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JAARLIKSE NASIONALE ASSESSERING 2014
GRAAD 4 WISKUNDE
MEMORANDUM
PUNTE: 50 Hierdie memorandum bestaan uit 5 bladsye.
Belangrike inligting:
1. Gee volpunte vir slegs antwoorde, tensy anders aangedui.
2. Aanvaar enige alternatiewe korrekte oplossing wat nie op die memorandum aangedui
word nie.
3. KA verwys na konsekwente akkuraatheid. Sien verduideliking by Vraag 7.1.
Vraag Verwagte Antwoord Verduideliking Punte
Totaal
Verdeling
1. 1.1 D 1
1.2 B 1
1.3 B 1
1.4 A 1 6
1.5 D 1
1.6 C 1
2. (32 + 25) + 16 = ( 25 + 16 )
1 1
3. 3.1 1 000 1
3.2
1 2
4. 7
1 1
5. <
1 1
6. 6.1 R20,00 R10,00 R5,00 R2,00 R1,00 50c 20c 10c
1
6.2 Kleingeld = R50,00 – R26,70
= R23,30 1 2
Graad 4 Wiskunde Memorandum 1
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2014 ANA Grade 4 Afrikaans Mathematics Memo.pdf
Mathematics · Grade 4 · ANA · 2014 · Afrikaans. Memorandum, 5 pages. Read online or download the PDF.
- Subject
- Mathematics
- Grade
- Grade 4
- Language
- Afrikaans
- Document type
- Memorandum
- Year
- 2014
- Exam period
- ANA
- Pages
- 5
- File size
- 197.7 KB
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7. 7.1 3 457 + 2 789 Metode: 1 punt
= 3 000 + 400 + 50 + 7 + 2 000 + 700 + 80 + 9 Antwoord: 1
= 3 000 + 2 000 + 400 + 700 + 50 + 80 + 7 + 9 punt
= 5 000 + 1 100 + 130 + 16 Pas KA toe
= 6 246
of
7+9 = 16
2
en 50 + 80 = 130
en 400 + 700 = 1 100
en 3 000 + 2 000 = 5 000
beteken 3 457 + 2 789 = 6 246
of
3 457 + 2 000 5 457 + 700 6 157 +80 6 237 + 9 6 246
of
3 457 + 9 3 466 + 80 3 546 + 700 4 246 + 2 000 6 246
7.2
7 874 – 3 785 Metode: 2
= 7 000 + 800 + 70 + 4 – 3 000 - 700 - 80 - 5 punte
= 7 000 - 3 000 + 800 – 700 + 70 – 80 + 4 – 5 Antwoord: 1
= 4 000 + 100 + 70-80 + 4- 5 punt
= 4 000 + 170 – 80 + 4 - 5 Pas KA toe
= 4 000 + 90 + 4 – 5
= 4 000 + 80 + 14 – 5
= 4 000 + 80 + 9
3
= 4 089
of
7 874 – 3 000 4 874 – 700 4 174 – 80 4 094 – 5
4 089
of
7 874 – 5 7 869 – 80 7 789 -700 7 089 -3 000 4 089
7.3 76 x 35 = 76 x 7x 5 of 76 x 35 = 76 x 5 x 7 Metode: 2
= 532 x 5 = 380 x 7 punte
= 2 660 = 2 660 Antwoord: 1
punt
of Pas KA toe
3
76 x 35 = 76 x (30 + 5) of 35 x ( 70 + 6)
= (76 x 30) + (76 x 5) = (35 x 70) + ( 35 x 6)
= 2 280 + 380 = 2 450 + 210
= 2 660 = 2 660
Graad 4 Wiskunde Memorandum 2
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7.4 852 ÷ 6 = ( 600 +240 + 12 ) ÷ 6 Metode : 2
= ( 600 ÷6 ) + ( 240 ÷6 ) + ( 12÷6) punte
= 100 + 40 + 2 Antwoord : 1
= 142 punt 11
of Pas KA toe
852 ÷ 6 = 852 ÷ 2 ÷ 3
= 426 ÷ 3
3
= 142
of
852 6 = 852 ÷ 3 ÷ 2
= 84 ÷ 2
= 142
8. 12 ÷ 3 = 8 ÷ 2
1
1
9. Die minuut-
wyser moet
wys na die 8.
Die uurwyser
moet tussen 9
en 10 wys. Die
uur- wyser
moet nader aan
tien wees.
1 1
10 10.1 C en D 1
2
10.2 6 uur 30 min. 1
11
Sy-aansig
1 1
12 Die simmetrie
. lyn hoef nie
getrek te word
nie.
A C
Aanvaar A of C
1 1
Graad 4 Wiskunde Memorandum 3
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13. 1, 5 m of 1 m
1 1
14. 36 uur
1 1
15.
12 +6 x3 54
1 1
16. 16.1 Aantal liters = 5 x 1
= 5 × (1 + ) 2
=5x1+5x
1
=5+2
=7 of 7,5
16.2 Aantal liters oor = 7,5 – 5
= 2,5 of 2 1
17. 17.1 Ja
1 1
17.2
1 1
18. 18.1
heksagoon
onreëlmatige 2 2
18.2 Vorm C is ‘n pentagoon.
2
Vorm B is ‘n trapesium. 2
19. 19.1
A.
1
2
19.2 5
1
2 Slegs
0. 10 1: 3+4+5=12 2: 5+6+7=18 3: 5+6+10=21 antwoord:
2 punte. 2 2
Graad 4 Wiskunde Memorandum 4
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21. 21.1 Papier
1
21.2 Glas en plastiek 1
21.3 2 1
4 of 2
1
21.4
Herwinningsmateriaal Telmerkies Frekwensie
Papier
30
Glas
2
15
Plastiek
15
5
TOTAAL: 50
Graad 4 Wiskunde Memorandum 5
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