1 (2) [6] 2

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (Paper 2) GRADE 10 QUESTION 2 2.1 4sin120 tan 200  cos 70 =157,82  answer (2) 2.2 2.2.1  simplify  (2) 2.2.2 ( )   (2) [6] 3

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (Paper 2) GRADE 10 QUESTION 3 3.1 √ 1 2  3  1  √   √     2   2  √  (4) 3.2 cos 50 . cos 30 . sec50  3 x . tan 60  tan 45 3  3 2 (cos 50 . sec50 ). x. 3  2 1  cos50 . sec50  1 3 x  1.  3 1 2 1 1 x  2 2 (5) 3.3 3.3.1 𝑦 f ( x)  2 tan x form asymptote 2 ( ) 0 𝑥 g ( x)  cos x  1 form -2  - intercept  - intercept (6) 4

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (Paper 2) GRADE 10 3.3.2 1 1 (1) 3.3.3 180 1 (1) 3.3.4 x  90 ; 90   critical values  inequality (2) [19] QUESTION 4 4.1 AB//DC co-interior angles B = ( ) R =  + = + = R AD//BC Co-interior angles supplementary (4) 4.2 ABCD is a parallelogram. Opposite sides parallel parallelogram Opposite angles equal  correct reason (2) [6] 5

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (Paper 2) GRADE 10 QUESTION 5 5.1 Cˆ1  Dˆ1 Alternate angles BD // CR R Cˆ  Cˆ 1 2 ˆ Given CR bisect DCE  Cˆ1  Cˆ 2 Cˆ 2  Bˆ 2 Corresponding angles BD // CR B/R Dˆ  Bˆ 1 2 Sides opposite equal angles BC  CD B R (5) 5.2 CD = BC Proven CD = AB Opposite sides parallelogram B/R AD = BC Opposite sides parallelogram B/R ABCD is a rhombus All 4 sides equal R (3) 5.3 BO = OD = 12 Diagonals bisect each other B/R Oˆ  90 Diagonals bisect at 90 B/R Pythagoras AB 2  AO 2  BO 2 (13) 2  AO 2  (12) 2  correct substitute AO 2  169  144 AO 2  25 AO = 5 AO  5 AO  OC Diagonals bisect each other AO = OC AC  10cm AC = 10 (5) [13] TOTAL: 50 6