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PREPARATORY EXAM I NATION
2416
MEMORANDUM
MATHEMATTCS (F|RST pApER) (10611)
15 pages
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Mathematics Grade 12 Paper 1 Gauteng Mock 2016 Memo
Grade 12 Mathematics Paper 1 memorandum from the Gauteng Mock Exam 2016, 15 pages. Read online or download the free PDF.
Mathematics · Grade 12 · Gauteng Mock Exam · 2016. Memorandum, 15 pages. Read online or download the PDF.
- Subject
- Mathematics
- Grade
- Grade 12
- Document type
- Memorandum
- Year
- 2016
- Exam period
- Gauteng Mock Exam
- Paper
- 1
- Curriculum
- CAPS
- Pages
- 15
- File size
- 1.8 MB
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1061 1/1 6
GAUTENG DEPARTMENT OF EDUCATION
PREPARATORY EXAMINATION
MATHEMATICS
(First Paper)
MEMORANDUM
QTTESTTON I
1.1 1. 1.1 3x3 + 5x=2
3x2 + 5x-2=0 / standard form
(:r-t)(r+2)=s / factors
I
x = 1...OR..x = -2 / both x values
J
(3)
L.t.z
J;n-r=x
J;n=x*l
x+7 =(x + tf { x+7:(x+l)2
x*l=x-+'2x+L
-a
/standard form
x2+x-6=0
(x +:)(x - 2)= o /factors
x=-3 OR x=2
N/A. /N/A
.Jt-./- { x=2
(s)
1.1.3 x' -8"r=10
/standard form
x' - 8x - 10:0
x: -brJu'-qac
2a
/substitution
x- -(-8) r - +(r[- ro)
2Q)
.[ = 9,1 OR x=-l.,1 / x :9,1
/x :-1,1
(4)
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1"t.4 3-t + 3-r*I.5 -8
3'*3-5-B
3'
32' - 9.3" + 15=0 /standard form
/lfactors
(r' - tXr' - :)= o
3'" =5 OR J =J
x=logr5 x=1 / x:l
x =1,46
/ x:log 5 ORx = 1,46
OR
Let 3* =k
&*3'5=8
k
y'substitute with
k2 -8k+15 =o
/standard forrn
(* -z)(r, - 5)= o y'factors
k=3 OR k=5
3* =3 3* =5
{ x:l
x=l x = log:5
/ x:log 5 OR x:1,46
x --1,46
(s)
1.2 22015 + 22013
71006
.+
/factors
Zrrrr{2, + t)
2"0r? / 2zotz
= z(s)
/answer
=10
(3)
t20l
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QUESTTON 2
2.1 kxl +Ix+1=0
L,= b2 - 4ac
=(k)' - +(r[r) /correct substitution rn
...= kz - 4k A
=t(t -+)
for non- realroots
a<0 / L<A
la and4
k(k - 4). o / inequality signs
:.a <k <4
gl
2.2 2**r = 4Y.... 2**' = 4Y.......1
x? +2y=3 xz + 2y =3......2
1x+l _ 17y 1.t+l _ e1?y
x +l=2y r + 1= 2y-........3 / simplify equation
x=2y-1.......3
Substitute in 2 Substitute tu 2
/ substitute
(zy -tY + 2y =3 xn +x+1=3
4y' -4y +1+ 21t - 3 = 0 x' + x -2=0
4y' -Zy -2=o (x+z)(x-l)=o
z{zy + t)(y - t)= o x=-2...OR...J=l / factors
Substilute in 3
...y--LoR
'2 v=t / both y values
-2+l-Zy...l+L=2y
Substitute in 3
,=-1.........v=l
"2
, =,f-1l - r...... x = z(r)- r
t2)
x= -2. .-..J = I lboth x values
OR
(s)
tel
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10611116
QUESTTON 3
3.r -8 -28 22
/ \to-/\=14/
\a ,/---.-4 ./
3.1.1 40 /answer
(1)
3.12 2a=4 3a+l=6 a+b+c:-8 /second difference :4
a=2 t(z)+b --o 2+c---8 / a=2
{b=0
b=0 c=-10 {c=-lO
=2n? -lO
"'7,
&\
3.2
3.2.1 a=5 / To=1AT.
To =107.,
a+5d:t0(a +2d) la + 5d =l}(a +2d)
5+5d:lo(5 +tul)
/simplification
5d -ZM = 50- 5
d=-3 /d=1
AI
3.2.2 s, =iP, + fu -lal / correct formula
/conect substitution
S.n =fft ttl+ (zo- rX-r)l
=-470 /answer
(3)
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.. /-\k
3.3 3.3.1
tr{ I )
t4'lt)
I \.'
= ./
r. 1. 1.
'2'4'
1 .l
rl y ---
2 2
e-a / correct substitution in,S*
-- l-r
I
I
t- ^
2
-2
(3)
3.3.2
.t,H.
).r. I
u2 L)
1
| --
2
*un-'(" -r)
r-L
/n=8
,[f1)' -,] /correct substitution in ,s,
=- [(2/ )
1-1 y'S,,=a
"<< 9B3.93
2
64
255
=-64 ..oR...3,99
(3)
3.3.3 ?55
64
t 63 y'answer
&
OR
=--127
64
OR
= - 1,98
(1)
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10611/16
3.4
le: tsl:
5)
n?:
u,t----
4 { d =- A'
5
5
Tn = ct + (n -tld
' rfl).
/correct substitution in
re + (n- o
't5,/ correct formula
AA
19--n+-<0 {7,<o
55
-4rr.-Lg! /inequality
55 y'answer
.24,75
44
.'.The 25th Tetm /conclusion
(6)
t2st
OUESTION 4
4.t P:4 / P=4
cl=2 { q:2
r(s;3) : y =++2
3=a+2
a=1 { a:l
(3)
4.2
&(-r) =
I +2 /answer
-x-4
OR
h(r)=* t')
(1)
4.3 y - - x + c........,{q;z)
/correct substitution of
z: -(+)+ c
@;2)
C:6 /answer
t6t
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QITESTI{}N 5
f{:,-} :ee" roug}r t}re Point {*4, rf,J
* "tr-*ft a /substitution
.l }#
fl:*:
t&u
l-
$"*
d /value of *
jift
\nJ
{4* t" /intercirange:r ancl Y
4!
t*I /equation
rtJ*46
/shnpe ./"
'rshap* l' '
*'asyrnptotes of br:th graPhs
1 t-rX
t4i
/ / \-
l+1
I.ri r.l
rit.r7- - -l i -_ II
t\i
\* /
Atrr:ut rhe line V ::.v
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QUESTTON 6
f
6.1
!=a{ /substitution (i; -4)
-4= a(L)z
-4=a ;x>0 lvalue of a
/equation
h(x)= 4*z
(3)
62 ! = -4xz
-9 = -4xz
9
"9 /simplification x2 =-
4 4
,=*{otr
lo \
x>o ..rll)'1:-91 /answer
I
/
(2)
vz-!'
Gradient of ST = !-
6_3
xz -Jt
- (-4) /substitution
=-91,5-l
/answer
= -10
(2\
6.4 /interchange x artdy
x = -4t-' ;y >-A
/restriction
-.: x
v ----
"4 y'the value of y'
t-..
II
v ='i- z
-1 l"\
t-
h'=-l-- /equation
\l4
(4)
6-5 /shape inverse
/point on inverse
/axis of symmetry
(s)
IT4I
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QUESTTON 7
7.1
l+0.164:lt*l=,..l
rrv,rw_L^, /correct substitution into
D) correct fonnulae
;
,"{troq - 11'nont
r, 12 /ld.:,rp
inon = 15,28o/o /answer
(3)
- r' 2 300 000
7.2
[(, - 9/2)" -,]
.Y) -, L( 4) l
{ n:32
0,r2
4 /answer
x = R43 807,22
(4)
7.3
7.3.1 A= P(r+ i)' r'substitution
( o.t+ts\'
A=Rr35000[. o
) / A: ft138 339,15
I = .R138 339,15
(2)
7.3.2
/correct formula (P)
-[,.T) '-] /correct substitution
{n=L8
aJ475
12
/answer
x = R8 613"99
(4)
l13l
{o
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10611/16
QUESTTON 8
8.1
.f(x)=4-3x?
f(x+h)=4-3(x+h)z /simplification of
=4-3x? -6xh-3hz .f(x+h)
f (x) /formula
J,,$) _r*"f(x+h)-
Ir+0 h
= lim
(4 - 3x2 - 6xh - 3h2 ) - (+ - 3x2)
h-+A
- 6xh-3hz /simplific ation - 6xh th?
= lim
h-+O h
h(-6x -3h)
= lim /common factor
i-+0
= lim(-6.r- 3i)
= -6x / answer-6x
{5)
8.2.t { 4x3
o.l *' -2* * 11 /-2
L J-J
/ -z)i-l
=4x3 -2-2x-3
(3)
8.2.2
1r:-
2x-3
Vx
1_1 /simplification
=2xa -3x a
dv 3+ 3-: /both values of derivatives
dx2 4
(2\
8.3
-f(x):x'-7x' { f'{x)
f'(x):3x2 -l4x
f'(x) =5 / J-'k) = s
3x2 -L4x = 5
3x2 -14x-5=0
/factors
(:x + t)(x - 5): o
*=-1 oR J
x=5 /both answers
NOTE
NO PENALTY IF
CANDIDATE COMMITS
AN ERROR IN WRITING
AN ANSWER WITH
POSITIVE EXPONENTS.
(41
It4t
11
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QUESTTON e
9.1 /y-intercept
/y-intercept
/shape
(3)
9.2 J'$)=a(x+?Xx-1){x-6) /corect f,ormulae
/substitution
12= alo + \{a - 1}t0 - 6)
{ a:L
c=l
.', .f(x) = (r + ?X, - 1)(.:r - 6) /expansion
=.r3-5x2-8x+12
(4)
9.3 f'(x) = o /equating to zero
.'.3x?-10x-8=0 /factors
(3x+2){x-4J=0
y'ansrvers.x
*:-Z3 oR r=4
/ansrvers y
,,-ooo oR v=-i6
"27
rurningpoints ** f- ,A ,#) AND (a; --36) r'TPs
(s)
9.4 2 /answer
---<x<4
3
(r)
9.5 l'" t-*1: 6x - 1o /second derivative
6x-10>0 /6x-10>0
jf>- 5 /ansrver
30
(3)
II6I
12
Downloaded from hlayiso.com t CIst 1116
*ITESTION le
f
ff
Y
4s
10 I Fl .= 128
/substirution
4.u-.r.lr = 128
.ft---- l?8 /ansrver
4-r-
f2'!
t{}"2 = 4..t:..r+ Zxh+&xh
/fonnula
=,,$yi 110rft
aa
'I otal surf*ce &rea /siniplilication
= 4xz + 10x.{
x-
. ?i 320
,il.v' y'answer
-
-- x
{s}
/ trn\
Dxl 4x'* --- l = 0
1*"3
t .rl
^ ,320 /derivative
6J ---- ::::: U
--r'' /equate lo zero
{3x'*320=*
8x3 =32*
32!
''t = x /sirnplific.ati*n
'11EoI
1. = r i_
1"=ffi
*.- - e..li
ri,r
/ answer
t?
"l;
Fleight: : :2,74
1' 1\-
l"-'
tk{
I
\ )/
{4}
I9t
13
Downloaded from hlayiso.com 10611I16
QI]ESTION 11
11"1 Let S represert the participants for swinrming; G represent the gynuastics ,/6
participants and A for the athletics parlicipants. /21-x
/14-x
/ all other
values in the
Venn diagram
correct
(CA }
AI
n.2 2l- x+x + l4-.r+ 9+14+ 1 0+ 6+ I I = B0 y'equation
85-x = 8O
/answer
-r=5
0\
I 1.3 5+14+10+9 u'equation
P (Particip*nts in at least 2 events) 80 /clivision by 80
/answer
= 4,47 5
(s)
tel
14
Downloaded from hlayiso.com 10611116
QUESTION 12
9! = 362 880
of the answer
/gt.
rzfiz { 5t,
/aRswer
=3024
OR
!.x 84Jx,6. 9x8x7x6
:3 024 /answer
{5
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