Mathematics Grade 10 P1 Gauteng June 2018 Memo (English)

Downloaded from hlayiso.com GAUTENG DEPARTMENT OF EDUCATION PROVINCIAL EXAMINATION JUNE 2018 GRADE 10 MATHEMATICS PAPER 1 MEMORANDUM 6 pages 1

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (PAPER 1) GRADE 10 GAUTENG DEPARTMENT OF EDUCATION PROVINCIAL EXAMINATION QUESTION 1 1.1 25  33  36 . 25  33  36  25 ; 36 answer 5  33  6 (2) 33 lies between 5 and 6 1.2 x  0, 4545454545 100 x  45, 45454545  100 x  45, 45454545 x  0, 4545454545  99 x  45 99 x  45 45 x  x 5 99 11 5 (3)  11 [5] 2

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (PAPER 1) GRADE 10 QUESTION 2 2.1 2.1.1 (3x) 2 ( 2 xy ) 3 2x5 y 4  9 x 2 .  8 x3 y 3 9 x .  8x y 2 3 3  2 x5 y 4 72 x5 y 3  2 x5 y 4  36y 1  36 x55 y 3 4  36  36 y 1 y (3) 36  y 2.1.2 1  1  q 1 2   q   q   2   qp  p  p  p q   1   1   q q p  2 2    2  q2    2  q2    2  2  p  p  pq p   q q p  2 2  1   1   2  2    2  q2    2  q2  pq p  p  p  1 1  2  q2  2  q2  1 1  q2  2  q2 p p p 2 p  2q 2  2q 2 (3) 2.2 2.2.1 6 p  40  p 2  ( p 2  6 p  40)  ( p 2  6 p  40)  ( p  10)( p  4)  ( p  10)  ( p  4) (3) 2.2.2  xy  ( y  x)b  b2   xy  by  bx  b2   xy  by  bx  b2   y ( x  b)  b( x  b) grouping  ( x  b)  ( x  b)( y  b)  ( y  b) (4) [13] 3

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (PAPER 1) GRADE 10 QUESTION 3 3.1 x2 3 1   x  3x  4 x  4 2  2 x 2 correct factors x2 3 1    x  4  x  1 x  4 2  x  1  2  x  2 CD: 2  x  4  x  1 Restriction: ;  6  x  1 2  x  2   6  x  1  1 x  4   x  4 2x  4  6x  6  x  4 answer 2 x  5 x  10  4 (5)  3x  6 x  2 3.2 x 2   1  3 2 x  3  2 x 2 3   2 2 6  x  4  6  x  4 number line (3) -6 4 [8] 4

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (PAPER 1) GRADE 10 QUESTION 4 4.1 4.1.1 T1  3(1)  2  5 T2  3(2)  2  8 method T3  3(3)  2  11  T4  3(4)  2  14 2 Tn  3n  2 (3) 4.2 4.2.1 3x  7; 2 x; 3x  1;....  values 2 x   3x  7   3x  1  2 x equate simplify 2 x  3x  7  x  1 answer  2x   6 (4) x3 4.2.2 2; 6; 10; … Tn  4n  2  4n  2  31 4n  2  31 4n  33  n  8, 25 n  8, 25 conclusion (3) n  9 [10] 5

Downloaded from hlayiso.com MATHEMATICS MEMORANDUM (PAPER 1) GRADE 10 QUESTION 5 5.1 q 1  q 1 y  b 1 x substitute coordinate 5  b2  1 b  2 b2  4 (3) b2 5.2 5.2.1 y   x  2........(1) 3 y  ..............(2) x Substitute (1) in (2): substitute 3 x  2  simplification x factors x  2x  3  0 2  values   x  3 x  1  0  values coordinate form x  3 OR x   1 (6) y   (3)  2 OR y   (1)  2 y  1 y3 Q(3;  1) P(1; 3) 5.2.2 B(2; 0) 2 0 (2) 5.2.3 y   (6)  2  GE  8 GE  8 1 3  EF  y 2 6 1 EF  2 1 7 2 1 (3)  GF  8  2 1 7 2 [14] TOTAL : 50 6