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NATIONAL
SENIOR CERTIFICATE
GRADE 11
MATHEMATICAL LITERACY PAPER 1
JUNE EXAMINATION 2018
MARKING GUIDELINE
MARKS: 75
Symbol Explanation
M Method
CA Continuous accuracy
A Accuracy
C Conversion
S Simplification
RT/RG/RM Read from Table / Read from graph/
2018Read from Map
SF Substitution in formula
O Opinion/Example / Deduction/conclusion
P Penalise for example no units / incorrect rounding etc
R Rounding
J Justification/ Motivation/ Supply a Reason
F Formula
NPR No penalty for rounding OR ommiting units
AO Answer only
Demo
NW/JUNE/MATLIT/ EMIS/6******* 1
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Mathematical Literacy Grade 11 P1 North West June 2018 Memo
Grade 11 Mathematical Literacy Paper 1 memorandum from the North West June 2018, 5 pages. Read online or download the free PDF.
Mathematical Literacy · Grade 11 · North West June · 2018. Memorandum, 5 pages. Read online or download the PDF.
- Subject
- Mathematical Literacy
- Grade
- Grade 11
- Document type
- Memorandum
- Year
- 2018
- Exam period
- North West June
- Paper
- 1
- Curriculum
- CAPS
- Pages
- 5
- File size
- 1.3 MB
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North West June 2018
- Paper 1Question paperMemo
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QUESTION 1 [13] TL
1.1.1 1M division
500 1 Answer 1
Mass = 1000 ü
= 0,5kgü
(2)
1.1.2 2 1Mmultiplying 1
𝑂𝑖𝑙 𝑛𝑒𝑒𝑑𝑒𝑑 = 3 × 250ü
1Answer
= 166,67 ü
1Rounding
= 167 ml oil neededü
(3)
1.1.3 1Multipying 1
Total muffins =12×2ü 1Answer
= 24ü
(2)
1.2.1 0 to 1 hourü 2 Answer
Sundays and public holidaysü 1
(2)
1.2.2 Total time = 13: 25 – 08: 45 ü 1Subtraction
= 4 hours 40 minutesü 1Answer
1
(2)
1.2.3 Amount paid =R6,00 üü 2Anwser 1
(2)
QUESTION 2 [16]
2.1 2 Answer 2
Total Cost = R 2 400 × R 50, 00 + n, where n is the number of people
attending the conference. üü
(2)
2.2 A= R2 400 + 50 × 20 ü 1Substitution
= R2 400 +R 1000 1Answer 2
= R3 400 ü
(2)
2.3 I = 130× n 1Substitution 2
10 400 = 130× n 1Answer
n = 80 (2)
Demo
NW/JUNE/MATLIT/ EMIS/6******* 2
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Income and Cost
14000
12000
Amouunt in Rands
10000
8000
6000 Cost
Income
4000
2000
0
0 20 40 60 80 100 120
Number of People
1M heading 1M (0, 2 400)
1M labelling both axis 1M(100,7 400)
1M (0,0) 2M joining the points
1M(100, 13 000) 1M labelling both graphs
(8)
2.5 30 Tickets üü 2A answer 2
(2)
QUESTION 3 [23]
3.1.1 R1 000, 61üü 2RT 1
(2)
3.12 R2 00,00 üü 2RT 1
(2)
3.1.3 Life style magazine feeüü 2A Answer 1
(2)
3.1.4 1substitution
𝑅23,73 1A 2
𝑖𝑛𝑡𝑒𝑟𝑒𝑠𝑡 𝑟𝑎𝑡𝑒 = 𝑅1 000,61×100ü
NPR
= 2,371553352%
=2,38%ü
(2)
3.2 12% 1Conversion
= 1% Per monthü
12%
1Substitution
1 1A answer
𝑓𝑖𝑟𝑠𝑡 𝑚𝑜𝑛𝑡ℎ = (100 × R13500) + ,R13500, 00ü 1A answer
Demo
NW/JUNE/MATLIT/ EMIS/6******* 3
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= R13 635,00 ü 1A answer 3
1
𝑠𝑒𝑐𝑜𝑛𝑑 𝑚𝑜𝑛𝑡ℎ = (100 × R13 635 ) + R13 635, 00
= R13 771,35 ü
(5)
1
Third month = (100 × R13 771,35) + R13 771, 35
= R13 909,02 ü
OR
First month = 1,01 × R13 500ü
= R13 635 ü
Second month = 1,01 × R13 635
= R13 771,35ü
Third month = 1,01 × R13 771,35
= R13 909,02 ü ü
3.3.1 6kl = 0ü 1A answer
6kl = R8,04× 6 = R48,24ü 1Method 2
6kl = R10,55× 6 = R63, 30 1A answer
6kl = R12,21× 6 = R73, 26 1A answer
3kl = R13,95× 3 = R41, 85ü 1A answer
Total paid = R48,24+ R63,30 + R73,26 + R41,85ü
= R226,65ü (5)
3.3.2 17 1Method
New charges = × R44,82 + R44,82ü 1Answer 2
100
= R52,44ü
(2)
3.4 R 25000 1 numerator
Earning in other country = üü 1denominator 1
16,93
= £1476,67ü 1A answer
(3)
QUESTION 4
[23]
4.1.1 150 1Dividing
Radius = ü
2
1A answer 2
= 75cmü
(2)
4.1.2 Volume = 𝜋𝑟 2 h 1Conversion
V = 3,142 × (75𝑐𝑚)2 ü × 250ü𝑐𝑚 1Substitution 3
V = 4418437,5 c𝑚3 ü 1A answer
1A answer
1000c𝑚3 = 1litre 1Rounding
4418437,5
V = 1000
V = 4418,4375ü (5)
V = 4418,43litresü
Demo
NW/JUNE/MATLIT/ EMIS/6******* 4
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4.1.3 H = 2,5m 1Radius
75 1Substitution
Radius = 100
1A answer 3
= 0,75mü
1units
Surface area = 2πr(r + h)
= 2 × 3,142 × 0,75( 0,75 + 2,5) 𝑚2 ü
(4)
= 2 × 3,142 × 0,75(3,25) 𝑚2
= 15,31725 𝑚2 ü
=15,32𝑚2 ü
4.2.1 8 Medical stations üü 2A answer 1
23 Refreshment stationsüü 2A answer
(4)
4.2.2 44 kilometres üü 2A answer 1
(2)
4.2.3 University of Cape townüü 2A answer 1
(2)
4.2.4 1Substitution 3
𝑑𝑖𝑠𝑡𝑎𝑛𝑒 1 Conversion
Speed = 𝑡𝑖𝑚𝑒 1A answer
56 1Unit
Speed = 3,25ü ü (4)
Speed = 17,23ü km/hü
Demo
NW/JUNE/MATLIT/ EMIS/6******* 5
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