basic education
& 4 Department:
y (O) Basic Education
pS REPUBLIC OF SOUTH AFRICA
NATIONAL
SENIOR CERTIFICATE/
NASIONALE
SENIOR SERTIFIKAAT
PHYSICAL SCIENCES: CHEMISTRY (P2) Hi
Hs FISIESE WETENSKAPPE: CHEMIE (V2) "
NOVEMBER 2017
MARKS/PUNTE: 150
SNDRIVA GaAOUdd
4 | -H- 2102
L106 WRIOLEd 'S68X Ove BawAnant |
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“SWS SO LNB L ret 35
These marking guidelines Consist of 10 pages.
Hierdie nasienriglyne bestaan uit 10 bladsye.
Approved
Hovo-P see ap cas
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Physical Sciences Grade 10 P2 2017 Memo
Grade 10 Physical Sciences Paper 2 memorandum from the Mpumalanga National Exemplar Exam (NSC) 2017, 10 pages. Read online or download the free PDF.
Physical Sciences · Grade 10 · Mpumalanga National Exemplar Exam (NSC) · 2017. Memorandum, 10 pages. Read online or download the PDF.
- Subject
- Physical Sciences
- Grade
- Grade 10
- Document type
- Memorandum
- Year
- 2017
- Exam period
- Mpumalanga National Exemplar Exam (NSC)
- Paper
- 2
- Curriculum
- CAPS
- Pages
- 10
- File size
- 442.0 KB
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This exam
Mpumalanga National Exemplar Exam (NSC) 2017
- Paper 1Question paperMemo
- Paper 2Question paperMemo
Questions in this paper
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QUESTION 1/VRAAG 1
1.1
1.2
1.3
1.4
1.5
1.6
1.7
1.8
1.9
1.10
Cvy
Avy
AVY
Avy
Cvv
Avy
Dyv
Avv
Byy
Cyvy
DEPARTMENT OF BASIC
EQUCATION
PRIVATE BAG X89d, PRETORIA 9004
2017 -11- 14
APPROVED MARKING GUIDELINE
PUBLIC EXAMINATION
Copyright reserved/Kopiereg voorbehou
(2).
(2) ©
(2)
(2)
(2)
(2)
(2)
(2)
(2)
(2)
[20]
Physical Sciences P2/Fisiese Wetenskappe V2 3 DBE/November 2017
CAPS/KABV — Grade/Graad 10 — Marking Guidelines/Nasienriglyne
QUESTION 2/VRAAG 2
2.1.1 CO2v ORIOF H20v (1)
21.2 Fev (1)
2.1.3 Coov (1)
2.1.4 NaClv (1)
ye 6B
2.2 eo? oy xe O° vv lg s 3
e F
oy’ ex 4° cle 3 gina (2)
ES xica
2.3 Covalent bond” /Kovalente binding’ 5 Fs = & Ba (1)
5/2 — aleg)
2.4 OPTION 4/OPSIE 1: 5 2 d za
319
Nax — Na + e- v ES 2b
2a 216
ae ee -7--
2Cle +e-_, 3cis] v
ee ee
ee ee —-
e +\@
Nax + 3Cl* — na[ seis]
ee
OPTION 2/OPSIE 2-
v v v
ee ec —-
e
Nax + 3Cle — na'[scis]
ee (3)
2.5.1 Potassium iodide v, /Kaliumjodiedv (1)
2.5.2 CHav (1)
2.5.3 Ammonia “/Ammoniak v (1)
2.6.1 Physical “/Fisies v (1)
2.6.2 Boiling point V/Kookpunt v (1)
one
2.6.3 Nitrogenv’ thas the lowest boiling point. v/Stikstof v -Laagste kookpunt V (2)
2.7.1. INCREASE. v/TOENEEMY (1)
2.7.2 DECREASE. “/AFNEEMY (1)
2.7.3. INCREASE. v/TOENEEMY (1)
[20]
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DEPART:
ED... i
PRIVATE BAG X896, PREToun Suu) H
Physical Sciences P2/Fisiese Wetenskappe V2 4 No! ferpey,20"7 Hl
CAPS/KABV — Grade/Graad 10 - Marking Guidelines/Nasie id . i
APPROVED MARKING GUIDELINE |
QUESTION 3/VRAAG 3 PUBLIC EXAMINATION ]
3.1 Energy needed per mole to remove an electron from an atom in a gaseous
3.2
3.3.1
3.3.2
3.4
3.5.1
3.5.2
3.5.3
Copyright reserved/Kopiereg voorbehou
phase. vv”
Energie benodig per mol om 'n elektron uit 'n atoom in die gasfase te
verwyder. vv (2)
lonisation energy increases from left to right, across a period. vv
lonisasie energie neem toe van links na regs oor 'n periode. VV (2)
Be:1s? 2s2vv
B:1s? 2s? 2p1vv (4)
B has a 2p energy level: 2p has a higher energy than 2s. v
Therefore less energy is needed to remove the valence electrons from B as
from Bev v.
B het 'n 2p energieviak; 2p het meer energie as 25 “
Dus minder energie word benodig om 'n valenselektron van B te verwyder in
vergelyking met Be. “~
OR/OF
2s electrons are paired and 2p electron is unpaired. “ Therefore, less energy
needed to remove 2p electron. vv
Die 2s elektrone is gepaard teenoor die ongepaarde 2p elektrone. V Daarom
word minder energie benodig om 'n 2p elektron te verwyder, vv
OR/OF
The 2p electron is further away from the nucleus v. Therefore, the
electrostatic force weaker and requires less energy. vv
Die 2p electron is verder van die kernv, dus is die elektrostatiese krag
swakker en daarom word minder energie benodig om die elektron te
verwyder, vv (3)
False” The energy is high because of filled s and p-orbitals. “/
Vals~ Die energie is hoog agv die gevulde s- en p-orbitale.v (2)
Alkali-metalsv
Alkali-metalev (1)
Reactivity increases from top to bottom v
Reaktiwiteit verhoog van bo na onder in die groep.vv (2)
lonisation energy decreases, Y thus less energy to remove an electron.
Therefore, reactivity increases, ”
lonisasie-energie neem af’ , daarom word minder energie benodig om 'n
elektron te verwyder. Reaktiwiteit neem dus toe. v (2)
[18]
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Physical Sciences P2/Fisiese Wetenskappe V2 5 DBE/November 2017
CAPS/KABV — Grade/Graad 10 — Marking Guidelines/Nasienriglyne
QUESTION 4/VRAAG 4
4.1.1 Isotope: atoms of the same element having the same number of Protons, but
different number of neutrons. OR Same atomic number, but different mass
numbers. vv
!sotoop: Atome van dieselfde element wat dieselfde getal protone het, maar
verskillende getalle neutrone. Vv OF Dieselfde atoomgetalle, maar
verskillende massagetalle. (2)
4.1.2 50% =106,9 amu
50% =109,1amu v
>) ;
v
_ (50x 106,9) + (50 109,1)
A
‘ 100 v
=108 v (5)
=PAS ST
41.3 Ag/Silver vv | DEPARINENT SF asic
Ag/Silwer VV PRIVATE BAG O88, PRETORIA 0007 (2)
42.2 14 ¥ APPROVED MARKING GUIDELINE
Er 1 3 ¥ PUBLIC EXAMINATION
425 19v
426 20v
427 18v (7)
[16]
QUESTION 5/VRAAG 5
5.1 An aqueous solution. “/A solution in water “/'n Waterige opiossing.v (1)
5.2 Redox. v Electron transfer took place. v/
Redoks. V Elektron oordrag het plaasgevind. v
Accept/Aanvaar. Change in oxidation number/ Verandering in
oksidasiegetal. (2)
5.3 Chemical change. “/Chemiese verandering, V (1)
5.4 The amount of substance having the same number of particles as there are
atoms in 12g C-12. vv
Die stofhoeveetheid wat dieselfde getal deeitjies het as wat daar atome in 12g
koolstof-12 is, vv (2)
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Physical Sciences P2/Fisiese Wetenskappe V2 6
CAPS/KABV — Grade/Graad 10 - Marking Guidelines/Nasienriglyne
5.5 —-H,0,:0,
2:1
“n(O2) = 2 mol v
n= ae v
m
2 Vv
Gav
V =448dm'v
5.6 m
n(H,02)= | NOTE/NOTA:
17 If molar mass of H2O2 is incorrect, mark
=a v positively. Max 2/4
34 Positiewe nasien indien molére Massa van
= 0,5 mol | He02 verkeerd is. Maksimum punte 2/4
Ny
Na
N
2) = ——
V2) = E0910"
N=6,02x 10” atoms/atome “
* WB 3) 9
ed §| 4
z\2 a]
a] sy ginal
QUESTION 6/VRAAG 6 gig S 2158)
jS]e xs F/Gz!
6.1.1 Gas forming ~/Gasvormende reaksie ¥ aes ' og a5
Pap z m109
6.2.1 M(Na,CO,) = 2(23) +12 +3(16) 4I5 so)
=106 Y g-mor v es g i
Li *
6.2.2 POSITIVE MARKING FROM QUESTION 6.2.1
POSITIEWE NASIEN VANAF VRAAG 6.2.1
n(Na,CO,) = a
10,6
06
,1 mol v
1
=0
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DBE/November 2017
Please turn over/Blaai om asseblief
(4)
(4)
[14]
(1)
(2)
(2)
df
Physical Sciences P2/Fisiese Wetenskappe V2 7 DBE/November 2017
CAPS/KABV — Grade/Graad 10 — Marking Guidelines/Nasienriglyne
6.2.3 POSITIVE MARKING FROM QUESTION 6.2.2
POSITIEWE NASIEN VANAF VRAAG 6.2.2
OPTION 1/OPSIE 1: OPTION 2/ OPSIE 2: |
n(NazCQs) : n(CO2 oo
} } a | 106 g of NaxCOs: 44 goof Con VY
Thus: n(COz)=0,1 mol | 10,6. g:4,4gCO2 vv |
m
n(CO,) =a” [__NPa:440C0 vv
m
01=— v
44 |
m=4,4g ¥ |
| (4)
6.2.4 Voo,
m(CO2)= <5 | NOTE/ NOTA:
4.87 One mark for any one formula
= 304 v Een punt vir enige een formule
=0,217 mol
n(COQz) : n(NaCl)
1:2” NOTE/ NOTA:
n(NaCl) = 0,434 mol If ratio 1:2 is not given, allocate
two marks for 0,434 in the
_my substitution.
n(NaCcl) M Indien verhouding 1:2 nie
m gewys word nie; gee twee
Y 0,434 = 5a 7 punte vir 0,434 vir die
fe 25.16 9 v | Invervanging. 6)
renee
[ DEPARTMENT SF BASIC
EDUCATION
PRIVATE BAG X895, PRETORIA 0004
2017 -l1- 14
APPROVED MARKING GUIDELINE
PUBLIC EXAMINATION
Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief Y ¢
Physical Sciences P2/Fisiese Wetenskappe V2
8
DBE/November 2017
CAPS/KABV - Grade/Graad 10 — Marking Guidelines/Wva.
sienriglyne
6.3 OPTION1/OPSIE 1:
Mass of H20 = 14.2-5,3
=89g v
m
n(Na,CO,).= M n(H,O) = M
5:3 - 89
~ 106 ~ 18
= 0,05 mol =0,5 mol
NazCO3 : H20
0,05 : 0.5
0,05: 0,05 ” Divide by smallest number clo
1:10 33 z|
ee
nm
Thus x= 10 ¥ Cim gigs
mez ~ les
xi 4. g\02
OPTION 2/OPSIE 2: [E ay ¥ 24
2,0 — F750
Mass of H2O = 14,2 -5,3 ei
eon v eg
M(NazCOs) = 160 g-mol" M(H20) = 18 g:mot* L4——__—
n(Na,CO,):n(H,0)
m(Na,CO,)_m(H,0O)
M(Na,CO,) M(H,O)
5,3 8,9
160° 48 v
0,05 :0,5
0,05 0,5
1:10
Thus x =10 v
0,05 0,05 ~ Divide by smallest number
Copyright reserved/Kopiereg voorbehou
(5)
[20]
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Physical Sciences P2/Fisiese Wetenskappe V2 9 DBE/November 2017
CAPS/KABV ~ Grade/Graad 10 — Marking Guidelines/Nasienriglyne
QUESTION 7/VRAAG 7
7.1 Distilled water does not contain free ions. ”
Gedistilleerde water bevat geen vrye ione nie. V
7.2 Electrolyte Vv /Flektroliet Vv
7.3 AgNOs(s) — Ag*(aq) Vv + NOs(aq) “
NOTE/NOTA: Phases need not be shown/ Fases kan uitgelaat word.
7.4.1 The conductivity of AgNOs solution will increase with an increase in the
concentration of the AgNOs solution at a constant temperature. vv
Die geleidingsvermoé van die AgNO oplossing sal toeneem met 'n toename
in die konsentrasie van die oplossing, mits die temperatuur konstant blyvv
7.4.2 Conductivity v/Geleidingsvermoé v
Accept/Aanvaar. Ammeter reading/ Ammeter lesing
7.4.3. Concentration (of the AgNOs solution) ¥
Konsentrasie (van die AgNO3 oplossing) ¥
Accept/Aanvaar. Spoons of AgNOs in distilled water/ Lepels AgNOs in
gedistilleerde water.
7.4.4 Temperature “/Temperatuur ”
7.6 Without water v/Sonder water/Watervry. ¥
7.6 Mass of AgNOs = (5,3)(2) _
=106g v ‘DEPARTMENT OF BASIC
EDUCATION
PRIVATE BAG X95, PRETGRIA 0901
°= MV 2017 -11- 14
- 106 APPROVED MARKING GUIDELINE
170(0,2) PUBLIC EXAMINATION
=0,31 mol-dm® ¥
7.7 No. ¥ Tap water contains ions and it will affect the conductivity of the AgNOs
solution. ¥
Nee, V Die kraanwater sal die geleidingsvermoé van die AgNOs oplossing
beinvioed. ¥
7.8 An increase in concentration of ions in a solution increases conductivity of a
solution. VW
Met 'n toename in konsentrasie van ione, neem die geleidingsvermoé toe. Vv
(1)
(2)
(2)
(2)
(1)
(1)
(1)
(1)
(4)
(2)
Physical Sciences P2/Fisjese Wetenskappe V2 10 DBE/November 2017
CAPS/KABV — Grade/Graad 10 — Marking Guidelines/Nasienriglyne
7.9.1 DECREASE “/AFNEEM v rs) (1)
7.9.2 Silver chloride precipitate forms/ a reaction takes place v’, thus decreasing
the concentration of the ions in the solution.”
Daar vorm 'n silwerchloried neerslag/n chemiese reaksie vind Plaas V wat die
konsentrasie van die ione in oplossing laat afneem.v (2)
[22]
QUESTION 8/VRAAG 8
8.1 BaChv (1)
8.2 COs"?(aq) + BaCle(aq) ¥ BaCOx(s)” + 2CI'(aq) v Bal ¥
NOTE/NOTA: Phases need not be shown/ Fases kan uitgelaat word (4)
v
8.3 BaCOs(s) + HNOs(aq) Vv —> Ba(NOs)(aq) + CO2(g)¥ + H20(I)v *
NOTE/NOTA: Phases need not be shown/ Fases kan uitgelaat word (4)
8.4 Barium carbonate V“/Bariumkarbonaat. Vv (2)
[11]
[PEPARaucaron |
QUESTION 9/VRAAG 9 | PRIVATE BAG X036, PRETORIA 0001
; ; 2017 -11- 14
9.1.1 Condensation v/Kondensasie v (1)
APPROVED MARKING GUIDELINE
9.1.2 Precipitation /Presipitasie V PUBLIC EXAMINATION (1)
9.1.3 Transpiration Y/Transpirasie V (1)
9.2 ReleasedY, energy is released to the Surrounding/cooling takes
place/particles moves closer together. ~
Vrygestel’, energie is vygestel na die omgewing toe/afkoeling vind
plaas/deeltjies beweeg-nader aan mekaar “ (2)
9.3 Water absorbs the infrared energy from the sun and re-emits it therefore
regulating the climate. Vv
Water absorber die infrarooi energie van die son en ste! dit weer vry om
klimaat te reguleer. VV (2)
9.4 Drilling of boreholes/Building of damsv “
Boorgate te sink/Damme te bou Vv
Accept/Aanvaar. Any applicable answer/ Enige toepaslike antwoord word
aanvaar. (2)
[9]
TOTALITOTAAL: 150
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