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Physical Sciences Grade 11 2025 QP & Memo
Grade 11 Physical Sciences question paper and memo from the North West March Test 2025, 22 pages. Read online or get the free PDF download.
Physical Sciences · Grade 11 · North West March Test · 2025. Question paper and memorandum, 22 pages. Read online or download the PDF.
- Subject
- Physical Sciences
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- Grade 11
- Document type
- Question paper and memo
- Year
- 2025
- Exam period
- North West March Test
- Curriculum
- CAPS
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- 22
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- 2.1 MB
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Physical Sciences/P1 Grade 11 NW/ March 2025
INSTRUCTIONS AND INFORMATION
ti
2.
10.
11.
12.
Write your name on the answer sheet provided.
This question paper consists of SIX questions. Answer ALL the questions
in the ANSWER BOOK.
You, may use a non-programmable calculator.
You may use appropriate mathematical instruments.
Number the ans
this question pa
ing to the numbering system used in
You are advised to u: ATA SHEETS.
The formulae and ons must be shown in ALL calculations.
‘ ¥
Give brief motivatioraeeeeeone et cetera where required.
Round off your final numerical answers to a minimum of TWO decimal
places.
Start EACH question on a NEW page.
All diagrams are not necessarily drawn according to scale.
Write neatly and legibly.
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Physical Sciences/P1 Grade 11 NW/ March 2025
QUESTION 1
1.1 -Ablock is moving with constant velocity to the right on a frictionless surface. Which
sketch below correctly illustrates all the forces acting on the block?
(2)
1.2 Ablock of mass m i
horizontal.
What is the magnitude of the normal force exerted by the surface on the block?
é
A mg
B= mgcos®@
C mgsine
D mgtanée (2)
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Physical Sciences/P1 Grade 11 NW/ March 2025
1.3 The vector diagram shows two forces in the same plane acting on an object O.
3N
s 4N
Another force of magnitude 5 N is applied on the object O. Which ONE of the
following represents the direction at which the 5 N force must be applied to ensure
object O is in equilibrium?
N\, (2)
1.4 Two hypothetical planets, X and Y, have the same mass. The diameter of planet
Y is twice that of planet X.
If the acceleration due to gravity on the surface of planet X is g, then the
acceleration due to gravity on the surface of planet Y will be ...
A
16
Bg
4
c g
2
D 2 (2)
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Physical Sciences/P1 Grade 11 NW/ March 2025
1.5 Two blocks of weight 7 N and 3 N are attached to two ropes, X and Y as shown
in the diagram below.
7™N
¥
i
The blocks hang vertically at rest. The masses of the ropes are negligible. What
is the tension in rope X and in rope Y?
TENSION IN X TENSION IN Y
A 10N 10N
B 10N 3N
Cc 7N 4N
D 7N 7N (2)
1.6 Two charges point charges of +2 nC and +2 nC are located on a straight line. S
and T are two points that lie on the same straight line as shown in the diagram
below.
+2nC Scetitt 2 NEw hie
o——-—— Nc Oe ie .
Which ONE of the following are the correct directions-of the resultant electric field
at point S and point T due to point charges +2 nC and #2 nC
DIRECTION OF THE RESULTANT | DIRECTION OF THE RESULTANT
ELECTRIC FIELD AT POINT S ELECTRIC FIELD AT POINT T
A Right ie Left
B Left Left
Cc Right Right
D Left Right (2)
[12]
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Physical Sciences/P1 Grade 11 NW/ March 2025
QUESTION 2
A car engine with weight w hangs from a chain(K) that is linked at point O to two other
chains, one chain(M) that is fastened at angle of 60° to the ceiling and the other chain(L)
to the wall as shown in the diagram below. Tension in M is 2540 N when point O is at
equilibrium.
2.1. Define the term resultant. (2)
2.2 What is the magnitude of the resultant force on point O. (1)
2.3 Draw a labelled free-body diagram showing ALL the forces acting on point O. (3)
2.4 Calculate:
2.4.1. The magnitude of the vertical component of M. (2)
2.4.2 Mass of the engine. (3)
2.4.3. Tension in L. (2)
[13]
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Physical Sciences/P1 Grade 11 NW/ March 2025
QUESTION 3
Block A, of mass 6 kg is placed on a table. The angle between the surface of the table
and the horizontal is 36° as shown in the diagram below. The block is just about to slide
and the maximum static frictional force acting on the block is 28,22 N.
3.1 (2)
3.2 Calculate the co-efficic tic friction between the block and the surface of the
table. ” ‘io co (4)
The table is now placed horizontal as shown in the diagram below.
3.3 How will the value calculated in QUESTION 3.2 be affected? Write only
INCREASES, DECREASES or REMAINS THE SAME. (1)
3.4 Explain the answer in QUESTION 3.3. (1)
Block A, is now connected by a massless string passing over a frictionless pulley,
to block B of mass 4 kg. A downwards force of 4 N is applied to block B as shown
in the diagram below. The kinetic frictional force between Block A and the table is
23,52 N. Block A accelerates to the right.
3.5 Draw a labelled free-body diagram for block B. (3)
3.6 Calculate the magnitude of the tension in the rope. (6)
[17]
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Physical Sciences/P1 Grade 11 NW/ March 2025
QUESTION 4
An athlete trains by pushing a heavy box A of mass 23 kg, which is in contact with another
identical box B of mass 31 kg, across a ROUGH surface of a field as shown in the diagram
below. The athlete exerts a force F at an angle of 40° to the horizontal on box A. Each box
experiences a frictional force of 45 N. The magnitude of the normal force acting on box A
is 303,8 N. The boxes accelerate horizontally to the right as a system.
4.1 State Newton’s First Law of Motion in words. (2)
4
4.2 Drawa labelled force diagram showing ALL the forces acting on box A. (5)
4.3 The magnitude of the force that box A exerts on box B is the same as the magnitude
of the force that box B exerts on box A.
Which Newton's Law of Motion explains this statement. (1)
4.4 Calculate the magnitude of the:
4.4.1 Force F, acting on box A. (3)
4.4.2 Acceleration of the boxes. (5)
4.4.3. Force that box B exerts on box A. (2)
4.5 Use a relevant formula(e) to explain why the two boxes experience the same
frictional force. (4)
[22]
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Physical Sciences/P1 Grade 11 NW/ March 2025
QUESTION 5
During a lunar eclipse, the Earth, the Moon, and the Sun are aligned on the same plane
such that the distance between the center of Moon and the Earth is 3,84 x10® m and
the distance between the Sun and the Earth is 1,50 x10'' m as shown in the diagram
below. The masses of the Moon and the Sun are 7,35 1072 kg and 1,99%10°° kg
respectively.
3,84 x10 m 1,50 10'' m
hy igi
Moon Earth P Sun
5.1 Distinguish between the mass and the weight of an object. (2)
5.2 State Newton's law of universal gravitation in words. (2)
5.3 Calculate the magnitude of the gravitational force exerted by the Sun on the Earth. (4)
The gravitational force exerted by the Earth on the Moon is 1.99 x1079 N
5.4 Write down the magnitude of the force that the Moon exert on the Earth. (1)
5.5 Calculate the net force experience by Earth due to the Moon and the Sun. (3)
[12]
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Physical Sciences/P1 Grade 11 NW/ March 2025
QUESTION 6
A polystyrene ball Y carrying a charge of +30 x10° C is covered with a thin layer of
graphite and placed in a glass cylinder. An identical ball X of mass 40 g, carrying a charge
of +100 x10° C is now placed in the measuring cylinder and is pushed away to a height
d as shown in the diagram below.
6.1 State Coulomb's Law in words.
6.2 Drawa labelled free-body diagram showing ALL the forces acting on ball X.
6.3 Calculate the distance d in mm, between ball X and Y.
In the diagram below, Q:, Q2 and Q; are three stationary point charges placed
along a straight line. The charges on Qu, Q2 and Q3 are +4 nC, -2 nC and -4 nC
respectively. The distance between Qi and Qz2 is 0,02 m and that between Q2 and
Q3 is also 0,02 m.
6.4 Define the term electric field at a point in words.
6.5 Draw the net electric field pattern due to charges Qi and Qs.
6.6 Calculate the net force exerted by Q2 and Q3 on Qi.
6.7 Calculate the net electric field experinced by Qi.
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(2)
(2)
(6)
(2)
(3)
(6)
(3)
[24]
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DATA FOR PHYSICAL SCIENCES GRADE 11
PAPER 1 (PHYSICS)
GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 11
VRAESTEL 1 (FISIKA)
TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES
SYMBOL/
NAME/NAAM SIMBOOL VALUE/WAARDE
Acceleration due to gravity / g 9,8 mes?
Swaartekragversnelling
Universal gravitational constant/ G 6,67 « 10°! Nem*kg?
Universelegravitasiekonstant _
Speed of light in a vacuu c 3,0 x 108 mes
vakuum =
Planck's constant / Planck se h 6,63 x 10 Jes
Coulomb's constant / Coulomb: ante k 9,0 x 10°Nem**C*
Charge on electron / Lading op ) e “1,6 x 10°C
Electron mass / Elektronmassa Me 9,11 x 10°" kg
Mass of earth / Massa op aarde M 5,98 x 10% kg
Radius of earth / Radius van aarde Re 6,38 x 10° km
TABLE 2: FORMULAE/TABEL 2: FORMULES
MOTION/BEWEGING
Ve = Vj +adt Ax =v At+tadt? or/of Ay =v,At+tadt?
V,+V Vi+V
V,; =V, + 2aAXx orlof Vv; =v; + 2aAy ax-( a ar oor Ay =( = “at
FORCE/KRAG
Fret = ma w=mg
_ Gm m, __fanax
=p Hs
Uy = fe
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ELECTROSTATICS/ELEKTROSTATIKA
F-KQ:Q, (k= 9,0x109Nm2ct) | E-F
ré q
e -58 (k=9,0x10°N.m2.C") |p 2
qe
ELECTROMAGNETISM/ ELEKTROMAGNETISME
Ad.
= ® = BAcos 0
At
ELECTRIC CIRCUITS/ELEH BANE
j= 2 v
At I
1 40, aif
= + .. =R,+R2+
R, R, R; oa
os pW
~ At
W=ViAt
P=VI
W=FPRAt
P=PR
- V?At _vB
we Ve P=5
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education
Department:
Education
North West Provincial Government
REPUBLIC OF SOUTH AFRICA
* Mark
*euausuesussas®
eee oye Beecasscccs®
Marks/ Punte: 100
Time/ Tyd: 2 hours/ uur
These marking guidelines consists of 8 pages.
Hierdie merkriglyne bestaan uit 8 bladsye
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Physical Sciences/ Fisiese Wetenskappe Grade/ Graad 11 NW/ March/ Maart 2025
Marking Guidelines/ Merkriglyne
QUESTION/ VRAAG 1
11 AVY (2)
12 BYY (2)
13 BYv (2)
14 Byv (2)
15 BYv (2)
16 Dvv (2)
[12]
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Marking Guidelines/ Merkriglyne
QUESTION/ VRAAG 2
2.1 Resultant is a single vector having the same effect as two or more vectors together (2)
/ the vector sum of two or more vectors. VW
Resultant is ‘n enkele vektor wat dieselfde effek het as twee of meer vektore saam/
die som van twee of meer vektore. VV
2.2 Zero/ Nul/ ON ¥ (1)
2.3 a
(3)
2.4.1. Ty =2540sin60 v
Tym = 2199,70 Nv (2)
2.4.2 [OPTION OPSIE 1 OPTION/ OPSIE 2
Tym - mg = 0 ¥ . mx9,8
60 =
2199,70- mx9,8 v =0 sino’ = 3499.70
m = 224,45 kg V m = 224,45 kg ¥ (3)
2.4.3 — oo
cos 60 = 575970 ¥
T.=1270NV (2)
[13]
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Physical Sciences/ Fisiese Wetenskappe Grade/ Graad 11 NW/ March/ Maart 2025
Marking Guidelines/ Merkriglyne
QUESTION/ VRAAG 3
3.1
3.2
3.3
3.4
3.5
3.6
It is the force that opposes the motion of an object and which acts parallel to the
surface.v ¥ (2)
Is die krag wat die beweging van ‘n voorwerp teenstaan en werk parallel tot die
opperviak in. vv
N = mgcos36
N =6 x 9,8cos36 Vv
N = 47,5702
fy max/maks _
= pN
H,=0,59 ¥ (4)
REMAINS THE SAME/ Y DIESELFDE. (1)
The type of material in contact is the same/was not changed/coefficient of friction
depends on the type of material in contact. ” (1)
Die tipe materiaal is dieselfde/ was nie verander nie/ wrywingskoéffisiént is
afhanklik van die tipe materiaal. ”
(3)
For/ Vir 4 kg
mg +f,-T=ma
4x98+4-Tv=4a y
T=43,2- 4a T =6a + 23,52
43,2- 4a=6a+ 23,52
a= 1,968 m-s?v
T = 43,2 - 4(1,968 ) v T =6(1,968 ) + 23,52 Vv
T = 35,33 NY T = 35,33 NV (6)
[17]
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Marking Guidelines/ Merkriglyne
QUESTION/ VRAAG 4
4.1 When_-a resultant/net force acts on an object, the object will accelerate in the
direction of the force at an acceleration directly proportional to the force and
inversely proportional to the mass of the object. vv
Wanneer ‘n resulante/ netto krag op ‘n voorwerp inwerk, versnel die voorwerp in
die_rigting van die krag teen ‘n versnelling wat direk eweredig is aan die krag en
omgekeerd eweredig is aan die massa van die voorwerp. Vv ¥
4.2
NY
Fea ¥
4.3 Newton's third law of motion/ Newton se derde bewegingswet. “
4.4.1 N=mg+Fsin40
303,8 = 23 x 9.8 + Fsin40 vv
F=121,97NVY
4.4.2 For object/ Vir voorwerp A For object / Vir voorwerpB
Fret =ma v
121,97cos40 - 45 -Faa = 23a Vv Fag -45=31av
Fea= 48,43 - 23a Fag = 31a- 45
48,43 -23a=31a -45v
a= 0,06 m-s?v
4.4.3 Fea = 48,43 - 23(0,06) v Fag = 31(0,06) — 45 v
Fea = 47,05 NY Fag = 47,17 NY
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(1)
(3)
(5)
(2)
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Marking Guidelines/ Merkriglyne
45 N=mg
N= 31 x 9,8=303,8 Nv
fe = uN ¥
Both boxes experiences same magnitude of the Normal force. ~
Boxes are identical and are placed on the same surface therefore will same
coefficient of kinetic friction. (4)
Beide bokse ervaar dieselfde grootte Normaalkrag. “
Bokse is identies en is op dieselfde opperviak, daarom_ dieselfde
wrywingskoéffisiént. ¥
=
[22]
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Marking Guidelines/ Merkriglyne
QUESTION/ VRAAG 5
5.1 Weight is the gravitational force exerted by the Earth on an object”. Mass as the
amount of matter in a body. ¥
Gewig is die gravitasiekrag uitgeoefen deur die Aarde op ‘n voorwerp. VY Massa is
die hoeveelheid materie wat ‘n voorwerp besit. ¥
5.2 Each particle in the universe attracts every other particle with a gravitational force
that is directly proportional to the product of their masses and inversely
proportional to the square of the distance between their centres. VV
Elke liggaam in dié ruimte trek elke er liggaam aan met ‘n gravitasiekrag wat
direk eweredig is k jul massas en omgekeerd eweredig is aan
die kwadraat van Aulle middelpunte. vv
5:3 _ Gmsgm_
}
_ 6,67 x10" 1999 «10° «5,98 x10 v
SE 41,2
(1,50 10" w
Fge = 3,53x1022 N v
5.4 4,99 x107° N v
5.5 Fre = 3,63x10° 71.99 x10 v
Tne 3,51*10™ N towards the sun/ na die son V
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(2)
(2)
(4)
(1)
(3)
[12]
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Physical Sciences/ Fisiese Wetenskappe Grade/ Graad 11 NW/ March/ Maart 2025
Marking Guidelines/ Merkriglyne
QUESTION/ VRAAG 6
6.1 The magnitude of the electrostatic force exerted by two point charges on each
other is directly proportional to the product of the magnitudes of the charges and
inversely proportional to the square of the distance between them. vv (2)
Die grootte van die elektrostatiese krag uitgeoefen deur twee puntladings op
mekaar is direk eweredig aan die produk van die grootte van hul ladings en
omgekeerd eweredig aan die kwadraat van die afstand tussen hulle. vv
6.2
We
(2)
; kQyQ =
6.3 Fis he w mg,
d w=0,04 x 9,8 v
_9x 10° x 30x 107° x 100x 107° w= 0,392 N
E 2 Vv
d
9 x 10° x 30 x 10° x100 x 10°
5 = 0,392 v
d
d= 0,008 m v
d=8mm v (6)
6.4 Itis the electrostatic force experienced per unit positive charge placed at that point. (2)
vv
Dit is die elektrostatiese krag ervaar per eenheid positiewe lading by ‘n punt. ¥W
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6.5
6.6
6.7
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Physical Sciences/ Fisiese Wetenskappe Grade/ Graad 11 NW/ March/ Maart 2025
Marking Guidelines/ Merkriglyne
(3)
Griteria/ Kriteria Marks/ Punte
Correct direction of the field lines./ Korrekte rigting van veldlyne v
Correct shape of the field lineS\between the charges and outside v
the charges./ Korrekte vorm Wan die veldlyne tussen die ladings
en rondom die ladings i
No field lines crossing each other. Field lines must touch the ¥
charge but must not go inside the charge./ Geen veldlyne kruis
mekaar.
_9x10°x 2x10°°x4x 10° _9* 10° x 4x 107° x 4x 10° |,
a (0,02) i (0.042
Fo4=0,00018 N F>1=0,0009 N
Fret = 0,00018 ¥0,0009 v
Fret = 0,00027 N ¥ Right/ Regs ¥ (6)
v
F
Enet= = v
_ 0,00027
net v
4x 10°
Enet = 67500 NC” Right/ Regs V (3)
[24]
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