Mathematics Grade 3 Gauteng Provincial November 2018 Memo

YS GAUTENG PROVINCE fe AN EDUCATION #3) REPUBLIC OF SOUTH AFRICA UMNYANGO WEZEFUNDO EGAUTENG UKUHLOLWA KWESIFUNDA MGWENGWENI 2018 IBANGA 3 ISINDEBELE - IIMBALO 6 AMAPHEPHA IMEMORANDAMU

IMEMORANDAMU |ISINDEBELE JIBANGA 3 IIMBALO UMNYANGO WEZEFUNDO EGAUTENG UKUHLOLWA KWESIFUNDA TIMBALO IMEMORANDAMU ere ANSWER MARK ALLOCATION I Av Tmaki linye lependulo ekungiyo 2 Civ Imaki linye lependulo ekungiyo 3 Av Imaki linye lependulo ekungiyo L Cy Imaki linye lependulo ekungiyo 5 Bev Tmaki linye lependulo ekungiyo 6 Cv Imaki linye lependulo ekungiyo 7 Cv Imaki linye lependulo ekungiyo 8 Bev Tmaki linye lependulo ekungiyo q Av Tmaki linye lependulo ekungiyo lo Cv Tmaki linye lependulo ekungiyo ll a. | imaki lependulo yinye v = 2 amamaki DAAAI\AL\AAAA v b.

IMEMORANDAMU |ISINDEBELE JIBANGA 3 IIMBALO | CURSTION ANSWER MARK ALLOCATION iW a. Makhulu amabili namat jhumi amathathu | imaki lependulo yinye anane = 2 amamaki b. Mat, jhumi alikhomba nahlanu B a. limpensela zabantwana | imaki lokuffaka umbala | imaki lependulo 50 £5 ZO 35 25 Number of pencils Robin Des v Mpho Tumi Children who own pencils b. Ngu Des Vv Ik 5x6=30 v | imaki ependulweni 6x5=30 v ekingiyo 30+5=6 v £ amamaki 30+6=5 v I5 a. Iphiramidi v T imaki lependulo ekungiyo b. Iyat jhelela v 3 amamaki c. Iye v d, I6 2h amathayela ov T imaki linye 35 amathayela v

IMEMORANDAMU ISINDEBELE IBANGA 3 IIMBALO | CURSTION ANSWER MARK ALLOCATION I7 Esinye nesinye isimedo sobudisi Igremu =g v Tmiligramu =mg v Tkilogramu = kg v | imaki lependulo ekungiyo 8 a. [bumbeko elikhulu kunalalo elililandelako | maki lependulo ekungiyo C) 2 amamaki. b. Iphethini ekhulako, engezelelako ngaphezulu. v 9 210 v | imaki linye 20 36L — 109 T imaki lependulo = 364-100-949 v = 26h -4 2 amamaki =255 v | BET + 239 T imaki linye lependulo = (500 + 200) + (60 + 30) +(9 +9) v ekungiyo = 700 + 108 = 808 v 2 amamaki 22 ] imigodlana =20 T imaki lependulo ekungiyo 2 imigodlana = 20+ 20 = L0 v 2 amamaki Nanuana 2x20=l0 v

IMEMORANDAMU ISINDEBELE IBANGA 3 IIMBALO | CURSTION ANSWER MARK ALLOCATION 23 £90 + 192 | imaki linye lependulo = (400 + 100) + (90+ 90) + (0+ 2) v ekungiyo = 600 + 80+2 = 682 v 2 amamaki 2L 75+5=15 | imaki linye lependulo Nanyana ekungiyo. TES5S555 5555555555 =0 v 25 v | imaki linye lependulo R20 R20 R20 ekungiyo Nanyana = R60, 3 = R20 Wange R20 + R20 =R{O0 v 26 Co? Xe?) @S @S> Ce) | imaki linye lokwenza OCDCOEDE | Ce) Ce) | imaki linue lesibalo cckuphindaphinda I2x3=36v 21 Imitha linye nehaf'u = umant ji munye T imaki linye lependulo Amamitha amathathu = 2 amamant ji v Amamitha asi 6 = 4 amamant ji Amamitha ali 9 = 6 amamant ji v ekun iyo | nal linye lendlela ekwenziwengayo = 2 amamaki

215 = 60 imizuzu = Lh 35 imizuzu ¥ Isikhathi sokufika = 14:35 v IMEMORANDAMU |ISINDEBELE IBANGA 3 IIMBALO | CURSTION ANSWER MARK ALLOCATION 28 d | imaki linye lomeq o « | t T t 1 | 1 | id | imaki linye lout, jho 100 110 120 30 rm) m0 weenomboro Nanyana v loo lo 120 10 140 50 105+ 45 =|150 v 24 | imaki linye lependulo ekun iyo v | nal linye lorneqo ania i ee ee ee ee ee ee ee ee | 0 5 |l0 & 20 25 30 35 40 45 50 55 60 30 =5x55 T imaki linye lependulo =215 v ekungiyo 2 amamaki wendlela ekwenziwe ngayo 3 amamaki INANI: 50