Physical Sciences Grade 11 P1 September 2018 Paper & Memo

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Downloaded from hlayiso.com Physical Sciences /P1 September 2018 Common Test Kes INSTRUCTIONS AND INFORMATION TO CANDIDATES 1. Write your name on the ANSWER BOOK. 2. This question paper consists of EIGHT questions. Answer ALL the questions in the ANSWER BOOK. 3. Questions 5.2.1 and 9.3 must be answered in the special answer sheet provided. Write your name on this sheet and submit it together with your answer book. 4. Start EACH question on a NEW page in the ANSWER BOOK. 5. Number the answers correctly according to the numbering system used in this question paper. 6. Leave ONE line between two subsections, for example between QUESTION 2.1 and QUESTION 2.2. 7. You may use a non-programmable calculator. 8. You may use appropriate mathematical instruments. 9. You are advised to use the attached DATA SHEET. 10. Show ALL formulae and substitutions in ALL calculations. 11. Round off your final numerical answers to a minimum of TWO decimal places. 12. Give brief motivations, discussions, et cetera where required. Copyright Reserved Please Turn Over

Downloaded from hlayiso.com 3 Physical Sciences /P1 September 2018 Common Test NSC QUESTION 1 : MULTIPLE CHOICE QUESTIONS Four options are provided as possible answers to the following questions. Each question has only ONE correct answer. Write only the letter (A - D) next to the question number (1.1 — 1.10) in the ANSWER BOOK, for example 1.11 D. 1.4 Which of the following pairs are both vector quantities? A Displacement and energy B Speed and force Cc work and mass D Weight and acceleration (2) 12 Two forces A and B each of magnitude 15 N act on the same point O. If the resultant of these forces is 15 N, what is the magnitude of the angle 0 between them? A —v fe) 8 / La A 60° B 120° B Cc 90° D 30° Copyright Reserved Please Turn Over

1 1.4 Downloaded from hlayiso.com Physical Sciences /P1 September 2018 Common Test NSC 3. Three forces with magnitudes F;,F2 and Fs; act on the same point P in the same plane. The system is in equilibrium. v The resultant of the Y components of the forces force is given by : A B Cc D Fysin 0 + F2+Fs F3-Fycos 0 F, + Fycos0 Fisin @- Fo In which of the following cases is the resultant force acting on an object equal to zero? A An object is moving with constant acceleration. B When the only force acting on the object is the gravitational force. Cc An object undergoes equal displacements every second. D An object is moving with increasing acceleration. Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Physical Sciences /P1 5 September 2018 Common Test NSC 1.5 Two blocks, A and B, with masses m and 2m respectively, are in contact with 1.6 each other. The blocks are accelerated by a horizontal force F along a frictionless, horizontal surface. B What is the magnitude of the force that B exerts on A? A 2F BOF C 2/3 DF (2) Which of the examples stated below best describes Weightlessness? A An object accelerates downwards towards the Earth at an acceleration of 9,8 mss”, B An object moving at a constant velocity upwards away from the ground. c An object moving at constant velocity downwards towards the ground. D An object that is accelerated upwards away from the ground by a constant (2) applied force. Copyright Reserved Please Turn Over

1.7 1.8 1.9 Downloaded from hlayiso.com Physical Sciences /P1 6 September 2018 Common Test NSC The diagram below represents a ray of monochromatic light passing from air into quartz. Normal \ air \ \ \ 1 \ 1 \ quartz ' \ ' i 1 \ \ \ \ \ Pp Which path will the ray follow in the quartz? iwRek OnDOTV The field generated around a current carrying conductor is a magnetic field an electric field parallel to the conductor greater further away from the conductor. (2) 0DOD>Y In the diagram below, a unit positive charge q is located between two charged spheres, A and B. Sphere A has a charge of +2q and is located x meter from charge q. Sphere B a charge of —2q and is located ’% x meter from charge q. +2q +q -2q ---( A} @- B }-- x xX 4 If the magnitude of the force on charge q due to sphere A is F, what is the magnitude of the force on charge q due to sphere B? A Ya F B 2F Cc AF D 4F Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Physical Sciences /P1 1.10 7 NSC Consider the circuit diagram below: O- AC) When switch S is closed, the readings on V and V2 (respectively) will change as follows: 2R Vi V2 A_ | decreases increases B_ | increases decreases C_ | decreases decreases D | increases remains the same Copyright Reserved September 2018 Common Test (2) [20] Please Turn Over

2.1 2.2 2.3 2.4 Downloaded from hlayiso.com Physical Sciences /P1 8 September 2018 Common Test NSC QUESTION 2 In the system below the two masses labelled m and 10 kg are connected to each other by two light strings A and B at point O. Point O is kept stationary by attaching it to a wall using string C. The coefficient of static friction between the 10 kg mass and its surface is 0,51. as] 140° O B 10 kg SS Define static friction. (2) Calculate the magnitude of the frictional force between the 10 kg mass and its surface. (3) Determine the mass of m. (5) Will the force in string A increase, decrease or stay the same if string B is detached from the 10 kg mass? (1) Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Physical Sciences /P1 9 September 2018 Common Test NSC QUESTION 3 3.1 3.1.3 A force of magnitude 40N is applied to a 3 kg block at an angle of 60° to the horizontal along a rough surface (surface1) as shown below. A second 2kg block is placed on the rough upper surface (surface 2) of the first block. The two blocks are joined by a string of negligible mass running through a frictionless pulley. The kinetic frictional force between the 3 kg block and surface 1 is 2 N whilst the kinetic frictional force between the 2kg block and surface 2 is 1,2 N. Let T be the tension in the strings connecting the two blocks as the 3kg block accelerates to the right. Surface 2 F=40N Surface 1 Define Newtons Second law of motion. (2) Draw a labelled free body diagram showing all the forces acting on the 3 kg block. (5) Calculate the Tension(T) in the string (7) [14] Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Physical Sciences /P1 10 September 2018 Common Test NSC QUESTION 4 4.1 State Newton’s Law of Universal Gravitation in words. (2) 4.2 The velocity - time graph shown below describes the motion of an object of mass m thrown upwards and then falling downwards on Planet X for 5s. Assume that the only force acting on the object is the gravitational force of planet X. Velocity(ms”) vs time(s) am T t a iia T 7 Teh ay ter | i i T Eee Cee CT COP rr i f | rt COE ala on it L I im i Tit The radius of planet X is 6,22x10° m. Using the graph above and relevant formulae, (5) calculate the mass of planet X. Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Physical Sciences /P1 an NSC September 2018 Common Test 4.3. Asatellite is orbiting planet X. When the satellite is on the line joining the centres of planet X and planet Y, the net gravitational force acting on the satellite due to planet X and planet Y is zero. The distance between the centres of planet X and planet Y is 4x10’m Planet Y If the mass of planet Y is twice the mass of planet X, calculate the distance of the : satellite from planet X. (4) [11] Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Physical Sciences /P1 12 September 2018 Common Test NSC QUESTION 5 5.1 Define refraction of light. (2) 5.2. A ray of light is incident upon the surface of a semi-circular glass block as 5.2.1 5.2.2 5.3 5.3.1 5.3.2 5.3.3 shown in the sketch below. Air Glass Air Using the diagram sheet provided, complete the diagram by showing the path taken by the light ray as it passes from air to glass and then to air. Label the angle of incidence, the refracted ray, the emergent ray and draw the normal at each surface. (4) If the refractive index of glass is 1,50, calculate the speed of light through glass given that the speed of light in air is 3x10° ms“ Take the refractive index of air to be 1,00. (3) The drawing shows a ray of light travelling through a gas (n = 1.00), then through a solid (n = 1.55), and then into a liquid (n = 1.45). The surfaces are parallel and the angle of refraction at the first surface is 25,42°. IQ Gas Solid Liquid State Snell’s law. (2) Calculate ty ,the angle of refraction at the second surface. (4) A If the size of i1 is increased, will the size of angle ty increase, decrease or remain the same? (2) [17] Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Physical Sciences /P1 13 September 2018 Common Test NSC QUESTION 6 6.1 The sketch below shows a phenomenon that takes place when parallel wave fronts approach a narrow opening in a barrier. Direction of wave motion ! J | 6.1.1 State and define the above phenomenon. (3) 6.1.2 Sketch the wave pattern that occurs when the wave fronts pass through the opening in a barrier. (2) 6.1.3 The wave pattern that forms is explained by Huygens principle. State this principle. (2) 6.2 When monochromatic blue light is passed through a narrow single slit, a pattern is observed on a screen. Describe the diffraction pattern which is observed on the screen. (3) [10] Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Physical Sciences /P1 14 September 2018 Common Test NSC QUESTION 7 fal 7.2 7.3 74 75 7.6 7.7 A small, conducting sphere, X, with a charge of +5 nC is suspended by an insulated inelastic thread of negligible mass, which is tied to point P. Another small conducting sphere, Y, on an insulated stand, with a charge of —3 nC, is brought closer to X until their centres are 15 mm apart on the same horizontal line. Draw the resultant electric field pattern produced by spheres X and Y. (3) State Coulomb's law in words. (2) Calculate the magnitude of the electrostatic force that sphere Y exerts on sphere X. (4) Define Electric field at a point. (2) Calculate the magnitude of the electric field 15mm away from sphere X (4) Sphere Y is now moved closer and makes contact with sphere X and moved back to its original position, that is 15mm from X. Will electrons be transferred from spheres X to Y or from spheres Y to X? Give a reason for your answer. * (2) Calculate the number of electrons transferred upon contact. (4) [21] Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Physical Sciences /P1 15 September 2018 Common Test NSC QUESTION 8 8.1 The sketch below shows a current carrying solenoid that is wrapped around a soft iron core. Does A represent the North pole or the South pole of the magnetic iron core? 8.1.1 Is the magnetic field direction outside the iron core from A to B or from Bto A? _. ; _ (1) 8.1.2 A coil is moved into or out of a magnetic field of a bar magnet as shown below so that the rate of change of magnetic field, AB = 0,6 Tes~' 8.2 N Ss N iS) The area through which the field links with the coil is given by A = 0,4 m?. 8.2.1 State Faraday’s law of electromagnetic induction in words. (2) 8.2.2 Calculate the magnitude of the average emf generated in the coil, if the coil has 8 turns. (4) 8.2.3 If the experiment is repeated with a new coil that has twice as many turns, what would the new emf be? (2) [10} Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Physical Sciences /P1 16 NSC QUESTION 9 September 2018 Common Test Learners conduct an investigation to verify Ohm’s law. They measure the current through a resistor for different potential differences across its ends, i.e. the potential difference was chosen as the independent variable. The results obtained are tabulated below: Potential Current Difference (V) | Strength (A) 21,4 0.80 35,8 1,20 56,0 1,90 72,04 2,30 98,04 3,20 124,04 4,13 a1 State Ohm’s law in words. g.2 The dependant variable in this investigation was the current. 9.2.1 Name one quantity that was controlled in this investigation. 9.2.2 State how the quantity in Q 9.2.1 was kept constant 9.3. Using the information in the table and the graph sheet provided, draw a graph of (5) Current versus Potential difference. 9.4 Calculate the gradient of the graph. 9.5 What quantity does the gradient of the graph represent? 9.6 Hence determine the resistance of the resistor. Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Physical Sciences /P1 17 September 2018 Common Test NSC QUESTION 10 10.1 You are given four identical resistors, each of magnitude ‘R’ and a battery of emf ‘V’ volts. 10.1.1. Sketch an appropriate circuit diagram, using all the above components, to show how you would connect them to obtain a total resistance of R in the circuit. (2) 10.1.2 Use relevant calculations to show that the total resistance in your circuit in Q10.1.1 is equal to R. (2) 10.2 The circuit diagram below shows a battery of unknown EMF with negligible internal resistance, connected as shown below. The reading on the voltmeter is 4 V. Calculate: 10.2.1 the effective resistance in the circuit. (3) 10.2.2 the current flowing through the 1 resistor. (3) 10.2.3 the reading on the ammeter. (4) 10.2.4 the EMF of the battery (3) 10.3 The switch S is now opened. 10.3.1 How will the energy dissipated by the 4 Q resistor change if the time it is in operation remains constant? State whether it will increase, decrease or remain the same. (1) 10.3.2 Briefly explain your answer using relevant formulae . (2) [20] TOTAL : 150 Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Physical Sciences /P1 18 September 2018 Common Test NSC DATA FOR PHYSICAL SCIENCES GRADE 11 PAPER 1 (PHYSICS) TABLE 1: PHYSICAL CONSTANTS NAME SYMBOL VALUE Acceleration due to gravity 9,8 ms? Gravitational constant 6,67 x 10°11 N-m2-kg2 Coulomb's constant 9,0 x 109N-m2-C2 Speed of light in a vacuum aO;xX,o!] a 3,0 x 10° m-s* Charge on electron -1,6x107C oO Electron mass 9,11 x 1031 kg Radius of earth Re 6,38 x 108m Mass of earth Me 5,98 x 1074 kg TABLE 2: FORMULAE MOTION Vv, =v, +adt Ax = v,At+ daat? Ve ty. Vy =v, + 2aAx Ax = (“ga FORCE FE ny e=ma w=mg Gm,m, f, r2 (max) f, = 14.N g= WAVES, SOUND AND LIGHT va=far T= F= =n,N al g = n, sind; =n, sin@, n== Copyright Reserved Please Turn Over

Downloaded from hlayiso.com Physical Sciences /P1 19 September 2018 Common Test NSC ELECTROSTATICS kQ,Q F FS 2 s (k = 9,0 x 10° N-m?-C*) wart E= LS (k = 9,0 x 10°N-m?-C-?) vet ELECTROMAGNETISM e--no® ®=BAcos0 At CURRENT ELECTRICITY j= Rar At | 424,444, R=y+ fh +h Rh & mht Ia His * W=Vq WwW “At We=VlAt W=PRAt Bet > P=PR w= wat \y? R = Copyright Reserved Please Turn Over

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Peo Air September 2018 Common Test NSC Glass Downloaded from hlayiso.com Air Physical Sciences /P1 NAME OF LEARNER : Question 5.2 Question 9.3 L33HS sdO-NVAL Copyright Reserved

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Physical Sciences 3 September — .8 Common Test NSC OR Fe / 49,98 N LI ¥ WIFg oO tan50°= W ev OR tan 40°= 49,98 v {o) 49,98 WwW ” WW S9.564N W =99,564N —_ | > Wem a) W=meg a} 59,564.45 m.9,87 59,564 = m-9,8v (5) —_ m = 6,08 kgv E 2.4 Stay the samew” (i) ) m . QUESTION THREE [tag ze} 3.1.1 Ifa non-zero NET force acts on an object, then the object accelerates in the direction of the NET force where the acceleration of the object is <b) directly proportional to the NET forceY and inversely proportional to the zo} mass of the object. ¥ (2) {o) 3.1.2 _ c F=40 Nv S ae ro) T/Tension ‘i fa) © NB : 1 mark for all 3 vertical forces present. Copyright reserved Please turn over Physical Sciences 4 September 2018 Common Test 3.1.3. Take the motion of the system to the right as being positive. NSC Consider the 3 kg block Fx = F-cos® = 40 cos60° = 20NY Fver = ma Fx #(T) + (fcr) + (fla) =3.a [ % anyone 20-T-2-1,2=3a 18 8-T= 38% cceccsce(1) Consider the 2 kg block Fuer = ma fk2 + (— T) = 2(-a) 1,2-T=-2a TH 2atd 2%. vee(2) Substitute equation (2) in equation (1) 16,8-(2a+12)=3a a=312 T =aietoy vet av = 7,44NV QUESTION FOUR 44 7) [14] Every body in the universe attracts every other body with a gravitational force that is directly proportional to the product of their masses” and versely propo! centres. ¥ Copyright reserved nal to the square of the distance between their Please turn over

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Downloaded from hlayiso.com Physical Sciences 7 September .. d Common Test 6.2.2 n= ov v 1,50 =3x108 v v v= 2x10 mst v 5.3.1 The ratio of the sine of the angle of incidence in one medium to the sine of the angle of refraction in the other medium is a constant. VV ( 2 or 0) A 5.3.2 iz = 25,420 nisin8; = nesin@2v 1,55-sin 25,42 = 1,45 sin 62¥ A Q2=2= 27,319 v 5.3.2 Increases vv QUESTION SIX 6.1.1 Single slit diffraction. v It is the ability of a wave to spread out in wave fronts as they pass through a small aperture or around a sharp edgev “ ( 2 or 0 marks) ha i as Ne Ee vv If shape is asymmetrical, minus 1 mark. Copyright reserved (3) (3) (2) Please turn over Physical Sciences 8 September 2018 Common Test NSC 6.1.3 According to Huygens’ principle each point on a wave front forms (2) secondary wavelets” that spreads out in all directions” forming the above pattern. 6.2 A broad central blue band” is observed flanked on either side by alternating narrower” dark and blue bands. “ (3) [10] QUESTION SEVEN Fat Marking Rubric : Electric field pattern | Criteria Mark allocation “| Correct direction of field lines 4 mark Correct shape of the field 1 mark pattern Field lines do not touch, evenly | 1 mark spaced, and perpendicular to surface and touches the surface (3) 7.2 The magnitude of the electrostatic force exerted by two point charges on each other is directly proportional to the product of the magnitudes of the charges” and inversely proportional to the square of the distance between them.” (2) Copyright reserved Please turn over

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Downloaded from hlayiso.com Physical Sciences 11 September ~ 18 Common Physical Sciences 12 Sepiember 2018 Common Test Test NSC NSC 9.3 9.4 Gradient(1/R) = AL” AV Current Strength versus Potential Difference = 45-14v 140 — 40 v + THe = iiabsaaaineaatata atetaed iis fatstaie = 0,031 Ov : + + + H + i $ ian u e Accept any suitable set of co-ordinates that is taken from the graph. (4) oe HH e Acceptable range (0,020 — 0.040 ) : is jaanae + 95 inverse of resistancev/ : (1) Ea : i : t 9.6 3 : : : Positive marking from Q 9.4 € : : oa £ ; i 2 - i 4 =0,031v : rt # H R (2) 5 : : R = 32,26 OV ° ana : + = [16] + QUESTION TEN imeeaaeeea Stas aaeee Hp TT fg i 10.1.1 + sr anauen v 4 rH mann asa i sean; apuasesne 0 20 40 60 30 100 120 140 Potential Difference (V) "Marking Rubric : Graph Criteria Mark allocation v v ° Suitable scale used on x and y 1 mark PON a “| re DB JR * Xand Y axes correctly labelled 1 mark | with correct units * Correct plotting of points 2 marks Best fit curve drawn joining points | 1 mark (2) Copyright reserved Please turn over Copyright reserved Please turn over

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