Physical Sciences Grade 12 Free State Prelim 2024 QP

Downloaded from hlayiso.com PREPARATORY EXAMINATION VOORBEREIDENDE EKSAMEN GRADE/GRAAD 12 PHYSICAL SCIENCES: CHEMISTRY (P2) FISIESE WETENSKAPPE: CHEMIE (V2) SEPTEMBER 2024 MARKS/PUNTE: 150 MARKING GUIDELINES/NASIENRIGLYNE These marking guidelines consist of 14 pages. Hierdie nasienriglyne bestaan uit 14 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 2 FS/VS/September 2024 Grade/Graad 12 Prep. Exam./Voorb. Eksam. Marking Guidelines/Nasienriglyne QUESTION 1/VRAAG 1 1.1 B ✓✓ (2) 1.2 B ✓✓ (2) 1.3 C ✓✓ (2) 1.4 D ✓✓ (2) 1.5 B ✓✓ (2) 1.6 C ✓✓ (2) 1.7 D ✓✓ (2) 1.8 C ✓✓ (2) 1.9 A ✓✓ (2) 1.10 A ✓✓ (2) [20] QUESTION 2/VRAAG 2 2.1.1 A ✓ (1) 2.1.2 E ✓ (1) 2.1.3 D ✓ (1) 2.2.1 Tertiary (alcohol) / Tersiêre (alkohol) ✓ The carbon atom bonded to the hydroxyl group is bonded to three other carbon atoms. ✓ Die koolstofatoom wat aan die hidroksielgroep gebind is, is aan drie ander koolstofatome gebind. (2) 2.2.2 3-methylheptan-3-ol / metielheptaan-3-ol Marking criteria/Nasienkriteria: • Correct stem of alcohol, i.e. heptanol.  • Substituent correctly identified, i.e. methyl.  • IUPAC name completely correct including numbering and hyphens.  • Korrekte stam van alkohol, d.i. heptanol. • Substituent korrek geïdentifiseer, d.i. metiel. • IUPAC-naam heeltemal korrek, insluitend nommering en koppeltekens. (3) 2.2.3 Hydroxyl (group) / Hydroksiel (groep) ✓ (1) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 3 FS/VS/September 2024 Grade/Graad 12 Prep. Exam./Voorb. Eksam. Marking Guidelines/Nasienriglyne 2.3.1 Marking criteria/Nasienkriteria: • Correct functional group of carboxylic acid.  • Whole structure of carboxylic acid correct.  • Correct functional group of alcohol.  • Whole structure of alcohol correct.  • Korrekte funksionele groep karboksielsuur. • Hele struktuur van karboksielsuur korrek. • Korrekte funksionele groep alkohol. • Hele struktuur van alkohol korrek. (4) 2.3.2 ✓ (1) 2.4 H H F H H Marking criteria/Nasienkriteria: • Methyl substituent on second C atom.  H C C C C C H • Two fluorine atoms on third C atom.  • Whole structure correct.  H H F H • Metielsubstituent op tweede C-atoom. H C H • Twee fluooratome op derde C-atoom. • Hele struktuur korrek. H (3) m 2.5 n(CO2) = M (a) Marking criteria/Nasienkriteria: m (a) Formula/Formule n = M  2750 = 44 m (b) Substitute/Vervanging M = 44 g·mol-1 in n = M  ✓(b) = 62,5 mol (c) Use mole ratio/Gebruik molverhouding: n(CH4) = n(CO2)  m n(CH4) = n(CO2)  (c) (d) Substitute/Vervanging M = 16 g·mol-1 in n = M  = 62,5 mol (e) Correct final answer/Korrekte finale antwoord: 1 000 g OR 1 kg ✓ m(CH4) = n(CH4) x M (CH4) = 62,5 x 16  (d) =1000g/ 1kg  (e) (5) [22] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 4 FS/VS/September 2024 Grade/Graad 12 Prep. Exam./Voorb. Eksam. Marking Guidelines/Nasienriglyne QUESTION 3/VRAAG 3 3.1 Marking criteria/Nasienkriteria: If any of the underlined key phrases in the correct context is omitted, deduct 1 mark. Indien enige van die onderstreepte sleutelfrases in die korrekte konteks weggelaat word, trek 1 punt af. The temperature at which the vapour pressure of a liquid is equal to the atmospheric pressure. Die temperatuur waarby die dampdruk van 'n vloeistof gelyk is aan die atmosferiese druk.       (2) 3.2.1 FROM A TO C • Increase branching/smaller surface area/more compact ✓ • Weaker intermolecular forces ✓ • Less energy needed to break the intermolecular forces ✓ • Boiling point decreases ✓ VANAF A TOT C • Vergroot vertakking/kleiner oppervlakte/meer kompak • Swakker intermolekulêre kragte • Minder energie benodig om die intermolekulêre kragte te breek • Kookpunt neem af (4) 3.2.2 C/2,2-dimethylpropane / dimetielpropaan ✓ (1) 3.2.3 Lowest boing point / Laagste kookpunt ✓ (1) 3.3 Greater than (103 °C) ✓ • Between compound D/pentanal molecules are dipole-dipole forces✓ (and London forces) and between compound E/butanoic acid are hydrogen bonds✓ (dipole-dipole and London forces). • Dipole-dipole forces are weaker than hydrogen bonds. ✓ OR Intermolecular forces between compound D/pentanal molecules are weaker than those between compound E/butanoic acid molecules. OR Less energy is needed to break the intermolecular forces between pentanal molecules. Groter as (103 °C) • Tussen verbinding D/pentanale molekules is dipool-dipoolkragte (en Londen-kragte) en tussen verbinding E/butaansuur is waterstofbindings (dipool-dipool en Londen-kragte). • Dipool-dipoolkragte is swakker as waterstofbindings. OF Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 5 FS/VS/September 2024 Grade/Graad 12 Prep. Exam./Voorb. Eksam. Marking Guidelines/Nasienriglyne Intermolekulêre kragte tussen verbinding D/pentanale molekules is swakker as dié tussen verbinding E/butaansuurmolekules. OF Minder energie benodig om die intermolekulêre kragte tussen pentanale molekules te breek. (4) 3.4 Yes/Ja ✓ (1) 3.5 Comparable molecular masses AND only functional group (homologous series) changed/only 1 independent variable ✓ Vergelykbare molekulêre massas EN enigste funksionele groep (homoloë reeks) verander/slegs 1 onafhanklike veranderlike. (1) [14] QUESTION 4/VRAAG 4 4.1 A reaction of a halogen with a compound.   'n Reaksie van 'n halogeen met 'n verbinding.     (2) 4.2.1 Heat/Sunlight/UV light / Hitte/Sonlig/UV-lig  (1) 4.2.2 HBr  (1) 4.3 CH3CH2Br ✓ + NaOH/ ✓ CH2CH2 ✓ + NaBr/ ✓ + H2O ✓ KOH/LiOH KBr/LiBr (5) 4.4 Addition/Hydration / Addisie/Hidrasie ✓ (1) 4.5 Methanoic acid / Metanoësuur ✓✓ (2) 4.6 Esterification/Condensation / Verestering/Kondensasie ✓ (1) ✓ 4.7 ✓ ✓ ✓ + H2O ✓ (4) [17] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 6 FS/VS/September 2024 Grade/Graad 12 Prep. Exam./Voorb. Eksam. Marking Guidelines/Nasienriglyne QUESTION 5/VRAAG 5 5.1 Mass meter/Scale / Massameter/Skaal  (1) 5.2 Calcium carbonate / Kalsiumkarbonaat  (1) 5.3 • Change in concentration/mass/amount/volume ✓ of reactants/products per unit time. ✓ • Concentration/amount/mass/volume of reactants used/products formed per unit time. • Rate of change in concentration/amount/mass/volume. (2 or 0) • Verandering in konsentrasie/massa/hoeveelheid/volume van reaktante/ produkte per tydseenheid. • Konsentrasie/hoeveelheid/massa/volume van reaktante gebruik/produkte gevorm per tydseenheid. • Tempo van verandering in konsentrasie/hoeveelheid/massa/volume. (2) 5.4 Marking criteria/Nasienriglyne: • Mass of CO2 formed/Massa van CO2 gevorm: 270-268,4 or/of 1,6g  m • Substituting/Vervanging 44 in n =  M • Substitute number of moles of CO2 in the rate formula  Vervang die aantal mol CO2 in die tempoformule • Substitute time in the rate formula / Vervang tyd in die tempoformule  • Correct final answer/Korrekte finale antwoord  • Range/Gebied: 0,001 to 0,0013 mol∙s-1 m n(CO2) = M 1,6 ✓ (a) = 44 ✓ (b) = 0,03636 mol △n Rate/Tempo = ( ) △t 0,03636-0 =( ) ✓ (c) 30-0 ✓ (d) = 1,21 x 10-3 (mol·s-1)  (e) (5) 5.5 Experiment 1 /Eksperiment 1  (1) 5.6 • High concentration results in more particles per unit volume  • More effective collisions per unit time/frequency of effective collisions increases   • Higher rate of reaction ✓/Higher rate of formation of CO2. • •• Hoë konsentrasie lei tot meer deeltjies per eenheid volume •• Meer effektiewe botsings per tydseenheid/frekwensie van effektiewe botsings neem toe • Hoër reaksietempo/Hoër tempo van vorming van CO 2. (3) [13] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 7 FS/VS/September 2024 Grade/Graad 12 Prep. Exam./Voorb. Eksam. Marking Guidelines/Nasienriglyne QUESTION 6/VRAAG 6 6.1.1 Rate of forward reaction is equal to rate of reverse reaction. ✓ Tempo van voorwaartse reaksie is gelyk aan tempo van terugwaartse reaksie. (2) 6.1.2 Addition of a catalyst / Addisie van 'n katalisator  (2) 6.1.3 (a) Decreased / Toeneem  (1) (b) Exothermic / Eksotermies (1)  (c) ● Decrease in temperature favours an exothermic reaction .  • The forward reaction is favoured /rate of forward reaction decreased less than that of the reverse reaction. • Verlaging in temperatuur bevoordeel 'n eksotermiese reaksie. • Die voorwaartse reaksie word bevoordeel/tempo van voorwaartse reaksie het minder afgeneem as dié van die terugwaartse reaksie (2) 6.2.1 When the products can be converted back to reactants ✓ Wanneer die produkte terug na reaktante omgeskakel kan word (1) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 8 FS/VS/September 2024 Grade/Graad 12 Prep. Exam./Voorb. Eksam. Marking Guidelines/Nasienriglyne 6.2.2 CALCULATIONS USING NUMBER OF MOLES/ Mark allocation: (a) USING ratio NOCℓ : NO : Cℓ2= 2:2:1 (b) Change in number of moles of NO = equilibrium moles of NO Equilibrium number moles of Cℓ2 = change in moles of Cℓ2 (c) Equilibrium moles NOCℓ = initial moles NOCℓ – change moles of NOCℓ  (d) Dividing equilibrium moles NOCℓ and Cℓ2 by 2 AND mutiplying equilibrium concentration NO by 2  (e) Correct Kc expression (formulae in square brackets)  ✓ (f) Correct substitution of concentrations into Kc correct expression  (g) Final answer : 0,33  BEREKENINGE MET GEBRUIK VAN AANTAL MOL Puntetoekenning: (a) GEBRUIK verhouding NOCℓ : NO : Cℓ2= 2:2:1 (b) Verandering in aantal mol NO = ewewigsmol NO Ekwilibriumgetal mol Cℓ2 = verandering in mol Cℓ2 (c) Ekwilibrium mol NOCℓ = aanvanklike mol NOCℓ – verander mol van NOCℓ (d) Deel ewewigsmol NOCℓ en Cℓ2 deur 2 EN vermenigvuldig ewewigkonsentrasie NO met 2 (e) Korrekte Kc-uitdrukking (formules tussen vierkantige hakies) (f) Korrekte vervanging van konsentrasies in Kc korrekte uitdrukking (g) Finale antwoord : 0,33 NOCℓ NO Cℓ2 Initial quantity (mol) Aanvanklike hoeveelheid (mol) 4 0 0 Change 1,8 1,8 Ratio ✓ (a) Verander (mol) 0,9 Verhouding Quantity at equilibrium (mol) ✓ (c) 2,2 1,8 0,9 ✓(b) Hoeveelheid by ewewig (mol) Equilibrium concentration (mol∙dm-3) ✓(d) Ekwilibriumkonsentrasie (mol∙dm-3) 1,1 0,9 0,45 ÷&x2 [NO]2 [Cl2] Kc = ✓ (e) [NOCl]2 (0,9)2 (0,45) Kc = ✓(f) 1,1 Kc = 0,33 ✓(g) Wrong Kc expression / Verkeerde Kc uitdrukking Max/Maks: 4⁄7 No Kc expression followed by correct substitutions / Geen Kc-uitdrukking gevolg deur korrekte vervangings Max/Maks: 6⁄7 (7) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 9 FS/VS/September 2024 Grade/Graad 12 Prep. Exam./Voorb. Eksam. Marking Guidelines/Nasienriglyne CALCULATIONS USING CONCENTRATIONS Mark allocation: (a) Initial concentration of NOCℓ = initial moles of NOCℓ  2  (b) USING ratio NOCℓ : NO: Cℓ2 = 2:2:1 (c) Change in concentration of NO = equilibrium concentration of NO Equilibrium concentration of Cℓ2 = change in concentration of Cℓ2  (d) Equilibrium concentration of NOCℓ = initial concentration of NOCℓ – change in concentration of NOCℓ  (e) Correct Kc expression (formulae in square brackets)  (f) Correct substitution of concentrations into Kc expression  (g) Final answer : 0,33  BEREKENINGE DEUR KONSENTRASIES Puntetoekenning: (a) Aanvanklike konsentrasie van NOCℓ = aanvanklike mol NOCℓ  2 (b) GEBRUIK verhouding NOCℓ : NO: Cℓ2 = 2:2:1 (c) Verandering in konsentrasie van NO = ewewigskonsentrasie van NO Ekwilibriumkonsentrasie van Cℓ2 = verandering in konsentrasie van Cℓ2 (d) Ekwilibriumkonsentrasie van NOCℓ = aanvanklike konsentrasie NOC – verandering in konsentrasie van NOCℓ (e) Korrekte Kc-uitdrukking (formules tussen vierkantige hakies) (f) Korrekte vervanging van konsentrasies in Kc uitdrukking (g) Finale antwoord: 0,33 NOCℓ NO Cℓ2 Initial concentration (mol∙dm-3l) Aanvanklike konsentrasie 2 0 0 (mol∙dm-3l) ✓ (a) ✓(c) Change concentration (mol∙dm-3) Ratio ✓ (b) 0,9 0,9 Verander konsentrasie (mol∙dm-3) 0,45 Verhouding Equilibrium concentration (mol∙dm-3) Ekwilibriumkonsentrasie (mol∙dm-3) 1,1 ✓ (d) 0,9 0,45 2 [NO] [Cl2] Kc = ✓ (e) [NOCl]2 (0,9)2 (0,45) ✓(f) Kc = 1,1 Kc = 0,33 ✓(g) Wrong Kc expression / Verkeerde Kc uitdrukking Max/Maks: 4⁄7 No Kc expression followed by correct substitutions / Geen Kc-uitdrukking gevolg deur korrekte vervangings Max/Maks: 6⁄7 (7) [16] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 10 FS/VS/September 2024 Grade/Graad 12 Prep. Exam./Voorb. Eksam. Marking Guidelines/Nasienriglyne QUESTION 7/VRAAG 7 7.1.1 The reaction of salt with water  Die reaksie van soutwater met water (2) 7.1.2 Acidic/Suur  (1) + 7.1.3 NH+4 (aq) + H2O(ℓ)  → NH3 + H3 O (aq)  OR / OF + + NH4 (aq) + 2H2O(ℓ)  → NH4OH + H3 O (aq)     (3) 7.2.1 Strong (acid) / Sterk (suur)      (1) 7.2.2 Ionises/dissociate completely in waterto form a high concentration of H3O+ ions.  Ioneer/dissosieer heeltemal in water om 'n hoë konsentrasie van H3O+ ione te vorm. (2) 7.2.3 Methyl orange / Metiel oranje  (1) 7.2.4 Titration of strong acid  and weak base  Titrasie van sterk suur en swak basis (2) 7.2.5 Marking criteria/Nasienriglyne: n • Formula / Formule c =  V • Substitute / Vervang 0,1 AND / EN 25 x 10-3 in n = cV  • Final answer/Finale antwoord: 0,0025 mol  n c=  V n = 0,1 x 25 x 10-3  n = 2,5 x 10-3 mol / 0,0025 mol (ACCEPT/AANVAAR: 0,003 mol) (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 11 FS/VS/September 2024 Grade/Graad 12 Prep. Exam./Voorb. Eksam. Marking Guidelines/Nasienriglyne 7.2.6 Marking criteria/Nasienriglyne: (a) Ratio / Verhouding n(HCℓ) = n(NH3)  n (b) Formula / Formule c = V / pH = -log[H3O+]  (c) Substituting n(NH3) and volume of 0,04dm3 / Vervang n(NH3) en volume van 0,04dm3 (d) Subtraction / Aftrekking: c(HCℓ)initial – c(HCℓ)used  (e) c(H3O+) = c(HCℓ)  (f) Substituting / Vervanging c(H3O+) in pH = -log[H3O+]  (g) Final answer / Finale antwoord = 1,43  RANGE: 1,4 – 1,6 n(HCℓ) = n(NH3) (a) = 2,5 x 10-3 n c(HCℓ) = V 2,5 x 10-3 = (c) 0,04 = 0,0625 mol·dm-3 ANY/ENIGE 1 (b) c(HCℓ) excess/oormaat = 0,1 – 0,0625 (d) = 0,0375 mol·dm-3 c(H3O+) = c(HCℓ) (e) = 0,0375 pH = -log[H3O+] = -log(0,0375) (f) = 1,43 (g)         (8) [23] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 12 FS/VS/September 2024 Grade/Graad 12 Prep. Exam./Voorb. Eksam. Marking Guidelines/Nasienriglyne QUESTION 8/VRAAG 8 8.1 Concentration / Konsentrasie = 1 mol·dm-3 ✓ Temperature / Temperatuur = 25 °C ✓ (2) 8.2.1 Potassium nitrate/KNO3/Any soluble salt ✓✓ Kaliumnitraat/KNO3/Enige oplosbare sout (2) 8.2.2 Cℓ- ✓ (1) ✓ 8.2.3 Pt(s) | Cℓ-(aq)│Cℓ2(g) ✓|| Au3+(aq) | Au(s) ✓ (3) 8.3 OPTION/OPSIE 1 Notes/Aantekeninge: Eθcell = Eθreduction - Eθoxidation  Accept any other correct formula from the data sheet. 0,14 = Eθreduction  – 1,36  Aanvaar enige ander korrekte formule uit die θ Ereduction = 1,5 V  datablad. Any other formula using unconventional Eθsel = Eθredukusie - Eθoksidasie     abbreviations, e.g. E =E cell −E OA RAfollowed 0,14 = Eθreduksie  – 1,36  by correct substitutions: 3⁄4 Eθreduksie = 1,5 V  Enige ander formule wat onkonvensionele    afkortings gebruik, bv. E =E cell −E OA gevolg RA 3 deur korrekte vervangings: ⁄4 OPTION/OPSIE 2 Au3+ + 3e- → Au Eθ = 1,5 V   2Cℓ- → Cℓ2 + 2e- Eθ = -1,36 (V)  6 Cℓ- + 2Au3+ → 3Cℓ2 + 2Au Eθ = 0,14 (V)  (4) [12] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 13 FS/VS/September 2024 Grade/Graad 12 Prep. Exam./Voorb. Eksam. Marking Guidelines/Nasienriglyne QUESTION 9/VRAAG 9 9.1 The chemical process in which electrical energy is converted to chemical energy/ use of electrical energy to produce a chemical reaction.    Die chemiese proses waarin elektriese energie na chemiese energie omgeskakel word/gebruik van elektriese energie om 'n chemiese reaksie te produseer.        (2) 9.2 X         (1) 9.3.1 2Cℓ- → Cℓ2 + 2e-  Marking criteria/Nasienkriteria: • 2Cℓ - ⇌ Cℓ2 + 2e- 12 Cℓ2 + 2e- ⇌ 2Cℓ - 0 2 - - - - Cℓ2 + 2e → 2Cℓ 0 2 Cℓ2 + 2e ← 2Cℓ 2 2 • Ignore if charge omitted on electron/Ignoreer as lading op electron weggelaat is • If charge (-) omitted on Cℓ -/Indien lading (+) weggelaat is op Cℓ -: Max./Maks: 1 2 Example/Voorbeeld: 2Cℓ → Cℓ2 + 2e- (2) 9.3.2 2H2O + 2e- → H2 + 2OH-  Marking criteria/Nasienkriteria: • 2H2O + 2e- ⇌ H2 + 2OH- 1 H2 + 2OH- ⇌ 2H2O + 2e- 0 2 2 H2 + 2OH ← 2H2O + 2e 2⁄2 - - H2 + 2OH- → 2H2O + 2e- 0⁄2 • Ignore if charge omitted on electron / Ignoreer as lading op elektron weggelaat is • If charge (-) omitted on OH- Indien lading (-) op OH- weggelaat is Max./Maks: 1 2 Example / Voorbeeld: 2H2O + 2e- → H2 + 2OH (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 14 FS/VS/September 2024 Grade/Graad 12 Prep. Exam./Voorb. Eksam. Marking Guidelines/Nasienriglyne 9.4 Marking criteria/Nasienriglyne: (a) Substitute / Vervang 0,5 x 18 000  (b) Dividing charge by / Deel lading deur 1,6 x 10-19  (c) Dividing number of electrons by Avogadro’s constant.  Deel die aantal elektrone deur Avogadro se konstante. (d) Using ratio / Gebruik verhouding n(Cℓ) : n(e-) = 1:2  V (e) Substituting / Vervanging n(Cℓ2) and / en 22,4 in n = V  m (f) Final answer / Finale antwoord 1,04 dm3  Range / Gebied: 1,04 to 1,12 dm3 Q = I△t = 0,5 x 18 000 (a) = 9 000 C Q n= qe 9 000 n = -19 ✓ (b) 1,6 x 10             = 5,625 x 1022 electrons / elektrone 5,625 x 1022 n(electrons) = 6,02 x 1023 ✓ (c) = 0,093 mol 1 n(Cℓ2) = 2n(e-) = 0,093  2 (d) = 0,0465 mol V n= Vm V = 0,0465 x 22,4 (e) = 1,04 dm3 (f) (6) [13] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief