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NATIONAL
SENIOR CERTIFICATE
GRADE 11
MATHEMATICAL LITERACY P1
JUNE EXAMINATION MEMO
2019
MARKS: 75
Symbol Explanation
M Method
CA Continuous accuracy
2018
A Accuracy
C Conversion
S Simplification
RT/RG/RM Read from Table / Read from graph/ Read from Map
SF Substitution in formula
O Opinion/Example / Deduction/conclusion
P Penalise for example no units / incorrect rounding etc
R Rounding
J Justification/ Motivation/ Supply a Reason
Demo
NW/JUNE/MATLIT/ EMIS/6******* 1
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Mathematical Literacy Grade 11 P1 North West June 2019 Memo
Grade 11 Mathematical Literacy Paper 1 memorandum from the North West June 2019, 5 pages. Read online or download the free PDF.
Mathematical Literacy · Grade 11 · North West June · 2019. Memorandum, 5 pages. Read online or download the PDF.
- Subject
- Mathematical Literacy
- Grade
- Grade 11
- Document type
- Memorandum
- Year
- 2019
- Exam period
- North West June
- Paper
- 1
- Curriculum
- CAPS
- Pages
- 5
- File size
- 1.2 MB
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North West June 2019
- Paper 1Question paperMemo
- Paper 2Question paperMemo
Questions in this paper
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QUESTION 1 [15]
OUES SOLUTIONS EXPLANATIONS L1-4
1.1.1 Rent 1
Cell phone contract 2A
(2)
1.1.2 R 250 ,00 × 4 = R 1 000, 00 1M 2
R 1 000, 00 + R 600, 00 1M
R 1 600,00 1A
(3)
1.1.3 B = R150, 00 + R 500,00 + R 300,00+ R 120,00 1M 2
= R 1 070,00 1A
(2)
1.1.4 1M 3
1 070,00 1A
× 100 1R
1 600,00
= 66,875%
= 67%
(3)
1.2.1 4:30 – 9:00 1M 2
= 5hours 30minutes 1A
(2)
12.2 5hours× 60minutes = 300minutes 1M 3
300minutes + 30minutes 1M
= 330minutes 1A
(3)
QUESTION 2 [19]
2.1.1 Cost = R450 +(R4×number of loaves) 2Correct formula 2
(2)
2.1.2 Value for A= R450 + (R4 ×300) 1 Substitution
= R1 650,00 1 Answer 2
Value for B= R6.50 × R180 1 Substitution
=R1 170,00 1 Answer
(4)
2.1.3 1 Substitution
Cost of 50 loaves = R450 + ( R4 × 50) 1 Answer (2)
= R650,00
Demo
NW/JUNE/MATLIT/ EMIS/6******* 2
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Graph: See attached page 1 heading 2
1 A (0;450)
1 A (0;0)
1 breakeven point
1 labelling both
axis
1 labelling both
graphs
1A joining the
points
(7)
2.1.5 Coordinates (180; R1 170) 2 coordinates
It means that both cost and income for baking and selling 2 Meaning 2
180 loaves is the same amount which is R1 170.
(4)
QUESTION 3
[20]
3.1.1 Two items 2A 1
(2)
3.12 33 1M
R 499, 00 × 100
1M 2
R 164, 00
(2)
3.1.3 Total including VAT 1Mmultiplication
15 1Maddition
R 768,00 × 100
1Aanswer 2
= R 115, 20 + R 768,00
= R 883,40
(3)
3.2.1 Cost of water used 1Multiplication
6kl = R0, 00 1Aanswer 2
24kl × 6,48 = R155, 52 1Aanswer
5kl × 16,20 = R81,00 1Maddition
R155, 52 +R81,70 =R236,52 1Madding R80,70
R236,52 + R80,70 + R17,15 1Madding R17,15
= R324,37 1Aanswer
(7)
3.2.2 15 1Mmultiplication
New price = R80,70 × 100 = R 12,01
1Maddition 2
= R80,82 + R12,01
1Aanswer
= R 92,81
(3)
3.3
7,5
1𝑠𝑡 𝑦𝑒𝑎𝑟 = ( × R120 000,00) + R 120 00,00
100
Demo
NW/JUNE/MATLIT/ EMIS/6******* 3
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= R129 000, 00 1Multiplication
1Aanswer 3
1Aanswer
7,5 1Aanswer
2𝑛𝑑 𝑦𝑒𝑎𝑟 = × R129 000,00 + R129 000, 00
100
= R138 675,00
7,5
3𝑟𝑑 𝑦𝑒𝑎𝑟 = 100 × R139 675,00 + R139 675,00
= R149 075,63 (4)
QUESTION 4
[15]
4.1.1 14 1dividing by 2
Radius = 2
1Aanswer 1
= 7cm (2)
4.1.2 1Substitution
𝑉𝑜𝑙𝑢𝑚𝑒 = 𝜋𝑟 2 × h 1Aanswer
V= 3,142 × (7𝑐𝑚)2 + 24 𝑐𝑚2 1M 3
V = 3694,99 c 𝑚3 1A
V= 3694.99 c 𝑚3 - 3456 c 𝑚3
V= 238.99 𝑚3
(4)
4.1.3 Volume = (𝑠𝑖𝑑𝑒)2 × height 1S
= 3456 c 𝑚3 = (𝐴)2 × 24cm 1M
(𝐴)2 = 3456 c𝑚3 ÷ 24cm 1M
(𝐴)2 = 144 𝑐𝑚3 1A 3
(𝐴)2 = √ 144
A = 12
(4)
4.2.1 Boipelo nature reserve (2) 2A 1
4.2.2 N 12, N 14 and N 4 (3) 3A 1
4.2.3 Turn into R505 and continue until you reach 2
Lichtenburg. Turn into R52 and join N14 and
continue until you reach Sannieshof.
(6)
Demo
NW/JUNE/MATLIT/ EMIS/6******* 4
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Cost and Income of loaves of Bread
2500
2000
1500 Costs
Cost in rands
1000
500
0
0 60 120 180 240 300
Number of loaves of bread
Demo
NW/JUNE/MATLIT/ EMIS/6******* 5
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