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Mathematics Grade 12 Paper 2 Eastern Cape Mock 2022 Errata

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Grade 12 Mathematics Paper 2 errata from the Eastern Cape Mock Exam 2022, 2 pages. Read online or get the free PDF download.

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Downloaded from hlayiso.com CHIEF DIRECTORATE: EXAMINATIONS AND ASSESSMENT Steve Vukile Tshwete Complex, Zone 6 Zwelitsha, 5608, Private Bag X0032, Bhisho, 5605 REPUBLIC OF SOUTH AFRICA: Enquiries: Mrs F. Ntsangani Tel: 040 602 7099 . Fax : 040 602 7295. E-mail: fezeka.ntsangani@ecdoe.gov.za Website: www.ecdoe.gov.za Ref. no. 13/P Tel.: (040) 602 7099/082 888 5419 Enquire: Mrs F. Ntsangani Fax: 040 602 7295 TO: DISTRICTS HEADS OF EXAMINATIONS PRINCIPALS OF SCHOOLS IN THE FET BAND FROM: (A) CES: ASSESSMENT INSTRUMENT DEVELOPMENT AND ITEM BANK MANAGEMENT MRS F. NTSANGANI SUBJECT: ERRATA – MATHEMATICS P2 GRADE 12 PREPARATORY EXAMS DATE: 15 SEPTEMBER 2022 Mathematics P2 was written on Monday, 12 September 2022. We were made aware of certain errors, amendments and omissions that were discovered during the marking process. In order to address this and to ensure that the learners are not disadvantaged, the following standardised approach to marking must be adopted across the Province. The following guidelines with regard to marking was prepared in conjunction with the examiner and moderator. ERRATA: MATHEMATICS P2 (MARKING GUIDELINE) 1.2 Anchor point must be (420 ; 0) Upper Limit – 780 Last point has 𝑦 − 𝑐𝑜𝑜𝑟𝑑𝑖𝑛𝑎𝑡𝑒 𝑜𝑓 100 1.3 Mark according to learner’s Ogive. 1.4 Please accept between 42% - 44%. Marking must be according to the learner’s response on their drawing of the Ogive. 2.1 No penalty for rounding. 2.2 No penalty for rounding. 2.3 Accept if learner states that 5,4 is within the domain of the data set. Or if learner mentions that it is valid as the correlation coefficient is 0,92. 2.4.1 Accept if learner merely states that the mean will change.
Downloaded from hlayiso.com 3.1.3 Alternative Solution: tan 𝑀𝑅̂ 𝐾 = 1 ∴ 𝑀𝑅̂ 𝐾 = 450 𝑅𝑀̂ 𝐾 = 900 ∴ 𝑀𝐾 ̂ 𝑅 = 450 5.2.2 Correction on Marking Guideline 1 + 2 cos 1050 . sin 150 = 1 − 2 cos 750 . sin 150 ✓ for reduction of cos 1050 = 1 − 2 sin 150 . sin 150 ✓ for reduction of cos 750 = 1 − 2𝑠𝑖𝑛2 150 = cos 2(150 ) = cos 300 ✓ for cos 300 √3 ✓ for the answer = 2 5.4 2 marks for values of 𝐭𝐚𝐧 𝒙. / One tick missing on marking guideline. 6.2.1 Period/ Periode = 10800 6.3 Maximum distance = 4 units 7.3 Final line: 𝑇𝑃 = √3. 300(cos 𝑥 − √3 sin 𝑥) 8.3 𝑅𝑄̂ 𝑇 = 1120 (sum of angles of a triangles) 10.1 Mark allocation to be done as follows: ✓ for construction. ✓ for proving triangles congruent ✓ for deduction that 𝐴𝑃̂𝑄 = 𝐸̂ ✓ for 𝑃𝑄||𝐵𝐶 ✓ for corresponding angles equal. ✓ for the deduction of the ratios. 10.2.3 In ∆ 𝐴𝐵𝑆 and ∆ 𝑆𝑇𝑀 (1) 𝐴̂ = 𝑆̂2 (2) 𝐵̂ = 𝑆𝑇̂𝑀 ( angles in same segment) (3) 𝑆̂1 = 𝑀 ̂3 (proven) ∆ 𝐴𝐵𝑆|||∆ 𝑆𝑇𝑀 ( A, A, A) We request that this must be brought to the attention of all educators marking this paper and sincerely apologise for the inconvenience. Yours in quality education. 15 SEPTEMBER 2022 Mrs F. Ntsangani DATE

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