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N3 MATHEMATICS SPOT ON R80

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EKURHULENI TECH COLLEGE. No. 3 Mogale Square, Krugersdorp. Website: www. ekurhulenitech.co.za Email: info@ekurhulenitech.co.za TEL: 011 040 7343 CELL: 073 770 3028/060 715 4529 Mathematics n3 Downloaded from hlayiso.com Typical exam questions Website: www.ekurhulenitech.co.za Email: info@ekurhulenitech.co.za
T870(E)(N21)T NOVEMBER EXAMINATION NATIONAL CERTIFICATE MATHEMATICS N3 (16030143) 21 November 2016 (X-Paper) 09:00–12:00 Nonprogrammable scientific calculators may be used. This question paper consists of 6 pages and 1 formula sheet. Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -2- T870(E)(N21)T DEPARTMENT OF HIGHER EDUCATION AND TRAINING REPUBLIC OF SOUTH AFRICA NATIONAL CERTIFICATE MATHEMATICS N3 TIME: 3 HOURS MARKS: 100 INSTRUCTIONS AND INFORMATION 1. Answer ALL the questions. 2. Read ALL the questions carefully. 3. Number the answers according to the numbering system used in this question paper. 4. Questions may be answered in any order but subsections of questions must NOT be separated. 5. Clearly show ALL calculations, diagrams, graphs, et cetera, which you have used in determining the answers. 6. If necessary, answers should be rounded off to THREE decimals, unless stated otherwise. 7. Diagrams are NOT drawn to scale. 8. Write neatly and legibly. Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -3- T870(E)(N21)T QUESTION 1 1.1 Simplify: 1.1.1 49 x 2  56 x  16 (2) 1.1.2  13   2 1 1  a  a 3  (a  a  2)   (7) 1.1.3 3x 2  7 x  2 x 2  x  6  2 2 x2  5x  3 x 9 (6) 1.2 If 16x 3  px 2  12x  3 is divided by 2x  1 , the remainder is –7. Determine the value of p . (4) [19] QUESTION 2 2.1 Express 0,125 as a power of 4. (3) 2.2 Solve for x : 3  3 2.2.1 2log x + log  log  2 x    0 4  4 Show All the steps. The use of a calculator is excluded. (6) 2.2.2 4 2x  3 5   x2 4 x 2 x2 (5) [14] QUESTION 3 3.1 Solve for x by completing the square: 18  x 2  9 x (5) 3.2 There are 302 residents in a town. There are 34 more women than men and 60 more children than women. How many women are there? (3) 3.3 Given: PV n  C Calculate the value of n if P =2000, V =0,48 and C =18,3. (5) [13] Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -3- T870(E)(N21)T QUESTION 4 Consider FIGURE 1 below. ABCD is a parallelogram with vertices A(-2;1), B (2;2), C(1;-2) and D ( x; y ) . FIGURE 1 4.1 1 1 Prove that the midpoint M, of AC is equal to ( ;  ) . 2 2 (2) 4.2 Use the co-ordinates of the midpoint, M to determine the co-ordinates of the fourth vertex, D. (3) 4.3 Determine the length of BC. (2) 4.4 Calculate the angle of inclination,  of the line BC. (2) 4.5 Determine the equation of the line in the form y  mx  c which is perpendicular to BC and passes through A. (3) 4.6 Determine the coordinates of the point of intersection of the line through A(-2;1), which is parallel to the y-axis and the line 2 y  x  5 . (3) [15] Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -3- T870(E)(N21)T QUESTION 5 5.1 Sketch the graph of y   36  x 2 in the ANSWER BOOK. ALL values at the points of intersection with the axes must be shown. (3) 5.2 FIGURE 2 shows the graph of f ( x)   x3  ax 2  bx  c . A and B(6;0) are turning points. FIGURE 2 5.2.1 Find the values of a , b and c . Show ALL your calculations. (5) 5.2.2 If f ( x)   x3  12 x 2  36 x , find the coordinates of A. (4) 1 dy 3 5.3 Determine if y  x 2  2 by making use of the rules of differentiation. ALL dx x final answers must be with positive exponents and in surd form where applicable. (4) [16] Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -6- T870(E)(N21)T QUESTION 6 6.1 Make use of trigonometric identities to prove the following: cos 2 (90o  x) 1  cos x  sin(90  x)  1  sin x o 2 cos x (7) 6.2 To find the height of a tower, a surveyor sets up his theodolite 150 m from the base of the tower. He finds that the angle of elevation to the top of the tower is 60°. What is the height of the tower? (3) 6.3 Consider FIGURE 3 below. The crew in a boat, C noticed two lighthouses A and B, one on either side of a beach. The two lighthouses are 0,67 km apart and one is exactly due east of the other. The lighthouses tell how close a boat is by taking bearings to the boat. The bearing from the lighthouse A to the boat C is 127° and the bearing from the lighthouse B to the boat C is 255°. A bearing is an angle measured clockwise from north. Calculate how far the boat, C is from the lighthouse at B. (5) FIGURE 3 6.4 6.4.1 Draw the graphs which are represented by f ( x)  2sin 2 x and g ( x)  cos 2 x on the same system of axes for 0  x  180 . ALL values at the points of intersection with the system of axes and the coordinates of the turning points must be shown. (6) 6.4.2 Use the graph to read off the value(s) of x if 2tan 2x  1 for 0  x  180 (2) [23] TOTAL: 100 Copyright reserved Downloaded from hlayiso.com
(16030143) T870(E)(N21)T FORMULA SHEET 1. Factors 3. Quadratic formula a3  b3  (a  b)(a 2  ab  b 2 ) b  b 2  4ac x 2a a3  b3  (a  b)(a 2  ab  b 2 ) 4. Parabola 2. Logarithms y  ax 2  bx  c log ab  log a  log b 4ac  b 2 y 4a a b log  log a  log b x b 2a log a logb a  c log c b log a m  m log a 5. Circle 1 x2  y 2  r 2 logb a  log a b log a a  1 , ln e  1 x2 D h 4h a loga t  t , eln m  m x  4 Dh  4h 2 6. Straight line 8. Trigonometry y  y1  m( x  x1 ) y 1 sin    r cos ec  Perpendicular lines : m1  m2   1 x 1 cos  cos    cot   Parallel lines : m1  m2 r sec sin  Distance : D  ( x2  x1 ) 2  ( y2  y1 ) 2 y 1 sin  tan    tan   x cot  cos  x x y y  sin 2   cos 2   1 Midpoint : M   1 2 ; 1 2   2 2  Angle of inclination :   tan 1 m 1  tan 2   sec 2  1  cot 2   cosec 2  7. Differentiation sin A sin B sin C   a b c dy f ( x  h)  f ( x ) a  b  c  2bc cos A 2 2 2  lim dx h 0 h d n 1 ( x )  nx n 1 Area of  ABC  ac sin B dx 2 For turning point : f '( x)  0 Copyright reserved Downloaded from hlayiso.com
MARKING GUIDELINE NATIONAL CERTIFICATE NOVEMBER EXAMINATION MATHEMATICS N3 21 NOVEMBER 2016 This marking guideline consists of 10 pages. Copyright reserved Downloaded from hlayiso.com Please turn over
 MARKING GUIDELINE -2- T870(E)(N21)H MATHEMATICS N3 ✓ = 1 Mark QUESTION 1 1.1 1.1.1 49 x 2  56 x  16   7 x  4 2   7x  4  (2) 1.1.2  13   2 1 1  13   2 1 1  a  a  (a  a  2) 3  a  a  (a  a  2) 3      1  1 1   1 1  3 a   (a   2) ✓ 1   a 3  2  (a  1  2) 1    a  a   3 2 a  a3   3 a . 3 a 2  1   a 2  2a  1  1      a  1   a 2  2a  1 1  3 2  a    2   a      3  a   a  1   (a  1) 2  1  a        a 1  a  a  a  3 2  2   3   a  12    a 1  a  a   2    3  (a  1) 2 1  a  a3   1 3 3  a  1 a a  or  (7) (a  1) a  1 1.1.3 3x 2  7 x  2 x 2  x  6  2 2 x2  5x  3 x 9 ✓ (3 x  1)( x  2) ✓ ( x  3)( x  3) ✓  (2 x  1)( x  3) ( x  2)( x  3) ✓ 3x  1   2x 1 ✓ (6) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -3- T870(E)(N21)H MATHEMATICS N3 1.2  1 If f ( x) is divided by 2x+1, then the remainder is f     2 ✓  1  3 2  1  1  1 Hence f     16    p     12     3  7 ✓  2  2   2  2  1 1 16     p  6  3  7  8 4 1 2  p  6  3  7 4 1  p  7  5 ✓ 4 4 p  2   1 p8 ✓ (4) [19] QUESTION 2 2.1 0,125 0,125  4 x 1 1  1 2 ✓   4x ✓   8 8 1  23  22 x ✓  1  2  3  ✓ 3 2    2 x 3 3 2   2 2 4 4 ✓ x   3 ✓ 4 3   0,125  4 4 (3) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -4- T870(E)(N21)H MATHEMATICS N3 2.2 2.2.1 3  3 3  3 2 log x + log  log  2 x    0 2 log x + log  log  2 x    0 4  4 4  4 3 2 3  3 x  log x 2 + log  log  2 x   ✓ log10 4 0 ✓ 4  4 3 2x   3x 2   3 4  log    log  2 x   ✓ 3 2  4   4 x 3x 2 3 100  4   2x  3 ✓ 4 4 ✓ 2x  4  3x 2  8 x  3 ✓ 2 3x 1 ✓  3x 2  8 x  3  0 ✓ 8x  3 ✓  (3x  1)( x  3)  0 3x 2  8 x  3  3x  1  0 x 3  0 3x 2  8 x  3  0 ✓ 1 (3 x  1)( x  3)  0  x  (n/a) x  3 ✓ 3 3x  1  0 x 3  0 1 x  (n/a) x  3 ✓ 3 (6) 2.2.2 4 2x  3 5   x2 4 x 2 x2 4 2x  3 5   ✓ ✓ x  2  x  2  ( x  2) x  2 4( x  2)  2 x  3  5( x  2) ✓ 4 x  8  2 x  3  5 x  10 3 x  21 ✓ x7 ✓ (5) [14] Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -5- T870(E)(N21)H MATHEMATICS N3 QUESTION 3 3.1 18  x 2  9 x x 2  9 x  18  0 ✓ 81 81 x2  9x   18  ✓ 4 4 2  9   x    2, 25  2 ✓ 9 x    2, 25 (5) 2 x  3 or x  6 ✓ ✓ 3.2 Let the number of women = x Let the number of men = x ∴ the number of men = x  34 let the number of women = x  34 ✓ ✓ let the number of children = and the number of children = x  60 x  34  60  x  x  34  x  60  302 ✓  x  x  34  x  94  302 ✓  3x  276 3 x  128  302  x  92 3 x  174 x  58 There are 92 women ✓ There are 92 women ✓ (3) 3.3 PV n  C PV n  C Vn  C  2000  (0, 48) n  18,3 ✓ ✓ P 18,3 C  (0, 48) n  ✓ logV n  log ✓ 2000 P  18,3  n logV  log C  log P ✓  log(0, 48) n  log  ✓  2000  logC  log P n  18,3  logV  n log(0, 48)  log   log18,3  log 2000 ✓  2000  n log18,3  log 2000 log 0, 48 n  log 0, 48 ✓ 1, 262  3,301 n 1, 262  3,301 0,319 n  n  6,395 ✓ 0,319 n  6,395 ✓ (5) [13] Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -6- T870(E)(N21)H MATHEMATICS N3 QUESTION 4 4.1  2  1 1  2  M ( xM ; yM )   ;   2 2 ✓  1 1   ;  ✓  2 2  (2) 4. 2 DM  MB ..... diagonals of parm  1 1  Midpoint of DB  M ( xM ; yM )   ;   2 2   x  2 y  2   1 1  ✓  M ( xM ; yM )   ;  ;   2 2   2 2  x  2 1 y  2 1   and  2 2 2 2 ✓  x  3 y  3 Coordinates of D  (3; 3) ✓ (3) 4.3 BC  ( x2  x1 ) 2  ( y2  y1 ) 2  [1  2]2  [2  2]2  1  16 ✓  17 units ✓ (2) 4.4 2  (2) mBC  4 ✓ 2 1   tan 1 m  tan 1 (4)  75,964o ✓ (2) 4.5 1 The gradient of a line perpendicular to BC   4 The equation of the line is 1 y  y A   ( x  xA ) 4 1 y  1   ( x  2) ✓ ✓ 4 1 1 y 1   x  4 2 1 1 y  x ✓ 4 2 (3) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -7- T870(E)(N21)H MATHEMATICS N3 4.6 The gradient is not defined when a line is parallel to the y-axis(that is, vertical). ALL x co-ordinates are equal  x  2 is the equation of the line …………..equation 1 ✓ 2y  x  5 ……………………….equation 2 Solve equation 1 and 2 simultaneously Substitute 1 into 2  2 y  (2)  5 3 y ✓ 2 3 Point of intersection ( 2; ) ✓ 2 (3) [15] QUESTION 5 5.1 y   36  x 2 ✓ 1 mark for scale 2 marks for correct graph ✓ ✓ (3) 5.2 5.2.1 Since the zeros of f ( x ) are 0, 6 and 6 (the x-axis is tangent to the curve): f ( x)   x( x  6)( x  6) ✓ Coefficient of x3 is -1 as given. f ( x)   x3  12 x 2  36 x ✓ a  12, b  36 and c=0 ✓ ✓ ✓ (5) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -8- T870(E)(N21)H MATHEMATICS N3 5.2.2 f ' ( x)  3x 2  24 x  36 ✓ but at the turning point , f ' ( x )  0 3x 2  24 x  36  0 ✓  x 2  8 x  12  0 ✓  ( x  6)( x  2)  0  x  6 or x  2 ✓ If x  2 then f (2)  (2)3  12(2) 2  36(2)  32  A(2; 32) (4) 5.3 1 3 yx  2 x2 1 y  x 2  3 x 2 ✓ dy 1   6 x 3 ✓ ✓ dx 2 x 1 6   3 2 x x ✓ (4) [16] QUESTION 6 6.1 cos 2 (90o  x) 1  cos x  sin(90  x)  1  sin x o 2 cos x cos 2 (90o  x) LHS  sin(90o  x)  1  sin 2 x  sin 2 x ✓ cos x  cos 2 x ✓ ✓ 1  cos x2 ✓  cos x(1  cos x) ✓  1  cos x 1  cos x  ✓ cos x(1  cos x) 1  cos x  ✓ cos x  RHS (7) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -9- T870(E)(N21)H MATHEMATICS N3 6.2 height of tower tan 60o  150 height of tower  150  tan 60✓o  259,808 m ✓ ✓ (3) 6.3 6.3.1 Aˆ  127o  90o =37o ✓ Bˆ  270o  255o  15o ✓ Cˆ  180o  15o  37 o  128o BC AB ✓  sin A sin C BC 0, 67  sin 37 o sin128o ✓ 0, 67  sin 37 o BC  sin128o  0,51 km ✓ (5) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -10- T870(E)(N21)H MATHEMATICS N3 6.4 6.4.1 ✓ ✓shape ✓ ✓shape ✓ ✓ Shape(1 each = 2) Min TP (1 each = 2) Max TP (1 each = 2) = 6 (6) 6.4.2 13° and 103° ✓ ✓ (2) [23] TOTAL: 100 Copyright reserved Downloaded from hlayiso.com
T950(E)(A)T APRIL EXAMINATION NATIONAL CERTIFICATE MATHEMATICS N3 (16030143) 1 April 2016 (X-Paper) 09:00–12:00 This question paper consists of 6 pages and 1 formula sheet of 2 pages. Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -2- T950(E)(A1)T DEPARTMENT OF HIGHER EDUCATION AND TRAINING REPUBLIC OF SOUTH AFRICA NATIONAL CERTIFICATE MATHEMATICS N3 TIME: 3 HOURS MARKS: 100 INSTRUCTIONS AND INFORMATION 1. Answer ALL the questions. 2. Read ALL the questions carefully. 3. Number the answers according to the numbering system used in this question paper. 4. Questions may be answered in any order but subsections of questions must NOT be separated. 5. Show ALL the calculations and intermediary steps. 6. ALL final answers must be accurately approximated to THREE decimal places. 7. ALL graph work must be done in the ANSWER BOOK. Graph paper is NOT supplied. 8. Diagrams are NOT drawn to scale. 9. Write neatly and legibly. Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -3- T950(E)(A1)T QUESTION 1 1.1 Factorise the following expressions as far as possible in prime factors: 1.1.1 x(3x  2)  y (3 y  2) (4) 1.1.2 4n 4 p  3n 2 p  1 (2) 1.2 Factorise the following expression completely: 2 x3  x 2  5 x  2 (5) 1.3 Simplify the following expression: x  1 2 x  1 2 x 2  7 x  17   2 x 1 3  x x  2x  3 (6) [17] QUESTION 2 2.1 Simplify the following: 1 x 2 x 3 3x 2 (4) 2.2 Use logs to the base 2 and simplify the following WITHOUT using a calculator: log0,5 128 (4) 2.3 Solve for x: 2.3.1 16  32 x  3x  2 2.3.2 (log x  2)  log( x  2)  0 (2  4) (8) [16] Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -4- T950(E)(A1)T QUESTION 3 3.1 Solve for x by completing the square: 4 x  48  2 x 2 (4) 3.2 Make ' b ' the subject of the formula: xb D x b (4) 3.3 Make ' w ' the subject of the formula: log e t  log e p  log e w  ds (3) 3.4 Alex paid a deposit of R3x for a computer. He paid the rest in 9 monthly instalments. He paid a total of R33x . What is the payment of each monthly instalment in terms of x . (4) [15] QUESTION 4 4.1 Consider FIGURE A below. ABC is an isosceles triangle with AB  BC and vertices A(2;1), B(4;5) and C(0;k). FIGURE A Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -5- T950(E)(A1)T 4.1.1 Find the length of AB. (2) 4.1.2 Determine the value(s) of k. (4) 4.1.3 Show that AB is perpendicular to BC if k  7 . (3) 4.1.4 Calculate the area of ABC when k  7 . (3) 4.2 P (2; 1) and Q (4; 7) are points in the plane with M as the midpoint of PQ. Determine the equation of the line parallel to the y-axis and passing through the point M. (4) 4.3 Consider FIGURE B below. The lines BA and CA with equations y  x  2 and ˆ where B and C y  3 x  3 respectively, intersect at A. Determine the size of BAC are the intercepts on the x-axis as shown. (5) FIGURE B [21] Downloaded from hlayiso.com
(16030143) -6- T950(E)(A1)T QUESTION 5 5.1 Draw the graph defined by the equation: 3x 2  3 y 2  27 (2) 5.2 Given : y  x3  6 x 2  9 x 5.2.1 Make use of differentiation to determine the coordinates of the turning points of the given equation. (5) 5.2.2 Draw the graph of the given function. Show ALL values at the points of intersection with the system of axes and the co-ordinates of the turning points. (3) dy 1 5.3 Determine if y   2 x . Leave the answers with positive indices and in dx x surd form. (4) [14] QUESTION 6 6.1 Prove the following trigonometric identity: sin 2 A  tan 2 A  cos 2 A  sec 2 A (4) 6.2 Calculate the value(s) of  which will satisfy the equation if 0o    270o : sin   1  cos 2  (5) 6.3 Consider FIGURE C below. An observer, standing at a point A is watching the top of a vertical tower BC . The angle of elevation of the top of the tower, BC, is 25o and the angle of depression of the foot of the tower is 20o . If the height of the tower BC is known to be 30 m, determine the following: 6.3.1 The distance between the observer at A and the point B. (3) 6.3.2 The distance between the two towers. (3) Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -7- T950(E)(A1)T FIGURE C 6.4 Consider FIGURE D below. The sketch represents the graph of f ( x)  a sin px where 0  x   . Determine the values of a and p . (2) FIGURE D [17] TOTAL: 100 Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -1- T950(E)(A1)T FORMULA SHEET Any applicable formula may also be used. 1. Factors 2. Logarithms a3 - b3 = (a - b)(a2 + ab + b2) log ab  log a  log b a a3 + b3 = (a + b)(a2 - ab + b2) log  log a  log b b logc a 3. Quadratic formula logb a  logc b  b  b 2  4ac x log a m  m log a 2a 1 4. Parabola logb a  loga b y  ax 2  bx  c loga a  1 ∴ 1n e  1 4ac  b 2 aloga t  t ∴ e1n m  m y 4a b x 2a 5. Circle 6. Straight line x2  y2  r 2 y  y1  m(x  x1 ) Perpendicular: m1  m2  1 x2 D h 4h Parallel lines: m1  m2 x  4Dh  4h 2 Distance: D  (x 2  x1 )2  (y 2  y1 )2  x  x 2 y1  y 2  Midpoint: P   1 ;   2 2  Angle of inclination: θ  tan -1m Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -2- T950(E)(A1)T 7. Differentiation dy lim f x  h  f x   dx h → 0 h d n dx   x  nx n - 1 Max/Min For turning points: f '  x   0 8. Trigonometry y 1 sinθ   r cosecθ x 1 cosθ   r secθ y 1 tanθ   x cotθ sin 2 θ  cos 2 θ  1 1  tan 2 θ  sec 2 θ 1  cot 2 θ  cosec2 θ sinθ tanθ  cosθ cosθ cotθ  sinθ sinA sinB sinC   a b c a 2  b 2  c 2  2bc cosA Area of ∆ABC = ½ ac sin B Copyright reserved Downloaded from hlayiso.com
MARKING GUIDELINE NATIONAL CERTIFICATE APRIL EXAMINATION MATHEMATICS N3 1 APRIL 2016 This marking guideline consists of 10 pages. Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -2- T950(E)(A1)T MATHEMATICS N3 QUESTION 1 1.1 1.1.1 x (3x  2)  y (3 y  2)  3x 2  2 x  3 y 2  2 y   3( x 2  y 2 )  2( x  y )   3( x  y )( x  y )  2( x  y )  ( x  y )[3( x  y )  2]  ( x  y )[3x  3 y  2] (4)   1.1.2 4n 4 p  3n 2 p  1  (n 2 p  1)(4n 2 p  1)   (2) 1.2 f ( x)  2 x 3  x 2  5 x  2  f (1)  2(1)3  (1) 2  5(1)  2 =2  1  5  2  =0  x-1 is a factor of f ( x)  2 x 2  3x  2 x-1 2 x3  x 2  5 x  2  2 x3  2 x 2 3x 2  5 x 3x 2  3 x - 2x  2 -2 x  2 . .  f ( x)  ( x  1)(2 x 2  3 x  2) = ( x  1)(2 x  1)( x  2)   (5) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -3- T950(E)(A1)T MATHEMATICS N3 1.3 x  1 2 x  1 2 x 2  7 x  17     x  1 x  3 ( x  1)( x  3) ( x  1)(x  3)  (2 x  1)(x  1)  2 x 2  7 x  17 =  ( x  1)(x  3) x 2  4 x  3  2 x 2  x  1  2 x 2  7 x  17 =  ( x  1)(x  3) 5( x 2  2 x  3)   ( x  1)(x  3)  (6) [17] Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -4- T950(E)(A1)T MATHEMATICS N3 QUESTION 2 2.1 1 x 2 x 3 3x 2 2x 1 3  1  3x 2  2 2x 2x 1 1  1  3  2 2 2x 3x 2x 1   6 x2 (4)  2.2 log 0,5 128 log 2 128   1 log 2  2 log 2 27   log 2 21 7 log 2 2  1log 2 2   7 (4) 2.3 2.3.1 16  32 x  3x  2   2 16  32 x  3x  2  16  32 x  32 x  4.3x  4  12  4.3x   3x  3 x 1  TEST : If x  1 then LHS=RHS=5 (4) 2.3.2 (log x  2)  log( x  2)  0  log x  2  0 or log( x  2)  0  log x  2  x  2=100   x  102 x 2 1  x  100  x3  (4) [16] Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -5- T950(E)(A1)T MATHEMATICS N3 QUESTION 3 3.1     (4) 3.2 xb D2   xb    (4) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -6- T950(E)(A1)T MATHEMATICS N3 3.3 tw loge  ds  p tw  e ds  p p ds w e  t (3) 3.4 Deposit is R3x  Total price is R33x  Total amount for 9 instalments= R30x 30 x 10 x  Each monthly instalment = R R 9 3   (4) [15] Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -7- T950(E)(A1)T MATHEMATICS N3 QUESTION 4 4.1 4.1.1  x2  x1    y2  y1  2 2 AB  =  4  2    5  1 2 2 = 4  16  = 20  =2 5 (2) 4.1.2 BC=2 5  0  4    k  5  20 2 2  16   k  5  2 = 20    k  5 = 4 2 k  5 =  2   k  5  2 or k  5  2 k  7  k 3  (4) 4.1.3 5 1  M AB  2  42 75 1  M CB    04 2 M AB  M CB  1  therefore CB  AB (3) 4.1.4 1 Area of ΔABC = × base × height 2 1 =AB  BC  2 1 = 20  20  2 =10 units 2  (3) Copyright reserved Downloaded from hlayiso.com
MARKING GUIDELINE -8- T950(E)(A1)T MATHEMATICS N3 4.2 x x y y  coordinates of M   1 2 ; 1 2   2 2   2  4 1  7  =  ;   2 2  =(1;3)    Equation x =1   (4) 4.3 M AB  1 M AC  3    tan   1  tan =3  =45o   =71,565o  ˆ =    = 71,565o  45o = 26,565o BAC  (5) [21] QUESTION 5 5.1 3x 2  3 y 2  27 Y 3  -3 0 3  X Copyright reserved Downloaded -3 from hlayiso.com Please turn over (2)
MARKING GUIDELINE -9- T950(E)(A1)T MATHEMATICS N3 5.2.1 y  x3  6 x 2  9 x dy  3x 2  12 x  9  dx Let y  0   3 x 2  12 x  9  0 3( x 2  4 x  3)  0 ( x  1)( x  3)  0   x  1 or x  3 f (1)  (1)3  6(1) 2  9(1)  4 f (3)  (3)3  6(3) 2  9(3)  0   (5) Turningpoints (3;0) and (  1; 4) 5.2.2    (3) 5.3 1 y 2 x x 1  1 y  x  2x 2 1 dy 2    x  2(0,5)x 2 dx dy 1 1  2  dx x x   (4) [14] Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -10- T950(E)(A1)T MATHEMATICS N3 QUESTION 6 6.1    (4) 6.2 sin   1  cos 2   sin   sin 2    sin 2   sin   0  sin  (sin   1)  0   sin   0 or sin   1   0 o or   90o  or  180o   (5) 6.3 6.3.1 In ABC : AB 30  o  sin 70 sin 45o 30sin 70o   AB  sin 45o (3)   39,868m 6.3.2 In ABD : AD   cos 25 o AB  AD  AB cos 25o   39,868  cos 25o (3)  36,133m  Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -11- T950(E)(A1)T MATHEMATICS N3 6.4 a2  p2 (2)  [17] TOTAL: 100 Copyright reserved Downloaded from hlayiso.com Please turn over
1 T950(E)(A2)T APRIL EXAMINATION NATIONAL CERTIFICATE+ MATHEMATICS N3 (16030143) 2 April 2015 (Y-Paper) 13:00–16:00 This question paper consists of 7 pages and a formula sheet of 2 pages. Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -2- T950(E)(A2)T DEPARTMENT OF HIGHER EDUCATION AND TRAINING REPUBLIC OF SOUTH AFRICA NATIONAL CERTIFICATE MATHEMATICS N3 TIME: 3 HOURS MARKS: 100 NOTE: Diagrams are NOT drawn to scale. INSTRUCTIONS AND INFORMATION 1. Answer ALL the questions. 2. Read ALL the questions carefully. 3. Number the answers according to the numbering system used in this question paper. 4. Show ALL the calculations and intermediary steps. 5. Questions may be answered in any order but subsections of questions must NOT be separated. 6. ALL final answers must be accurately approximated to THREE decimal places. 7. ALL graph work must be done in the ANSWER BOOK. Graph paper is NOT supplied. 8. A formula sheet is attached to this question paper. The list is NOT necessarily complete. Any other applicable formula may be used. 9. Write neatly and legibly. Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -3- T950(E)(A2)T QUESTION 1 1.1 Simplify the following expression without using a calculator. 1  1  12   1 x x 2 2  x  x 2    (4) 1.2 Determine the value of p if x  2 is a factor of the following function: f ( x)  2 x 3  px 2  4 x  5 (3) 1.3 Factorise as far as possible in prime factors: 1.3.1 x2  y 2  2 x  2 y (3) 1.3.2 2 2x2  3  (4) x2 1.4 Simplify: p 2  121 p2 2 p  22   2 (6) p  4 2 p  22 p  2 p  11( p  2) 2 [20] QUESTION 2 2.1 Solve for x : 2.1.1 27 x  9 x  2  1 (3) 2.1.2 2x  2x2  12 (4) 2.1.3 log x  log 3  log(3 x  1)  log 4 (4) 2.2 The area of a rectangular swimming pool, 10 m long and 3 m wide, doubles if its length and width are increased by the same amount. Calculate the dimensions. (4) 2.3 Make m the subject of the following formula: 2mgh W mr 2  I (4) 2.4 Make T the subject of the following formula: 900 t  0,1e T (4) Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -4- T950(E)(A2)T 2.5 Determine x by completing the square: 3 x  10  x 2 (4) [27] QUESTION 3 3.1 In FIGURE 1 below L(-5;-2), M(-1;-6) and K(5;4) are vertices of triangle KLM in a Cartesian plane. FIGURE 1 3.1.1 Calculate the coordinates of the midpoint of MK. (2) 3.1.2 Determine the gradient of LM. (2) 3.1.3 Determine the length of LM. Leave the answer in surd form. (2) 3.1.4 Determine the equation of the line parallel to LM passing through the point K. Leave your answer in general form. (3) 3.2 Determine the equation of the straight line that passes through the points A(2;4) and B(-1;-3). Leave your answer in gradient-intercept form. (3) 3.3 Downloaded from hlayiso.com Calculate the angle of inclination of the line in QUESTION 3.2. Copyright reserved Please turn over (3)
(16030143) -5- T950(E)(A2)T 1 3.4 Determine the equation of the line AB that is perpendicular to the line f ( x)  x in 3 FIGURE 2 below. AB cuts the x-axis at x  6 . Leave the answer in surd form and in gradient-intercept form. (3) FIGURE 2 [18] QUESTION 4 dy 4.1 Determine by using the rules of differentiation. Leave the answers with positive dx indices and in surd form. 2 4.1.1 y 2 x (3) x x5  x3 4.1.2 y (3) 5x2 Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -6- T950(E)(A2)T 4.2 Consider FIGURE 3 below. Determine the x-coordinates of the turning points P and Q of f ( x)  x3  9 x . (3) FIGURE 3 [9] QUESTION 5 5.1 The design of a bridge in FIGURE 4 shows an arch represented by a parabola, which is defined by the equation y  2 x  0, 25 x 2 . ww.dragoart.com FIGURE 4 5.1.1 Draw the graph of the parabola. (3) 5.1.2 Use the graph to determine the height of the bridge (in meters) if the line y = 0 represents the water level of the river. (1) 5.1.3 Copyright reserved Downloaded from hlayiso.com How wide is the river that flows through the arc when y = 0?. Please turn over (1)
(16030143) -7- T950(E)(A2)T 5.2 Draw the graphs of the following trigonometric functions on the same system of axes for 0  x  180 : y  3 sin 2 x and y  2 cos 3 x ALL values at the point of intersection with the system of axes and the co-ordinates of the turning points must be shown. (6) [11] QUESTION 6 6.1 Simplify the following without using a calculator: tan(180o  A) 1  sin 2 A cos 2 (180o  A)  sin 2 (360o  A) (4) 6.2 Make use of basic trigonometric identities to prove that: 1  cos  sin    2 cos ec sin  1  cos  (4) 6.3 Calculate the values of  that will satisfy the following equation for 0    360 : sin   2 cos (3) 6.4 Consider FIGURE 5. From the top of a cliff 60 m above sea level the angles of depression of two ships on the same vertical plane as the observation point are 20° and 25° respectively. Calculate the distance between the two ships. FIGURE 5 (4) [15] TOTAL: 100 Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -8- -1- T950(E)(A2)T MATHEMATICS N3 FORMULA SHEET Any applicable formula may also be used. 1. Factors/Faktore 2. Logarithms/Logaritmes a 3  b 3  a  b a 2  ab  b 2  log ab  log a  log b a 3  b 3  a  b a 2  ab  b 2  a log  log a  log b b 3. Quadratic formula/ log c a logb a  Kwadratiese formule log c b  b  b 2  4ac x 2a log a m  m log a 1 4. Parabola/Parabool logb a  log a b 5. y  ax  bx  c 2 log a a  1 ln e  1 4ac  b 2 y 4a a loga t  t  e ln m  m b x 2a 5. Circle/Sirkel 6. Straight Line/Reguitlyn x2  y2  r 2 y  y1  mx  x1  Perpendicular: x2 m1  m2  1 D h Loodreg: 4h Parallel Lines: x  4 Dh  4h 2 Ewewydige lyne: m1  m2 Distance: Afstand: D x 2  x1 2   y 2  y1 2 Midpoint:  x  x 2 y1  y 2  Middelpunt: P 1 ;   2 2  Angle of inclination: Hellingshoek:   tan 1 m Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -2--9- T950(E)(A2)T 7. Differentiation/Differensiasie dy lim f  x  h   f  x   dx h 0 h d n dx   x  nx n 1 Max/ Min Maks/ Min For turning points: Vir draaipunte: f 1 x   0 8. Trigonometry/Trigonometrie y 1 sin    r cos ec x 1 cos   r sec y 1 tan    x cot  sin 2   cos 2   1 1  tan 2   sec 2  1  cot 2   cos ec 2 sin  tan   cos cos cot   sin  sin A sin B sin C   a b c a 2  b 2  c 2  2bc cos A Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE NATIONAL CERTIFICATE APRIL EXAMINATION MATHEMATICS N3 2 APRIL 2015 This marking guideline consists of 9 pages. Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -2- T930(E)(A2)T MATHEMATICS N3 QUESTION 1 1.1 1  12    11 1  1  12   1 x  x  x  x 2  2 2 x x2 2 x  x 2      1  1  1  1 1  1  x  x    x2  x 2  x2  x 2 x  x 1  x 1  x 1   2x 2      x  x  2 2 x   x 1 x 1  x x  x 2 2 x (4)    x x 1.2 x  2 f ( x)  2 x3  px 2  4 x  5 f (2)  2(2)3  p(2)2  4(2)  5   16  4 p  8  5  4 p  13 4 p  13  0  13 p 4  (3) 1.3 1.3.1 x2  y 2  2 x  2 y    ( x  y )( x  y )  2( x  y )  ( x  y )( x  y  2)  (3) 1.3.2 2  2x2  3  x2 2 x 4  3x 2  2    x2 (2 x 2  1)( x 2  2)   x2 (4) 1.4 p 2  121 p2 2 p  22   2    p  4 2 p  22 p  2 p  11( p  2) 2   p  11 ( p  11)  p 2  p(p 2)  11( p  2)  p  2  ( p  2) 2( p  11) 2( p  11)    p  11 ( p  11)  (p 2)  (p 2)(p 11)   p  2  ( p  2) 2( p  11) 2( p  11) p  11   (6) Downloaded from hlayiso.com 4 [20] Copyright reserved Please turn over
MARKING GUIDELINE -3- T930(E)(A2)T MATHEMATICS N3 QUESTION 2 2.1 2.1.1 33x  3 2 x4  30  3x  2x  4  0 5x  4  4  x (3) 5 2.1.2 2 x  2 x  2  12 x x2  2 2  2 2  12 x x 2 2  2 2 .2  12  x 2 2 1  2   12 x  2 2  22 x4  (4) 2.1.3 log x  log 3  log(3 x  1)  log 4 log x  log 3  log(3 x  1)  log 4 3x  log  log 4 (3x  1)  3x  12 x  4  4 x  9 (4) 2.2 (10  x)(3  x)  30  2 30  13x  x 2  60  x 2  13x  30  0  x  15 or x  2 New length = 12 m New width = 5 m   (4) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -4- T930(E)(A2)T MATHEMATICS N3 2.3 2mgh w2   mr 2  I w2 mr 2  w2 I  2mgh  w2 mr 2  2mgh   w2 I m( w2 r 2  2 gh)   w2 I  w2 I w2 I m or m  w2 r 2  2 gh 2 gh  w2 r 2  (4) 2.4 900 t  0,1e T 900 t e T 0,1  900 t ln  ln e T 0,1  t 900 ln  0,1 T 900 900   T  ln t ln t  ln 0,1 0,1 (4) 2.5 3 2 3 2 x 2  3 x     10    2 2 2  3 9  x    10    2 4 3 9 x   10  2 4 x  3 49  2 4 3 7 x  2 2 x  2 or x  5 (4) [27]   QUESTION 3 3.1 3.1.1 midpoint of MK  1  5 6  4   ;   2 2    (2) = (2;-1) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -5- T930(E)(A2)T MATHEMATICS N3 3.1.2 62 m 1 5 4 =  4 m  1  (2) 3.1.3 LM  (1  5)2  (6  2)2 = 16  16  = 2 16 (2)  =4 2 3.1.4 y  y1  m( x  x1 ) y  4  1( x  5)  y  4  x  5  y x90  (3) 3.2 43 m 2 1 7  3  y  y1  m( x  x1 ) 7 y  4  ( x  2)  3 7 14 y4 x 3 3  7 2 y  x or y  2,333x  0,667 (3) 3 3 3.3 m  tan  7    tan 1    3 (3) = 66,8  3.4 m2   3  y  y1  m( x  x1 ) y  0   3( x  6)  y   3x  6 3  (3) [18] Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -6- T930(E)(A2)T MATHEMATICS N3 QUESTION 4 4.1 4.1.1 2 y 2 x x 1 y  2 x 1  2 x 2  dy 1  2 x 2  x 2 dx  2 1 = 2  x x  (3) 4.1.2 x5  x3 y 5x2  1 1 y  x3  x 5 5 dy 3 2 1  x    dx 5 5 (3) 4.2 y  x 3  9x dy  3x 2  9 dx  3( x 2  3)  0  x2  3 x 3  x-coordinate of P   3   (3) [9] x coordinate of Q= 3 Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -7- T930(E)(A2)T MATHEMATICS N3 QUESTION 5 5.1 5.1.1     (3) 5.1.2 4 meters  (1) 5.1.3 8 meters  (1) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -8- T930(E)(A2)T MATHEMATICS N3 5.2       y  3sin 2 x y  2 cos 3 x x-intercepts: 0o ,90o ,180o x-intercept : 30o ,90o ,150o y-intercept:0o y-intercept : 2 maxpoint:(45o ,3) maxpoint:(0o , 2), (120o , 2) (6) minpoint : (135 , 3), o minpoint : (60 , 2), (180 , 2) o o [11] QUESTION 6 6.1 tan(180o  A) 1  sin 2 A cos 2 (180o  A)  sin 2 (180o  A)  tan A cos 2 A     cos A   sin A 2 2  tan A cos A     cos 2 A  sin 2 A   sin A  (4) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -9- T930(E)(A2)T MATHEMATICS N3 6.2 (1  cos  )(1  cos  )  (sin  )(sin  ) sin  (1  cos  ) 1  2 cos   cos2   sin 2   = sin  (1  cos  ) 2(1  cos  )  = sin  (1  cos  )  2 = sin   = 2 cos ec  LHS  RHS (4) 6.3 sin   2 cos  cos cos tan   2    tan 1  2   reference α  63, 4   116,6 or  (3)   296,6 6.4 60 In  ABD tan 20o  BD BD  164,849 m  60 In  ACD tan 25o   CD CD  128, 67 m BC=BD  CD=36,179 m   (4) [15] TOTAL: 100 Copyright reserved Downloaded from hlayiso.com Please turn over
16030143 -2- T930(E)(N18)T T940(E)(N18)T NOVEMBER EXAMINATION NATIONAL CERTIFICATE MATHEMATICS N3 (16030143) 18 November 2014 (Y-Paper) 13:00–16:00 This question paper consists of 6 pages and 1 formula sheet of 2 pages. Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -2- T940(E)(N18)T DEPARTMENT OF HIGHER EDUCATION AND TRAINING REPUBLIC OF SOUTH AFRICA NATIONAL CERTIFICATE MATHEMATICS N3 TIME: 3 HOURS MARKS: 100 ________________________________________________________________________ INSTRUCTIONS AND INFORMATION 1. Answer ALL the questions. 2. Show ALL the calculations and intermediary steps. 3. Questions may be answered in any order but subsections of questions must NOT be separated. 4. ALL final answers must be accurately approximated to THREE decimal places. 5. All graph work must be done in the answer book. Graph paper is NOT supplied. 6. Note that diagrams are NOT drawn to scale. 7. A formula sheet is attached to this question paper. The list is NOT necessarily complete. Any other applicable formula may be used. 8. Write neatly and legibly. Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -3- T940(E)(N18)T QUESTION 1 1.1 Simplify the following WITHOUT using a calculator: 1.1.1  log x a  (log a b) (2) 1.1.2 x y  (3) x x 1.1.3 2 18  3 32 (3) 2 8 1.2 Make use of the factor theorem to prove that x  7 is a factor of the function f ( x)  x 3  39x  70 (3) 1.3 Factorise the following two expressions as far as possible in prime factors: 1.3.1 p 2  4m 2  4m  1 (3) 1.3.2 12a 2  27b 2 (2) 1.4 Simplify the following expression: x 2  2x x 3 x 3  3  (4) x  4 x  x  4x  4 x  2 2 2 [20] QUESTION 2 2.1 Solve for x in the following equations : 2.1.1 x5  x  3 (3) 2.1.2 log5 x  log5 x3  log5 x5  18 (3) 2.1.3 x x 1 x2 1 3 3    11 3 (4) 2.2 Make r the subject of the following formula: P  0, 4 e  k r (4) 2.3 Make x the subject of the formula: x 1 H (4) x2 Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -4- T940(E)(N18)T 2.4 Solve for x by completing the square: x 2  12x  10 (4) 2.5 Calculate the coordinates of the points of intersection of the graphs defined by the following two equations: x  2 y  17 5 y x7 (5) 4 2.6 The length of the rectangular field is 6 m longer than 3 times its breadth. What are the measurements of the rectangle if the perimeter is 188 m ? (3) [30] QUESTION 3 3.1 Consider FIGURE 1. The parabola f in the sketch cuts the x-axis at E and P and the y-axis at M. The straight line g cuts the x- and y-axis at E and M respectively. The functions f and g are defined by f ( x)   x 2  4 x  5 and g ( x)  mx  c . FIGURE 1 Determine the following: 3.1.1 The co-ordinates of M, E and P which are the intercepts of the graphs with the system of axes (3) 3.1.2 The co-ordinates of the turning point N of the graph of f (2) 3.1.3 The values of m and c in g ( x)  mx  c (2) Downloaded from hlayiso.com 3.1.4 The length of EM in simplified surd form (2) Copyright reserved Please turn over
(16030143) -5- T940(E)(N18)T 3.2 Determine the equation of a straight line that passes through the point  1; 2  and which is perpendicular to the line y  4 x  2 .Write your answer in general form. (3) 3.3 Determine the value of p if: 3.3.1 p is the x -coordinate of the midpoint of the line segment joining (3, 1) and (1, 3) 3.3.2 p is the angle of inclination of the line y  3x  1 x2 y 2 3.3.3 p is the radius of the circle defined by   81 9 9 3.3.4 p is the gradient of the line which is parallel to x  2 y  0 3.3.5 p is the y-intercept of the ellipse defined by x 2  9 y 2  81 (5 x 2) (10) [22] QUESTION 4 4.1 f ( x  h)  f ( x ) Determine lim for the following function: h 0 h f ( x)  4 x 2 (4) 4.2 dy Determine by making use of the rules of differentiation. Write your answer with dx positive exponents and in surd form when applicable. 4.2.1 1 y 4 4 x (4) x4 4.2.2 x3  x y (3) x 1 [11] QUESTION 5 5.1 Solve the following equation if 0o    360o : 3cot   2  9,5 (3) 5.2 Use trigonometric identities to prove that tan 2   sin 2   tan 2  .sin 2  (4) Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -6- T940(E)(N18)T 5.3 Consider FIGURE 2. A window washer on a ladder looks at a nearby building 100 m away, noting that the angle of elevation of the top of the building is 18, 7 o and the angle of depression of the foot of the building is 6,5o . How tall is the nearby building? FIGURE 2 (4) 5.4 Consider FIGURE 3. Calculate the length of AB by using the sine rule. FIGURE 3 (2) 5.5 Draw the graphs which are represented by the following trigonometric equations on the same system of axes for 0  x  180 : f ( x)  cos x g ( x)  sin( x  30o ) (4) [17] Copyright reserved Downloaded from hlayiso.com TOTAL: Please turn over 100
16030143 -1- T930(E)(N18)T FORMULA SHEET Any other applicable formula may also be used. 1. Factors/Faktore 2. Logarithms/Logaritmes a 3  b 3  a  b a 2  ab  b 2  log ab  log a  log b a 3  b 3  a  b a 2  ab  b 2  a log  log a  log b b 3. Quadratic formula/ log c a Kwadratiese formule logb a  log c b  b  b 2  4ac log a m  m log a x 2a 1 logb a  4. Parabola/Parabool log a b 5. y  ax  bx  c 2 log a a  1 ln e  1 4ac  b 2 y 4a a loga t  t  e ln m  m b x 2a 5. Circle/Sirkel 6. Straight line/Reguitlyn x2  y2  r 2 y  y1  mx  x1  Perpendicular: x2 m1  m2  1 D h Loodreg: 4h Parallel lines: x  4 Dh  4h 2 Ewewydige lyne: m1  m2 Distance: Afstand: D x 2  x1 2   y 2  y1 2 Midpoint:  x  x 2 y1  y 2  Middelpunt: P 1 ;   2 2  Angle of inclination: Hellingshoek:   tan 1 m Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -2- T930(E)(N18)T 7. Differentiation/Differensiasie dy lim f  x  h   f  x   dx h 0 h d n dx   x  nx n 1 Max/Min Maks/Min For turning points: Vir draaipunte: f 1 x   0 8. Trigonometry/Trigonometrie y 1 sin    r cos ec x 1 cos   r sec y 1 tan    x cot  sin 2   cos 2   1 1  tan 2   sec 2  1  cot 2   cos ec 2 sin  tan   cos cos cot   sin  sin A sin B sin C   a b c Downloaded from hlayiso.com a 2  b 2  c 2  2bc cos A Copyright reserved Please turn over
MARKING GUIDELINE NATIONAL CERTIFICATE NOVEMBER EXAMINATION MATHEMATICS N3 18 NOVEMBER 2014 This marking guideline consists of 9 pages. Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -2- T940(E)(N18)T MATHEMATICS N3 QUESTION 1 1.1 1.1.1  log x a  (log a b) or log x a  log x b apply law log x a  simplify and log a log b    write it as ONE log x log a  log x b log log b   log x   log x b (2) 1.1.2 x y  x x common x . x  xy  denominator  x x factorisation x  xy x (1  y ) divide and    rationalized x x x x denominator (1  y )  x x (1  y )   x (3) 1.1.3 2 3 2  3 4 2  prime factors in 22 2 roots 2 6  12  factorisation  2 1  2  value (3)  2  1.2 Let x  7 f (7)  7 3  39(7)  70 value of x  substitution  343  273  70 =0 deduction x  7 is a factor of f(x)  (3)  1.3 1.3.1 p 2  4m 2  4m  1 factorise  p 2  (2m  1)(2m  1)  factorise  p 2  (2m  1) 2 simplify   [ p  2m  1][ p  2m  1]  (3) 1.3.2  3 4a 2  9b 2  factorise factorise  32a  3b2a  3b Copyright reserved Downloaded  from hlayiso.com Please turn over (2)
MARKING GUIDELINE -3- T940(E)(N18)T MATHEMATICS N3  1.4 x2  2x x3 x3 division sign  3 2  factorise first x  4 x  x  4x  4 x  2 2 term x( x  2) x 2 ( x  1)  4( x  1) x  3 grouping  2   x 4 x 3 x2 answer   x( x  2)  ( x  4)( x  1)  x  3 2  x2  4 x 3 x2  x( x  1) (4)  [20] QUESTION 2 2.1 2.1.1 x5  x  3 square both sides x  5   x  3 2  factorise x  5  x2  6x  9 solve (penalise with ½ x2  5x  4  0  mark if -4 is not ( x  1)( x  4)  0 shown as invalid) x  1 or x  4  (3) 2.1.2 log 5 x  log 5 x 3  log 5 x 5  18 write it as one log by applying law log 5 x 9  18 9 log 5 x  18 applying log 5 x  2  definition of log x  52  value x  25  (3) 2.1.3 x x 1 1 x2 3  3     11 applying 3 exponent law x 1 x2  3  3  3x  11 factorising 3x  3  9  1  11 use exponent rule  to find value 3 1x value 3x  30  (4) x0  Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -4- T940(E)(N18)T MATHEMATICS N3 2.2 P  0, 4 e k r manipulate using logs P e  k r  simplify 0, 4 make r the subject P ln ln e k r  0, 4 P ln  kr  0, 4 P ln r 0, 4  k ln P  ln 0, 4 ln 0, 4  ln P   (4) k k 2.3 x 1 H square both sides x2 cross multiply x 1 take out t as H2   x2 common factor H  x  2  x 1 2 simplify  H 2 x  2H 2  x  1 H 2 x  x  2 H 2  1  x( H 2  1)  2 H 2  1  (2 H 2  1) (4) x H 2 1 2.4 x 2  12 x  10  0  write LHS as 2 2 perfect square  12   12   x subject of the x  12 x      10     2  2  2 formula  both values  x  6   46 2 correct rounded  x  6   46 off-penalize only with one here x  6  46 x  12, 782 or x  0, 782   (4) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -5- T940(E)(N18)T MATHEMATICS N3 2.5 x  2 y  17 ...(1)  simplify 5 y substitutions x7 ....(2) simplifying 4  value of x x  10 y  85  x  85  10 y value of y  Replace x by 85 -10 y in equation 2: y  4 x  28 y  4(85  10 y )  28  y  340  40 y  28 39 y  312 y 8 Replace y by 8 in equation 2 :  8 x7 4 x5 (5) 2.6 Let breath be equal to x Any steps Then length  3x   6 answer Perimeter  2  l  b  188  2[ x  3 x  6]  8 x  12  188 x  22m  3x  6  72m (3)  [30] QUESTION 3 3.1 3.1.1 let y  0 M let x  0 E 0   x2  4 x  5 y  005 P  x  5 y5   or x  1  M  (0;5)  (3)  E  (5;0) and P  (1;0) 3.1.2   4 x-coordinate x 2 1 y-coordinate x  2 y   2  4 2  5 2 y 9 (2)  N   2;9 Copyright reserved Downloaded   from hlayiso.com Please turn over
MARKING GUIDELINE -6- T940(E)(N18)T MATHEMATICS N3 3.1.3 50 y  mx  c m m 05 5  10  c  c (2) m  1  c  5 3.1.4 EM  ( x 2  x1 ) 2  ( y 2  y1 ) 2 answer in  (5  0) 2  (0  5) 2 surd form  25  25 (2)  50 = 5 2   3.2 1 m1  4 m2   gradient 4 y  y1  m( x  x1 ) substitution simplify y  2   1 ( x  1)   4 1 y21 x 4 4 1 7 y x 0 (3) 4 4 4y  x  7  0  3.3.1 x1  x2  value of p p 2 3 1  2   (2) 2 3.3.2 tan p  3  value of p (2) p  60o   3.3.3 x2 y 2  value of p   81 9 9 x 2  y 2  729 r  p  27   (2) 3.3.4 x  2y  0  value of p 1 y x 2   (2) 1 p 2 Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -7- T940(E)(N18)T MATHEMATICS N3 3.3.5 or y-intercept  value of p x 2  9 y 2  81 (2) 9 y 2  81 x2 y 2  1 y2  9 92 32   y  3 p  3 [22] p  3 QUESTION 4 4.1 f ( x  h)  f(x) lim multiplying of h 0 h 4 x 2  8 xh  4h 2   4 x 2  2(x+h)² and   lim substituting h 0 h factorising 4h(2 x  h)   simplifying  lim answer h 0 h  4(2 x  0)  (4)  8 x 4.2.1 1 y 4 4 4 x rewriting by x 1 applying y  x 4  4 x 4  exponential rules 1 1 applying dy 1  4 x 5  4  x 4 differentiation dx 4 rule  5  3 writing it as  4 x  x 4 positive exponent  4 1 and in surd form (4)  5   x 4 x3 4.2.2 x( x 2  1) factorise y differentiate x 1  x( x  1)( x  1) y x 1 yx x 2 dy (3)  2x  1 dx   [11] Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -8- T940(E)(N18)T MATHEMATICS N3 QUESTION 5 5.1 3cot   2  9,5 cot   2,5 manipulate for  two answers tan   0, 4  (3)   21,801 o or   201,801 o   5.2 tan 2   sin 2   tan 2  .sin 2  applying quotient LHS  tan 2   sin 2  identity sin 2  finding die LCD   sin 2  cos  2 factorise sin 2   sin 2  cos 2   proof  cos 2   sin 2  (1  cos 2  )  cos 2    tan 2  .sin 2  (4)  RHS  5.3 BC determining tan18, 7 o  BC 100 BC  33,848 determining CD  adding BC and CD tan 6,5o   CD to determine 100 the height CD  11,394  Height  BC  CD  (4)  45, 242m 5.4 17 sin 72o replacing AB   sin 50o answer  21,106 m  (2) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -9- T940(E)(N18)T MATHEMATICS N3 5.5 x f ( x )  cos 2  y-intercept=1  x- intercept=90° Or any other point on the graph g ( x)  sin( x  300 )   y-intercept= - 0,5 x- intercept=30° Or any other point on the (4) graph [17] TOTAL: 100 Copyright reserved Downloaded from hlayiso.com Please turn over
T930(E)(J28)T AUGUST EXAMINATION NATIONAL CERTIFICATE MATHEMATICS N3 (16030143) 28 July 2014 (Y-Paper) 13:00–16:00 Diagrams are NOT drawn to scale. This question paper consists of 7 pages, and 1 formula sheet of 2 pages. Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -2- T930(E)(J28)T DEPARTMENT OF HIGHER EDUCATION AND TRAINING REPUBLIC OF SOUTH AFRICA NATIONAL CERTIFICATE MATHEMATICS N3 TIME: 3 HOURS MARKS: 100 INSTRUCTIONS AND INFORMATION 1. Answer ALL the questions. 2. Show ALL the calculations and intermediary steps. 3. Questions may be answered in any order but subsections of questions must NOT be separated. 4. ALL final answers must be accurately approximated to THREE decimal places. 5. All graph work must be done in the ANSWER BOOK. Graph paper is NOT supplied. 6. A formula sheet is attached to this question paper. The list is NOT necessarily complete. Any other applicable formula may be used. 7. Write neatly and legibly. Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -3- T930(E)(J28)T QUESTION 1 1.1 Simplify the following WITHOUT using a calculator: (5) a 1 a 1 2  8 3 4a 1 1.2 Prove that  log c a  logb c  log a b   1 (3) 1.3 Determine the factors of the following function if x  1 is one of the factors. f ( x)  x 3  3 x 2  x  3 (4) 1.4 Factorise the following expressions as far as possible in prime factors 1.4.1 x 2 ( x  1)  (1  x) (3) 1.4.2 a 2  2a  3  ab  b (3) 1.5 Simplify the following: a 2  b 2 a 2  2ab  b 2 a  b   2a  b 4a 2  b 2 ab (4) [22] QUESTION 2 2.1 Solve for ' a ' by completing the square: 4a 2  12a  7  0 (5) 2.2 Solve for ' x ' : 2.2.1 x (4) x2 x 2 1 2 2    42 2 2.2.2 2x 4 4 x   2 x 1 x 1 x 1 (4) 2.3 Make ‘ n ‘ the subject of the formula : P =100e 0,3n (4) 2.4 Make ‘ r ’ the subject of the formula: a   r 2   rs (2) Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -4- T930(E)(J28)T 2.5 Calculate the coordinates of the points of intersection of the graphs defined by the following two equations: y  2 x 2  8 x  10 (4) y  9 x 2.6 The product of two consecutive odd numbers is 143. Calculate the numbers. (3) [26] QUESTION 3 3.1 ABC has vertices A(2;3) , B ( 2; 1) and C (4;1) . 3.1.1 Draw ABC on a set of axes. (1) 3.1.2 Determine the gradient of AB . (1) 3.1.3 Determine the angle of inclination of the line AB . (1) 3.1.4 Show that AB is perpendicular to AC . (2) 3.1.5 Determine the equation of the line through C and parallel to AB . (3) 3.1.6 Find D and E , the midpoints of AC and BC respectively. (4) 3.1.7 Show that AB  2 DE (5) 3. 2 Choose a description from COLUMN B that matches an item in COLUMN A. Write only the letter (A-G) next to the question number(3.2.1-3.2.4) in the ANSWER BOOK. COLUMN A COLUMN B 3.2.1 A x 2  y 2  10 x y B   100 1 10 (2) x2 y2 C   100 1 10 Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -5- T930(E)(J28)T D x  y2 3.2.2 (2) E y   1  x2 x2 y 2 F  1 1 1 3.2.3 x y (2) G  1 1 1 H y  x2 x2 y 2 I  1 1 100 (2) 3.2.4 [25] Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -6- T930(E)(J28)T QUESTION 4 4.1 dy Determine by making use of the rules of differentiation. Write your answer with dx positive exponents and in surd form when applicable. 4.1.1 2 y2 x  x (4) 4.1.2 x8  1 y x4  1 (2) 4.2 Determine the gradient of the tangent to the following curve at the point where x  2 : y  ( x 2  3)( x  1) (3) [9] QUESTION 5 5.1 Make use of basic trigonometric identities to prove that 1  sin  cos   2 sec cos 1  sin  (5) 5.2 ˆ  250 , length AB  80 and length AC  46 . Given: ABC with BAC Use the cosine rule to determine the length of BC . (3) 5.3 Solve the following equation if 0    360 : 2 sec   4  0 (3) Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -7- T930(E)(J28)T 5.4 A vertical antenna AC is mounted on top of a pole CD . The technician measures the angles of elevation of two points on the antenna at a distance of 40 m from D , the base ˆ and ABD of the pole . If the angles, CBD ˆ , are 20° and 24° respectively, find the length (4) of the antenna. 5.5 The graphs represent the functions f ( x)  2 sin 2 x and g ( x)  cos x . A , B and P are turning points. Determine the coordinates of A , B and P . (3) [18] Copyright reserved Downloaded from hlayiso.com TOTAL: Please turn over 100
(16030143) -8- -1- T930(E)(J28)T MATHEMATICS N3 FORMULA SHEET Any applicable formula may also be used. 1. Factors/Faktore 2. Logarithms/ Logaritmes a3 - b3 = (a - b)(a2 + ab + b2) log ab  log a  log b a a3 + b3 = (a + b)(a2 - ab + b2) log  log a  log b b logc a 3. Quadratic formula/ logb a  logc b Kwadratiese formule  b  b 2  4ac x log a m  m log a 2a 1 4. Parabola/ Parabool logb a  loga b y  ax 2  bx  c loga a  1 ∴ 1n e  1 4ac  b 2 aloga t  t ∴ e1n m  m y 4a b x 2a 5. Circle/ Sirkel 6. Straight line/ Reguitlyn x2  y2  r 2 y  y1  m(x  x1 ) Perpendicular: x2 Loodreg: m1  m2  1 D h 4h Parallel lines: x  4Dh  4h 2 Ewewydige lyne: m1  m2 Distance: Afstand: D  (x 2  x1 )2  (y 2  y1 )2 Midpoint:  x  x 2 y1  y 2  Middelpunt: P   1 ;   2 2  Angle of inclination: Hellingshoek: θ  tan -1m Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -9- -2- T930(E)(J28)T 7. Differentiation/ Differensiasie dy lim f x  h  f x   dx h → 0 h d n dx   x  nx n - 1 Max/Min Maks/Min For turning points: Vir draaipunte: f '  x   0 8. Trigonometry/ Trigonometrie y 1 sinθ   r cosecθ x 1 cosθ   r secθ y 1 tanθ   x cotθ sin 2 θ  cos 2 θ  1 1  tan 2 θ  sec 2 θ 1  cot 2 θ  cosec2 θ sinθ tanθ  cosθ cosθ cotθ  sinθ sinA sinB sinC   a b c a 2  b2  c 2  2bc cosA Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE NATIONAL CERTIFICATE AUGUST EXAMINATION MATHEMATICS N3 28 JULY 2014 This marking guideline consists of 9 pages. Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -2- T1020(E)(J28)T MATHEMATICS N3 QUESTION 1 MARKING INSTRUCTION &NOTES 1.1 2a 1  3 8a 1 writing 8 as power with  base 2 4a 1 writing 4 as power with 3a 3  base 2 2 2 2 2 a 1 3 3   simplifying root 22 a  22 applying multiplication rule of powers by adding   2a 1 a 1 2 a  2  24  16 exponents  simplifying (5) 1.2 LHS   log c a  log b c  log a b  RHS  1 applying log rule where bases changed log a log c log b      simplifying log c log b log a  1  RHS  (3) 1.3 x2  4 x  3  for correct quotient  x  1 x  3x 2  x  3 3  two factors-  (x+3)(x+1) x 3 -1x 2 no credit to (x-1) it  4 x2  x was given 4 x2 - 4 x  3x  3 3x  3 0 0   Factors : (x-1)(x+3)(x+1) (4) 1.4 1.4.1 x 2 ( x -1)  (1- x) taking out -1 as common  factor  x 2 ( x -1) - ( x -1)  factorise   ( x -1)( x 2 -1) applying factorisation of  ( x -1)( x -1)( x  1)  difference between two squares (3) 1.4.2 a 2  2a  3  ab  b  factorising of quadratic trinomial  (a 2  2a  3)  ab  b taking out of common  (a  3)(a  1)  b(a  1)  factor  (a  1)[a  3  b]   taking out of common factor (3) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -3- T1020(E)(J28)T MATHEMATICS N3 1.5 a 2  b 2 a 2  2ab  b 2 a  b change of division sign to   multiplication sign 2a  b 4a 2  b 2 ab  (x2) factorisation using   difference between two (a  b)(a  b) (2a  b)(2a  b) a  b squares    2a  b (a  b)(a  b) a  b  factorisation of trinomial  2a  b simplifying  (4)  [22] QUESTION 2 2.1 4a 2  12a  7  0 taking out 4 as common factor 4a 2  12a  7  adding the 7 2 a 2  3a   coeffcient of a  4   both sides 2  2   3 7 9 writing lhs as a square and (a  3a     )   2 ✓  2 4 4 simplification of RHS 2 get rid of squares by drawing  3  16 a     4 ✓ square roots both sides-  2 4 Mark will not be awarded if 3  is left out. a  2 ✓ 2 (x2) two answers 3 a 2 2 7 1 a or a   2 2 (5)   2.2.1 1 x simplifying of negative x2 x2 2  2     42 power 2 taking out common factor  2 x.22  2 x.22  2 x  42 simplification of power 2 x  22  22  1  42  solving by equating like  powers 2 5, 25  42 x  (4)  2 2 x 3 x3 Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -4- T1020(E)(J28)T MATHEMATICS N3 2.2.2 2x 4 4 x correct LCD(denominator)   2 rewrite fractions to x 1 x 1 x 1 2 x( x  1)  4( x  1) 4 x LCM(numerator)   simplification  x  1 ( x  1)  x  1 ( x  1) (x2)-solution  2 x2  2 x  4 x  4  4  x Check the roots 2 x2  x  0 x(2 x  1)  0  1 x  0 or x 2   (4 ) 2.3 P =100e 0,3n manipulation using logarithms to manipulate P  e 0,3n  simplify 100  P    ln  e  0,3 n ln   100  ln P  ln100  0,3n ln e  ln P  ln100  n or 0,3  ln100  ln P  n or 0,3  100  ln    P  n  0,3 (4) 2.4 a   r 2   rs  using correct values in the  place of a,b,c in the quadratic  r 2   rs  a  0 formula  s   2 s 2  4 a  manipulation and simplification r 2 (2) 2.5 y  2 x 2  8 x  10  finding the x-coordinates  finding the y-coordinates of y  9 x points of intersection 2 x 2  8 x  10  9 x 2 x 2  x  10  0 (2 x  5)( x  2)  0 5 x or x  2 2   (4) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -5- T1020(E)(J28)T MATHEMATICS N3 5 1 ( ; 22 ) and  2;  18   2 2 2.6 x  ( x  2)  143 any steps to show how the x  2 x  143  0 2 student determined the answers   answers ( x  13)( x  11)  0 Students could determine answers also using inspection. x= -13 x=11   Two numbers: 11 and 13 Or -11 and -13 (3) [26] QUESTION 3 3.1 3.1.1 sketch of triangle  (1) 3.1.2 YA  YB substituting values and M AB  XA  XB simplifying 3  (1)  2  (2) 4 (1)  1 4  3.1.3 M AB  1 substituting value and   tan 1 1 simplifying   450 (1) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -6- T1020(E)(J28)T MATHEMATICS N3 3.1.4 YA  YC finding the gradient of M AC  line AC X A  XC multiplication of gradients 3  (1)  to show that lines are 2  (4) perpendicular 2   1  2 M AB  M AC  (1)  (1)  1 Therefore the two lines are perpendicular.  (2) 3.1.5 Parallel lines have equal gradients. using identity on parallel The gradient of the line through C (4;1) lines to find gradient of line and parallel to AB with M AB  1 AB  finding y-intercept by y  yC  m( x  xC ) substituting y 1  (1)(x  4)  equation y  x 4 1 y  x 3  (3) 3.1.6 x x y y  substituting D  PAC   1 2 ; 1 2  simplify  2 2  substituting  2  4 3 1  simplify  ;   2 2   D  (3; 2)  x x y y  E  PBC   1 2 ; 1 2   2 2   2  4 1  1   ;    2 2  E  (1;0)  (4) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -7- T1020(E)(J28)T MATHEMATICS N3 3.1.7 DAB  ( x A  xB ) 2  ( y A  yB ) 2 using the distance formula and substitute  (2  (2)) 2  (3  (1)) 2 simplify using the distance formula  16  16  and substitute  32  simplify rewriting surds to prove DDE  ( x A  xB ) 2  ( y A  yB ) 2 that AB=2DE  (3  1) 2  (2  0) 2   44   8 AB  32  4  8  2 8  AB  2 DE (5) 3.2 3.2.1 G   Choosing the correct equation to describe the graph (2) 3.2.2 E Choosing the correct (2)   equation to describe the graph 3.2.3 D   Choosing the correct equation to describe the graph (2) 3.2.4 I Choosing the correct   equation to describe the graph (2) [25] QUESTION 4 4.1 4.1.1 2 rewriting square root y2 x  x rewriting a fraction 1 differentiate function  2 x  2 x 1 2 √ √ differentiate function rewriting function   dy  1 rewriting function   x 2  2 x 2 dx 1 2   2 x x (4) √ √ Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -8- T1020(E)(J28)T MATHEMATICS N3 4.1.2 x8  1 (2x)simplify fraction y differentiation x4  1 ( x 4  1)( x 4  1) y  x4  1 y  x4 1  dy  4 x3 dx  (2) 4.2 y  ( x 2  3)( x  1) multiplication differentiation y  x3  x 2  3x  3 substitution  f '( x)  3x 2  2 x  3  f '(2)  3(2) 2  2(2)  3  3(2) 2  4  3  13  (3) [9] QUESTION 5 5.1 1  sin  cos LCD   2 sec writing fractions to cos 1  sin   LCD LHS  (1  sin  )(1  sin  )  cos   cos  RHS  2sec  applying square identity cos  (1  sin  ) cos 2 x  1  sin 2 x  simplifying 1  2sin   sin 2   (1  sin 2  )  indicating that lhs = rhs  cos(1  sin  ) 2  2sin    cos  (1  sin  ) 2(1  sin  )  cos  (1  sin  ) 2  cos   2sec  LHS  RHS  (5) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -9- T1020(E)(J28)T MATHEMATICS N3 5.2 a 2  462  802  2  46  80  Cos 25 substituting using cosine  rule a 2  2116  6400  2  46  80  0,906 simplifying a 2  1845,575  simplifying a  42,96 units  (3) 5.3 2Sec  4  0 manipulating sec   2  finding solutions reference angle  60    120 and   240   (3) 5.4 CD trigonometric equation tan 200   length CD 40 CD  14,558 length AD  length AC AD tan 240  40  AD  17,809 AD  CD  AC (lenght of antenna) 17,809 -14,558  AC AC  3, 250m (4)  5.5 A  (450 ; 2) (x2)  (x2) B  (2250 ; 2) (x2)  (3) P  (180 ; 1) 0  [18] TOTAL: 100 Copyright reserved Downloaded from hlayiso.com Please turn over
T930(E)(M31)T APRIL EXAMINATION NATIONAL CERTIFICATE MATHEMATICS N3 (16030143) 31 March 2014 (Y-Paper) 13:00–16:00 This question paper consists of 6 pages and 2 formula sheets. Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -2- T930(E)(M31)T DEPARTMENT OF HIGHER EDUCATION AND TRAINING REPUBLIC OF SOUTH AFRICA NATIONAL CERTIFICATE MATHEMATICS N3 TIME: 3 HOURS MARKS: 100 NOTE: Diagrams are NOT drawn to scale. INSTRUCTIONS AND INFORMATION 1. Answer ALL the questions. 2. Read ALL the questions carefully. 3. Number the answers according to the numbering system used in this question paper. 4. ALL final answers must be accurately approximated to THREE decimal places. 5. All graph work must be done in the ANSWER BOOK. Graph paper is NOT supplied. 6. Two FORMULA SHEETS are attached to this question paper. The list is NOT necessarily complete. Any other applicable formula may also be used. 7. Write neatly and legibly. Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -3- T930(E)(M31)T QUESTION 1 1.1 Simplify the following WITHOUT using a calculator. 1.1.1 1 x 9 2  3x 1 3x  2 (3) 1.1.2 log 27  log 8  log 125 log 6  log 5 (5) 1.2 Factorise as far as possible in prime factors: 1.2.1 2( x  2)2  9( x  2)  5 (3) 1.2.2 (m  n)36 x2  49ny 2  49my 2 (3) 1.3 Given that x  1 is a factor of f ( x) . Determine the other factors if f ( x)  x3  13x  12 (3) 1.4 Simplify: 1.4.1 1 1 2  2 x y 1 1  y x (3) 1.4.2 4x 2x 5x2   3x  1 1  3x 9 x 2  1 (5) [25] QUESTION 2 2.1 Solve for x : 2.1.1 3x  10  x  2 (3) 3 x3 2.1.2  x5 x x (3) 2.2 Make ' x ' the subject of the formula by completing the square: x 2  8 x  5a  0 (3) Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -4- T930(E)(M31)T 2.3 Make 't' the subject of the formula: V1  V0 e  at (4) 2.4 Thomas is 4 times as old as John. In 12 years' time Thomas will be twice as old as John. What are their present ages? (3) 2.5 Determine the points of intersection of the graphs represented by the following equations algebraically: x 2  y 2  25 yx5 (5) [21] QUESTION 3 3.1 Complete the following sentences by filling in the missing values, expressions or equations. Write only the missing answer next to the question number (3.1.1–3.1.3) in the ANSWER BOOK. P(-1;-1) and Q(-3;3) are two points. The coordinates of the midpoint of 3.1.1 PQ are … (2) 3.1.2 The acute angle of inclination formed between the x-axis and y  x  3 is equal to … (2) 3.1.3 The equation of the line passing through the points (2,0) and (2, 2) is … (1) 3.2 In the diagram below, P(-3;2) is a point on the circle with the centre at the origin. AB is a tangent to the circle at point P. Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -5- T930(E)(M31)T 3.2.1 Calculate the length of OP. (2) 3.2.2 Determine the equation of the circle. (2) 3.2.3 Determine the equation of the tangent AB. (4) 3.3 Determine the equation of the straight line that passes through point O (0;0) and which is parallel to the line 18 x  3 y  9  0 . (3) [16] QUESTION 4 4.1 Consider the function y  1  4 x2 dy 4.1.1 Determine the derivative, , from first principles. dx (4) 4.1.2 Determine the gradient of the function at the point where x =1. (1) dy 4.2 Determine if dx x2  2 x y x x2 (Leave the answer with positive exponents and in surd form) (4) 4.3 Sketch the graphs defined by the following equations in the ANSWER BOOK. Each graph should be on its own system of axes. Calculations need NOT be shown. ALL values at the points of intersection with axes and the coordinates of the turning points (where applicable) must be shown. x2 y2 4.3.1  1 256 144 (2) 4.3.2 y  3x 2  2 x 3 (4) 4.3.3 x y  1 4 3 (2) [17] Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -6- T930(E)(M31)T QUESTION 5 5.1 Calculate the exact value WITHOUT using a calculator: sin 2 120 sec2 150  sin150 cosec 30 cos 60 (3) 5.2 Calculate the value(s) of  which will satisfy the equation if 00    3600 : 2sin  cos   sin   0 (5) 5.3 From the top of a tower, 100 m high, the angles of depression of two objects on the ground, due west of the tower, are 41,45 and 21,68 respectively. Calculate the distance between the TWO objects. (5) 5.4 Given : ABC with, A = 600, AB  2 and AC  8 . Calculate: 5.4.1 The value of 'x' (3) 5.4.2 The area of the triangle. (2) 5.5 Sketch the graph of 3 y  sin 3 for 0    1200 (3) [21] TOTAL: 100 Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -7- -1- T930(E)(M31)T FORMULA SHEET Any applicable formula may also be used. 1. Factors/Faktore 2. Logarithms/Logaritmes a3 - b3 = (a - b)(a2 + ab + b2) log ab  log a  log b a a3 + b3 = (a + b)(a2 - ab + b2) log  log a  log b b log c a 3. Quadratic formula/ log b a  log c b Kwadratiese formule  b  b 2  4ac x log a m  m log a 2a 1 4. Parabola/ Parabool log b a  log a b y  ax 2  bx  c loga a  1 ∴ 1n e  1 4ac  b 2 aloga t  t ∴ e1n m  m y 4a b x 2a 5. Circle/ Sirkel 6. Straight line/ Reguitlyn x2  y2  r 2 y  y1  m(x  x1 ) Perpendicular: x2 D h Loodreg: m1  m 2  1 4h Parallel lines: x  4Dh  4h 2 Ewewydige lyne: m1  m 2 Distance: Afstand: D  (x2  x1 )2  (y2  y1 )2 Midpoint:  x  x 2 y1  y 2  Middelpunt: P   1 ;   2 2  Angle of inclination: Hellingshoek: θ  tan -1 m Copyright reserved Downloaded from hlayiso.com Please turn over
(16030143) -2- -8- T930(E)(M31)T 7. Differentiation/Differensiasie dy lim f x  h   f x   dx h → 0 h d n dx   x  nx n - 1 Max/Min Maks/Min For turning points: Vir draaipunte: f ' x   0 8. Trigonometry/ Trigonometrie y 1 sinθ   r cosecθ x 1 cosθ   r secθ y 1 tanθ   x cotθ sin 2 θ  cos 2 θ  1 1  tan 2 θ  sec 2 θ 1  cot 2 θ  cosec 2 θ sinθ tanθ  cosθ cosθ cotθ  sinθ sinA sinB sinC   a b c a 2  b 2  c 2  2bc cosA Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE NATIONAL CERTIFICATE APRIL EXAMINATION MATHEMATICS N3 31 MARCH 2014 This marking guideline consists of 12 pages. Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -2- T930(E)(M31)T MATHEMATICS N3 QUESTION 1 1.1 1.1.1 1 x 9 2  3x 1 3x  2 x  3   3 2 2 x 1  x2 3 3  3x.31x  3x.32  1 3x  1    x  3  3 .9 2 2 1 2 3    9 3 9 27 (3) 1.1.2 log 27  log 8  log 125 log (3)3  log (2)3  log (5)3 log 6  log 5 log 6  log 5 27  8 (3)3  (2)3 log  log  125 (5)3 6  log    6 5 log   5 216 log (3)3 (2)3 125 log  (5)3 6  log   6 5 log   3 5 6  log   6 3 5 log    5 6 log   6 5 log   5  3 6 log   3 6  2 5  3 log    2 5 3 6 2   log   6 2 5 log   5 (5) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -3- T930(E)(M31)T MATHEMATICS N3 1.2 1.2.1 2( x  2) 2  9( x  2)  5 or 2( x  2) 2  9( x  2)  5 let x  2  k  2( x 2  4 x  4)  9 x  18  5  2k 2  9k  5  2 x 2  8 x  8  9 x  18  5  (2k  1)(k  5)    2 x 2  x  15 Factors of 2( x  2) 2  9( x  2)  5  (2 x  5)( x  3)  [2( x  2)  1][( x  2)  5]  (2 x  5)( x  3)  (3) 1.2.2 (m  n)36 x 2  49ny 2  49my 2  (m  n)36 x 2  49 y 2  m  n     (m  n)  36 x  49 y  2 2  (m  n)  6 x  7 y  6 x  7 y   (3) 1.3 x 2  x  12  x 1 x 3  13x  12 x3 + x 2 - x 2 -13x - x2 - x -12 x - 12 -12x - 12    f ( x)  ( x  1)( x 2  x  12)  ( x  1)( x  4)( x  3) (3) 1.4 1.4.1  1 1  1 1  2  2     x y   y x y 2  x2 x  y  2 2   x y xy ( y  x)( y  x) xy    2 2 x y ( x  y) yx   xy (3) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -4- T930(E)(M31)T MATHEMATICS N3 1.4.2 4x 2x 5x2   2 3x  1 1  3x 9 x  1 4x 2x 5x2      3x  1 3 x  1 (3 x  1)(3 x  1) 4 x(3x  1)  2 x(3x  1)  5 x 2   (3x  1)(3x  1) 12 x 2  4 x  6 x 2  2 x  5 x 2   (3x  1)(3x  1) 11x 2  6 x   (3x  1)(3x  1) (5) [25] QUESTION 2 2.1 2.1.1 3x  10  x  2  3x  10   x  2   2  3x  10  x 2  4 x  4  x2  x  6  0    x  3 x  2   0 x 3  0 or x - 2  0   x  3 or x=2 x  -3 (n.a) extraneous solution x=2 is the only solution any clear rejection of the root is acceptable. (3) 2.1.2 3 x3  x5  x x 3  x  5x  x  3 2  x2  4 x  0   x( x  4)  0  x0 or x+4=0 x0 x  -4  (3) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -5- T930(E)(M31)T MATHEMATICS N3 2.2 x 2  8 x  5a  0  x 2  8 x  5a  x 2  8 x  16  5a  16    x  4   5a  16 2   x  4   5a  16  x  4  5a  16  (3) 2.3 V1  V0e  at V  1  e at  V0 V    ln  1   ln e at  V0  V   ln  1   at   V0  V  ln  1  t   0  V  a V  ln  0  ln V0  ln V1 or t   1  or V a a (4) 2.4 AGE NOW AGE IN 12 YEARS John x (x+12) Thomas 4x (4x+12) age of Thomas=2  age of John 4 x  12  2( x  12)  4 x  12  2 x  24 2 x  12  x6 present ages = 6 & 24 years  (3) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -6- T930(E)(M31)T MATHEMATICS N3 2.5 x 2  y 2  25.......(1) y  x  5.............(2) replace y by x  5 in (1) x 2  ( x  5) 2  25 x 2  x 2  10 x  25  25  2 x 2  10 x  0 2 x( x  5)  0 x  0 or x  5    If x  0 then y  5 or if x  -5 then y  0  (5) [21] QUESTION 3 3.1 3.1.1  (-2;1) (2) 3.1.2  45° (2) 3.1.3 x2  (1) 3.2 3.2.1 OP  (3) 2  (2) 2  = 9  4  13 units (2) 3.2.2 x2  y 2  r 2  x 2  y 2  ( 13) 2   x 2  y 2  13 (2) 3.2.3 mOP  mAB  1  OP  AB  2   mAB  1 3 3  mAB   2 y  y1  m( x  x1 ) 3 y2 ( x  3)  2 3 9 y2 x 2 2 3 13 y  x   2 2 (4) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -7- T930(E)(M31)T MATHEMATICS N3 3.3 18 x  3 y  9  0   y  6x  3   Required line : y  6 x  (3) [16] QUESTION 4 4.1 4.1.1 y  1  4 x2 f ( x  h)  f ( x ) lim h 0 h 1  4( x  h) 2  (1  4 x 2 )  lim h 0 h 1  4( x  2 xh  h 2 )  1  4 x 2 2  lim h 0 h 1  4 x  8 xh  4h 2  1  4 x 2 2  lim  h 0 h 8 xh  4h 2  lim  h 0 h h(8 x  4h)  lim  h 0 h  8 x  (4) 4.1.2 dy if x  1 then  -8(1)  -8  dx (1) 4.2 x2  2 x f ( x)  x  x2 1    f ( x)  x  1  2 x 1 2 1 1  f '( x)  x 2  2 x 2 2 1 2  f '( x)   2   2 x x (4) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -8- T930(E)(M31)T MATHEMATICS N3 4.3 4.3.1 y  12 -16 16  x -12 MARK ALLOCATION MARKS x intercepts at (16;0) and (-16;0) 1 y intercepts at (0;12) and (0;-12) 1 (2) 4.3.2 y  3x 2  2 x3 dy   6 x  6 x2 dx 0  6 x(1  x)  x  0 or 1  x  0  x  0 or x  1 TP:(0;0) or (1;1) x-intercepts 3 x 2  2 x3  0  x 2 (3  2 x)  0  x  0 or x  0 or 3 - 2 x  0 3 x0 x 2 y-intercept y  0 Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -9- T930(E)(M31)T MATHEMATICS N3     ALLOCATION OF MARKS MARKS 1 mark for turning point(1;1) 1 1 mark for turning point(0;0)/ 1 y-intercept at 0/x-intercept at 0 3 1 x-intercepts at and 0 2 Shape 1 (4) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -10- T930(E)(M31)T MATHEMATICS N3 4.3.3 y 3  -4 0 x  ALLOCATION OF MARKS MARKS 1 mark for x-intercept (-4;0) 1 1 mark for y-intercept at (0;3) 1 (2) [17] QUESTION 5 5.1 sin 2 120 sec 2 150  sin150 cosec 30 cos 60 2  3  2  1 2      2      3 2  2 1    1 2 1 1  2 3 2 1 2   1 2 (3) 5.2 2sin  cos   sin   0  sin  (2 cos   1)  0  sin   0 or 2 cos   1  0   00 or 1800 or 3600   600 or 3000      (5) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -11- T930(E)(M31)T MATHEMATICS N3 5.3 x y Tan 68,32   Tan 48,55  100 100  x  251,544 m  y  113,228 m   Distance between objects = 251,544 m – 113,228 m = 138,316 m  100 100 or tan 41, 45  y x tan 21, 65 x  100  251,929 m tan 41, 45 Distance  y  x  113, 228 m  138, 701m (5) 5.4 5.4.1 x  ( 8 ) 2  ( 2 ) 2  2. 8. 2 Cos 60   8  2  8Cos 60   = 6 OR 2,449 (3) 5.4.2 1 Area  bcSinA 2 1   8  2 Sin60  2  1,732 m 2  (2) Copyright reserved Downloaded from hlayiso.com Please turn over
MARKING GUIDELINE -12- T930(E)(M31)T MATHEMATICS N3 5.5 3 y  sin 3 sin 3 y 3    ALLOCATION OF MARKS MARKS 1 mark for x-intercept at 00 ,600 or1200 1 1 mark for y-intercept at 00 1 Height 1 (3) [21] TOTAL: 100 Copyright reserved Downloaded from hlayiso.com Please turn over

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