Physical Sciences Grade 10 P1 2012 Memo (Afr)

- NATIONAL SENIOR CERTIFICATE NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 10 PHYSICAL SCIENCES: PHYSICS (P1) FISIESE WETENSKAPPE: FISIKA (V1) EXEMPLAR/MODEL 2012 MEMORANDUM MARKS/PUNTE: 150 This memorandum consists of 11 pages. Hierdie memorandum bestaan uit 11 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physical Sciences P1/Fisiese Wetenskappe V1 2 DBE/2012 NSC/NSS – Grade 10 Exemplar/Graad 10 Model – Memorandum QUESTION 1/VRAAG 1 1.1 C  (2) 1.2 B  (2) 1.3 D  (2) 1.4 B  (2) 1.5 A  (2) 1.6 C  (2) 1.7 C  (2) 1.8 A  (2) 1.9 B  (2) 1.10 C  (2) [20] QUESTION 2/VRAAG 2 2.1 A single force  having the same effect as all other forces acting together.  'n Enkele krag  wat dieselfde effek het as al die ander kragte tesame.  (2) 2.2 Upward positive/Opwaarts positief: Notes/Aantekeninge: F net = F + w + f The force of 1 550 N must have an = 1 550 + (-1 480) + (-20)  opposite sign than the other two = 1 550 – 1 500 forces. = 50 Die krag van 1 550 N moet 'n teken ∴ F net = 50 N upwards/opwaarts  hê wat die teenoorgestelde is van die ander twee kragte. Upward negative/Opwaarts negatief: F net = F + w + f = -1 550 + (1480 + 20)  = -1 550 + 1 500 (3) = -50 ∴ F net = 50 N upwards/opwaarts  2.3 2.3.1 Distance/Afstand = 80 + 60 (1) = 140 m  Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physical Sciences P1/Fisiese Wetenskappe V1 3 DBE/2012 NSC/NSS – Grade 10 Exemplar/Graad 10 Model – Memorandum 2.3.2 Upward positive/Opwaarts positief: Notes/Aantekeninge: Displacement /Verplasing The two displacements = +80 + (-60) must have opposite signs. = 20 m  upwards/opwaarts  Die twee verplasings moet teenoorgestelde tekens hê. Upward negative/Opwaarts negatief: Displacement /Verplasing = -80 + 60 = 20 m  upwards/opwaarts  (2) [8] QUESTION 3/VRAAG 3 3.1 3.1.1 Starts from rest/0 m∙s-1  Velocity increases at a constant rate  until he reaches 2,5 m∙s-1 after 25 s.  Begin uit rus/0 m∙s-1  Snelheid vermeerder teen 'n konstante tempo  totdat hy 2,5 m∙s-1 bereik na 25 s.  OR/OF Starts from rest/0 m∙s-1  Constant positive acceleration  until he reaches 2,5 m∙s-1 after 25 s.  Begin uit rus/0 m∙s-1  Konstante positiewe versnelling  totdat hy 2,5 m∙s-1 bereik na 25 s.  (3) 3.1.2 Constant/uniform velocity  for another 25 s.  Konstante/uniforme snelheid  vir 'n verdere 25 s.  OR/OF Velocity remains 2,5 m∙s-1 in the direction of motion  for another 25 s.  Snelheid bly 2,5 m∙s-1 in die rigting van beweging  vir 'n verdere 25 s.  OR/OF Zero/No acceleration  for another 25 s.  Nul/Geen versnelling  vir 'n verdere 25 s.  (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physical Sciences P1/Fisiese Wetenskappe V1 4 DBE/2012 NSC/NSS – Grade 10 Exemplar/Graad 10 Model – Memorandum ∆v 3.2 Acceleration/Versnelling = ∆t 0 − 2,5  = 100 − 60  = - 0,0625 ∴ a = 0,063 m∙s-2  opposite to direction of motion/teenoorgesteld aan bewegingsrigting  (4) 3.3 Length of track = Area between the graph and the time axis  Lengte van baan = Area tussen grafiek en tydas = ½(2,5) (35 + 100)  = 168,75 m  OR/OF Length of track/Lengte van baan = Area of trapezium/Area van trapesium = ½(2,5) (35 + 100)  = 168,75 m  OR/OF Length of track/Lengte van baan = ½h(sum of // sides)/½h(som van // sye) = ½(2,5) (35 + 100)  = 168,75 m  OR/OF Length of track = Area between the graph and the time axis  Lengte van baan = Area tussen grafiek en tydas = ½bh + ½bh + lb = ½(25)(2,5) + ½(40)(2,5)  + (35)(2,5)  = 31,25 + 87,5 + 50 = 168,75 m  OR/OF Length of track = Area of triangle + area of triangle + area of rectangle Lengte van baan = Area van driehoek + area van driehoek + area v. reghoek = ½bh + ½bh + lb = ½(25)(2,5) + ½(40)(2,5)  + (35)(2,5)  = 31,25 + 87,5 + 50 = 168,75 m  OR/OF Length of track/Lengte van baan = ½bh + ½bh + lb = ½(25)(2,5) + ½(40)(2,5)  + (35)(2,5)  = 31,25 + 87,5 + 50 = 168,75 m  (4) [13] QUESTION 4/VRAAG 4 4.1 To compensate for friction.  Om vir wrywing te vergoed.  OR/OF To ensure that the trolley moves at constant acceleration.  Om te verseker dat die trollie teen konstante versnelling beweeg.  (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physical Sciences P1/Fisiese Wetenskappe V1 5 DBE/2012 NSC/NSS – Grade 10 Exemplar/Graad 10 Model – Memorandum 4.2 4.2.1 Time/Tyd  (1) 4.2.2 Displacement/Verplasing  (1) 4.3 Graph of position versus time/Grafiek van posisie teenoor tyd 3,0 • 2,5 Position/Posisie (m) 2,0 • 1,5 • 1,0 • 0,5 • 0• 0 0,2 0,4 0,6 0,8 1,0 Time/Tyd (s) Criteria for graph: Kriteria vir grafiek: • Suitable heading.  • Geskikte opskrif.  • Correct labels on both axes.  • Korrekte benoemings op beide asse.  • Appropriate scale on both axes.  • Geskikte skaal op beide asse.  • Any three points plotted correctly.  • Enige drie punte korrek gestip.  • All six points plotted correctly.  • Al ses punte korrek gestip.  • Curve joining the points.  •Kromme wat die punte verbind.  (6) 4.4 Uniformly accelerated motion.  The gradient of the graph increases constantly.  Uniform versnelde beweging.  Die gradiënt van die grafiek vermeerder konstant.  OR/OF Uniformly accelerated motion.  The velcoity increases constantly each 0,2 s.  Uniform versnelde beweging.  Die snelheid vermeerder konstant elke 0,2 s.  (2) [12] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physical Sciences P1/Fisiese Wetenskappe V1 6 DBE/2012 NSC/NSS – Grade 10 Exemplar/Graad 10 Model – Memorandum QUESTION 5/VRAAG 5 5.1 5.1.1 Acceleration/Versnelling  (1) 5.1.2 Straight line/Reguitlyn  (1) 5.2 3600 15 m∙s-1 = (15) ( )  km∙h-1 = 54 km∙h-1  < 60 km∙h-1 1000 No /He did not. Nee /Hy het nie. OR/OF 1000 60 km∙h-1 = (60) ( )  m∙s-1 = 16,67 m∙s-1  > 15 m∙s-1 3600 No /He did not. Nee /Hy het nie. (3) 5.3 OPTION 1/OPSIE 1 Notes/Aantekeninge: Δx = v i Δt  Accept/Aanvaar: = (15)(1)  s = vt = 15 m  s = ut + ½at2 OPTION 2/OPSIE 2 u+ v  s=  t Δx = v i Δt + ½aΔt2   2  = (15)(1) + ½(0)(1)2  = 15 m  OPTION 3/OPSIE 3  v + v1  Δx =  f ∆t   2   15 + 15  =  (1)   2  = 15 m (3) 5.4 POSITIVE MARKING FROM QUESTION 5.3 POSITIEWE NASIEN VAN VRAAG 5.3 Braking distance/Remafstand:  v + v1  Δx =  f ∆t   2   0 + 15  =   (3)   2  = 22,5 m Total stopping distance/Totale stilhouafstand = 22,5 + 15 m  = 37,5 m  Yes/He will stop before the pedestrian crossing. Ja/Hy sal voor die voetoorgang tot stilstand kom. (6) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physical Sciences P1/Fisiese Wetenskappe V1 7 DBE/2012 NSC/NSS – Grade 10 Exemplar/Graad 10 Model – Memorandum 5.5 Increases  For the same change in velocity,  the stopping time will increase.  Toeneem  Vir dieselfde verandering in snelheid,  verhoog die stilhoutyd.  (3) [17] QUESTION 6/VRAAG 6 6.1 The total mechanical energy remains constant/is conserved  in a closed/isolated system.  Die totale meganiese energie bly konstant/bly behoue  in 'n geslote/geïsoleerde sisteem.  (2) 6.2 E p = mgh  = (0,2)(9,8)(0,8)  = 1,568 J  (3) 6.3 E M (B) = E M (A)  / (E p + E k ) B = (E p + E k ) A / mgh B + ½mv B2 = mgh A + ½mv 2A (0,2)(9,8)h  + ½(0,2)(3)2 = (0,2)(9,8)(0,8)  + ½(0,2)(0)2  ∴ h = 0,34 m  (6) 6.4 6.4.1 Mechanical/kinetic energy converted to heat/sound/internal energy.  Meganiese/kinetiese energie omgeskakel na hitte-/klank-/interne energie.  (1) 6.4.2 v f 2 = v i 2 + 2aΔx  (0)2  = (3,96)2 + 2a(2)  a = -3,92 m∙s-2 ∴ a = 3,92 m∙s-2  opposite to the direction of motion  teenoorgesteld aan bewegingsrigting  (5) [17] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physical Sciences P1/Fisiese Wetenskappe V1 8 DBE/2012 NSC/NSS – Grade 10 Exemplar/Graad 10 Model – Memorandum QUESTION 7/VRAAG 7 7.1 7.1.1 The maximum displacement of a particle  from its equilibrium position/position of rest.  Die maksimum verplasing van 'n deeltjie  van sy ewewigsposisie/posisie van rus.  (2) 7.1.2 Position/posisie (m) a+b Time/tyd (s) Criteria for diagram: Kriteria vir diagram: Diagram shows two complete waves.  Diagram toon twee volledige golwe.  Amplitude correctly shown.  Amplitude korrek getoon.  Correct shape.  Korrekte vorm.  (3) 7.1.3 (Constructive) interference  (Konstruktiewe) interferensie  (1) 7.1.4 Principle of superposition  Beginsel van superposisie  (1) 7.2 7.2.1 The distance between two consecutive points in phase.  Die afstand tussen twee opeenvolgende punte in fase.  OR/OF The distance between two consecutive crests/troughs.  Die afstand tussen twee opeenvolgende kruine/buike.  (2) 7.2.2 Upward/Opwaarts  (2) 7.2.3 1 f =  T 1 =  5 = 0,2 Hz  (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physical Sciences P1/Fisiese Wetenskappe V1 9 DBE/2012 NSC/NSS – Grade 10 Exemplar/Graad 10 Model – Memorandum 7.2.4 POSITIVE MARKING FROM QUESTION 7.2.3 POSITIEWE NASIEN VAN VRAAG 7.2.3 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 v = fλ  Δx = vΔt  = 0,2 x 1,5  1,5 = v(5)  = 0,3 ms-1 ∴ v = 0,3 ms-1 (3) [18] QUESTION 8/VRAAG 8 8.1 8.1.1 Compression/Verdigting  (1) 8.1.2 Wavelength/Golflengte  (1) 8.2 8.2.1 Longitudinal wave/Longitudinale golf  (1) 8.2.2 Y (1) 8.2.3 Higher amplitude/Hoër amplitude  (1) 8.2.4 Shorter wavelength/Korter golflengte  OR/OF Points X, Y and Z closer together. Punte X, Y en Z sal nader aan mekaar wees. (1) [6] QUESTION 9/VRAAG 9 9.1 Accelerating charges/Versnelde ladings  (1) 9.2 9.2.1 Infrared/Infrarooi  (1) 9.2.2 Ultraviolet/Ultraviolet  (1) 9.2.3 γ rays/γ-strale  (1) 9.2.4 γ rays/γ-strale  (1) 9.3 High energy/frequency/penetrating ability.  Damage living cells/Cause cancer/Cause mutations  Hoë energie/frekwensie/deurdringingsvermoë.  Beskadig lewende selle./Veroorsaak kanker./Veroorsaak mutasies.  (2) 9.4 hc E=  λ 6,63 × 10 -34 × 3 × 108  = 2,1× 10 - 9 = 9,47 x 10-17J  (4) [11] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physical Sciences P1/Fisiese Wetenskappe V1 10 DBE/2012 NSC/NSS – Grade 10 Exemplar/Graad 10 Model – Memorandum QUESTION 10/VRAAG 10 10.1 10.1.1 Region in space where another magnet/ferromagnetic material will experience a magnetic force.  Gebied in die ruimte waar 'n ander magneet/ferromagnetiese materiaal 'n magnetiese krag sal ondervind.  (2) 10.1.2 S pole/S-pool  (1) 10.2 10.2.1 Criteria for magnetic field pattern Kriteria vir magneetveldpatroon • Correct shape.  • Korrekte vorm.  • Correct direction.  • Korrekte rigting.  • Filed lines do not touch/cross each other.  • Veldlyne raak/kruis nie mekaar nie.  (3) 10.2.2 Fewer magnetic field lines further apart./less dense.  Minder magneetveldlyne verder uitmekaar/minder dig.  (1) [7] QUESTION 11/VRAAG 11 11.1 During contact, electrons are transferred from A to B.  The spheres acquire equal charges.  Spheres thus repel each other.  Tydens kontak word elektrone van A na B oorgedra.  Die sfere verkry gelyke ladings. Sfere stoot mekaar dus af. (3)  11.2 4,5 × 10 −9 + ( −2,8 × 10 −9 ) Q= = + 8,5 x 10-10 C  2 (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physical Sciences P1/Fisiese Wetenskappe V1 11 DBE/2012 NSC/NSS – Grade 10 Exemplar/Graad 10 Model – Memorandum 11.3 ∆ Q A = Q A (final/finaal) – Q A (initial/aanvanklik) = 8,5 x 10-10 – (-2,8 x 10-9)  = 3,65 x 10-9 C  OR/OF ∆ Q B = Q B (final/finaal) – Q B (initial/aanvanklik) = 8,5 x 10-10 – 4,5 x 10-9  = 3,65 x 10-9 C  3,65 × 10 −9 Number of electrons/Aantal elektrone =  1,6 × 10 −19 = 2,28 x 1010  (4) [10] QUESTION 12/VRAAG 12 12.1 1 1 1 = +  Rp R1 R 2 1 1 = +  2 2 ∴Rp = 1 Ω  (3) 12.2 12.2.1 6V (1) 12.2.2 4,5 V  (2) 12.3 POSITIVE MARKING FROM QUESTION 12.2.2. POSITIEWE NASIEN VAN VRAAG 12.2.2. Q = I∆t  = (2)(3)  =6C W V=  q W 4,5 =  6 ∴ W = 27 J  (5) 12.4 Increases/Vermeerder  (1) [12 GRAND TOTAL/GROOTTOTAAL: 150 Copyright reserved/Kopiereg voorbehou