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MATHEMATICAL LITERACY P2
COMMON TEST
JUNE 2014
MEMORANDUM
NATIONAL
SENIOR CERTIFICATE
GRADE 12
SYMBOL EXPLANATION
M Method
MA Method with accuracy
CA Consistent accuracy
A Accuracy
C Conversion
S Simplification
RT/RG Reading from the table/ reading from the graph
SF Substitution in the formula
O Opinion
R Rounding off
F deriving a formula
MARKS: 100
TIME: 2 hours
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MATHS LIT P2 JUNE MEMO(GRADE 12 2014) hlayiso.com
Mathematical Literacy · Grade 12 · Eastern Cape June · 2014. Memorandum, 9 pages. Read online or download the PDF.
- Subject
- Mathematical Literacy
- Grade
- Grade 12
- Document type
- Memorandum
- Year
- 2014
- Exam period
- Eastern Cape June
- Paper
- 2
- Pages
- 9
- File size
- 293.1 KB
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Mathematical Literacy P2 2
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Common Test June 2014
Gr.12 - MEMO
QUESTION 1
1.1.1 72 1A substitution
(a) BMI = √
1.7 x1.7 1CA simplification (2)
=24.9√
65
(b) BMI = √
1.5 x1.5 1A substitution
1A simplification (2)
= 28.9√
1.1.2 W 2 =method
BMI =
H2
69
27 = 1 = CA
H2
27H 2 69
27 27
H2 = 2,56
H2 = 2,56
H = 1,6 (3)
1.2.1 Normal 2 A= RG (2)
1.2.2 BMI Range = 26 – 18 √ 1A concept of Range
= 8√ 1A Answer (2)
1.2.3 It means only 5%√ of learners of the same age are 2A concept of
having a weight more than him/her √√ PERCENTILE
Or
Out of 100 learners of the same age, this learner’s
weight is above the weight of 95 learners
Or
The learner is overweight because her BMI is above
95th percentile (2)
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Common Test June 2014
Gr.12 - MEMO
1.2.4 27,1 – 23 2A = Values
= 4,1 1CA =
Simplification (3)
1.2.5 Start exercising √√ 2 x 2 = Opinion
Start dieting√√
Participate in sporting activities to keep their
bodies active.
Any other valid advice / suggestion (4)
1.3.1 40km – 26.9 km√ = 13.1km√ 1M = Method
1CA = Answer
(2)
1.3.2 (a) Time = 2 : 47 : 30 1A for calculating
06:00:00 + 2 : 47: 30 = 08:47:30 time
08:47:30 1M = adding correct
time
1CA = Answer
(3)
(b) Athlete 2 finished the race at 11:31:29 2A = CORRECT
Athlete 3 arrived at 11:37:00 TIME
Therefore athlete 3 was wrong, athlete 2 1CA =
arrived before CONCLUSION
OR
Athlete 2 finished earlier than athlete 3 (3)
[28]
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Common Test June 2014
Gr.12 - MEMO
Question 2
2.1.1 Coastline = 40% x 580km√ Alternative 1A= Concept of %
= 232km√ 0,4 x 580 1A = simplification (2)
2.1.2 210mm = 580km 1A = Ratio / equation
210mm = 580 000 000mm 1A = conversion
1: 2761904,76 1CA = Simplification
1: 2800 000 1A = Rounding off hundred
thousands (4)
2.1.3 45mm = 125 000 000mm√ 1A =concept of scale
210mm = mm 1A = simplification
210x125000000 1A = converting to km
=
45
= 583 333 333,3
√
583333333,3
=
1000000
=583km√
(3)
It is approximately 580km
2.2 Any valid suggestion 2 O = opinion (2)
2.3.1 One line = 15km ÷20cm 15km = 1500 000 1A = conversion to cm
= 1 500 000cm ÷ 20cm 1A = dividing
= 75 000 fish 1A = answer
OR
1 fish = 20 cm
Straight line of fish = 1 500 000cm
= 1 500 000cm ÷ 20cm
= 75 000 fish (3)
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Common Test June 2014
Gr.12 - MEMO
2.3.2 1 crate = 500 sardines 1A = dividing by 500
Crates = 75 000 1CA = answer
= 75000 ÷ 500
= 150 crates
(2)
2.4.1 3 1=M
P(below 23) = 2 1 or
8
8 1= Simplification
1A = percentage
= 0,375 x 100%
= 37.5% (3)
2.4.2 It is true that the weather of Durban is more 2 O = Opinion
attractive than Cape Town. Durban temperature is
high.
(2)
2.4.3 60% 2 RG / RT (2)
2.4.4 Refer to “ Annexure A” 2A for plotting all
correct bars
1A for correct double
bars
2A for labelling Y-
axis,X-axis and the
graph correctly
(5)
2.4.5 Saturday, because the minimum temperature is 23o 3 O = Opinion
OR any valid reason. (3)
[31]
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Common Test June 2014
Gr.12 - MEMO
QUESTION 3
3.1.1 Perimeter = 2L+ 2B 1A= substituting
= 2(32m) + 2 (24m) √ correct values
= 64m + 48m√ 1A= simplification
= 112m√ 1CA = answer (3)
3.1.2 Volume of pool = Volume of pool – Volume of inner 1A = subtracting
circle 2A= Simplification
= 193,91m3 – √3.142 x1. 9m x 1.9 x 0.75m) √ 1A= correct unit (m3)
=193,91m3 – 8,5069m3
= 185.4m3√ (4)
3.2.1 Total SA of pool = 27m2 + π r x h 2A = Substituting
= 27m2√ +√11,7825m2√ correct values
= 38,78m2√ 1M = addition
1CA = Answer (4)
3.2.2 1litre = 3m2√ 1A = scale / equation
2 38,78 m 2 1CA= Simplification
Liters = 38,78m √ OR
3m 2 1CA= Answer
= 12,94litres√ = 12,94litres√ 1A = Rounding (4)
= 13 litres = 13 litres
3.2.3 5 liters = R64 per liter√ 3A= simplification
10 liters = 58 per liter√ 1A= conclusion
20 liters = 47.50 per liter
Therefore, 20 liter tin is cheaper √
(4)
3.2.4 They must buy 1 x 10 litres and 1 x 5 litres √ 1CA = choice
10 liter x 1 @ R580 = R580 1A= correct Amounts
1 x 5 litres at R320.00 1A = adding /
= R900 multiplying amounts
(3)
[22]
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Common Test June 2014
Gr.12 - MEMO
4.1
4.1.1 30.6 : 22.8 2A = correct ratio
15.3√ : 11. 4 √ 0r 15 : 11 (2)
4.1.2 The national bachelor increased by 10.5 % whereas 2A = opinion
Kwazulu- natal is 14.3%. This means bachelor pass
increased more than the National pass rate. √√
OR any valid opinion (2)
4.1.3 Passes = 77.4% x 145 278 1M = for %
= 112445 √ 1A = Correct passes
Therefore Bachelor passes = 32,5% x 112445 √
= 36544.625 √ 1A = Concept of %
= 365445 √ 1CA = simplification
1CA = Rounding off
(5)
4.1.4 Gauteng or Western Cape 1 A = for Province
For consistency and higher percentage √√ 2 O = Opinion
OR
Any correct justification
No mark for National (3)
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Common Test June 2014
Gr.12 - MEMO
4.2.1 17050 7500 1A= simplification
% increase = x 100
7500
1A = annual inflation
= 127.33%
127.33%
Average % inflation rate =
11
(2)
= 11.58%
4.2.2 Yes, because the inflation reduces the value of 1A= reason (yes)
R15 000.
Interest rate – inflation rate 1A = Concept of
10,8% – 7,7% inflation
= 3,1% 3CA = simplification
value of R15 000 = R15 000 + 3,1% x R15 000
= R15465 (5)
[19]
TOTAL MARKS: [100]
Mathematical Literacy P2
Downloaded from
9
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Common Test June 2014
Gr.12 - MEMO
ANNEXURE A
QUESTION 2.4.4 NAME OF THE LEARNER:………………………………………..
Minimim afternoon Temperatures in Durban and Cape Town
28
24
√ √ √
20
Min. Temperatures
16
12
8
4
0 FRIDAY SATURDAY SUNDAY√
DAYS
KEY√
DURBAN
CAPE TOWN
GRAND TOTAL: 100
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