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PREPARATORY EXAMINATION
VOORBEREIDENDE EKSAMEN
GRADE/GRAAD 12
PHYSICAL SCIENCE: PHYSICS (P1)
FISIESE WETENSKAPPE: FISIKA (V1)
SEPTEMBER 2020
MARKS/PUNTE: 150
MARKING GUIDELINES
NASIENRIGLYNE
These marking guidelines consist of 18 pages.
Hierdie nasienriglyne bestaan uit 18 bladsye.
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Physical Sciences Grade 12 Free State Mock 2020 Memo
Grade 12 Physical Sciences memorandum from the Free State Mock Exam 2020, 18 pages. Read online or download the free PDF.
Physical Sciences · Grade 12 · Free State Mock Exam · 2020. Memorandum, 18 pages. Read online or download the PDF.
- Subject
- Physical Sciences
- Grade
- Grade 12
- Document type
- Memorandum
- Year
- 2020
- Exam period
- Free State Mock Exam
- Curriculum
- CAPS
- Pages
- 18
- File size
- 1.2 MB
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Physical Sciences P1/Fisiese Wetenskappe V1 2 FS/VS/September 2020
Grade 12 Prep. Exam./Graad 12 Prep. Eksam.
Marking Guidelines/Nasienriglyne
QUESTION/VRAAG 1
1.1 A (2)
1.2 B (2)
1.3 C (2)
1.4 D (2)
1.5 C (2)
1.6 B (2)
1.7 B (2)
1.8 B (2)
1.9 C (2)
1.10 B (2)
[20]
QUESTION/VRAAG 2
2.1.1 When a resultant/net force acts on an object, the object will accelerate
in the direction of the force at an acceleration directly proportional to the
force and inversely proportional to the mass of the object.
Wanneer 'n resulterende krag/netto krag op 'n voorwerp inwerk, sal die
voorwerp in die rigting van die krag versnel wat direk eweredig is aan die
krag en omgekeerd eweredig aan die massa van die voorwerp.
OR/OF
The net or resultant force acting on an object is equal to the rate of change
of momentum of the object in the direction of the net force. (2 or 0)
Die netto/resulterende krag wat op 'n voorwerp inwerk, is gelyk aan die
tempo van die verandering van momentum van die voorwerp in die rigting
van die netto krag. (2)
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Physical Sciences P1/Fisiese Wetenskappe V1 3 FS/VS/September 2020
Grade 12 Prep. Exam./Graad 12 Prep. Eksam.
Marking Guidelines/Nasienriglyne
2.1.2 F
Fg
T (3)
Accept the following symbols/Aanvaar die volgende simbole
F Fapplied /Force applied/ Toegepaste krag/FA
Fg w / Fw / weight /gewig
T FT / Tension/Spanning
NOTE/LET WEL:
Mark awarded for label and arrow./Punt word toegeken vir byskrif
en pyltjie.
Do not penalise for length of arrow since drawing is not to scale.
Moenie vir die lengte van pyltjies penalseer nie omdat diagram nie
volgens skaal geteken is nie.
Any additional force(s)./Enige addisionele krag(te): 32
If force(s) do not make contact with body./Indien krag(te) nie met die
voorwerp kontak maak nie: 32
No labels/Geen byskrifte: 03
2.1.3 Option/Opsie 1 Option/Opsie 2
fk kN
k mg
0,3 5 9,8
14,7 N
N
(3)
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Physical Sciences P1/Fisiese Wetenskappe V1 4 FS/VS/September 2020
Grade 12 Prep. Exam./Graad 12 Prep. Eksam.
Marking Guidelines/Nasienriglyne
2.1.4 POSITIVE MARKING FROM 2.1.3/POSITIEWE NASIEN VANAF 2.1.3
Option/Opsie 1
Direction of motion as positive/Rigting van beweging as positief
Notes/Aantekeninge:
Formula/Formule
Substitution for forces/
Vervanging van kragte
Substitution for both
masses/Vervanging vir beide
massas
Equating Tension forces/
Vergelyk spanningskragte
Answer with units/Antwoord
met eenhede
N
N
(6)
Option/Opsie 2
Direction of motion as negative/Bewegingsrigting as negatief
N
N
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Physical Sciences P1/Fisiese Wetenskappe V1 5 FS/VS/September 2020
Grade 12 Prep. Exam./Graad 12 Prep. Eksam.
Marking Guidelines/Nasienriglyne
2.2.1 Each body in the universe attracts every other body with a force that
is directly proportional to the product of their masses and inversely
proportional to the square of the distance between their centres. (2)
Elke liggaam in die heelal trek elke ander liggaam aan met 'n krag wat
direk eweredig is aan die produk van hul massas en omgekeerd eweredig
is aan die kwadraat van die afstand tussen hul middelpunte.
2.2.2 Fplanet/planeet = 1 Fearth/aarde
2
Notes/Aantekeninge:
G Mm2Me
(X)2 Formula of Gravitational law
applied for each object.
Formule van Gravitasiewet
wat vir elke voorwerp
toegepas word.
Relationship between Fplanet
and Fearth.
Verhouding tussen Fplaneet en
Faarde
Answer/Antwoord (4)
[20]
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Physical Sciences P1/Fisiese Wetenskappe V1 6 FS/VS/September 2020
Grade 12 Prep. Exam./Graad 12 Prep. Eksam.
Marking Guidelines/Nasienriglyne
QUESTION/VRAAG 3
3.1 Motion of an object under the influence of gravity/gravitational force/weight
only. (2 or 0)
Beweging van 'n voorwerp slegs onder die invloed van gravitasie/
gravitasiekrag/gewig.
OR/OF
Motion in which the only force acting on the object is gravity/gravitational
force/weight.
Beweging waartydens die enigste krag wat inwerk gravitasie/gravitasie-
krag/gewig is.
ACCEPT/AANVAAR
An object that is launched (or synonyms) with an initial velocity under
the influence of the force of gravity only.
'n Voorwerp wat gegooi (of sinonieme) word met 'n aanvanklike snelheid
onder die invloed van slegs gravitasiekrag. (2)
3.2 Newton's First Law/Newton se Eerste Wet
A body will remain in its state of rest or motion at a constant velocity
unless a non-zero net/resultant force acts on it.
'n Voorwerp sal in sy posisie van rus of beweging bly teen 'n konstante
snelheid tensy 'n nie-nul netto/resulterende krag daarop inwerk. (3)
3.3.1 OPTION/OPSIE 1 + Positive/Positief OPTION/OPSIE 2 - Negative/Negatief
Height/ = 13,06 + (2500)
Height/Hoogte Hoogte
m = 2513,06 m
(4)
3.3.2 Option/Opsie 1 Option/Opsie 2
Whole motion Positive Whole motion Negative
Algehele beweging Positief Algehele beweging Negatief
y v i t 21 at 2
16(15) 21 ( 9,8)(15)2
862,5
height 2500 862,5
Height/Hoogte
Height/ = 2500 – 862,5
1637,5 m Hoogte
= 1637,5 m
(5)
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Grade 12 Prep. Exam./Graad 12 Prep. Eksam.
Marking Guidelines/Nasienriglyne
Option/Opsie 3 Option/Opsie 4
Motion from the maximum Motion from the maximum
height. Positive height. Negative
Beweging vanaf die maksimum Beweging vanaf die maksimum
hoogte. Positief hoogte. Negatief
Vf = vi + g∆t Vf = vi + g∆t
0 = 16 − 9,8∆t 0 = 16 − 9,8∆t
∆t = 1,63 s ∆t = 1,63 s
= − 875,56
Height/Hoogte
Height/Hoogte = 2513,06 – 875,56
= 1637,5 m = 1637,5 m
Option/Opsie 5 Option/Opsie 6
Motion point of projection Motion point of projection
down. Positive down. Negative
Bewegingspunt van afwaartse Bewegingspunt van afwaartse
projeksie. Positief projeksie. Negatief
Vf = vi + g∆t Vf = vi + g∆t
O = 16 − 9,8∆t O = 16 − 9,8∆t
∆t = 1,63 s ∆t = 1,63 s
= − 862,5 = − 862,5
Height/Hoogte = 2500 – 862,5 Height/Hoogte = 2500 – 862,5
= 1637,5 m
m = 1637,5 m
RANGE/GEBIED: 1637,5 – 1638,1 m
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Physical Sciences P1/Fisiese Wetenskappe V1 8 FS/VS/September 2020
Grade 12 Prep. Exam./Graad 12 Prep. Eksam.
Marking Guidelines/Nasienriglyne
3.3.3 OPTION/OPSIE 1 OPTION/OPSIE 2
Whole motion + Whole motion -
Algehele beweging Algehele beweging
Note: For options 3 and 4 use any of the equations of motion containing ∆t to
calculate ∆t and substitute into equation of ∆y = vi∆t + ½g∆t2.
Aantekening: Vir opsies 3 en 4, gebruik enige van die bewegingsvergelykings
wat ∆t bevat om ∆t te bereken en vervang in vergelyking van
∆y = vi∆t + ½g∆t2.
1) vf = vi + g∆t ∆t = 1,633 s
2) ∆y = 13,061 m; Max height/Maks hoogte =
2513,06 m
3) ∆y = 13,061 m; Max height/Maks hoogte =
2513,06 m
OPTION/OPSIE 3 OPTION/OPSIE 4
Motion from maximum height + Motion from maximum height -
Beweging vanaf maksimum Beweging vanaf maksimum
hoogte hoogte
s s
(4)
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Physical Sciences P1/Fisiese Wetenskappe V1 9 FS/VS/September 2020
Grade 12 Prep. Exam./Graad 12 Prep. Eksam.
Marking Guidelines/Nasienriglyne
3.4 POSITIVE MARKING FROM 3.3.3/POSITIEWE NASIEN VANAF 3.3.3
Take Ground as zero position/Neem grond as zero-posisie
Upward motion as positive./Opwaartse beweging as positief.
2 513,06
Position/ 2 500
Posisie (m)
0 Time/Tyd (s)
3,26 24,28
Upwards motion negative/
Opwaartse negatiewe beweging
3,26 24,28
0 Time/Tyd (s)
Position/
Posisie (m) -2 500
-2 513,06
Marking criteria/Nasienriglyne
Graph with correct shape, starts at 2 500 and
ends on x axis at tf (24,28 s).
Grafiek met korrekte vorm begin by 2 500 en
eindig op x-as by tf (24,28 s).
Maximum height/Maksimum hoogte (2513,06)
Time of/Tyd van 24,28
(3)
[21]
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Physical Sciences P1/Fisiese Wetenskappe V1 10 FS/VS/September 2020
Grade 12 Prep. Exam./Graad 12 Prep. Eksam.
Marking Guidelines/Nasienriglyne
QUESTION/VRAAG 4
4.1 When object A exerts a force on object B, object B will simultaneously
exert an oppositely directed force of equal magnitude on object A. (2 or 0)
Wanneer voorwerp A 'n krag op B uitoefen, sal voorwerp B terselfdertyd
'n krag in die teenoorgestelde rigting, van gelyke grootte op voorwerp A
uitoefen. (2)
4.2 Equal in magnitude and opposite in direction.
Gelyk in grootte en rigting is teenoorgesteld. (2)
4.3
Motion to the left/Beweging na links (+)
ΣPf = ΣPi
(mB + mG)viBG = mBvfB + mGvfG Any/Enige
(80 + 50)(4) = 80(8) + 50vfG
vfG = 2,40 m·s-1 to the right/backwards
na regs/terugwaarts (4)
Motion to the left/Beweging na links (-)
ΣPf = ΣPi
(mB + mG)viBG = mBvfB + mGvfG
(80 + 50)(–4)= 80(–8) + 50vfG
vfG = 2,40 m·s-1 to the right/backwards
na regs/terugwaarts
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Physical Sciences P1/Fisiese Wetenskappe V1 11 FS/VS/September 2020
Grade 12 Prep. Exam./Graad 12 Prep. Eksam.
Marking Guidelines/Nasienriglyne
4.4 OPTION/OPSIE 1:
OPTION/OPSIE 2:
Motion to left//Beweging na links +
Motion to right/Beweging na regs (+)
Fnet∆t = ∆p (boy/seun)
Fnet∆t = ∆p(boy/seun)
= m(vfB – viB) Any/Enige Any/Enige
= m(vfB – viB)
= 80(8 – 4)
= 80(– 8 – (–4))
= 320 N·s to the left/na links
= –320
= 320 N·s to the left/na links
OR/OF
OR/OF
POSITIVE MARKING FROM 4.3/
POSITIEWE NASIEN VANAF 4.3
POSITIVE MARKING FROM 4.3/
POSITIEWE NASIEN VANAF 4.3
Fnet∆t = ∆p(girl/dogter)
= m(vfB – viB) Any/Enige Fnet∆t = ∆p(girl/dogter)
Any/Enige
= 50(– 2,4 – 4) = –320 = m(vfB – viB)
= 320 N·s to the right/ = 50(2,4 – (–4))
na regs
= 320 N·s to the right/na regs
Fnet∆t (boy/seun) = 320 N·s to the Fnet∆t (boy/seun) = 320 N·s to the
left/na links left/na links
(4)
[12]
QUESTION/VRAAG 5
5.1 A force for which the work done in moving an object between two points
is dependent of the path taken. (2 or 0)
'n Krag waarvoor die arbeid wat verrig is om 'n voorwerp tussen twee
punte te beweeg, afhanklik is van die pad wat gevolg word. (2)
5.2 Frictional (force)/Wrywing (krag) (1)
5.3 Option/Opsie 1
(U + K)i = (U + K)f
mghi + ½mv2i = mghf +m ½mv2 f Any/Enige
(38)(9,8)(0,75) + ½ 38(1,5)2 = 9,8(0) + ½ 38v2f
vf = 4,12 m·s-1 (4)
Option/Opsie 2
Any/Enige
m·s-1
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Grade 12 Prep. Exam./Graad 12 Prep. Eksam.
Marking Guidelines/Nasienriglyne
5.4
Any/Enige
N (4)
5.5 POSITIVE MARKING 5.3 AND 5.4/POSITIEWE NASIEN 5.3 EN 5.4
Option/Opsie 1
Wnet K
Wf Wfg 21 m(v 2f v i2 ) Any/Enige
fk x cos mgsin x cos 21 m(v 2f v i2 )
77,016x cos180 38x9,8 sin10x cos0 21 (38)(0 4,122 )
12,35x 322,514
x 26,11
h
sin10
x
h
26,11
h 4,535 m
(6)
[17]
QUESTION/VRAAG 6
6.1 It is the (apparent) change in frequency (or pitch) of the sound (detected
by a listener) because the sound source and the listener have different
velocities relative to the medium of sound propagation.
Dit is die (waarskynlike) verandering in frekwensie (of toonhoogte) van die
klank (soos waageneem deur 'n luisteraar) omdat die bron van die klankgolf
en die waarnemer verskillende snelhede het relatief tot die medium van
klankvoortplanting. (2)
OR/OF
An (apparent) change in (observed/detected) frequency (pitch),
(wavelength) as a result of the relative motion between a source and
an observer (listener).
'n (Waarskynlike) verandering in (waargenome) frekwensie (toonhoogte),
(golflengte) as 'n gevolg van die relatiewe beweging tussen die bron en die
waarnemer (luisteraar).
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Physical Sciences P1/Fisiese Wetenskappe V1 13 FS/VS/September 2020
Grade 12 Prep. Exam./Graad 12 Prep. Eksam.
Marking Guidelines/Nasienriglyne
6.2
Hz (3)
6.3 POSITIVE MARKING FROM 6.2/POSITIEWE NASIEN VANAF 6.2
f=1 f = waves/golwe
T OR/OF Time/tyd
1 2
= 8 x 10-4 = 16 x 10-4
= 1250 Hz
v±v v
fL= (v ± vL ) fs OR/OF fL = (v − v ) fs
S S
340
1250 = ( ) 1133,33
340 − vS
(7)
vs = 31,73 m·s-1
[12]
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Physical Sciences P1/Fisiese Wetenskappe V1 14 FS/VS/September 2020
Grade 12 Prep. Exam./Graad 12 Prep. Eksam.
Marking Guidelines/Nasienriglyne
QUESTION/VRAAG 7
7.1 The electrostatic force of attraction or repulsion between two point charges
is directly proportional to the product (of the magnitudes) of the charges
and inversely proportional to the square of the distance between them.
Die elektrostatiese aantrekkingskrag of afstootkrag tussen twee puntladings
is direk ewereding aan die produk (van die groottes) van die ladings en
omgekeerd eweredig aan die kwadraat van die afstand tussen hulle. (2)
NOTE/LET WEL:
-1 for every key word/phrase omitted. If masses used instead of charges, 0/2.
-1 vir elke sleutelwoord/frase wat uitgelaat is. Indien massas en nie ladings
gebruik word nie, 0/2.
7.2
Marking criteria/Nasienkriteria
Correct direction away from the +
sphere/Korrekte rigting weg van die +
sfeer
Shape of the electric field/Vorm van die
elektriese veld
Field lines starting on the sphere and
not crossing/Veldlyne begin op die
sfeer en kruis nie (3)
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Physical Sciences P1/Fisiese Wetenskappe V1 15 FS/VS/September 2020
Grade 12 Prep. Exam./Graad 12 Prep. Eksam.
Marking Guidelines/Nasienriglyne
7.3
kQ Q
F 1 2
r2
9 6
1 2 9 10 (6 10 )z
kQ Q
F
(30 102 )2
13
r2
6 105 z
kQ Q 9 6
F 2 3 9 10 (3 10 )z
(10 102 )2
23
r2
27 105 z
F2 F2 F2
net 13 23
2
(13,83) (6 105 z)2 (27 105 z)2
(5)
z 55x10 6CC
10–6
7.4 The electric field at a point is the (electrostatic) force experienced per unit
positive charge placed at that point.
Die elektriese veld op 'n punt is die (elektrostatiese) krag wat ervaar word
per eenheid positiewe lading wat op daardie punt geplaas word. (2)
NOTE/LET WEL:
- 1 for every key word omitted.
- 1 vir elke sleutelwoord wat uitgelaat is.
7.5 ENET = FNET
q
= 13,83
5 x 10-6
= 2,77 x 10-6 N.C-1 (3)
[15]
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Grade 12 Prep. Exam./Graad 12 Prep. Eksam.
Marking Guidelines/Nasienriglyne
QUESTION/VRAAG 8
8.1 Potential difference across a conductor is directly proportional to the
current in the conducter provided the temperature is constant.
Potensiaalverskil oor 'n geleier is direk eweredig aan die stroom in die
geleier mits die temperatuur konstant is. (2)
8.2 Emf of the battery/Emk van die battery (1)
8.3.1 Option/Opsie 1 Option/Opsie 2
(3)
A
A
8.3.2 Option/Opsie 1 Option/Opsie 2
Vlost = Ir Emf/Emk = IR + Ir
(4)
3,25 = I(1) 38,25 = 35 + I(1)
I = 3,25 A I = 3,25 A
8.3.3 POSITIVE MARKING FROM 8.3.1 & 8.3.2
POSITIEWE NASIEN VANAF 8.3.1 & 8.3.2
Option/Opsie 1 Option/Opsie 2 Option/Opsie 3
(7)
Ω
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Grade 12 Prep. Exam./Graad 12 Prep. Eksam.
Marking Guidelines/Nasienriglyne
8.4 Increase
Total resistance in circuit increase and the total current decrease.
Vinternal will decrease.
Therefore: Vexternal will increase (because emf stays constant).
Toeneem
Totale weerstand in stroombaan neem toe en die totale stroom neem af.
Vintern sal afneem.
Daarom: Vekstern sal toeneem (omdat emk konstant bly). (4)
[21]
QUESTION/VRAAG 9
9.1 Generators: Electromagnetic induction
Generators: Elektromagnetiese induksie (1)
9.2 A
Split ring commutator/Spleetring kommutator (2)
9.3.1 The rms voltage of AC is the DC potential difference which dissipates
the same amount of energy as AC.
Die wgk spanning van WS is die GS-potensiaalverskil wat dieselfde
hoeveelheid energie as WS verbruik. (2)
9.3.2
V (3)
9.3.3 Increase/Neem toe (1)
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Physical Sciences P1/Fisiese Wetenskappe V1 18 FS/VS/September 2020
Grade 12 Prep. Exam./Graad 12 Prep. Eksam.
Marking Guidelines/Nasienriglyne
9.4 Graph of voltage versus time/Spanning-teenoor-tydgrafiek
311,13
+Vmax
Potential difference (V)
Potensiaalverskil (V)
0
Time/Tyd (s)
-311,13
-Vmax
(3)
Marking criteria/Nasienkriteria
Shape – sinusoidal curves
Vorm – sinusvormige krommes
Peak value/Piek waarde
One cycle/Een siklus
[12]
TOTAL/TOTAAL: 150
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