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SENIOR CERTIFICATE
GRADE 11
TECHNICAL MATHEMATICS P2
NOVEMBER EXAMINATION 2026 (MOCK)
MARKS: 150
TIME: 3 hours
This question paper consists of 12 pages and a 2-page information sheet.
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Technical Mathematics Grade 11 P2 2026 QP (Eng)
Grade 11 Technical Mathematics Paper 2 question paper from the November Mock Exam 2 2026 (English), 14 pages. Read online or download the free PDF.
Technical Mathematics · Grade 11 · November Mock Exam 2 · 2026 · English. Question paper, 14 pages. Read online or download the PDF.
- Subject
- Technical Mathematics
- Grade
- Grade 11
- Language
- English
- Document type
- Question paper
- Year
- 2026
- Exam period
- November Mock Exam 2
- Paper
- 2
- Publisher
- Hlayiso
- Curriculum
- CAPS
- Pages
- 14
- File size
- 185.4 KB
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This exam
November Mock Exam 2 2026
- Paper 1Question paperMemo
- Paper 2Question paperAnswer bookMemo
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Technical Mathematics/P2 2 Hlayiso/Mock 2026
NSC Mock
INSTRUCTIONS AND INFORMATION
Read the following instructions carefully before answering the questions.
1. This question paper consists of TEN questions.
2. Answer ALL the questions in the SPECIAL ANSWER BOOK provided.
3. Clearly show ALL calculations, diagrams, graphs, et cetera that you have used in determining
your answers.
4. Answers only will NOT necessarily be awarded full marks.
5. You may use an approved scientific calculator (non-programmable and non-graphical), unless
stated otherwise.
6. If necessary, round off answers to TWO decimal places, unless stated otherwise.
7. Diagrams are NOT necessarily drawn to scale.
8. An information sheet with formulae is included at the end of the question paper.
9. Write neatly and legibly.
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Technical Mathematics/P2 3 Hlayiso/Mock 2026
NSC Mock
QUESTION 1
In the diagram below, △ABC has vertices A(−3 ; −1), B(5 ; 3) and C(−1 ; 5).
α is the angle of inclination of the line AC.
y
C(−1 ; 5)
B(5 ; 3)
α
x
O
A(−3 ; −1)
Determine:
1.1 The gradient of AB (2)
1.2 The length of AB (leave your answer in simplest surd form) (3)
1.3 The coordinates of M, the midpoint of AB (2)
1.4 The equation of the line that passes through M and is perpendicular to AB, in the form
y = mx + c (3)
1.5 Show that C lies on the line in QUESTION 1.4 and hence explain why △ABC is
isosceles. (3)
1.6 The size of α (2)
1.7 The size of CÂB (3)
1.8 The area of △ABC (4)
√
1.9 E(x ; −3) is a point such that BE = 2 13 units and x < 5. Calculate the value of x. (4)
[26]
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Technical Mathematics/P2 4 Hlayiso/Mock 2026
NSC Mock
QUESTION 2
2.1 Given: A = 48,6◦ and B = 117,3◦
Use a calculator to determine the value of:
2.1.1 tan(2A − B) (2)
sec B
2.1.2 (3)
cot2 A
2.2 Given: 17 cos θ − 8 = 0 and sin θ < 0
With the aid of a sketch and WITHOUT using a calculator, determine the value of:
2.2.1 tan θ (3)
2.2.2 8 tan θ − 17 sin θ (3)
2.3 Solve for θ , correct to ONE decimal place: 4 cot θ + 7 = 2 for θ ∈ [0◦ ; 360◦ ] (4)
[15]
QUESTION 3
sin(360◦ − x) · tan(180◦ + x)
3.1 Simplify: (6)
cos(180◦ + x) · tan 225◦
cos x
3.2 Prove that: − tan x = sec x (4)
1 − sin x
[10]
QUESTION 4
Given the functions defined by f (x) = 2 cos x and g(x) = sin(x − 30◦ ) for x ∈ [0◦ ; 360◦ ].
4.1 Sketch the graphs of f and g on the same set of axes on the grid provided in the
SPECIAL ANSWER BOOK. Clearly indicate ALL the intercepts with the axes, the
turning points and the end points. (6)
4.2 Write down the period of g. (1)
4.3 Write down the range of f . (2)
4.4 Use your graphs to determine the values of x for which f (x) · g(x) > 0. (3)
[12]
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Technical Mathematics/P2 5 Hlayiso/Mock 2026
NSC Mock
QUESTION 5
The diagram below shows the triangular frame PQR of a roof truss. PR is the horizontal tie
beam and QS is a vertical support with S on PR.
• PQ = 4,2 m and QR = 5,6 m
• PQ̂R = 105◦
Q
105◦
4,2 m 5,6 m
P S R
5.1 Calculate the length of the tie beam PR. (3)
5.2 Calculate the size of QP̂R. (3)
5.3 Calculate the area of △PQR. (2)
5.4 Hence, or otherwise, calculate the length of the vertical support QS. (3)
[11]
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Technical Mathematics/P2 6 Hlayiso/Mock 2026
NSC Mock
Give reasons for your statements in QUESTIONS 6, 7 and 8.
QUESTION 6
6.1 Complete the following statement:
The exterior angle of a cyclic quadrilateral is equal to … (1)
6.2 In the diagram below, O is the centre of the circle and A, B, C and D are points on the
circle. ABCD is a cyclic quadrilateral and DC is produced to E. Chord AC and radii
OA and OC are drawn.
AÔC = 124◦ and DÂB = 95◦
B E
A C
124◦
O
D
Determine, stating reasons, the size of:
6.2.1 AD̂C (2)
6.2.2 AB̂C (2)
6.2.3 OÂC (3)
6.2.4 BĈE (2)
6.2.5 BÂC, if it is further given that AD = DC (2)
[12]
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Technical Mathematics/P2 7 Hlayiso/Mock 2026
NSC Mock
QUESTION 7
7.1 Complete the following statement:
The tangent to a circle is perpendicular to the … at the point of contact. (1)
7.2 In the diagram below, O is the centre of the circle and A, B, C and D are points on the
circle. BC is a diameter. SAT is a tangent to the circle at A and meets BC produced at
T . Chords AB, AC, AD and DB, and radius OA are drawn.
CÂT = 32◦
S
A
32◦
B T
O C
D
Determine, stating reasons, the size of:
7.2.1 AB̂C (2)
7.2.2 BÂC (2)
7.2.3 T̂ (3)
7.2.4 AD̂B (2)
7.3 Prove that △TAC ||| △T BA. (4)
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Technical Mathematics/P2 8 Hlayiso/Mock 2026
NSC Mock
7.4 In the diagram below, O is the centre of the circle. KM and KN are tangents to the
circle at M and N. P is a point on the minor arc MN. Chords MN, MP and NP, and
radii OM and ON are drawn.
M K̂N = 64◦
M
P
O 64◦ K
N
7.4.1 Prove that KMON is a cyclic quadrilateral. (3)
7.4.2 Determine, stating reasons, the size of M P̂N. (3)
[20]
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Technical Mathematics/P2 9 Hlayiso/Mock 2026
NSC Mock
QUESTION 8
8.1 Complete the following statement:
The line drawn from the centre of a circle perpendicular to a chord … (1)
8.2 In the diagram below, O is the centre of the circle. AB and CD are parallel chords on
opposite sides of O. F lies on AB and E lies on CD such that F, O and E are on a
straight line with OF ⊥ AB and OE ⊥ CD.
AB = 48 cm, CD = 40 cm and FE = 22 cm. Let OF = x.
F
A B
O
C D
E
8.2.1 Write down, with a reason, the length of AF. (2)
8.2.2 Write down the length of OE in terms of x. (1)
8.2.3 By writing OA2 and OC2 in terms of x, show that x = 7. (4)
8.2.4 Hence, calculate the radius of the circle. (2)
[10]
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Technical Mathematics/P2 10 Hlayiso/Mock 2026
NSC Mock
QUESTION 9
9.1 The wheels of a car have a diameter of 0,64 m. The car travels at a constant speed of
72 km/h without the wheels slipping.
72 km/h
0,64 m
9.1.1 Convert 72 km/h to metres per second. (2)
9.1.2 Calculate the rotational frequency of a wheel in revolutions per second. (3)
9.1.3 Calculate the angular velocity of a wheel in radians per second. (2)
9.1.4 How many complete revolutions does a wheel make in 5 minutes? (2)
9.2 A garden sprinkler waters a region OPQ in the shape of a sector of a circle with centre
O, as shown below. The radius is 3 m and the area watered is 6,75 m2 .
P Q
θ 3m
O
9.2.1 Calculate the central angle θ in radians. (3)
9.2.2 Convert θ to degrees. (2)
9.2.3 Calculate the length of arc PQ. (2)
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Technical Mathematics/P2 11 Hlayiso/Mock 2026
NSC Mock
9.3 The diagram below shows the circular cross-section of a service tunnel with a
diameter of 2 m. The flat floor KL of the tunnel is a chord that is 1,6 m wide. Calculate
the height h of the tunnel from the middle of the floor to the highest point of the roof. (5)
h
K L
1,6 m
9.4 A closed rectangular water tank is 1,2 m long, 0,8 m wide and 0,75 m high, as shown
below.
The following formulae may be used:
Volume of a rectangular prism = l × b × h
Total surface area of a rectangular prism
0,75 m
= 2(lb + lh + bh)
0,8 m
1 m3 = 1 000 litres
1,2 m
9.4.1 Calculate the capacity of the tank in litres. (3)
9.4.2 A workshop makes 6 of these tanks from sheet metal that costs R185,50
per m2 . Calculate the cost of the sheet metal needed for the 6 tanks. (Ignore
overlaps and waste.) (5)
[29]
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Technical Mathematics/P2 12 Hlayiso/Mock 2026
NSC Mock
QUESTION 10
The diagram below shows an irregular plot with an area of 294 m2 . The straight boundary of
36 m is divided into 6 equal parts. The ordinates are 6 m; 7,5 m; 8 m; y m; 9 m; 8,5 m and 7 m
respectively.
6m 7,5 m 8m y 9m 8,5 m 7m
36 m
10.1 Write down the width of each equal part. (1)
10.2 Use the mid-ordinate rule to calculate the value of y. (4)
[5]
TOTAL: 150
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Technical Mathematics/P2 13 Hlayiso/Mock 2026
NSC Mock
INFORMATION SHEET: TECHNICAL MATHEMATICS
√
−b ± b2 − 4ac b 4ac − b2
x= x=− y=
2a 2a 4a
a = b ⇔ x = loga b , a > 0 , a ̸= 1 and b > 0
x
A = P(1 + ni) A = P(1 − ni) A = P(1 + i)n A = P(1 − i)n
( )
i m
ieff = 1 + −1
m
f (x + h) − f (x)
f ′ (x) = lim
h→0 h
∫ ∫
xn+1 k
kxn dx = k · +C , n ̸= −1 dx = k · ln x +C , x>0
n+1 x
∫
anx
k anx dx = k · +C , a>0
n ln a
√ ( )
x2 + x1 y2 + y1
d = (x2 − x1 )2 + (y2 − y1 )2 M ;
2 2
y2 − y1
y = mx + c y − y1 = m(x − x1 ) m= tan θ = m
x2 − x1
x2 y2
+ =1
a2 b2
a b c
In △ABC : = = a2 = b2 + c2 − 2bc · cos A
sin A sin B sinC
1
Area of △ABC = ab · sinC
2
sin2 θ + cos2 θ = 1 1 + tan2 θ = sec2 θ 1 + cot2 θ = cosec2 θ
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Technical Mathematics/P2 14 Hlayiso/Mock 2026
NSC Mock
π rad = 180◦
Angular velocity = ω = 2π n where n = rotation frequency
Angular velocity = ω = 360◦ n where n = rotation frequency
Circumferential velocity = v = π Dn where D = diameter and n = rotation frequency
Circumferential velocity = v = ω r where ω = angular velocity and r = radius
Arc length = s = rθ where r = radius and θ = central angle in radians
rs
Area of a sector = where r = radius and s = arc length
2
r2 θ
Area of a sector = where r = radius and θ = central angle in radians
2
4h2 − 4dh + x2 = 0 where h = height of segment, d = diameter of circle and
x = length of chord
o1 + o2
AT = a (m1 + m2 + m3 + . . . + mn ) where a = width of equal parts, m1 = ,
2
on = nth ordinate and n = number of ordinates
OR
( )
o1 + on
AT = a + o2 + o3 + . . . + on−1 where a = width of equal parts, on = nth ordinate and n
2
= number of ordinates
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