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Physical Sciences Grade 12 Paper 2 Limpopo June 2025 Memo

MemorandumPhysical SciencesGrade 1220258 pages

Grade 12 Physical Sciences Paper 2 memorandum from the Limpopo June Exam 2025, 8 pages. Read online or download the free PDF.

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Limpopo June Exam 2025

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DoE/June 2025 “NSC pik, LIMPOPO PROVINCIAL GOVERNMENT REPUBLIC OF SOUTH AFRICA DEPARTMENT OF EDUCATION NATIONAL SENIOR CERTIFICATE PHYSICAL SCIENCES (PHYSICS) PAPER 2: MAY - JUNE 2025 MARKS: 150 TIME: 3 Hours This Marking Guidelines consist of 8 pages including the cover page Copyright reserved Please turn over
QUESTION 1 1100 AY 1.2 Cvv 1.3 Cvy 1.4 _ are ALS BYY 1.6 Byy 1.7 ore 1.8 Cv¥v 1.9 Av’ 1.10 Byy QUESTION 2 2.1 21.1 Fr 212 CH 2.1.3 AY 2.1.4 FY 2.1.5 Av and HY 2.16 Gv 21.7 EF 2:2 2.2.1. 2-methylv butanev 2.2.2 methyl”propan-2-olv v 2.2.3 2-bromov butanalv Copyright reserved DoE/June 2025 Notes: 1. Methyl identifiedy 2. Propanolv 3. Whole structure correctv’ Please turn over (2) (2) (2) (2) (2) (2) (2) (2) (2) (2) [20] (1) (1) (1) (1) (2) (1) (1) (2) (3) (2)
DoE/June 2025 2.2.4 3,3-dimethylv pent-1-ynev Vv Notes: 1. dimethyl identifiedv 2. Pentynev 3. Whole structure correctv (3) Zid 2.3.1 i H , HOY jaar, Notes: Cc Fi \ \ 1. Correct functional groupy 2. Whole structure correctv (2) 23:2 HH 8 woet-€ v Notes: hu 2 1. Correct functional groupY 4 2. Whole structure correctY (2) 2.4 2.4.1 CsaHeQ2v” (1) 2.4.2 fe) i tiv -C—C—C— | | (1) 2.4.3 CHsCOOHv v/(Accept: CHs - COOH) (2) 2.4.4. Methanolv (1) 2.4.5 Formylv (group)/Accept: carbonyl (1) 2.4.6 Alkynev (1) [29] QUESTION 3 3.1 3.1.1. The temperature at which the vapour pressure is equal to the atmospheric pressure.” ¥ (2 or 0) (2) 3.1.2 Thermometerv /Accept: Bunsen burner/heat source/flame (1) 3.2 3.2.1. Molar mass”/molecular size/chain length/number of C atoms/surface ined (1) Copyright reserved Please turn over
DoE/June 2025 3.2.2 Boiling point” (1) 3.2.3 Relationship between dependant and independent variables: As molar mass/molecular size/chain length increasesv the boiling point also increases. Vv OR 4 molec msssinoecusr xathnn Inf decesser” the ella okt (DIRECTLY PROPORTIONAL NOT ACCEPTED) (2) 3.3 London forcesv (2) 3.4 Ev (1) 3.5 E has a smaller surface area/shorter chain length/more sphericalv than D therefore the intermolecular forces in E are weaker” and need less (3) energy to overcome than those in D. ¥ [13] QUESTION 4 4.1 Secondary.” The carbon atom bonded to the halogen/chlorine, is bonded (3) to two other carbon atoms.v¥ 4.2 Substitution/hydrolysis Vv” (2) 4.3 CH3aCH(OH)CH2CH3” — CHsCHCHCHs + H2Ov (” balancing) (3) 44 Dilute strong base/Dilute NaOH v/Excess water/moderate heat/ethanol as solver (2) 4.5 Suiphuric acidy H2SO4v (2) 4.6 Hydrohalogenation/hydrochlorinationY (1) [13] Copyright reserved Please turn over
QUESTION 5 5.1 5.2 5.3 5.4 5.5 5.6 5.7 5.8 5.9 DoE/June 2025 Reactant that is totally consumed when a chemical reaction is completed. v v (2) CaCOs is the limiting reagentv’ (1) N(caco3) = rd = wav (3) = 0,004molv (1) 0,004molY n Rate = rad = COON 10 = 0,0004mol/sv (3) co, formed = Ncaco,)Teae 0,004molvY = 0,896dm3v When concentration is increased, there are more reactant particlesY in the same volume, the number of effective collisions per unit time increase, v V increase in the rate of reaction. (3) Decreases.” When granules are used, the surface area decreasesY and therefore the number of effective collisions per unit time decreases. @) The reaction is complete/CaCOs has been used up.¥ (1) Copyright reserved Please turn over
DoE/June 2025 5.10 5.10.1 Cv (1) 5.10.2 Dv (1) 5.10.3 The average kinetic energy is the samev as for graph A showing that the temperature is the same. The area under the graph D is @) double/largerY showing that the quantity of nitrogen gas is larger. v [26] QUESTION 6 6.1 OPTION 4 2802 OQ2 280s Initial amount(mol) | x 1,25v 0 v (ratio) Change | 1,0 0,5 1,0 Equilibrium amount x-1,0 0,75 1,0 v Equilibrium conc. x—1,0 1,5 05 v (+ 0,5) OPTION 2 [- _ | 2802 Oz 2S03 Initial amount(mol) <3 y 05 2,5 0 ¥(+0,5) Change -2 -1 +2 ¥ (ratio) | Equilibrium amount | _*_ _ 5 15 2 - 0,5 _ _[s03}? Ke = Sosttion 42,67 = — Fy aty'as) x = 1,125(mol)v (8) 6.2 6.2.1 Concentration of O2 increased.v v (2) 6.2.2 Pressure was increased.v v (2) 6.2.3. Increase in pressure favours the reaction that produces less number of moles.v The forward reaction was favoured.v As the concentrations of the reactants decrease,” the concentration of the products increases.v (4) Copyright reserved Please turn over
DoE/June 2025 6.3 6.3.1. System that is isolated from its surroundings.vv/ A system that does not . (2) 6.3.2 Turns yellow.” (1) 6.3.3 Sodium hydroxide reacts with H* and reduces their concentration.v The forward reaction is favoured.v The concentration of chromate ions increases.’ (3) [22] QUESTION 7 7.1 An acid is a proton (H* ion) donor.v ¥ (2) 7.2 7.2.1. HCfLand Civ H3O* and H20 ¥ (2) 7.2.2 Substance that can either act as acid or base.vv (2) 7.2.3 H20Y (1) 7.2.4 HsO*v (1) 7.2.5 OPTION1 c= ay = 3,65 (36,5)(0,2) =0.1 mol 5 a 3) 20.5 mol.dm? Copyright reserved Please turn over
7.3 7.2.6 7.3.1 7.3.2 DoE/June 2025 (0) NaOH + HNOsv — NaNO; + H2OvY (reactants, products, balancing) (3) Number of moles of MgCo»/ m n= ET RATE ACRES = Ley 84 = 0,02mol sf Number of moles of ve which reacted with MgCO3 n = 2(0,02)” = 0,04mol Let the initial concentfation of the acid be x n c= Vv Vv n 0,039 «n= 0,039x n(HNO); in 12cm? = 0,012xv Ratio HNOs:NaGH = 1 : 1 «. n(NaOH) in A5cm? = 0,012xv 3) = 0,039x — 0,02xv = 0,019x 9x = 0,04 x=2,11 03] = 2,11moldm-3v (0) [27] Copyright reserved Please turn over

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