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PREPARATORY EXAMINATION
GRADE 12
LIFE SCIENCES P2
SEPTEMBER 2022
MARKS: 150
TIME: 2½ HOURS
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Life Sciences Grade 12 Paper 2 Free State Mock 2022 Memo
Grade 12 Life Sciences Paper 2 memorandum from the Free State Mock Exam 2022, 27 pages. Read online or download the free PDF.
Life Sciences · Grade 12 · Free State Mock Exam · 2022. Memorandum, 27 pages. Read online or download the PDF.
- Subject
- Life Sciences
- Grade
- Grade 12
- Document type
- Memorandum
- Year
- 2022
- Exam period
- Free State Mock Exam
- Paper
- 2
- Curriculum
- CAPS
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- 27
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Grade 12 Prep. Exam.
INSTRUCTIONS AND INFORMATION
Read the following instructions carefully before answering the questions.
1. Answer ALL the questions.
2. Write ALL the answers in the ANSWER BOOK.
3. Start the answer to EACH question at the top of a NEW page.
4. Number the answers correctly according to the numbering system used in this
question paper.
5.
s.co
Present your answers according to the instructions of each question.
6. Do ALL drawings in pencil and label them in blue or black ink. m
si c
7. Draw diagrams, tables or flow charts only when asked to do so.
st
8. an
The diagrams in this question paper are NOT necessarily drawn to scale.
9. Do NOT use graph paper. mor
10. ep
You must use a non-programmable calculator, protractor and a compass, where
necessary. hy
11. Write neatly and legibly.
om
fr
oa
de
d
do
wn
l
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Grade 12 Prep. Exam.
SECTION A
QUESTION 1
1.1 Various options are given as possible answers to the following
questions. Choose the answer and write only the letter (A to D) next to
the question numbers (1.1.1 to 1.1.10) in the ANSWER BOOK, for
example, 1.1.11 D.
1.1.1 Which ONE of the following represents a single RNA
nucleotide?
A
B
Deoxyribose-adenine-thymine
Adenine-ribose-phosphate
s.co
C Deoxyribose-thymine-phosphate
D Uracil-deoxyribose-phosphate m
si c
1.1.2 What percentage of adenine bases is present in a DNA molecule
st
with 2000 bases if 400 bases are cytosine?
A 20
an
B 40 mor
C 30
D 60 ep
1.1.3
hy
Which organelle is responsible for producing spindle fibres?
A Nucleus om
B Centromere
C fr
Centriole
D Chromosome
oa
1.1.4 de
Which ONE of the following represents the correct order for
d
the possible evolution of modern humans?
do A Ardipithecus → Australopithecus → Homo
wn B Australopithecus → Ardipithecus → Homo
l C Homo → Australopithecus → Ardipithecus
D Ardipithecus → Homo → Australopithecus
1.1.5 Which ONE of the following represents a trend in human
evolution?
A More developed brow ridges
B Increased size of canines
C More developed cranial ridges
D More forward position of the foramen magnum
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Grade 12 Prep. Exam.
1.1.6 Which ONE of the following distinguishes prophase I of meiosis
from prophase of mitosis?
A Homologous chromosomes pair up
B Spindle forms
C Nuclear membrane breaks down
D Chromosomes become visible
1.1.7 When a cell divides by meiosis, it results in …
A four haploid gametes.
B two diploid gametes.
C four haploid somatic cells.
D two haploid somatic cells.
1.1.8 Comparison of the amino acid sequences in a protein have been
made between humans and several other organisms. The number
of differences is shown in the table below.
ORGANISM SHARK KANGAROO FISH COW LIZARD
Number of
differences
in amino
acids
79 27 68 17 62
sequences
in a protein
compared
to humans
The type of evidence for evolution in the table above is …
A fossil evidence.
B modification by descent.
C cultural evidence.
D genetic evidence.
1.1.9 Down syndrome occurs when …
A a male sex cell undergoes mitosis.
B every cell of an organism has an extra pair of chromosomes.
C all somatic cells of an organism have an extra chromosome.
D a female sex cell undergoes mitosis.
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Grade 12 Prep. Exam.
1.1.10 The graph below shows the pace at which evolution occurs in a
species of butterfly.
Which type of evolution is represented by the graph?
A Speciation
B Inheritance of acquired characteristics
C Punctuated equilibrium
D Artificial selection
(10 x 2) (20)
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Grade 12 Prep. Exam.
1.2 Give the correct biological term for each of the following descriptions. Write
only the term next to the question numbers (1.2.1 to 1.2.10) in the ANSWER
BOOK.
1.2.1 A section of DNA that carries the code for a particular trait
1.2.2 The production of gametes during meiosis
1.2.3 A diagram showing possible evolutionary relationships
1.2.4 The allele that is expressed in the phenotype in the
heterozygous condition
1.2.5 The study of animal and plant distribution as a form of evidence
for evolution
1.2.6 A group of organisms that share the same gene pool and that
can interbreed to produce fertile offspring
1.2.7 A characteristic of primates that enables them to have
precision in grip
1.2.8 A set of well-tested ideas that explains a phenomenon in
science and is supported by sufficient experimental evidence
1.2.9 The mistake that occurs when two homologous chromosomes
do not separate from each other during meiosis
1.2.10 The type of dominance where a long-tailed dog and a short-
tailed dog produces a puppy with a medium length tail
(10)
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Grade 12 Prep. Exam.
1.3 Indicate whether each of the statements in COLUMN I applies to A
ONLY, B ONLY, BOTH A AND B or NONE of the items in COLUMN
II. Write A only, B only, both A and B or none next to the question
numbers (1.3.1 to 1.3.3) in the ANSWER BOOK.
COLUMN I COLUMN II
1.3.1 A place in the plant cell where A: Nucleus
DNA is found B: Mitochondrion
1.3.2 The evidence used to support A: Mitochondrial DNA
the 'Out of Africa' hypothesis by B: Y- chromosome DNA
tracing the maternal lineage
1.3.3 Phase during which cytokinesis A: Telophase I
takes place B: Telophase II
(3 x 2) (6)
1.4 In watermelons, there are two alleles for taste, bitter fruit and sweet fruit. The
allele for bitter fruit (B) is dominant over the allele for sweet fruit (b). There are
two alleles for skin appearance, yellow spots and no spots. The allele for yellow
spots (N) is dominant over the allele for no spots (n).
Plant A, which is heterozygous for bitter fruit and for yellow spots, was crossed
with plant B, which has sweet fruit and no spots.
1.4.1 Give the term that describes a genetic cross involving two
characteristics. (1)
1.4.2 Give:
(a) The genotype of plant B (2)
(b) The dominant phenotype for taste in watermelons (1)
(c) All possible genotypes of the gametes of plant A (2)
1.4.3 List TWO ways in which the phenotype of a watermelon with
genotype bbNn differs from the phenotype of a watermelon with
genotype Bbnn. (2)
(8)
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Grade 12 Prep. Exam.
1.5 The diagram below show two molecules that are required during proteins
synthesis.
B
C U C
A
W
1.5.1 Identify:
(a) Molecule A (1)
(b) The bond at B (1)
(c) The base triplet sequences for W (2)
1.5.2 Name the organelle at which this phase of protein synthesis takes
place. (1)
1.5.3 Name the nitrogenous base represented by U in the diagram. (1)
(6)
TOTAL SECTION A: 50
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Grade 12 Prep. Exam.
SECTION B
QUESTION 2
2.1 The table below shows the anticodons of tRNA, that carry specific amino acids
during protein synthesis.
Number Amino Acid tRNA
1 Alanine CGA
2 Valine GUA
3 Aspartic acid CUA
4 Valine CAC
5 Glutamine CUC
6 Arginine GCC
7 Cysteine UGC
8 Threonine UCC
9 Histidine CAG
10 Tryptophan ACC
11 Tyrosine AUA
2.1.1 Write down the DNA base triplet that codes for the amino acid Valine
at number 2. (2)
2.1.2 From the table, write down the names of two amino acids which are
coded for by thymine (T) as the first base in the DNA triplets. (2)
2.1.3 Name AND describe the process that occurred in the cytoplasm,
which led to amino acid number 11 becoming part of a protein. (5)
(9)
2.2 Tabulate any TWO structural differences between DNA and RNA. (5)
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Grade 12 Prep. Exam.
2.3 The diagrams below show how a sheep was cloned.
1. A somatic cell are
removed from
sheep V
V
2. The nucleus are
removed from the
somatic cells and placed
into the 'empty' ova
removed from sheep W.
These cells are allowed
to develop into embryos.
'Empty' ova of
sheep W
3. The embryos are implanted into
the uterus of the sheep W and
W allowed to develop for the full
gestation.
OFFSPRING
2.3.1 What is a somatic cell? (2)
2.3.2 Why is the nucleus from the ovum of sheep W removed? (1)
2.3.3 Explain why the lambs produced by the technique are identical to
each other. (4)
2.3.4 Give ONE reason why the lambs are not genetically identical to
sheep W, which produced the ova. (1)
2.3.5 State TWO reasons why cloning livestock be can beneficial to
humans. (2)
2.3.6 Give ONE reason why some people may be against cloning. (1)
(11)
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Grade 12 Prep. Exam.
2.4 Mr and Mrs Wilson are concerned because their baby boy does not appear
to resemble either of them. They suspected that the baby they were given
at the hospital is not theirs. Mr Wilson has blood type AB, Mrs Wilson has
blood type B. Their daughter has blood type A. The baby boy they were
given, has blood type O. They learn that blood groups are determined by
multiple alleles – and that there are four phenotypes for blood groups.
2.4.1 Describe how multiple alleles determine blood groups. (2)
2.4.2 Give the genotype of the daughter. (2)
2.4.3 Explain why the baby boy with blood type O, cannot be Mr and
Mrs Wilson's biological son. (3)
2.4.4 Blood types are not conclusive in paternity testing.
Explain how DNA profiling could be used to determine that Mr
Wilson is the father of the daughter. (4)
(11)
2.5 Using your knowledge of gonosomes, explain why the sex of a child is
determined by the male gamete. (4)
2.6 A population of squirrels lived in the mountains. A landslide caused the river
to change direction, thereby separating the populations into two groups on
either side of the river. Over a long period of time, the two populations
became different species.
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2.6.1 Describe the process of speciation in the squirrels. (7)
2.6.2 Give THREE reproductive isolation mechanisms that help to keep
species separate. (3)
(10)
[50]
QUESTION 3
3.1 The diagrams below show the skulls of three primate genera.
The diagrams are NOT drawn to scale.
A B
C
3.1.1 Give the LETTER only of a skull that:
(a) Most likely belongs to a bipedal organism (1)
(b) Is attached to a C-shaped vertebral column (1)
(c) Is most prognathous (1)
(d) Has the largest brain size (1)
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Grade 12 Prep. Exam.
3.1.2 State TWO advantages of having a large brain. (2)
3.1.3 State any THREE features of skull B shown in the diagram above
that allows scientists to determine that this was a much earlier
species of genus Homo than modern humans. (H. sapiens
sapiens.) (3)
3.1.4 Name TWO lines of evidence that support the idea that humans
originated on the African continent. (2)
(11)
3.2 Brassica plants have hair on their leaves to reduce transpiration. The number of
hairs on the leaves varies from plant to plant.
An investigation was conducted to determine whether artificial selection could
increase the number of plants with more hair on their leaves.
The students carried out the following procedure:
• 180 Brassica plants were selected randomly.
• The number of hairs present on the edge of each mature leaf was counted
per plant, and an average was calculated.
• The number of plants, with different averages, was counted and recorded.
• The plants with more than 25 hairs per leaf were separated from the rest of
the group and allowed to cross-pollinate.
• The seeds produced by these plants were germinated and allowed to grow
into mature plants. 180 of these plants were selected randomly.
• The number of hairs present on the edge of mature leaves was counted per
plant and the average number of hairs was calculated again.
The number of plants with different averages was counted and recorded.
The results of the investigation are shown in the table below.
WITHOUT ARTIFICIAL
WITH ARTIFICIAL SELECTION
SELECTION
Average Number of Average Number of
number of hairs plants number of hairs plants
0–5 50 0–5 8
6–10 35 6–10 5
11–15 24 11–15 18
16–20 20 16–20 25
21–25 25 21–25 35
26–30 12 26–30 45
31–35 8 31–35 30
36–40 6 36–40 14
[Adapted from: www.media.collegeboard.com]
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Grade 12 Prep. Exam.
3.2.1 Identify the:
(a) Independent variable (1)
(b) Dependent variable (1)
3.2.2 State ONE way the students could have made their results
more reliable. (1)
3.2.3 Give a conclusion for this investigation. (2)
3.2.4 Draw a histogram showing the results with artificial selection. (6)
(11)
3.3. The diagram below shows the somatic cells of an organism in one of the
phases of meiosis.
3.3.1 Which phase of meiosis is represented in the diagram? (1)
3.3.2 Give the LETTER and NAME of the part that:
(a) Carries the genetic information (2)
(b) Holds the chromatids together (2)
3.3.3 State the number of chromosomes present in each of the
cells of this organism.
(a) At the beginning of meiosis (1)
(b) In a gamete of this organism (1)
(7)
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Grade 12 Prep. Exam.
3.4 The pedigree diagram below shows the inheritance of colour blindness in a
family. The normal allele is represented by XD and the allele causing colour
blindness is represented by Xd.
A
B C
D E
K ey:
Unaffected male Unaffected female
Colour blind male Colour blind female
3.4.1 Determine the:
(a) Phenotype of individual D (1)
(b) Genotype of individual A (1)
3.4.2 State ONE reason why colour blindness is regarded as a sex-
linked disorder. (1)
3.4.3 Explain why females have a lesser chance of suffering from
colour blindness than males. (4)
3.4.4 Represent a genetic cross to show the percentage chance of
individuals B and C having another colour-blind son. (6)
(13)
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Grade 12 Prep. Exam.
3.5 The photographs of two butterflies are provided below. Both butterflies live in the
same habitat and are preyed on by predators. Although these butterflies are very
similar in appearance, they are two separate biological species.
Amauris ochlea has an unpleasant taste, while Hypolimnas deceptor does not
have an unpleasant taste.
Amauris ochlea Hypolimnas deceptor
TWO SPECIES OF BUTTERFLY
3.5.1 Explain why most predators are less likely to feed on Hypolimnas
deceptor. (2)
3.5.2 Use Darwin's theory of evolution through natural selection to
explain the evolution of the appearance of the Hypolimnas
deceptor butterfly. (6)
(8)
[50]
TOTAL SECTION B: 100
GRAND TOTAL: 150
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Grade 12 Prep. Exam. Marking Guidelines
PREPARATORY EXAMINATION
GRADE 12
LIFE SCIENCES P2
SEPTEMBER 2022
MARKS: 150
MARKING GUIDELINES
These marking guidelines consist of 11 pages.
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Grade 12 Prep. Exam. Marking Guidelines
PRINCIPLES RELATED TO MARKING LIFE SCIENCES
1. If more information than marks allocated is given
Stop marking when maximum marks are reached and put a wavy line and 'max'
in the right-hand margin.
2. If, for example, three reasons are required and five are given
Mark the first three irrespective of whether all or some are correct/incorrect.
3. If the whole process is given when only a part of it is required
Read all and credit the relevant part.
4. If comparisons are asked for, but descriptions are given
Accept if the differences/similarities are clear.
5. If tabulation is required, but paragraphs are given
Candidates will lose marks for not tabulating.
6. If diagrams are given with annotations when descriptions are required
Candidates will lose marks.
7. If flow charts are given instead of descriptions
Candidates will lose marks.
8. If the sequence is muddled and links do not make sense
Where sequence and links are correct, credit. Where sequence and links are
incorrect, do not credit. If sequence and links become correct again, resume
credit.
9. Non-recognised abbreviations
Accept if first defined in answer. If not defined, do not credit the unrecognised
abbreviation, but credit the rest of the answer, if correct.
10. Wrong numbering
If the answer fits into the correct sequence of questions, but the wrong number
is given, it is acceptable.
11. If the language used changes the intended meaning
Do not accept.
12. Spelling errors
If recognisable, accept the answer, provided it does not mean something else
in Life Sciences or if it is out of context.
13. If common names are given in terminology
Accept, provided it was accepted at the national memo discussion meeting.
14. If only the letter is asked for, but only the name is given (and vice versa)
Do not credit.
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Grade 12 Prep. Exam. Marking Guidelines
15. If units are not given in measurements
Candidates will lose marks. Memorandum will allocate marks for units separately.
16. Be sensitive to the sense of an answer, which may be stated differently.
17. Caption
All illustrations (diagrams, graphs, tables, etc.) must have a caption.
18. Code-switching of official languages (terms and concepts)
A single word or two that appear(s) in any official language other than the
learner's assessment language used to the greatest extent in his/her answers
should be credited if it is correct. A marker that is proficient in the relevant official
language should be consulted. This applies to all official languages.
19. Changes to the memorandum
No changes must be made to the memoranda. The Provincial Internal
Moderator must be consulted.
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Grade 12 Prep. Exam. Marking Guidelines
SECTION A
QUESTION 1
1.1 1.1.1 B
1.1.2 C
1.1.3 C
1.1.4 A
1.1.5 D
1.1.6 A
1.1.7 A
1.1.8 D
1.1.9 C
1.1.10 C (10 x 2) (20)
1.2 1.2.1 Gene
1.2.2 Gametogenesis
1.2.3 Phylogenetic tree
1.2.4 Dominant
1.2.5 Biogeography
1.2.6 Species
1.2.7 Opposable thumb
1.2.8 Theory
1.2.9 Non-disjunction
1.2.10 Incomplete dominance (10 x 1) (10)
1.3 1.3.1 Both A and B
1.3.2 A only
1.3.3 Both A and B (3 x 2) (6)
1.4 1.4.1 Dihybrid cross (1)
1.4.2 (a) bbnn (2)
(b) Bitter (1)
(c) BN Bn bN bn (2)
1.4.3 bbNn is sweet with yellow spots
Bbnn is bitter with no yellow spots (2)
(8)
1.5. 1.5.1 (a) mRNA (1)
(b) Peptide bond (1)
(c) GAG (2)
1.5.2 Ribosome (1)
1.5.3 Uracil (1)
(6)
TOTAL SECTION A: 50
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Grade 12 Prep. Exam. Marking Guidelines
SECTION B
QUESTION 2
2.1 2.1.1 GTA (2)
2.1.2 Cysteine and Threonine (2)
2.1.3 The process is translation *
The codon UAU of mRNA
was exposed on the ribosome
The tRNA with the complementary anticodon AUA
brought the amino acid tyrosine
from the cytoplasm to the ribosome
It was then bonded to the neighbouring/previous amino
acid by a peptide bond
(* compulsory mark + any 4) (5)
(9)
Credit compulsory mark and any 4 points in sequence
NB. No credit for generic description of translation
process if it does not relate to amino acid 11 in the
table.
2.2 Structural difference between DNA and RNA
DNA RNA
Deoxyribose sugar Ribose sugar
Nitrogenous base Nitrogenous base Uracil
Thymine
Double stranded Single stranded
Helix structure Straight molecule
1 mark for table and any 2 x 2 (5)
Mark first TWO only
2.3 2.3.1 A diploid body cell ✓✓ (2)
2.3.2 It is a haploid cell ✓/Does not have the desired
characteristic (1)
2.3.3 - The diploid ✓ embryonic cell removed from an embryo
of sheep V
- multiplied by mitosis ✓
- Producing identical cells ✓
- The identical nuclei of the cells were removed and
implanted into empty ova ✓
- which developed into genetically identical embryos ✓
/lambs Any 4 (4)
2.3.4 The nucleus/genetic material originated from sheep V /
the genetic material of sheep W was removed from the ova (1)
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2.3.5 − Produce superior livestock ✓
− Produce livestock more rapidly
− As market changes, livestock can be bred to respond to
market changes and demands
Mark first TWO only Any 2 (2)
2.3.6 − Against ethical/moral believes
− It is not safe don't know what can happen to clone /
unsure of long- term effects
− Against nature
− Potential health impact
− Expensive (1)
− Reduce genetic variation (11)
Mark first TWO only Any 1
2.4 2.4.1 – There are 3 different alleles that determines blood
groups
– An individual only inherit two alleles. (2)
2.4.2 IAi (2)
2.4.3 – The baby’s genotype is ii /homozygous for the
recessive allele
– The baby must inherit one allele for type O blood/i from
each parent
– The father/Mr Wilson’s genotype is AB and does not
have the recessive/ i allele (3)
2.4.4 − Compare the DNA profiles of the daughter, mother and
father ✓
− Identify the DNA bands of the daughter that are the same
as that of the mother
− All the remaining bands of the daughter must be the
same as that of Mr Wilson /the father (4)
(11)
2.5 − Males have one X – chromosome and one Y - chromosome on
the gonosome/ 23 chromosome pair
− Females have two X- chromoomes on the gonosomes ✓ / 23
chromosome pair
− All ova have an X- chromosome from the gonosome ✓
− If an ovum is fertilized by an X-chromosome bearing sperm
a female/girl is formed (4)
− If an ovum is fertilized by a Y-chromosome bearing sperm
a male/boy is formed Any 4
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2.6 2.6.1 − The population of a single species of squirrels becomes
separated by a geographical barrier, (the river)
− The population split into two populations.
− There was no gene flow between the two populations
− Since each population was exposed to different
environmental conditions /the selections pressure was
different
− natural selection occured independently in each of the
two populations
− such that the individuals of the two populations became very
different from each other
− genotypically and phenotypically
− Even if the populations are to mix again
− they will not be able to interbreed
− The two populations are now different species
1 Compulsory mark + Any 6 (7)
2.6.2 − Breeding at different times of the year
− Species-specific courtship behaviour
− Plant adaptations to different pollinators
− Infertile offspring
− Prevention of fertilisation
Mark first THREE only Any 3 (3)
(10)
(50)
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QUESTION 3
3.1 3.1.1 (a) A/B ( mark first one only) (1)
(b) C (1)
(c) C (1)
(d) A (1)
3.1.2 Large brain give rise to:
− Well-developed hand-eye coordination
− Capacity of language
− Improved intelligence
− The ability to receive and process more stimuli from the
environment
− Better decision making
Mark first TWO only Any 2 (2)
3.1.3 − Smaller cranium size
− Brow ridges are well developed
− Cranial ridges present
− Larger jaws
− Sloping face
− Less developed chin
Mark FIRST THEE only Any 3 (3)
3.1.4 Fossil evidence
Genetic evidence (2)
(11)
3.2 3.2.1 (a) With OR without artificial selection (1)
(b) Number of plants with more hairs on their leaves (1)
3.2.2 Repeat the investigation
Increase the sample size
Mark FIRST ONE only (1)
3.2.3 With artificial selection the number of plants with more hairs
on their leaves increases (2)
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Grade 12 Prep. Exam. Marking Guidelines
3.2.4
Number of plants with their average
number of hair on their leaves
50
45
40
Number of plants
35
30
25
20
15
10
5
0
0-5 6-10 11-15 16-20 21-25 26-30 31-35 36-40
Average numbers of hair on plant leaves
Mark Allocation
Correct type of graph (T) 1
Caption for graph with both
variables ( C ) 1
Correct label for X-axis and
label for Y-axis (L) 1
Correct scale for X-axis, scale
for Y-axis and width of bars (S) 1
Plotting of points (P) 1 (1 to 7points correct)
2 (All 8 points correct)
Note: If the wrong graph is drawn, marks will be lost
for 'correct type of graph' and correct scale. If
axes are transposed, marks will be lost for
labelling of X-axis and Y-axis.
(6)
(11)
3.3 3.3.1 Prophase II (1)
3.3.2 (a) B – chromosome (2)
(b) E – centromere (2)
3.3.3 (a) 4 (1)
(b) 2 (1)
(7)
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3.4 3.4.1 (a) Unaffected male (1)
(b) XdY (1)
3.4.2 The recessive alleles are only carried on the X chromosome of
the gonosome / 23 chromosome pair (1)
3.4.3
− Colour blindness is carried by a recessive allele
− On the X-chromosome of the gonosome
− Females have two X chromosomes on the gonosome
− Females must inherit two copies of the recessive allele
to show the disorder /females who inherit only one of the
recessive allele are still normal (4)
3.4.4 P1
Phenotype : Colour blind female x Unaffected male
Genotype : XdXd x XDY
Meiosis
G/gametes Xd, Xd XD, Y
Fertilization
F1 Genotype XDXd XdY XDXd XdY
Phenotype 1 normal daughter :1 colour blind son
50% chance of having a colour blind son *
P1 and F1
Meiosis and fertilization
(*Compulsory 1 + Any 5) (6)
OR
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P1
Phenotype: Colour blind female x Unaffected male
Genotype: XdXd x XDY
Meiosis
Gametes Xd Xd
XD XD Xd XD X d
Fertilization
Y Xd Y Xd Y
1 mark for correct gametes
1 mark for correct genotypes
F1 Genotype XDXd XdY XDXd XdY
Phenotype 1 normal daughter : 1colour blind son
50% chance of having a colour blind son *
P1 and F1
Meiosis and fertilization (6)
(*Compulsory 1 + Any 5) (13)
3.5 3.5.1 − Predators may mistake it /avoid eating them
− because they resemble A. ochlea which has an unpleasant
taste (2)
3.5.2 − There was a variation in the appearance and taste of
butterflies √
− The Amauris ochlea did have an unpleasant taste and
the Hypolimnas deceptor that looks like the Amauris
ochlea did not have an unpleasant taste√
− Predators feed on butterflies in this habitat √
− Hypolimnas deceptor that look like the Amairis ochlea
with the unpleasante taste were avoided by predetors√ /
predators did not prey on them
− they were mistaken by their appearance for unpleasant
taste√
− the Hypolimnas deceptor survive√
− They reproduced and √ (6)
− Passed the alle of apperence/allele of looking similar to (8)
A. ochle to the offsprings√ [50]
− More H deceptor butterflies is in the next generation that
look like A ochlea.√
Any 6
TOTAL SECTION B: 100
GRAND TOTAL: 150
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