Physical Sciences Grade 11 LP March Test 2026 Paper & Memo

Downloaded from Stanmorephysics.com PhySicalSciences/Gr 11 a . . ” / . 1 . o w s ¢ MARKS: 100 TIME: 2 hours LDoE/March., 2026 “ety, LIMPOPO es “+ PROVINCIAL GOVERNMENT REPUBLIC OF SOUTH AFRICA DEPARTMENT OF EDUCATION NATIONAL NIOR CERTIFICATE GRADE 11

Downloaded from Stanmorephysics.com Confidential Information - This is for official consumption Physical Sciences/Gr 11 2 LDoE/March, 2026 INSTRUCTIONS AND INFORMATION if 10. 11. 12. Write your centre number and examination number in the appropriate spaces on the ANSWER BOOK. This question paper consists of SEVEN questions. Answer ALL the questions in the ANSWER BOOK. Start EACH question on a NEW page in the ANSWER BOOK. Number the answers correctly according to the numbering system used in this question paper. Leave ONE line between two sub questions, for example between QUESTION 2.1 and QUESTION 2.2. You may use a non-programmable calculator. You may use appropriate mathematical instruments. You are advised to use the attached DATA SHEETS. Show ALL formulae and substitutions in ALL calculations. Round off your final n vers" 4jminimum of TWO decimal places. Give brief motivations ) a where required. Write neatly and legibly. Copyright reserved

“Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 3 LDoE/March. 2026 QUESTION 1: MULTIPLE-CHOICE QUESTIONS Four options are provided as possible answers to the following questions. Each question vas only ONE correct answer. Write only the letter (A — D) next to the question number (1.41.10) in the ANSWER BOOK, for example 1.11 D. 1.4 The statement below refers to the vector and scalar quantities. (i) A vector has magnitude and direction, while a scalar has magnitude only. (ii) | A-scalar quantity can always be added to a vector quantity. (iii) | Force is an example of a vector quantity, while distance is an example of a scalar quantity. Which of the above statements is /are TRUE? A (i) and (ii) only B (i) and (iii) only C (ii) and (iii) only D_ (i) only (2) Four forces act on a body in jorephysics.com and direction of the resultant force? C 8Neast D 8Nsouth (2) Copyright reserved Please turn over

Downloaded from Stanmorephysics.com LDoE/March. 2026 ~ If) net force F is applied on an object of mass m kg and causes an acceleration In of am-s-. When the net force F on the same object is doubled, the resulting I NNN cceleration, in m-s~, will be ... ¢ f oe | = Nf a (2) ards along a frictionless slope, own in the sketch below. Which ONE of the following equations can be used to calculate the magnitude of the normal force (N)? A N=(4)(9,8)sin8 B N=F-(4)(9,8)cos' N =F + (4)(9,8)cos6 ie: D N=(4)(9,8)cos@ (2) Sidhimorephysics.com Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 LDoE/March, 2026 15 5 agnitude F acts on a Ree at.an.angle @ to the horizontal, as agi e 1 DIOCK wit at rest on a flat, frictionless DRCE and the NET NORMAL NET HORIZONTAL FORCE A Increases Increases B Decreases Increases Cc Increases Decreases D Decreases Decreases (2) 1.6 Three objects of mass 1 spectively, are suspended by a light string as shown i 2kg 0,7 kg A 15N B 42N C 27N D 35N (2) Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 6 LDoE/March. 2026 ectively exert a force F on each What is the new force that the bodies exert on each other, in terms of F? A 8F B 16F Cc 4F D 2F (2) 1.8 The distance between two charges, Q: and Q: is r. The force exerted by the spheres on each other is F. Both charges are now doubled without changing the distance between them. The magnitude of the electrostatic force on Q1 will be: A 4F BMF C 2F D “AF (2) 1.9 Which one of the following diagrams indicates the direction of magnetic fields and how it is determined with a test charge around charged sphere: correct! (2) Copyright reserved Please turn over

_ Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 7 LDoE/March. 2026 1.10 A negative charge Q is placed at a distance of 5d from another charge R. Q Pgneutteaep e . e #------------- caine > RATIO OF THE CHARGES | CHARGE ONR Q:R A 4:9 Positive B 3:2 Negative Cc 5:2 Positive D 9:4 Negative (2) [20] QUESTION 2 (Start on a new page) $, as shown in the diagram below. in rope A, is 530 N and the force (0° with the horizontal and rope B A heavy object is lifted using two The two pulleys are a distance Fs, in rope B, is 1 240 N. Rope makes an angle of 20° with the verti FA =530N FB = 1240N 2.1. Define the term resultant vector. (2) 2.2 Explain why the vector diagram of force Fa, force Fe and the weight will NOT be a closed vector diagram. (2) 2.3 Calculate the: 2.3.1 Vertical component of Fa (2) 2.3.2 Horizontal component of Fa (2) Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 8 LDoE/March. 2026 2.4 Calculate the maximum weight that force Fa and force Fe will be able to lift from the ground. Show ALL calculations. (4) 25 Explain why the rope and pulley system will be less effective if the distance x between the pulleys is increased (2) [14] QUESTION 3 (Start on a new page) A horizontal force, F, is applied to a 200 kg block by means of a massless, inextensible rope, as shown in the sketch below. The block remains stationary when the rope makes an angle of 15° with the vertical... wig 3.1 Explain why the block is st (2) 3.2 Determine the magnitud (4) 3.3 Determine the magnitude F. (3) [09] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 9 LDoE/March. 2026 QUESTION 4 (Start on a new page.) A block Of mass 4 kg is sliding down a rough plane (AB) inclined at 30° to the horizontal, as shown in the diagram below. The coefficient of kinetic friction between the surface and the block is 0.2. A c 4.1 Define the term frictional force. (2) 4.2 Calculate the magnitude of the: 4.2.1. Kinetic frictional force between the 4 kg block and the surface (3) 4.2.2 Acceleration of block while is moving on section AB (5) The block is NOW moving on s : n is frictionless. 4.3. Will the block in section BC” LOWER, a HIGHER or a ZERO ACCELERATION? Give the f the answe (2) [14] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 10 LDoE/March. 2026 QUESTION 5 (Start on a new page.) 4kg respectively. 5.1 State Newton's second law of motion in words. (2) 5.2 Drawa labeled free-body diagram showing all the forces acting on the 4 kg block (4) 5.3. Calculate the magnitude of the: 5.3.1 Acceleration of the system. (4) 5.3.2 Tension in the string connecting the two blocks. (2) 5.4 ied IS decreased to 20°. How will the change? Write down only SAME. (1) The angle at which the force frictional force experien INCREASES, DECREA [13] hmorephysics.com Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Confidential Information - This is for official consumption Physical Sciences/Gr 11 1 LDoE/March. 2026 QUESTION 6 (Start on a new page.) A satellite of mass 1 200 kg is orbiting the Earth at a distance d from the surface of the Earth as shown on the diagram below. Earth The radius of the Earth is 20 times the atstone 6.1 State Newton's Law of Universal Gravitation in words (2) 6.2 Calculate the: 6.2.1 Distance between the ce of the:Earth and the centre of satellite (Distance d). z (2) 6.2.2 Magnitude of the fo on the satellite to keep it in orbit (4) 6.3 Calculate the weight of the s (2) [10] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 12 LDoE/March. 2026 QUESTION 7 (Start on a new page.) Three charged spheres, A, B and C, with charges of -4 nC, +7 nC and +10 nC respectively, are placed on rubber stands as shown below A B c 7.1 Can metal stands be used instead of rubber stands? Write down only YES or NO. Give a reason for the answer. 7.2 State Coulomb's law in words. 7.3 Calculate the net force acting on charge C. 7.4 Aand B are brought into n Adetinen separated. Charge A is returned to it ile charge B is removed. 7.4.1 In which direction did | Choose from A to B of 7.4.2 Calculate the number of ele ansferred to or from charge AtoB. (2) (2) (4) (1) (5) Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical 'Seiences/Gr 11 13 LDoE/March. 2026 7.5, Acharged sphere A carries a charge of -0.65 UC. It is placed 10 cm away from another charged sphere B, which carries a charge of +0.8 uC, along a ‘straight line in a vacuum. Point P is located 7cm to the right of sphere A. 7.5.1 Define electric field at a point. (2) 7.5.2 Draw electric field lines on sphere A. (2) 7.5.3 Calculate the magnitude of the net electric field at point P. (5) [23] TOTAL: [100] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 14 LDoE/March. 2026 DATA FOR PHYSICAL SCIENCES GRADE 12 PAPER 1 (PHYSICS) GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 12 VRAESTEL 1 (FISIKA) TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES NAME/NAAM SYMBOL/S/IMBOOL VALUE/WAARDE Acceleration due to gravity g 9,8 m-s@ Swaartekragversnelling Universal gravitational constant . ote G 6,67 x 10°11 N-m2-kg? Universele gravitasiekonstant Speed of light in a vacuum P pia c 3,0 x 10° m-s" Spoed van lig in 'n vakuum Planck's constant h 6,63 x 10% J-s Planck se konstante Coulomb's constant 9,0 x 109N-m?-C2 Coulomb se konstante Charge on electron -1,6 x 10°C Lading op elektron Electron mass 9,11 x 10°" kg Elektronmassa Mass of Earth M 5,98 x 10% kg Massa van Aarde Radius of Earth Re 6,38 x 10 km Straal van Aarde Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical Sciences/Gr 11 15 LDoE/March. 2026 TABLE 2: FORMULAE/TABEL 2: FORMULES MOTION/BEWEGING vp=vitadt Ax =v At+4adt? or/of Ay = v,At+taat? Vv =v, + 2adx orlof v,? =v, +2ady | Ax= (“ - Ja orlof Ay = (“Ja FORCE/KRAG Fue: = mal p=mv C= iN f, =y,N F,,,At=Ap Ap= mv, - mv, mm, F=G ae orlof =F ELECTROSTATICS/ELEKTROS kQ,Q Fe 5 2 we! pel q q _Q _Q a or/ of “a Copyright reserved

Downloaded from Stanmorephysics.com fee, LIMPOPO PROVINCIAL GOVERNMENT REPUBLIC OF SOUTH AFRICA DEPARTMENT OF EDUCATION NATIONAL SENIOR CERTIFICATE MARKS/PUNTE: 100 This marking guideline consists of 11 pages/ Hierdie nasienriglyn bestaan uit 11 bladsye

wal Sack oy s/Gr. 11 LDoE/March 2026 rom Stanmonephysiosteam Marking Guidelines/Nasienriglyne QUESTION 1/VRAAG 1 1.1 B vv 1.2 IB vv 13)0.C vv 14 a vv 1S Bw 1. 6a. NG 17 A vv 18 A 4 19°C vv 1.10 D vv [20] QUESTION 2/VRAAG 2 2.1. The sum of two or more vec is acting together on the object. ¥v/ Die som van twee ofn Saam op die voorwerp inwerk OR/OF as two or more vectors together.v “/ fek ee of meer vektore saam (2) 2.2. The object is lifted/mo' ere will be a resultant/net force not equal to zero. “/ Di rp word opwaarts gelig/beweeg. Daar sal 'n resulterende/netto krag wees wat nie gelyk is aan nul nie. (2) 2.3.1 A single vector having the ‘n Enkele vektor met diese Fy = Fa sin 60° = 530(sin60°) ¥ = 458,99 NY (2) 2.3.2 POSITIVE MARKING FROM 2.2/POSITIEWE NASIEN VANAF 2.2 F x = Fa (cos60°) = 530(cos60°) v = 265NV (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asb

wal cade s/Gr. 11 St pe. LDoE/March 2026 rom Stanmerephysiastesm Marking Guidelines/Nasienriglyne 2.4 Fy = Fe cos20° ao 240)cos20°v iv i 1165,21N a y = Fe sin 70° = (1-240)sin70° : a / SIE = 1165,21N Maximum w = Fya + Fys = 265 +1165,21v = 1430,21NV (4) 2.5 If the distance x increases, ihe vertical components of the applied forces will decrease v and tl fill possibly not be able to pick up the weight. “/As die af: x die vertikale komponente van die toegepaste kragte afneem e stelsel moontlik nie die gewig kan optel nie. (2) [14] QUESTION 3/VRAAG 3 3.1 The forces acting on the block are balanced/in equilibrium. “/ Die kragte wat op die blok inwerk, is gebalanseerd/in ewewig OR/OF The resultant/net force is equal to zero. /Die resulterende/netto krag is gelyk aan nul. OR/OF There is no resultant force acting on the box Y / Daar is geen resulterende krag wat op die boks inwerk nie (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asb

Physical Scj s/Gr. 11 A: ee LDoE/March 2026 Downloaded from Stanmorephysiasteam _ 3.2 Copyright reserved/Kopiereg voorbehou Marking Guidelines/Nasienriglyne Fretiy) =O0 Vv Ty=w=mg = (200)(9.8) ¥ = 1960 N OPTION 1/OPSIE 1 aa OPTION 2/OPSIE 2 Ty=T cos 6 1960 = Tcos15° ¥ «T= 2029,14N ¥ OSTIEWE NASIEN VANAF 3.2 14s v= : RIOF 2029,14cos75° =F «F = 525,18 NV «F = 525,18 N OR/OF F Tan 15° = iy F = 1960Tan15° = 528,18 N OR/OF T? = F2 + F,? (Pythag F= Jr- EK? g P= 2029, 147— 19602 F?=257728.18 F=525,18N (4) (3) [09] Please turn over/Blaai om asb

Physical Scjences/Gr. 11 LDoE/March 2026 5 Downloaded from Stanmerephysiasteem Marking Guidelines/Nasienriglyne QUESTION 4/VRAAG 4 4.1. Frictional force: the force that opposes the motion of an object and acts parallel to the surface the object is in contact withY v/ Wrywingskrag: die krag wat die beweging van 'n voorwerp teenwerk en parallel met die opperviak waarmee die voorwerp in kontak is, werk. (2) Marking criteria/Nasien kriteria If any of the underlined key words/phrases in the correct context is omitted deduct/ Indien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks weggelaat word, trek af (2 or/of 0) 4.2 4.2.1 Fhet(y) =0 v f = ukN Any one/enige een = ukmg cos @ f= ! sf, = ae (3) 4.2.2 re orep nn Fnet = ma + “Se | Fgll — fk = ma v mg sin® — uxmgsin 8 =ma Any one/ enige een (4)(9,8)sin30°v — (4)(9,8)sin30° v= (4)av a= 3,20 ms? v (5) 4.3 ZERO ACCELERATIONY/ NUL VERSNELLING The block continues at constant velocity/no frictional force/ the net force is equals to zero. “/Die blok beweeg voort teen konstante snelheid/geen wrywingskrag nie/die netto krag is gelyk aan nul. (2) [14] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asb

Physical Scjences/Gr. 11 LDoE/March 2026 Downloaded from Stanmenephysiasteam Marking Guidelines/Nasienriglyne QUESTION 5/VRAAG 5: 5.1. Marking criteria/Nasien kriteria If any of the underlined key words/phrases in the correct context is omitted deduct/ Indien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks weggelaat word, trek af When a resultant/net force acts on an object, the object will accelerate in the direction of the force atan acceleration is directly proportional to_the resultant/net force and inversely proportional to the mass of the object. vv/ Wanneer 'n resulterende/netto krag op 'n voorwerp inwerk, sal die voorwerp in die rigting van die krag versnel teen 'n versnelling wat direk eweredig is aan die resulterende/netto krag en omgekeerd eweredig aan die massa van die voorwerp. (2 or 0) (2) 5.2 Nv fe ¥ N Fn/ Normal force / Normaal krag / Fnormal / Fnormaat / v 212,18 N fk (kinetic) friction / (kinetiese) wrywing / Fi f / 40 N v F Applied force / Toegepaste krag / Fappiied / Ftoegepas / v Fa w Fg/ Fw/ mg / 245 N/ weight/ gewig / gravitational v force / gravitasie krag Notes/Notas: Mark is awarded for label and arrow./Punte word toegeken vir byskrif en pyl e Do not penalize for length of arrows/ Moenie penaliseer vir die lengte van pyle nie lf arrows do not touch the dot: Max 3/4/ Indien pyle nie die punt raak nie: Maks 3/4/ e_ Any other additional force(s): Max/ % / Enige ander bykomende krag(e): Maks/ 3/4 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asb

wal pac lec s/Gr. 11 y* om LDoE/March 2026 rom Stanmerephysiasteem Marking Guidelines/Nasienriglyne e |f everything is correct, but no arrows: Max %/ Indien alles korrek is, maar geen pyle nie: Maks. 3/4 e If components are drawn: Max % / Indien komponente geteken word: Maks 3/4 (4) 5.3.1 For the 4 kg block/ Vir die 4 kg-blok Fret = ma ‘i T +(- fk) =ma T-2=4av T=4at+ 2.0.0.0... (1) Any one/enige een For the 10 kg block/ Vir die 10 kg-blok Fret = ma Fx -T-fk =ma 60cos 25° ¥ —-T-3,5 =10a 54,378-T-3,5 = 10a (4) 5.3.2, POSITIVE MARKING T = 4(3,491) + 2v T = 15,97 NV SITIEWE NASIEN VANAF 5.3.1 (2) 5.4 Increases. V /Neem toe (1) [13] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asb

Physical Scjences/Gr. 11 8 px LDoE/March 2026 Downloaded from Stanmorephysiasteam Marking Guidelines/Nasienriglyne QUESTION 6/VRAAG 6: 6.1 Any two objects attract each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of the _ distance between their centresY “/ Enige twee voorwerpe trek mekaar aan met 'n krag wat direk eweredig is aan die produk van hul massas en omgekeerd eweredig aan die kwadraat van die afstand tussen hul middelpunte. (2) 6.2.1 R=20d . 7 (2) _ (6,67 x 10711)(5,98 x 10 Fe= (6,69 x 10° F = 1,06x104 NY (4) 6.3 W=mgv =1200x9,8Y Suu a = 1,18 x 104 NV (2) [10] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asb

canalee Scjences/Gr. 11 LDoE/March 2026 loaded from Stanmenephysiasteam Marking Guidelines/Nasienriglyne QUESTION 7/VRAAG 7: 7.1. NO V/NEE The spheres will lose their chargev/ Die sfere sal hul lading verloor OR/OF The metal stands are electrical conductors / Die metaalstaanders is eleKtriese geleiers (2) 7.2 The magnitude of the electrostatic force exerted by one point charge on another point charge is directly proportional to the product of the magnitudes of the chargesv and inversely proportional to the square of the distance between them. v / Die grootte van die elektrostatiese krag wat deur een puntlading op 'n ander puntlading uitgeoefen word, is direk eweredig aan die produk van die groottes van die ladings en omgekeerd eweredig aan die kwadraat van die afstand tussen hulle. 107 (2) 7.3 OPTION 1/OPSIE 1 paki; , r? — (9 x 109)( 4x 107 CA = (0, = 4,28 x 10-°N ui (9x 10°)(7 x 107-°)(10 x 107°) ce = v (0,17)? = 2.18 x 10-5N Fnet = Fos - Fea = 2,18 x 1075 -v (4,28 x 10~°) = 1,75 x 10 ©N to the right“/na regs Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asb

Dowhilo oar jences/Gr. 11 10 x LDoE/March 2026 led from Stanmenephysiesteam Marking Guidelines/Nasienriglyne OPTION 2/OPSIE 2 _ (9x 10°)(4x 107°) , ~ (0,29)2 = 428,06 N.C t= (2 736 x12 x 10° ) 3,28 x 10 © N due Eastv/ reg oos (4) 7.4.1 A tolna BY (1) 742 Q =2t& #c5,cCOoMm Q =15x10°C Charge transferred/lading oorgedra = 1,5 x 10-°-v (—4 x 107°) =5,5 x 107°C OR/OF = 15 x 10°°-7 x 107°) > =-5,5 x 10-°C n= ay qe _ 5,5x107? ~ 1,6 x 10719 n= 3,44 x 10?° (electrons/elektrone) V (5) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asb

Physical Scjences/Gr. 11 LDoE/March 2026 Downloaded from Stanmenephysiasteam Marking Guidelines/Nasienriglyne 7.5.1 The electric field at a point is the electrostatic force experienced per unit positive charge placed at that point.vv / Die elektriese veld by 'n punt is die elektrostatiese krag wat per eenheid positiewe lading wat by daardie punt geplaas word, ervaar word (2 orlof0) = (2) 152 Notes/Notas: more than one charge or combined field_drawn 0/2 /meer as een lading of gekombineerde veld geteken 0/2 Criteria for sketch/Kriteria vir skets: Correct shapev / korrekte vorm Correct direction towards the charge / Korrekte rigting na die lading / Nota: If electric field lines $ or touch 1/2 / As elektriese llyne kruis of raak 1/2 (2) 753. _ kQ E= nm v (9 x 10°)(0,65 x 107°) A = YY (0,07)? = 1,19 x 10 ®N.C* _ (9x 10)(0,8 x 107°) | ~ (0,03)2 = 8,0 x 10 §N.C* Enet = Ea + Es = (1,19 x 10 ®) + (8,0 x 10 §) v Enet = 9,19 x 10 ®N.C1 ¥ (5) TOTALITOTAAL: [100] Copyright reserved/Kopiereg voorbehou