Mathematics Grade 10 P1 Gauteng June 2017 Memo (English)

Downloaded from hlayiso.com GAUTENG DEPARTMENT OF EDUCATION PROVINCIAL EXAMINATION JUNE 2017 GRADE 10 MATHEMATICS PAPER 1 MEMORANDUM 6 pages 1

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (PAPER 1) GRADE 10 GAUTENG DEPARTMENT OF EDUCATION PROVINCIAL EXAMINATION QUESTION 1 1.1 Rational ✓ (1) 1.2 Irrational ✓ (1) 1.3 Rational ✓ (1) [3] QUESTION 2 2.1 5 0   ✓answer  12  1 (1) 2.2 1  x 1 ✓answer x (1) 2.3 9 x 1.5 x  2 45 x 1  3  .5 2 x 1 x2 3 . 5 2 x 1 32 x  2.5 x  2 ✓ 32 x  2  2 x  2 x 1 ✓ 32 x2 . 5 x1 3 .5  32 x2( 2 x2).5 x2( x1) ✓answer (3)  51 [5] QUESTION 3 3.1 2 x 2  14 x  60 ✓common factor  2 x  10  x  3 ✓ ( x 10) ✓ ( x  3) (3) 3.2 1 3 9 x b 8 ✓first factor ✓second factor 1  1 1    x  b 3  x 2  b 3 x  b 6  (2) 2  4 2  [5] 2

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (PAPER 1) GRADE 10 QUESTION 4 4.1 2  3x  6  4 x 4 x  3x  6  2 ✓transposing x4 ✓answer (2) 4.2 x x 3x  2   2 2  x 3 x x  x  6 ✓change sign  x x x 3x  2 x 3   x  2 x  3 x  3x  2 ✓common denominator x  x  3  x  x  2   3 x  2 x  2 x  3 ✓simplify x 2  3x  x 2  2 x x 2  3x  x 2  2 x  3x  2 ✓  8x   2  8x   2 ✓answer 1 x 4 (5) 4.3 3 x . 92 x1  81 3 x . 34 x  2  34 35 x2  34 ✓same bases 5x  2  4 ✓equating indices 2 ✓answer x (3) 5 4.4  4  3x  1  5  4  1  3x  5  1 ✓add 1 to both sides  3  3x  6 ✓  3 : on both sides 3: 1  x  2 ✓answer (3) [13] 3

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (PAPER 1) GRADE 10 QUESTION 5 Pattern 1 Pattern 2 Pattern 3 5.1 Tn  7n  3 ✓ 7n ✓3 (2) 5.2 Tn  2n ✓ 2n (1) 5.3.1 T12  2(12) ✓answer  24 (1) 5.3.2 Tn  7 n  3 150  7 n  3 ✓ = 150 ✓ n  21 n  21 (2) [6] 4

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (PAPER 1) GRADE 10 QUESTION 6 y f D(3; 4) B C xx h D 0 6.1 y  ax 2 (3;4) 4  a.32 ✓substitution (3; 4) 4  9a 4 4 ✓a  a 9 9 4 y  x2 (2) 9 6.2 2 4 2 y x2 and y x 3 9 4 2 2 x  x2 ✓equating 9 3 9: 4 x  6 x  18 2 ✓simplification 2: 2 x 2  3x  9  0 (2 x  3)( x  3)  0 3 x  0:  xC   2 ✓correct x co-ordinate 2 3 yC      2 ✓substitute 3 2  1 2 ✓ y co-ordinate 1  3  C   ; 1  2  (5) 5

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (PAPER 1) GRADE 10 6.3 x -intercept: y  0 2 0 x2 3  3 : 0  2x  6 ✓sub y  0 2 x  6  2 : x  3 ✓answer (+) WO = 3 units (2) 6.4 T 4 ; 3 ✓answer (1) [10] QUESTION 7 y  3. 2 x  1 y ✓ asymptote ✓shape ✓ y -intercept (1; 7) 4 6 y  1 x 1 ✓shape -6 0 x ✓ x -intercept ✓any other coordinate Point of intersection (1;7) ✓✓ answer (1; 7) (8) [8] TOTAL: 50 6