Grade 9 FS/ November 2022
Mathematics Paper 2 English Marking Guideline
GRADE 9
MATHEMATICS PAPER 2 ENGLISH
MARKING GUIDELINE
NOVEMBER 2022
This mathematics marking guideline consist of 13 pages
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Mathematics Grade 9 Paper 2 Free State November 2022 Memo
Grade 9 Mathematics Paper 2 memorandum from the Free State November Exam 2022, 13 pages. Read online or download the free PDF.
Mathematics · Grade 9 · Free State November Exam · 2022. Memorandum, 13 pages. Read online or download the PDF.
- Subject
- Mathematics
- Grade
- Grade 9
- Document type
- Memorandum
- Year
- 2022
- Exam period
- Free State November Exam
- Paper
- 2
- Curriculum
- CAPS
- Pages
- 13
- File size
- 552.5 KB
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This exam
Free State November Exam 2022
- Paper 1Question paper
- Paper 2Question paperMemoMemo (2)
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Grade 9 FS/ November 2022
Mathematics Paper 2 English Marking Guideline
QUESTION 1
1.1
G
ሺ2𝑥 − 9ሻ0
H
𝑥
F
Statement Reason Statement: 1 mark (3)
𝑥=
900 + 90 Compl. angles add up to 900 Reason: 1 mark
3
Answer: 1 mark
= 330
1.2 H
A F B
𝑚
C D
2𝑝 + 300 E
G
Statement Reason Statement: 1 mark (3)
𝑝=
1100 −300 Corr, angles AB ‖ CD Reason: 1 mark
2
Answer: 1 mark
= 400
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Grade 9 FS/ November 2022
Mathematics Paper 2 English Marking Guideline
1.3.1
U
Q 800
𝑎
𝑏 1200
S V
600 R
T
Statement Reason Statement: 1 mark (4)
𝑎 = 800 Vert. opp angles Reason: 1 mark
𝑏 = 600 Alt. angles, ST‖QR OR Statement: 1 mark
𝑏 = 600 Angles on a str. line Reason: 1 mark
1.3.2 A B
1050
a
C D
E
Statement Reason Statement: 1 mark (2)
𝑎 = 750 Co-int, angles, AB‖CD Reason: 1 mark
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Grade 9 FS/ November 2022
Mathematics Paper 2 English Marking Guideline
1.3.3 E F
1060
𝑥
G H
Statement Reason Statement: 1 mark (2)
𝑥 = 1060 alt, angles, EF‖GH Reason: 1 mark
1.3.4
𝑎
430
Statement Reason Statement: 1 mark (2)
𝑎 = 2ሺ430 ሻ = 860 Ext. angle of ∆=twice int. angle Reason: 1 mark
of a ∆
[16]
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Grade 9 FS/ November 2022
Mathematics Paper 2 English Marking Guideline
QUESTION 2
2.1
𝑦
380
𝑥
Statement Reason Statement: 1 mark (4)
𝑥 = 520 Int. angles of a ∆ add up Reason: 1 mark
1800
Statement: 1 mark
𝑦 = 52 0 Alt, angles, ‖ lines
Reason: 1 mark
2.2
𝑦
𝑥
Statement Reason Statement: 1 mark (4)
𝑥 = 900 Diag. bisect each other ⟂ Reason: 1 mark
𝑦 = 450 Diag. bisect the corners Statement: 1 mark
Reason: 1 mark
[8]
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Grade 9 FS/ November 2022
Mathematics Paper 2 English Marking Guideline
QUESTION 3
3.1 i. SSS or ii. AAS or iii. SAA or iv. RHS One answer: 1 mark (1)
3.2
R
Q
U
T
S
In ∆QRU and ∆TSU
Statement Reason 𝐓𝐒̂𝐑 : 1 mark (3)
̂ T = QT
RQ ̂S alt angle, QR ‖ ST Reason: 1 mark
̂S
QR = 𝐓𝐒̂𝐑 alt angle, QR ‖ ST ̂ 𝐑 : 1 mark
𝐐𝐔
̂𝐑
𝐐𝐔 = ̂S
TU vert. opp. angles
∴ ∆QRU ⫼∆TSU equal angles or AAA
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Grade 9 FS/ November 2022
Mathematics Paper 2 English Marking Guideline
3.3 B
A
D
C
E
Statement Reason Statem & Reason: 1 (4)
mark
In ∆ABD and ∆CED
Statem & Reason: 1
AD = DC given mark
̂ B = CD
AD ̂E Vert. opp. angles Statem & Reason: 1
mark
̂ D = EĈD
BA Alt. angles, AB‖EC
AAS: 1 mark
∆ABD ≡ ∆CED AAS
[8]
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Grade 9 FS/ November 2022
Mathematics Paper 2 English Marking Guideline
QUESTION 4
4.1.1
Answer/ translate: 1 (1)
mark
•
•
4.1.2 Aሺ4 ; 0ሻ Answer: 1 mark (1)
4.2.1 Answer: 1 mark (1)
Aሺ−3; 5ሻ
•
•Bሺ−6; 3ሻ • •
Cሺ−2; 3ሻ
• A′ ሺ−2; 0ሻ
•
B ′ ሺ−3; −4ሻ
•C′ ሺ1; −4ሻ
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Grade 9 FS/ November 2022
Mathematics Paper 2 English Marking Guideline
4.2.2
Answer: 1 mark (1)
A′ ሺ3 ; 5ሻ
• •
• • •′ • B′ ሺ6 ; 3ሻ
C ሺ2 ; 3ሻ
4.3
𝐂′ ሺ4 ; 10ሻ
𝐂ሺ𝟐 ; 𝟓ሻ
𝐀′ ሺ4 ; 2ሻ
𝐁′ ሺ10 ; 2ሻ
𝐀ሺ𝟐 ; 𝟏ሻ 𝐁ሺ𝟓 ; 𝟏ሻ
Determine the coordinates of the vertices of ∆A′ B′ C′
4.3.1 A′ ሺ4 ; 2ሻ Answer: 3 marks (3)
B ′ ሺ10 ; 2ሻ
C ′ ሺ4 ; 10ሻ
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Grade 9 FS/ November 2022
Mathematics Paper 2 English Marking Guideline
4.3.2 Determine the lengths of the sides of ∆A′ B′ C′ . Each side: 1 mark (3)
A′ B′ = 6 units OR (count the blocks)
A′ C′ = 8 units OR (count the blocks)
ሺB′ C′ ሻ2 = ሺ6ሻ2 + ሺ8ሻ2 (Pythagoras)
= 36 + 64
= 100
√ሺB′ C′ ሻ2 = √100
BC = 10 units
[10]
QUESTION 5
5.1
22 𝑚
15 𝑚 − 𝟗 𝒎 = 6 𝑚
9𝑚
15 𝑚
𝟔𝒎
𝟏𝟒 𝒎
8𝑚
22 𝑚 − 𝟖 𝒎 = 𝟏𝟒 𝒎
This is irregular shape 6 m + 14 m: 1 mark (2)
P = 22 𝑚 + 15 𝑚 + 9 𝑚 + 𝟔 𝒎 + 𝟏𝟒 𝒎 + 8 𝑚 Answer: 1 mark
= 74 𝑚
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Grade 9 FS/ November 2022
Mathematics Paper 2 English Marking Guideline
5.2
11 𝑐𝑚
9 𝑐𝑚
8 𝑐𝑚
17 𝑐𝑚
1 Area (answer): 1 (2)
𝐴𝑟𝑒𝑎 = 2 ሺ𝑎 + 𝑏ሻ × 𝐻
mark
1 ሺ11 𝑐𝑚+17 𝑐𝑚ሻ × 8 𝑐𝑚
Area = 2 ሺ11 cm + 17 cmሻ × 8 𝑐𝑚 OR Perimeter (answer):
2
1 mark
= 28 𝑐𝑚 × 4 𝑐𝑚
= 112 𝑐𝑚2
P = 9 𝑐𝑚 + 17 𝑐𝑚 + 9 𝑐𝑚 + 11 𝑐𝑚
= 46 𝑐𝑚
5.3 Not drawn to scale. Formula: 1 mark (3)
ሺ2𝑥 + 5ሻ 𝑐𝑚 Subst: 1 mark
Simplify: 1 mark
ሺ𝑥 + 6ሻ 𝑐𝑚 Answer: 1 mark
If a learner did not
write the formula,
give 2 marks for
P= 46 cm showing distributive
law OR simplifying
𝐴𝑟𝑒𝑎 = 𝑙 × 𝑏
= [ሺ2𝑥 + 5ሻሺ𝑥 + 6ሻ]𝑐𝑚2
= 2𝑥ሺ𝑥 + 6ሻ + 5ሺ𝑥 + 6ሻ]𝑐𝑚2
= ሺ2𝑥 2 + 12𝑥 + 5𝑥 + 30ሻ𝑐𝑚2
= ሺ2𝑥 2 + 17 𝑐𝑚 + 30ሻ𝑐𝑚2
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Grade 9 FS/ November 2022
Mathematics Paper 2 English Marking Guideline
5.4 1 𝑘𝑚2 = 1 000 000 𝑚2 (1)
∴ 1,12 𝑠𝑞𝑢𝑎𝑟𝑒 𝑘𝑖𝑙𝑜𝑚𝑒𝑡𝑟𝑒 ሺ𝑘𝑚2 ሻ = 𝟏 𝟏𝟐𝟎 𝟎𝟎𝟎 𝒎𝟐
= 1,12 × 1 000 000 𝑚2 Answer: 1 mark
= 1 120 000 𝑚2
5.5 Not drawn to scale
10 𝑐𝑚
20 𝑐𝑚
30 𝑐𝑚
back
end base end
20 𝑐𝑚
front 10 𝑐𝑚
10 𝑐𝑚
top
20 𝑐𝑚
30 𝑐𝑚
Area of base = ሺ30 × 20ሻ𝑐𝑚2 (3)
= 600 𝑐𝑚2
Area of each end = ሺ10 × 20ሻ 𝑐𝑚2
= 200 𝑐𝑚2
Area of front = ሺ10 × 30ሻ𝑐𝑚2
= 300 𝑐𝑚2
Total surface area = 2ሺ600 + 200 + 300ሻ𝑐𝑚2
= 2 × 1 100 𝑐𝑚2
= 2 200 𝑐𝑚2
OR
𝑆𝐴 = 2ሺ𝑙 × 𝑏ሻ + 2ሺℎ × 𝑏ሻ + 2ሺℎ × 𝑙ሻ
= 2ሺ30 × 20ሻ + 2ሺ10 × 20ሻ + 2ሺ10 × 30ሻ
= 2ሺ600 + 200 + 300ሻ
= 1 200 + 400 + 600
= 2 200 𝑐𝑚2
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Grade 9 FS/ November 2022
Mathematics Paper 2 English Marking Guideline
5.6 A cylinder has a radius of 7 𝑐𝑚 and height of 10 𝑐𝑚.
Not drawn to scale
7 𝑐𝑚
10 𝑐𝑚
5.6.1 Volume of cylinder = 𝜋𝑟 2 𝐻
22
= 7 × 7 × 7 × 10 𝑐𝑚 Formula: 1 mark (2)
= 1 540 𝑐𝑚2 Answer: 1 mark
5.6.2 TSA = 2𝜋𝑟ℎ + 2𝜋𝑟 2 Formula: 1 mark (3)
22 22
= ሺ2 × 7 × 7 × 10ሻ + ሺ2 × 7 × 7 × 7ሻ Subst: 1 mark
= 440 + 308 Answer: 1 mark
2
= 748𝑐𝑚
5.6.3 Doubled Answer: 1 mark (1)
[17]
TOTAL [60]
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