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JAARLIKSE NASIONALE ASSESSERING 2014
GRAAD 6 WISKUNDE
MEMORANDUM
PUNTE: 75
Hierdie memorandum bestaan uit 4 bladsye.
Algemene notas vir nasien:
1. Gee volpunte vir slegs antwoorde, tensy anders gespesifiseer.
2. Aanvaar enige korrekte alternatiewe antwoord, wat nie op die memorandum aangedui word
nie.
3. KA verwys na konsekwente akkuraatheid. Sien Vraag 4.3 as voorbeeld.
VRAAG VERWAGTE ANTWOORDE VERDUIDELIKENDE PUNTE TOTAAL
NOTAS
1 1.1 D ✓ 1
1.2 B ✓ 1
1.3 A ✓ 1
1.4 D ✓ 1
1.5 D ✓ 1
1.6 B ✓ 1
1.7 A ✓ 1
1.8 C ✓ 1
1.9 B ✓ 1
1.10 D ✓ 1 10
2 4 × 10 000 of 40 000 of 4 x 104 Enige van die gegewe
of veertig duisend ✓ opsies : 1 punt
1
3 60 000 ✓ 60 000: 1 punt
1
4 4.1 42 152 Indien die ene, Alle syfers korrek
28 945 tiene en 147 458: 2 punte
+76 361 honderde Syfers 458: 1 punt
syfers reg
147 458 Syfers 147: 1 punt
opgetel is,
✓ ✓ word een punt
gegee as die
antwoord
verkeerd is. 2
4.2 87 546 Indien die ene, Alle syfers korrek.
43 968 tiene en 43 578: 2 punte
honderde Syfers 578: 1 punt
43 578
syfers reg
✓ ✓ Syfers 43: 1 punt
afgetrek is
word een punt
gegee as die
antwoord 2
verkeerd is.
Graad 6 Wiskunde Memo 1
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2014 ANA Grade 6 Afrikaans Mathematics Memo.pdf
Mathematics · Grade 6 · ANA · 2014 · Afrikaans. Memorandum, 4 pages. Read online or download the PDF.
- Subject
- Mathematics
- Grade
- Grade 6
- Language
- Afrikaans
- Document type
- Memorandum
- Year
- 2014
- Exam period
- ANA
- Pages
- 4
- File size
- 243.0 KB
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4.3 3 107 of of Slegs antwoord: 3
3 107 x 7 x 5 3 107 x 5 x 7
x 35 =21 749 x 5 =15 535 x 7 punte
15 535 ✓ =108 745 =108 745 3107 x 5 =15 535:
93 210 ✓ 1 punt
108 745 ✓ 3107 x 30 =93 210:
1 punt
Voorbeeld van KA 15 535 + 93 210 =
3 107 3 107 108 745: 1 punt
x 35 x 35
12 532 x (verkeerd geen punt) 12 532 x (verkeerd geen punt)
93 210 ✓ 83 210 x (verkeerd geen punt)
105 742 ✓ (korrek opgetel) 95 742 ✓(korrek opgetel) 3
4.4 476 ✓ of Of Antwoord : 3 punte
7 140 ÷ 15 7 140 ÷ 15
15 7140 = 7 140 ÷ 5 ÷ 3 = 7 140 ÷ 3 ÷ 5 60: 1 punt 105: 1 punt
= 1 428 ÷ 3 = 2 380 ÷ 5 Pas KA toe.
60 ✓ = 476 = 476
114
105 ✓
90
90 3
4.5 3 1 3 1 Antwoord: 2 punte
4 +2 of 4 +2
8 8 8 8 6: 1 punt
4
: 1 punt
3 1 35 17 8
=4+ +2+ = + ✓
8 8 8 8 1
6 : 2 punte
2
4 52
=6+ ✓✓ = ✓
8 8
2
1 1
=6 =6
2 2
4 2 52
Moet nie penaliseer 6 of 6 of ✓✓
8 4 8
4.6 2 2 120: 2 punte
van 300 of van 300
5 5 Bewerking: 1 punt
= 300 ÷ 5 ×2 ✓ = 2 x 60 ✓(want 300 ÷ 5 = 60)
= 120 ✓ = 120 ✓
2
Graad 6 Wiskunde Memo 2
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4.7 3 1 3 1 Antwoord: 2 punte
5 –2 of 5 –2
5 5 5 5 3: 1 punt
2 3 1 2
=3 ✓✓ =5+ 2 : 1 punt
5 5 5 5
3 1
=5 2+
5 5
2 17
= 3 of ✓✓
5 5
2
4.8 59,3 of 59,3 25,8 = 33,5 ✓✓ 33,5 : 2 punte
25,8 33 : 1 punt
33,5 ✓✓ 0,5 : 1 punt
18
2
5 14 ÷ 2 = 7; 51 – 48 =3 ; 7 + 3 =10 ✓ 10 : 1 punt 1
6 4,01 , 4,3 , 4,5 , 4,8✓ 1 punt : korrekte
volgende 1
7 28, 35, 42, 49 ✓ 28, 35, 42, 49
1 punt 1
8 Aantal pakkies = 947 ÷ 8 ✓ 118: 3 punte
= 118 r 3 ✓ 947 ÷ 8: 1 punt
118 r 3: 1 punt
11 8 r 3 ✓
8 947 ✓
8
14
8
67
64
∴ Aantal pakkies benodig = 118 ✓ 3
9 336 ✓ 336 : 1 punt 1
10 10.1 75% ✓ 75%: 1 punt 1
10.2 0,5 ✓ 0,5 : 1 punt 1
10.3 1 1
✓ : 1 punt
4 4 1 3
11 25 280 ✓ 25 280: 1 punt 1
12 Peter se bedrag = R240 ÷ 12 ✓ R20: 2 punte
= R20 ✓ R240 ÷ 12: 1 punt 2
13 24 ✓ 24: 1 punt 1
14 Invoergetal : 15 ✓ 29: 1 punt
Uitvoergetal : 29✓ 15: 1 punt 2
15 15.1 Invoergetal : 3 ✓ 3: 1 punt 1
15.2 Invoergetal : 7 ✓ 7: 1 punt 1 2
16 13 vuurhoutjies✓ 13 : 1 punt 1
17 17.1 Stomphoek ✓ 1 punt 1
Graad 6 Wiskunde Memo 3
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17.2 Regte hoek of inspringende hoek ✓ 1 punt 1 2
18 18.1 Oktagoon of agthoek ; Trapesium ; Enige 3 antwoorde 1
18.2 Reghoek ; Heksagoon of seshoek ✓✓✓ 1 punt elk 1
18.3 1 3
19 19.1 teenoorstaande ✓ 1 punt 1
19.2 twee ✓ 1 punt 1 2
20 Aantal hoekpunte : 10 ✓ 1 punt elk
Aantal rante : 15 ✓
Aantal vlakke : 7✓ 3
21 Aantal liters gespaar = 9,5 8,7 ✓ 0,8: 2 punte
= 0,8 ✓ 9,5 – 8,7 :1 punt 2
22 22.1 9 ure ✓ 9 ure: 1 punt 1
22.2 8.00 vm. ✓of 08:00 of 8 uur 1 punt 1 2
23 600 ml = 0,6 l ✓ 0,6 l : 1 punt 1
24 Zola ✓ Zola : 1 punt 1
25 25.1 56,8 kg ✓ 56,8 kg : 1 punt 1
25.2 56 800 g ✓ 56 800 g: 1 punt 1 2
26 26.1 Pete, Alice en Ruth ✓ Moet al drie name
skryf: 1 punt 1
26.2 Thato ✓ 1 punt 1
26.3 Aantal albasters = 10 + 50 = 60 ✓ 60 : 1 punt 1
26.4 10 10 : 2 punte
Pete se % = ✓x 100 = 10 ✓
100 10
: 1 punt
100 2
26.5 50 5 1 1 1 6
Breukdeel = of of ✓ : 1 punt
100 10 2 2
27 Modus = 7 ✓ 7: 1 punt 1
28 A = 50 ✓ Fig 1:1 x 2 + 2 x 3 = 8
Fig 2:2 x 3 + 3 x 4 = 18
Fig 3:3 x 4 + 4 x 5 = 32
Fig 4:4 x 5 + 5 x 6 = 50 1
TOTAAL 75
Graad 6 Wiskunde Memo 4
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