Mathematical Literacy Grade 11 P2 North West June 2018 Memo

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE NATIONAL SENIOR CERTIFICATE GRADE 11 MATHEMATICAL LITERACY P2 MARKING GUIDELINES JUNE 2018 MARKS: 75 CODES EXPLANATION M Method M/A Method with accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification RT/RG/RD Read from table/graph/diagram AO Answer only SF Substitution in a formula O Opinion P Penalty e.g. no units, incorrect rounding R Rounding off J Justification/Reason/Explain NP No penalty for rounding OR omitting units This marking guidelines consists of 6 pages. Demo NW/JUNE/MATLIT/ EMIS/6*******

Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY/P2 NW/JUNE 2018 Ques Solution Explanation TL QUESTION 1 [18 MARKS] 1.1.1 P = R450 + R0,50×250 1M multiplying and F = R450 + R125 adding L2 = R575 1A answer AO (2) 1.1.2 Q = R200 + R2 ×(200 − 100)  1M multiplying and F = R200 + R200 adding L2 = R400 1A answer AO (2) 1.2 F Cost of hiring a car L3 700 650 600 Option 1 1A (0;200) 550 500 1A any point between 450 Option 2 100 km and 300 km Amount in rand 400 1A (300;600) 350 300 1A (350;700) 250 200 1A joining the points 150 1A naming the graphs 100 50 1A heading 0 0 50 100 150 200 250 300 350 Distance in km (7) 1.3 Breakeven point is the point where the cost of hiring a car for 2O explanation F option 1 and option 2 is the same for the same distance travelled.  L4 (2) 1.4 Distance = time × average speed M 250 km = time × 100 km/h 1SF substitution L4 250 𝑘𝑚 1S change subject of time =  100 𝑘𝑚/ℎ formula time = 2,5 hours 1CA time 2,5 hours = 2 hours 30 minutes 1C in hours & minutes Jabulani’s claim is incorrect.  1O opinion Demo NW/JUNE/MATLIT/ EMIS/6*******

Downloaded from hlayiso.com 3 MATHEMATICAL LITERACY/P2 NW/JUNE 2018 OR OR 2 hours 45 minutes = 2,75 hours Distance = time × average speed 1C time in hours 250 km = 2,75h × average speed 1SF substitution 250 𝑘𝑚 1S change subject of average speed =  formula 2,75 ℎ average speed = 90,9 km/h 1CA average speed Jabulani’s claim is incorrect.  1O opinion OR OR 2 hours 45 minutes = 2,75 hours Distance = time × average speed 1C time in hours Distance = 2,75 h × 100 km/h 1SF substitution = 275 km 2CA distance Jabulani’s claim is incorrect.  1O opinion (5) QUESTION 2 [24 MARKS] 2.1 Area of the four additional family members= 4 ×0,7 m2 M = 2,8 m2  1M additional area L3 Total area = (2 + 2,8) m2 = 4,8 m2  1A total answer Area of rectangle = length × breadth 4,8 m2 = length ×1,5 m 1SF substitution 4,8 = length 1S changing the subject of 1,5 the formula 1CA length 3,2 m = length (5) 2.2 150 ℓ = 150 000 cm3 1C conversion M Volume of cylinder = π × r × h 2 L3 150 000 cm3 = 3,142 × r2 × 120 cm 1SF substitution 150 000 1S changing the subject of = r2  377,04 the formula 1S simplification 397,8357734 = r2  1CA radius 19,94582095 = r (5) 20 cm = r 2.3.1 15 F Discount = 100× R11 590 L4 =R1 738,50 1A discount Total cost required = R11 590 – R1 738,50  1M subtraction = R9 851,50 1CA total cost Her claim is correct.  1O opinion Demo NW/JUNE/MATLIT/ EMIS/6*******

Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY/P2 NW/JUNE 2018 OR 100% -15% = 85 % OR 85 Total cost required = 100× R11 590 1A percentage 1M multiplying with 85% = R9 851,50 1CA total cost Her claim is correct.  1O opinion (4) 2.3.2 350 1M multiplying and F Percentage = 10 000×100% (a) dividing L2 = 3,5 % 1A percentage (2) 2.3.2 Total monthly repayments = R764,84×36 1MA multiplying the F (b) = 27 534,24 correct values L2 Interest = R27 534,24 – R10 000 1A total repayment = R17 534,24 1CA interest (3) 2.3.3 In case of death 2O opinion F OR L4 Permanent disability OR Retrenchment OR Diagnosed with critical illness (2) Accept any relevant reason 2.4 ˚F = 1,8 × ˚C + 32˚ 1SF substitution M 140˚= 1,8 × ˚C + 32˚ L3 1S changing the subject of 108˚ ˚C =  the formula 1,8 1A temperature ˚C = 60˚ (3) QUESTION 3 [17 MARKS] 3.1 Measurement = 5,2 cm (Accept 5,1 cm to 5,3 cm ) 1A measured distance MP Scale 2,1 cm : 300 km (Accept 2 cm to 2,2 cm) 1A measured scale L3 5,2 cm ×300 km 1M using scale Actual distance =  2,1 𝑐𝑚 = 742, 86 km 1CA actual distance OR OR Measurement = 52 mm (Accept 51 mm to 53 mm 1A measured distance Scale 21 mm : 300 km (Accept 20 mm to 22 mm) 52 mm ×300 km Actual distance =  1A measured scale 21 𝑚𝑚 1M using scale = 742,86 km 1CA actual distance NPR (4) 3.2 Cost of half full tank = R14,01 ×30 1M multiplying F 1A cost L4 Demo NW/JUNE/MATLIT/ EMIS/6*******

Downloaded from hlayiso.com 5 MATHEMATICAL LITERACY/P2 NW/JUNE 2018 = R420,30 1O opinion The gauge was properly working OR OR 𝑅420,30 1M dividing No. of litres =  1A number of litres 𝑅14,01 = 30 ℓ 1O opinion The gauge was properly working (3) 3.3 30 ℓ×100 𝑘𝑚 CA from 3.1 & 3.2 MP Distance covered =  9ℓ 1M working with L4 = 333 km consumption rate 1CA distance covered Distance left to East London = 742,86 km – 333 km = 409,86 km 1CA remaining distance Mr Thibedi’s claim is not valid.  1O opinion (4) 3.4 From East London take N2 pass Port Elizabeth. At Knysna 1A N2 MP take N12 to Beaufort West. 1A Port Elizabeth L3 1A Knysna 1A N12 OR OR 1A N2 From East London take N2 then before you reach Port Elizabeth 1A Port Elizabeth join N10. Continue straight until you cross N9 then join N1to 1A N10 and N9 Beaufort West. 1A N1 (4) 3.5 Fixing a tyre burst 2O opinion MP OR L4 Buying food OR Going to bathroom OR Stretch legs Accept any relevant reason (2) QUESTION 4 [16 MARKS] 4.1 Height of the mountain = 3 559 ×12 inches M = 42 708 inches 1C conversion L3 42 708 1A height in inches = metres 39,37 1C conversion = 1 084,78537 metres 1CA height in metres ≈ 1 085 metres (4) 4.2 From 08:30 to 18:00 = 9 hours 30 minutes 1A duration M = 570 minutes 1C conversion L4 570 𝑚𝑖𝑛𝑢𝑡𝑒𝑠 1M dividing with 30 number of trips =  1A number of trips 30 𝑚𝑖𝑛𝑢𝑡𝑒𝑠 = 19  The opetator’s statement is correct.  1O opinion Demo NW/JUNE/MATLIT/ EMIS/6*******

Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY/P2 NW/JUNE 2018 OR OR 30 minutes = 0,5 hour 1C conversion From 08:30 to 18:00 = 9,5 hours  1A duration 9,5 ℎ𝑜𝑢𝑟𝑠 1M dividing with 30 number of trips =  0,5 ℎ𝑜𝑢𝑟 1A number of trips = 19  1O opinion The controller’s statement is correct.  (5) 4.3 8+5 = 13 1A adding ratio values M 8 1M using ratio values L2 Number of adults = × 65 13 1A number of adults = 40  (3) 4.4 Total cost = 40 ×7,6 $ + 25 ×4,8 $ CA from 4.3 F = 424 $ 1M multiplying and L4 424 adding =R  1CA cost in $ 0,08 = R5 300 1C conversion The cashier’s claim is valid.  1O opinion OR 7,6 OR Adult rate = R = R95  0,08 4,8 1A adult rate Children’s rate = R = R60  0,08 1A children’s rate Total cost = R95 × 40 + R60 × 25  1M multiplying and = R5 300 adding The cashier’s claim is valid.  1O opinion (4) Demo NW/JUNE/MATLIT/ EMIS/6*******