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ANNUAL NATIONAL ASSESSMENTS 2013
GRADE 6 MATHEMATICS
MEMORANDUM
MARKS: 75
This memorandum consists of 4 pages.
General marking note:
1. Give full marks for answers only, unless otherwise stated.
2. Accept any alternative correct solution that is not included in the memorandum.
3. CA refers to consistent accuracy. See clarification at 5.7.
QUESTION EXPECTED ANSWER CLARIFICATION MARK TOTAL
1 1.1 B / 29 ✓ 1
1.2 C / 9,11 ✓ 1
1.3 D / 5,6 ✓ 1
1.4 A/6 ✓ 1
1.5 C / 40 ✓ 1
1.6 A / 300 000 ✓ 1
1.7 D / 27 ✓ 1
1.8 B / 325 ✓ 1
1.9 B/ ✓ 1
1.10 B ✓ 1 10
2 342 650 798 ✓ All digits must be
correct 1
3 31 ✓ 1
4 40 000 000 ✓ The following
answers are also
acceptable.
40 M; forty million
4 TM
40 x 1 000 000 1
5 5.1 43 489 All digits must be
345 987 correct.
+ 307 Answer only, all
389 783 digits correct, full
✓ ✓ marks.
783 ✓
389 ✓
Apply CA 2
5.2 495 089 All digits must be
− 85 847 correct.
409 242 Answer only - all
✓ ✓ digits correct, full
marks.
242 ✓
409 ✓
Apply CA
2
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ANATest+Grade+6+Mathematics+2013+Memo+Eng
Mathematics · Grade 6 · ANA · 2013. Memorandum, 4 pages. Read online or download the PDF.
- Subject
- Mathematics
- Grade
- Grade 6
- Document type
- Memorandum
- Year
- 2013
- Exam period
- ANA
- Pages
- 4
- File size
- 237.5 KB
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QUESTION EXPECTED ANSWER CLARIFICATION MARK TOTAL
5.3 3 097 Accept any method
× 249 that is
27 873 ✓ mathematically
123 880 ✓ correct.
619 400 ✓ Apply CA.
771 153 ✓
4
5.4 109 ✓
36 3 924
− 36 ✓
324
− 324 ✓
000
3
5.5 1 3 7 ✓
4 +3
8 8 4
✓
8
4 1
7 ✓✓ or 7 ✓✓
8 2 1
7 is also
2
acceptable, but no
extra mark is
awarded for
simplifying. 2
5.6 20% of 400 Answer only - all
correct, full marks.
20 1
= ✓ × 400 or x 400 ✓
100 5 Apply CA
= 80 ✓ = 80 ✓
2
5.7 7,83 + 5,39 − 4,86 X
13,57 – 4,86
= 13,22 ✓ − 4,86 = 8,71.
= 8,36 0,71 ✓
8✓
✓✓
Award two marks for
CA. 3 18
6 3 ✓ 1
7 4 ✓ 1
8 Change = R100 – (R65,81 + R18,23) Apply CA.
= R100 – R84,04 ✓
= R15,96 ✓
or
Change = R100 – R65,81 – R18,23
= R34,19 – R18,23 ✓ 2
Grade 6 English Mathematics Memorandum 2
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QUESTION EXPECTED ANSWER CLARIFICATION MARK TOTAL
= R15,96 ✓
9 614 ✓ 1
10 No ✓ 1
11 Number of busses 12 r 5 ✓ Apply CA.
= 785 ÷ 65 ✓ or 65 785
= 12 rem 5 ✓ − 65
135 ✓
− 130
5
Number of busses needed = 13 ✓ 3
12 Decimal Fraction = 0,2 ✓
Percentage = 75% ✓
Common Fraction = ✓
3
13 0,42 4,24 42,4 ✓ 1
14 31 ✓ 4 x 8 = 32
32 – 1 = 31 1
15 Replace A with 10 ✓
Replace B with 2 ✓ 2
16 14 ✓✓ 1 x 1 square 9
2 x 2 squares 4
3 x 3 squares 1
9 + 4 + 1 = 14
If answer from 9 to
13 give 1 mark. ✓ 2
17 17.1 Obtuse angle ✓ 1
17.2 Right angle ✓ 1 2
18 Stack number 1 2 3 4 6 8 ✓
No. of cans 1 4 9 16 36 ✓ 64
2
19 No of vertices: 4 ✓
No of edges: 12 ✓
No of faces: 4 ✓ 3
20
✓
1
Grade 6 English Mathematics Memorandum 3
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QUESTION EXPECTED ANSWER CLARIFICATION MARK TOTAL
21 length = 4 ✓
breadth = 2 ✓
✓
✓ or
2
22 22.1 4 hours ✓ 1
22.2 15:00 or 3.00 p.m. ✓ 11 + 4 = 15
Apply CA 1 2
23 23.1 3 000 l ✓ 1
23.2 0,435 ✓ 1 2
24 R18, 95 x 2 = R37, 90 ✓ Apply CA.
or
R36,95 ÷ 2 = R 18,475 ✓
Thus, 5 kg at R36,95 is a better buy. ✓ 2
25 Difference = 37 °C – 28 °C = 9 ºC ✓ 1
26 Perimeter = 12 x 1,5 + 6 x 1,5 ✓ 3 x 1,5 = 4,5
= 18 + 9 6 x 1,5 = 9 ✓
= 27 ✓ 13,5 x 2 = 27 ✓
Apply CA. 2
27 27.1 Bike riding. ✓ 1
27.2 Difference in time spent = 80 h – 10 h
= 70 h ✓ 1 2
28 25 ✓ 1
29 Parallelogram ✓ Answer must be at
Hexagon ✓ correct place. 2
30 30.1 32 ✓ 8 x 4 = 32 1
30.2 3 clouds. Any
✓
drawing with 3
clouds. 1 2
TOTAL: 75
Grade 6 English Mathematics Memorandum 4
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