Mathematical Literacy Grade 12 P2 NW June 2025 Memo (Eng)

PROVINCIAL ASSESSMENT GRADE 12 MATHEMATICAL LITERACY P2 JUNE 2025 MARKING GUIDELINES MARKS: 100 Symbol Explanation MA Method with accuracy MCA Method with consistent accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification RT Reading from a table/a graph/document/diagram SF Correct substitution in a formula O Opinion/Explanation/Reasoning P Penalty, e.g. for no units, incorrect rounding off, etc. R Rounding off NPR No penalty for correct rounding AO Answer only These marking guidelines consist of 9 pages. Copyright reserved Please turn over

Mathematical Literacy/P2 2 NW/June 2025 Grade 12 – Marking Guidelines NOTE:  If a candidate answers a question TWICE, only mark the FIRST attempt.  If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled) version.  Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however, it stops at the second calculation error.  NOTE: consistent accuracy (CA) does not apply in cases of a breakdown.  If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalize for every extra item presented.  General principle of marking, if the candidate makes one mistake one mark is deducted.  Rounding is an independent mark.  In opinion type questions marks will only be awarded if relevant calculations are shown. Copyright reserved Please turn over

Mathematical Literacy/P2 3 NW/June 2025 Grade 12 – Marking Guidelines QUESTION 1 [20 MARKS] ANSWER ONLY FULL MARKS QUE Solution Explanation T/L 1.1.1 Radius is the line drawn from the centre of a circle to a point on 2A explanation M the circle.A L1 OR Radius is the line joining the centre of a circle to a point on the circle.A OR Radius is half of a diameter.A (2) 1.1.2 Scale is the factor that relates the measurement on paper with 2A explanation MP the real measurement.A L1 OR Scale is a ratio that gives the relationship between the measurement on paper and the real measurement.A (2) 1.1.3 Probability is a chance/likelihood of an event to occur / 2A explanation P happen.A (2) L1 1.2.1 B A 2A answer M (2) L1 1.2.2 D A 2A answer M (2) L1 1.2.3 F A 2A answer M (2) L1 1.2.4 G A 2A answer M (2) L1 1.3.1 Bar scale OR Linear scale OR Graphic scale.A 2A answer MP (2) L1 1.3.2 5  2A answer MP (2) L1 1.3.3 PretoriaA MP JohannesburgA L1 OR 1A answer MusinaA 1A answer Accept WeipeA (2) [20] Copyright reserved Please turn over

Mathematical Literacy/P2 4 NW/June 2025 Grade 12 – Marking Guidelines QUESTION 2 [28 MARKS] Ques Solution Explanation T/L 2.1 Limpopo riverA 2A answer MP (2) L1 2.2 Probability = 0% A 2A answer MP (2) L2 2.3 NWA 2A answer MP OR (2) L2 NorthwestA 2.4 Measured length = 1,8 cm A 1A measured distance MP 1,8 cm: 125 kmMA 1MA correct ratio L4 1,8 cm: 125 × 100 000 cm 1C conversion 1,8 cm: 12 500 000 cmC 1S simplification 1 : 6 944 444 S 1O opinion ∴The claim is not valid.O OR Measured length = 18 mm A 18 mm: 125 kmMA 18 mm: 125 × 1 000 000 mm 18 mm: 125 000 000 mmC [Accept 1,7 cm to 1,9 cm 1 : 6 944 444 S OR 17 mm to 19 mm] ∴The claim is not valid. O (5) 2.5.1 1 852 𝑘𝑚 1SF substitution MP Time = 80 𝑘𝑚/ℎ SF L2 = 23,15 hoursS 1S simplification A A 1A hours = 23 hours and 9 minutes 1A minutes (4) 2.5.2 Total time for the trip CA from Q2.5.1 MP = 23 hours 9 min + 48 min + 1 hour 30 minMCA 1MCA adding correct values L3 = 25 hours 27 minutesCA 1CA total 1CA day Day of arrival is Saturday CA= 24 hours 1MCA addition Arrival time = 13:15 + 1:27MCA = 14: 42CA 1CA arrival time OR OR Total time for the trip 1MA adding time spent at 13:15 + 48 = 14:03MA border 14:03 + 1:30 = 15:33MCA 1MCA adding time spent at Bulawayo 1MCA adding travelling time 15:33 + 23:09 = 38:42MCA 1CA day Day of arrival = SaturdayCA at 14:42CA 1CA arrival time (5) 2.5.3 Stretch legs OR Bathroom break OR Refreshments 2R reason MP OR Petrol OR Sight-seeingR (2) L4 Copyright reserved Please turn over

Mathematical Literacy/P2 5 NW/June 2025 Grade 12 – Marking Guidelines 2.6.1 Livingstone islandA 2A answer MP (2) L1 2.6.2 Turn right at the entrance then turn left A 1A turn right and left MP At the crossroad turn rightA 1A turn right L2 Walk along the footpath, pass the right junctionA 1A pass right junction Turn left A 1A turn left Then you will be facing point ⑨ OR OR 1A turn right a Turn right at the entrance A 1A turn left Pass toilets then turn left. A 1A pass right Walk along the footpath then turn right at the 1A turn left T-JunctionA (4) Turn left A Then you will be facing point ⑨ [28] Copyright reserved Please turn over

Mathematical Literacy/P2 6 NW/June 2025 Grade 12 – Marking Guidelines QUESTION 3 [28 MARKS] Ques Solution Explanation T/L 3.1.1 Perimeter is the total length around the borders of the 2A answer M silo.R (2) L1 3.1.2 3 000 mm = 3 mC 1C conversion M 2 Volume = s × h L2 = (2,3 m)2 × 3 mSF 1SF substitution = 15,87 m3 S 1S simplification = 16 m3 R 1R rounding (4) 3.1.3 Area = 4s × height + s 2 M = 4 × 2,3 m × 3 m + (2,3 m)2 SF 1SF substitution L3 2 = 27,6 m + 5,29S 1S simplification = 32,89 m2S 1S simplification Total area for 3 silo covers = 3 × 32,89 m2 MCA 1MCA multiplying by 3 = 98,67 m2 CA 1CA answer (5) 3.1.4 To avoid damageR OR to protect them from 2R reason M getting moistR OR to protect from rustingR (2) L4 Accept any relevant reason 3.2.1 3 962,5808 gallons = 3 962,5808 × 3,7854 litresC 1C conversion to litres M = 14 999,95336 litresS 1S simplification L2 = 15 000 litresR 1R rounding = 15 m3 C 1C conversion to m3 OR OR 962,5808 gallons = 3 962,5808 × 3,7854 litresC 1C conversion to litres = 14 999,95336 litresS 1S simplification = 14,99995336 m3 C 1C conversion to m3 = 15 m3 R 1R rounding (4) 3.2.2 CA from Q3.2.1 M Radius = 2,3 m ÷ 2 = 1,15 mA 1A radius L3 15 m3 = 3,142 × (1,15 m)2 × hSF 1SF substitution 15 𝑚3 h = 3,142 × (1,15 𝑚)2MA 1MA changing subject h = 3,609852008 mS 1S simplification NPR (4) Copyright reserved Please turn over

Mathematical Literacy/P2 7 NW/June 2025 Grade 12 – Marking Guidelines 3.2.3 Total area to be painted = 3 × 34,33 m2 MA 1MA multiplying by 3 M = 102,99 m2 A 1A total area L4 102,99 𝑚2 First coat paint = 9 𝑚2 /𝑙𝑖𝑡𝑟𝑒MCA 1MCA dividing = 11,443333333 litresCA 1CA simplification 102,99 𝑚2 Subsequent coat paint = 12𝑚2 /𝑙𝑖𝑡𝑟𝑒 = 8,5825 litresS Total paint = 11,4433333333 litres + 8,5825 litres 1S simplification = 20,026 litresCA OR 21 litresCA ∴ The claim is valid.O 1CA total paint OR 1O opinion 34,33 𝑚2 OR First coat paint = 9𝑚2 /𝑙𝑖𝑡𝑟𝑒MA 1MA dividing = 3,814444444 litresS 1S simplification 34,33 𝑚2 Subsequent coat paint = 12𝑚2 /𝑙𝑖𝑡𝑟𝑒 = 2,860833333 litresS 1S simplification 1 silo paint = 3,814444444 litres + 2,860833333 litres = 6,675277777 litresCA 1CA paint for 1 silo Total paint = 3 × 6,675277777 litres MCA 1MCA multiplying by 3 = 20,02583333 litres CA 1CA total paint ∴ The claim is valid.O 1O opinion OR OR 34,33 𝑚2 First coat paint = 9𝑚2 /𝑙𝑖𝑡𝑟𝑒MA 1MA dividing = 3,814444444 litresS 1S simplification 34,33 𝑚2 Subsequent coat paint = 12𝑚2 /𝑙𝑖𝑡𝑟𝑒 = 2,860833333 litresS 1S simplification 1 silo paint = 3,814444444 litres + 2,860833333 litres = 7 litresCA 1CA paint for 1 silo Total paint = 3 × 7 litres MCA 1MCA multiplying by 3 = 21 litres CA 1CA total paint ∴ The claim is valid.O 1O opinion (7) [28] Copyright reserved Please turn over

Mathematical Literacy/P2 8 NW/June 2025 Grade 12 – Marking Guidelines QUESTION 4 [24 MARKS] Ques Solution Explanation T/L 4.1 Body Mass IndexA 2A answer M (2) L1 4.2 4 + 3 + 2 = 9A 1A adding values M 2 2 L3 Supper calories = × 2 500MCA 1MCA multiplying 9 9 = 555,55S 1S simplification = 560R 1R rounding OR OR 4 + 3 + 2 = 9A 1A adding values 2 500 Unit calory = CA 9 1CA unit calory = 277,78 Supper calories = 277,78 × 2MCA 1MCA multiplying by 2 = 555,555 = 560R 1R rounding (4) 4.3 RT 1RT correct male calories M Maximum daily calory intake = 2 500 – 500MA 1MA subtracting 500 L2 = 2 000 caloriesCA 1CA answer (3) 4.4 170 cm = 1,7 mC 1C conversion M mass in kg L3 BMI = (height in m)2 1SF substitution 𝑚𝑎𝑠𝑠 23,1 kg/m = 2 SF 1MA changing subject (1,7 𝑚)2 1A answer Mass = 23,1 kg/m2 × (1,7 m)2 MA NPR = 66,759 kgA (4) 4.5 450° = (1,8 × ℃) + 32°SF 1SF substitution M ℃ = (450° - 32°) ÷ 1,8MA 1MA changing subject L4 ℃ = 232,222° ℃ = 230°AR 1AR rounded answer ∴ Mac converted correctly.O 1O opinion (4) 4.6.1 Street mapA 2A answer MP (2) L1 4.6.2 Francis Baard StreetA 2A answer MP (2) L2 Copyright reserved Please turn over

Mathematical Literacy/P2 9 NW/June 2025 Grade 12 – Marking Guidelines 4.6.3 Farenden Street; Arcadia StreetA 1A first two correct streets MP Beckett Street, Park StreetA 1A second two correct streets L2 Farenden Street A 1A last correct street (3) [24] TOTAL: 100 Copyright reserved