Mathematics Grade 10 P2 Gauteng June 2017 Memo (English)

Downloaded from hlayiso.com GAUTENG DEPARTMENT OF EDUCATION PROVINCIAL EXAMINATION JUNE 2017 GRADE 10 MATHEMATICS PAPER 2 MEMORANDUM 6 pages

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (Paper 2) GRADE 11 GAUTENG DEPARTMENT OF EDUCATION PROVINCIAL EXAMINATION MATHEMATICS (Paper 2) MEMORANDUM QUESTION 1 OP 2  4  3  Pythagoras ✓ OP2  4  3 1.1 2 2 2 2 OP 2  25 ✓ OP2  25 OP  5 ✓ OP  5 (3) 1.2 1.2.1 sin  3 ✓ answer  (1) 5 1.2.2 cot 4 ✓ answer  (1) 3 1.2.3 sin 2   cos2  2 2 3  4     ✓ 4 5  5 5 9 16   25 25 ✓ answer 1 (2) [7] 2

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (Paper 2) GRADE 11 QUESTION 2 PENALISE JUST ONCE FOR INCORRECT ROUNDING-OFF. 2.1 2.1.1 3 sin 138,7 1,980 ✓ answer (1) 2.1.2 sec 50 1,556 ✓ answer (1) 2.1.3 4 tan 2 288,2. cos164,6 sin 199,4 ✓✓ answer 107 ,402 (2) 2.2 2.2.1 cos 30  tan 60 3 3   3 ✓ 2 2 32 3 ✓ 3  2 ✓ answer 3 3  (3) 2 2.2.2 sin 45  5 cos ec 90  3 tan 2 30 cos 45 sin 45 ✓ 1 cos 45 2  1  2 ✓ cosec 90 1  2    5 1  3  1 2  3 ✓ tan 30  2 3 1 1 ✓ 1  5  3   3 3 ✓ answer  3 (5) [12] 3

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (Paper 2) GRADE 11 QUESTION 3 3.1 tan   4,96   78,60 ✓ answer (1) 3.2 2 sin 2 10 1 sin 2 10  1 ✓divide by 2 2 2 10 30 ✓ 30 2  40   20 ✓answer (3) [4] QUESTION 4 4.1 y f ( x)  2 tan x ✓ shape 2 ✓ asymptote ✓ (45 ; 2) g ( x)  cos x 1 90 180 270 360 x 0 ✓ shape ✓ x -intercept -2 ✓ y -intercept (6) 4.2 4.2.1 1 ✓ answer (1) 4.2.2 180 ✓ answer (1) 4.2.3 y  0 ; 2 ✓ critical values OR ✓ correct brackets/ 0 y  2 inequality (2) [10] 4

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (Paper 2) GRADE 11 QUESTION 5 5.1 Both pairs of opposite sides are parallel. All sides are equal. Diagonals bisect the angles. ✓✓ any two Diagonals bisect at right angles. answers Both pairs of opposite angles are equal. (2) 5.2 A B x  20 2x  60 D C Aˆ  Cˆ Opp angles of // m ✓ statement x  20  2 x  60 x  80 ✓ answer Cˆ  100  (2) [4] QUESTION 6 6.1 A 1 B 2 2 D 1 C Construct diagonal AC In  ADC and  ABC ✓ construction AC  AC Common ✓alternate angles Aˆ  Cˆ 1 1 Alternate angles AB//DC AB//CD Aˆ 2  Cˆ 2 Alternate angles AD//BC ✓alternate angles  ADC  ABC s<< AD//BC  AB = DC ✓  ADC  ABC  ADC  ABC  AD = BC ✓ AB = DC AND  ADC  ABC AD = BC (5) 5

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (Paper 2) GRADE 11 6.2 A D 1 2 2 1 F O E 2 1 1 B 2 C 6.2.1 Fˆ1  Eˆ 2 Alternate angles AF//EC ✓statement and reason Fˆ  Fˆ  Eˆ  Eˆ 180 Angles on straight line 1 2 1 2 ✓statement and Fˆ2  Eˆ 2 reason ✓Fˆ2  Eˆ 2 (3) 6.2.2 In  AFD and  BEC ✓identify correct  AF = EC Opposite sides // m ✓ AF = EC Dˆ 1  Bˆ 2 Alternate angles AD//BC Fˆ  Eˆ 2 1 proved ✓ AFD  BEC  AFD  BEC s<< ✓ AD=BC AD = BC AFD  BEC AB//BC ✓ reason ABCD is a parallelogram One pair of opp sides =// (5) [13] TOTAL: 50 6