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Physical Sciences Grade 11 2025 QP & Memo

Question paper and memoPhysical SciencesGrade 11202522 pages

Grade 11 Physical Sciences question paper and memo from the North West March Test 2025, 22 pages. Read online or get the free PDF download.

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Testpapers.co.za education Department: Education North West Provincial Government REPUBLIC OF SOUTH AFRICA auusaeeeas? « Marks: 100 Time: 2 hours This question paper consists of 9 pages and 2 data sheets. Copyright reserved Please turn over
Testpapers.co.za Physical Sciences/P1 Grade 11 NW/ March 2025 INSTRUCTIONS AND INFORMATION ti 2. 10. 11. 12. Write your name on the answer sheet provided. This question paper consists of SIX questions. Answer ALL the questions in the ANSWER BOOK. You, may use a non-programmable calculator. You may use appropriate mathematical instruments. Number the ans this question pa ing to the numbering system used in You are advised to u: ATA SHEETS. The formulae and ons must be shown in ALL calculations. ‘ ¥ Give brief motivatioraeeeeeone et cetera where required. Round off your final numerical answers to a minimum of TWO decimal places. Start EACH question on a NEW page. All diagrams are not necessarily drawn according to scale. Write neatly and legibly. Copyright reserved Please turn over
Testpapers.co.za Physical Sciences/P1 Grade 11 NW/ March 2025 QUESTION 1 1.1 -Ablock is moving with constant velocity to the right on a frictionless surface. Which sketch below correctly illustrates all the forces acting on the block? (2) 1.2 Ablock of mass m i horizontal. What is the magnitude of the normal force exerted by the surface on the block? é A mg B= mgcos®@ C mgsine D mgtanée (2) Copyright reserved Please turn over
Testpapers.co.za Physical Sciences/P1 Grade 11 NW/ March 2025 1.3 The vector diagram shows two forces in the same plane acting on an object O. 3N s 4N Another force of magnitude 5 N is applied on the object O. Which ONE of the following represents the direction at which the 5 N force must be applied to ensure object O is in equilibrium? N\, (2) 1.4 Two hypothetical planets, X and Y, have the same mass. The diameter of planet Y is twice that of planet X. If the acceleration due to gravity on the surface of planet X is g, then the acceleration due to gravity on the surface of planet Y will be ... A 16 Bg 4 c g 2 D 2 (2) Copyright reserved Please turn over
Testpapers.co.za Physical Sciences/P1 Grade 11 NW/ March 2025 1.5 Two blocks of weight 7 N and 3 N are attached to two ropes, X and Y as shown in the diagram below. 7™N ¥ i The blocks hang vertically at rest. The masses of the ropes are negligible. What is the tension in rope X and in rope Y? TENSION IN X TENSION IN Y A 10N 10N B 10N 3N Cc 7N 4N D 7N 7N (2) 1.6 Two charges point charges of +2 nC and +2 nC are located on a straight line. S and T are two points that lie on the same straight line as shown in the diagram below. +2nC Scetitt 2 NEw hie o——-—— Nc Oe ie . Which ONE of the following are the correct directions-of the resultant electric field at point S and point T due to point charges +2 nC and #2 nC DIRECTION OF THE RESULTANT | DIRECTION OF THE RESULTANT ELECTRIC FIELD AT POINT S ELECTRIC FIELD AT POINT T A Right ie Left B Left Left Cc Right Right D Left Right (2) [12] Copyright reserved Please turn over
Testpapers.co.za Physical Sciences/P1 Grade 11 NW/ March 2025 QUESTION 2 A car engine with weight w hangs from a chain(K) that is linked at point O to two other chains, one chain(M) that is fastened at angle of 60° to the ceiling and the other chain(L) to the wall as shown in the diagram below. Tension in M is 2540 N when point O is at equilibrium. 2.1. Define the term resultant. (2) 2.2 What is the magnitude of the resultant force on point O. (1) 2.3 Draw a labelled free-body diagram showing ALL the forces acting on point O. (3) 2.4 Calculate: 2.4.1. The magnitude of the vertical component of M. (2) 2.4.2 Mass of the engine. (3) 2.4.3. Tension in L. (2) [13] Copyright reserved Please turn over
Testpapers.co.za Physical Sciences/P1 Grade 11 NW/ March 2025 QUESTION 3 Block A, of mass 6 kg is placed on a table. The angle between the surface of the table and the horizontal is 36° as shown in the diagram below. The block is just about to slide and the maximum static frictional force acting on the block is 28,22 N. 3.1 (2) 3.2 Calculate the co-efficic tic friction between the block and the surface of the table. ” ‘io co (4) The table is now placed horizontal as shown in the diagram below. 3.3 How will the value calculated in QUESTION 3.2 be affected? Write only INCREASES, DECREASES or REMAINS THE SAME. (1) 3.4 Explain the answer in QUESTION 3.3. (1) Block A, is now connected by a massless string passing over a frictionless pulley, to block B of mass 4 kg. A downwards force of 4 N is applied to block B as shown in the diagram below. The kinetic frictional force between Block A and the table is 23,52 N. Block A accelerates to the right. 3.5 Draw a labelled free-body diagram for block B. (3) 3.6 Calculate the magnitude of the tension in the rope. (6) [17] Copyright reserved Please turn over
Testpapers.co.za Physical Sciences/P1 Grade 11 NW/ March 2025 QUESTION 4 An athlete trains by pushing a heavy box A of mass 23 kg, which is in contact with another identical box B of mass 31 kg, across a ROUGH surface of a field as shown in the diagram below. The athlete exerts a force F at an angle of 40° to the horizontal on box A. Each box experiences a frictional force of 45 N. The magnitude of the normal force acting on box A is 303,8 N. The boxes accelerate horizontally to the right as a system. 4.1 State Newton’s First Law of Motion in words. (2) 4 4.2 Drawa labelled force diagram showing ALL the forces acting on box A. (5) 4.3 The magnitude of the force that box A exerts on box B is the same as the magnitude of the force that box B exerts on box A. Which Newton's Law of Motion explains this statement. (1) 4.4 Calculate the magnitude of the: 4.4.1 Force F, acting on box A. (3) 4.4.2 Acceleration of the boxes. (5) 4.4.3. Force that box B exerts on box A. (2) 4.5 Use a relevant formula(e) to explain why the two boxes experience the same frictional force. (4) [22] Copyright reserved Please turn over
Testpapers.co.za Physical Sciences/P1 Grade 11 NW/ March 2025 QUESTION 5 During a lunar eclipse, the Earth, the Moon, and the Sun are aligned on the same plane such that the distance between the center of Moon and the Earth is 3,84 x10® m and the distance between the Sun and the Earth is 1,50 x10'' m as shown in the diagram below. The masses of the Moon and the Sun are 7,35 1072 kg and 1,99%10°° kg respectively. 3,84 x10 m 1,50 10'' m hy igi Moon Earth P Sun 5.1 Distinguish between the mass and the weight of an object. (2) 5.2 State Newton's law of universal gravitation in words. (2) 5.3 Calculate the magnitude of the gravitational force exerted by the Sun on the Earth. (4) The gravitational force exerted by the Earth on the Moon is 1.99 x1079 N 5.4 Write down the magnitude of the force that the Moon exert on the Earth. (1) 5.5 Calculate the net force experience by Earth due to the Moon and the Sun. (3) [12] Copyright reserved Please turn over
Testpapers.co.za Physical Sciences/P1 Grade 11 NW/ March 2025 QUESTION 6 A polystyrene ball Y carrying a charge of +30 x10° C is covered with a thin layer of graphite and placed in a glass cylinder. An identical ball X of mass 40 g, carrying a charge of +100 x10° C is now placed in the measuring cylinder and is pushed away to a height d as shown in the diagram below. 6.1 State Coulomb's Law in words. 6.2 Drawa labelled free-body diagram showing ALL the forces acting on ball X. 6.3 Calculate the distance d in mm, between ball X and Y. In the diagram below, Q:, Q2 and Q; are three stationary point charges placed along a straight line. The charges on Qu, Q2 and Q3 are +4 nC, -2 nC and -4 nC respectively. The distance between Qi and Qz2 is 0,02 m and that between Q2 and Q3 is also 0,02 m. 6.4 Define the term electric field at a point in words. 6.5 Draw the net electric field pattern due to charges Qi and Qs. 6.6 Calculate the net force exerted by Q2 and Q3 on Qi. 6.7 Calculate the net electric field experinced by Qi. Copyright reserved Please turn over (2) (2) (6) (2) (3) (6) (3) [24]
Testpapers.co.za DATA FOR PHYSICAL SCIENCES GRADE 11 PAPER 1 (PHYSICS) GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 11 VRAESTEL 1 (FISIKA) TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES SYMBOL/ NAME/NAAM SIMBOOL VALUE/WAARDE Acceleration due to gravity / g 9,8 mes? Swaartekragversnelling Universal gravitational constant/ G 6,67 « 10°! Nem*kg? Universelegravitasiekonstant _ Speed of light in a vacuu c 3,0 x 108 mes vakuum = Planck's constant / Planck se h 6,63 x 10 Jes Coulomb's constant / Coulomb: ante k 9,0 x 10°Nem**C* Charge on electron / Lading op ) e “1,6 x 10°C Electron mass / Elektronmassa Me 9,11 x 10°" kg Mass of earth / Massa op aarde M 5,98 x 10% kg Radius of earth / Radius van aarde Re 6,38 x 10° km TABLE 2: FORMULAE/TABEL 2: FORMULES MOTION/BEWEGING Ve = Vj +adt Ax =v At+tadt? or/of Ay =v,At+tadt? V,+V Vi+V V,; =V, + 2aAXx orlof Vv; =v; + 2aAy ax-( a ar oor Ay =( = “at FORCE/KRAG Fret = ma w=mg _ Gm m, __fanax =p Hs Uy = fe Copyright reserved Please turn over
Testpapers.co.za ELECTROSTATICS/ELEKTROSTATIKA F-KQ:Q, (k= 9,0x109Nm2ct) | E-F ré q e -58 (k=9,0x10°N.m2.C") |p 2 qe ELECTROMAGNETISM/ ELEKTROMAGNETISME Ad. = ® = BAcos 0 At ELECTRIC CIRCUITS/ELEH BANE j= 2 v At I 1 40, aif = + .. =R,+R2+ R, R, R; oa os pW ~ At W=ViAt P=VI W=FPRAt P=PR - V?At _vB we Ve P=5 Copyright reserved
Testpapers.co.za education Department: Education North West Provincial Government REPUBLIC OF SOUTH AFRICA * Mark *euausuesussas® eee oye Beecasscccs® Marks/ Punte: 100 Time/ Tyd: 2 hours/ uur These marking guidelines consists of 8 pages. Hierdie merkriglyne bestaan uit 8 bladsye Copyright reserved/ Kopiereg voorbehou Please turn over/ Blaai asseblief om
Testpapers.co.za Physical Sciences/ Fisiese Wetenskappe Grade/ Graad 11 NW/ March/ Maart 2025 Marking Guidelines/ Merkriglyne QUESTION/ VRAAG 1 11 AVY (2) 12 BYY (2) 13 BYv (2) 14 Byv (2) 15 BYv (2) 16 Dvv (2) [12] Amorephysies.com Copyright reserved/ Kopiereg voorbehou Please turn over/ Blaai asseblief om
Testpapers.co.za Physical Sciences/ Fisiese Wetenskappe Grade/ Graad 11 NW/ March/ Maart 2025 Marking Guidelines/ Merkriglyne QUESTION/ VRAAG 2 2.1 Resultant is a single vector having the same effect as two or more vectors together (2) / the vector sum of two or more vectors. VW Resultant is ‘n enkele vektor wat dieselfde effek het as twee of meer vektore saam/ die som van twee of meer vektore. VV 2.2 Zero/ Nul/ ON ¥ (1) 2.3 a (3) 2.4.1. Ty =2540sin60 v Tym = 2199,70 Nv (2) 2.4.2 [OPTION OPSIE 1 OPTION/ OPSIE 2 Tym - mg = 0 ¥ . mx9,8 60 = 2199,70- mx9,8 v =0 sino’ = 3499.70 m = 224,45 kg V m = 224,45 kg ¥ (3) 2.4.3 — oo cos 60 = 575970 ¥ T.=1270NV (2) [13] Copyright reserved/ Kopiereg voorbehou Please turn over/ Blaai asseblief om
Testpapers.co.za Physical Sciences/ Fisiese Wetenskappe Grade/ Graad 11 NW/ March/ Maart 2025 Marking Guidelines/ Merkriglyne QUESTION/ VRAAG 3 3.1 3.2 3.3 3.4 3.5 3.6 It is the force that opposes the motion of an object and which acts parallel to the surface.v ¥ (2) Is die krag wat die beweging van ‘n voorwerp teenstaan en werk parallel tot die opperviak in. vv N = mgcos36 N =6 x 9,8cos36 Vv N = 47,5702 fy max/maks _ = pN H,=0,59 ¥ (4) REMAINS THE SAME/ Y DIESELFDE. (1) The type of material in contact is the same/was not changed/coefficient of friction depends on the type of material in contact. ” (1) Die tipe materiaal is dieselfde/ was nie verander nie/ wrywingskoéffisiént is afhanklik van die tipe materiaal. ” (3) For/ Vir 4 kg mg +f,-T=ma 4x98+4-Tv=4a y T=43,2- 4a T =6a + 23,52 43,2- 4a=6a+ 23,52 a= 1,968 m-s?v T = 43,2 - 4(1,968 ) v T =6(1,968 ) + 23,52 Vv T = 35,33 NY T = 35,33 NV (6) [17] Copyright reserved/ Kopiereg voorbehou Please turn over/ Blaai asseblief om
Testpapers.co.za Physical Sciences/ Fisiese Wetenskappe Grade/ Graad 11 NW/ March/ Maart 2025 Marking Guidelines/ Merkriglyne QUESTION/ VRAAG 4 4.1 When_-a resultant/net force acts on an object, the object will accelerate in the direction of the force at an acceleration directly proportional to the force and inversely proportional to the mass of the object. vv Wanneer ‘n resulante/ netto krag op ‘n voorwerp inwerk, versnel die voorwerp in die_rigting van die krag teen ‘n versnelling wat direk eweredig is aan die krag en omgekeerd eweredig is aan die massa van die voorwerp. Vv ¥ 4.2 NY Fea ¥ 4.3 Newton's third law of motion/ Newton se derde bewegingswet. “ 4.4.1 N=mg+Fsin40 303,8 = 23 x 9.8 + Fsin40 vv F=121,97NVY 4.4.2 For object/ Vir voorwerp A For object / Vir voorwerpB Fret =ma v 121,97cos40 - 45 -Faa = 23a Vv Fag -45=31av Fea= 48,43 - 23a Fag = 31a- 45 48,43 -23a=31a -45v a= 0,06 m-s?v 4.4.3 Fea = 48,43 - 23(0,06) v Fag = 31(0,06) — 45 v Fea = 47,05 NY Fag = 47,17 NY Copyright reserved/ Kopiereg voorbehou Please turn over/ Blaai asseblief om (2) (1) (3) (5) (2)
Testpapers.co.za Physical Sciences/ Fisiese Wetenskappe Grade/ Graad 11 NW/ March/ Maart 2025 Marking Guidelines/ Merkriglyne 45 N=mg N= 31 x 9,8=303,8 Nv fe = uN ¥ Both boxes experiences same magnitude of the Normal force. ~ Boxes are identical and are placed on the same surface therefore will same coefficient of kinetic friction. (4) Beide bokse ervaar dieselfde grootte Normaalkrag. “ Bokse is identies en is op dieselfde opperviak, daarom_ dieselfde wrywingskoéffisiént. ¥ = [22] Copyright reserved/ Kopiereg voorbehou Please turn over/ Blaai asseblief om
Testpapers.co.za Physical Sciences/ Fisiese Wetenskappe Grade/ Graad 11 NW/ March/ Maart 2025 Marking Guidelines/ Merkriglyne QUESTION/ VRAAG 5 5.1 Weight is the gravitational force exerted by the Earth on an object”. Mass as the amount of matter in a body. ¥ Gewig is die gravitasiekrag uitgeoefen deur die Aarde op ‘n voorwerp. VY Massa is die hoeveelheid materie wat ‘n voorwerp besit. ¥ 5.2 Each particle in the universe attracts every other particle with a gravitational force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centres. VV Elke liggaam in dié ruimte trek elke er liggaam aan met ‘n gravitasiekrag wat direk eweredig is k jul massas en omgekeerd eweredig is aan die kwadraat van Aulle middelpunte. vv 5:3 _ Gmsgm_ } _ 6,67 x10" 1999 «10° «5,98 x10 v SE 41,2 (1,50 10" w Fge = 3,53x1022 N v 5.4 4,99 x107° N v 5.5 Fre = 3,63x10° 71.99 x10 v Tne 3,51*10™ N towards the sun/ na die son V Copyright reserved/ Kopiereg voorbehou Please turn over/ Blaai asseblief om (2) (2) (4) (1) (3) [12]
Testpapers.co.za Physical Sciences/ Fisiese Wetenskappe Grade/ Graad 11 NW/ March/ Maart 2025 Marking Guidelines/ Merkriglyne QUESTION/ VRAAG 6 6.1 The magnitude of the electrostatic force exerted by two point charges on each other is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them. vv (2) Die grootte van die elektrostatiese krag uitgeoefen deur twee puntladings op mekaar is direk eweredig aan die produk van die grootte van hul ladings en omgekeerd eweredig aan die kwadraat van die afstand tussen hulle. vv 6.2 We (2) ; kQyQ = 6.3 Fis he w mg, d w=0,04 x 9,8 v _9x 10° x 30x 107° x 100x 107° w= 0,392 N E 2 Vv d 9 x 10° x 30 x 10° x100 x 10° 5 = 0,392 v d d= 0,008 m v d=8mm v (6) 6.4 Itis the electrostatic force experienced per unit positive charge placed at that point. (2) vv Dit is die elektrostatiese krag ervaar per eenheid positiewe lading by ‘n punt. ¥W Copyright reserved/ Kopiereg voorbehou Please turn over/ Blaai asseblief om
6.5 6.6 6.7 Testpapers.co.za Physical Sciences/ Fisiese Wetenskappe Grade/ Graad 11 NW/ March/ Maart 2025 Marking Guidelines/ Merkriglyne (3) Griteria/ Kriteria Marks/ Punte Correct direction of the field lines./ Korrekte rigting van veldlyne v Correct shape of the field lineS\between the charges and outside v the charges./ Korrekte vorm Wan die veldlyne tussen die ladings en rondom die ladings i No field lines crossing each other. Field lines must touch the ¥ charge but must not go inside the charge./ Geen veldlyne kruis mekaar. _9x10°x 2x10°°x4x 10° _9* 10° x 4x 107° x 4x 10° |, a (0,02) i (0.042 Fo4=0,00018 N F>1=0,0009 N Fret = 0,00018 ¥0,0009 v Fret = 0,00027 N ¥ Right/ Regs ¥ (6) v F Enet= = v _ 0,00027 net v 4x 10° Enet = 67500 NC” Right/ Regs V (3) [24] Copyright reserved/ Kopiereg voorbehou Please turn over/ Blaai asseblief om
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