Mathematical Literacy P1 Feb March 2018 Memo Eng hlayiso.com

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 12 MATHEMATICAL LITERACY P 1 FEBRUARY/MARCH 2018 MARKING GUIDELINES MARKS: 150 SYMBOL EXPLANATION M Method MA Method with accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification RT/RG Reading from a table/graph/diagram SF Correct substitution in a formula O Opinion/Example/Definition/Explanation P Penalty, e.g. for no units, incorrect rounding off, etc. R Rounding off NPR No penalty rounding or omitting units AO Answer only, full marks These marking guidelines consist of 12 pages. Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 2 DBE/Feb.–Mar. 2018 Marking Guidelines Question 1 [30Marks] AO Ques Solution Explanation Topic/L 1.1.1 M 3 12 years A 2A numerical period L1 OR OR Three and half a years A 2A period in words OR 3 years 6 months 3,5 years A (only 1 mark) (2) 1.1.2 F Total Repayment Cost = R1 078,26 × 42 M/A 1MA multiply term by L1 instalment = 45 286,92 CA 1CA Total cost From Q1.1.1. (2) 1.1.3 M F Discount = R29 999,00 × 15% 1M calc. discount L1 = R4 499,85 A 1A saving (2) 1.2.1 M AD : CB = 10,9 : 9,45 1M ratio form MP L1 = 218 : 189  CA 1CA simplified form Accept unit ratio (1: 0,87) OR (1,15 : 1) (2) 1.2.2  M/A CD = 125,92m – (57,5 + 10,9 + 9,45) 1M/A subtracting all M lengths L1 = 48,07m CA 1CA length (2) 1.2.3 M Radius = 4,73 m  M 1M dividing by 2 L1 2 = 2,365 m A 1A simplification NPR (2) 1.2.4 M/A F Total Cost = R97,56/m × 57,5m 1M/A multiply cost by L1 correct distance = R5 609,70 CA 1CA simplification (2) 1.3.1 C A 2A city D (2) L1 1.3.2 Range = 8oC – (– 7oC) MA 1MA subtracting correct values D L1 = 15oC CA 1CA temperature (2) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 3 DBE/Feb.–Mar. 2018 Marking Guidelines Ques Solution Explanation Topic/L 1.3.3 (a) B A 2A city P (2) L1 1.3.3 P (b) Likely OR less likely A 2A correct words L1 (2) 1.4.1 D Bar graph A L1 OR Single bar graph. A OR 2A correct type Vertical bar graph A OR Column graph A (2) 1.4.2 A M Three hundred and sixty one thousand nine hundred 2A number in words L1 and forty eight. (2) 1.4.3 D Q5 A 2A correct question L1 (2) 1.4.4 D 1MA numerator and L1 Average time per mark = 180 min MA denominator 150 = 1,2 min CA 1CA simplification OR 3 ℎ𝑜𝑢𝑟𝑠 OR Average time per mark = 150 MA 1MA numerator and denominator = 0,02 × 60 min = 1,2 min CA 1CA simplification OR OR 150 marks : 180 min MA 1MA correct ratio 1mark : 1,2 min CA 1CA simplification (2) [30] Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 4 DBE/Feb.–Mar. 2018 Marking Guidelines Question 2 [44 Marks] Ques Solution Explanation Topic/L 2.1.1 F Stop order: an instruction to an employer or bank to L1 pay / divert monthly or transfer regularly a certain amount to a person or an account.  O OR Stop order: an instruction that an employee 2O explanation (individual) issue to the employer (bank) to make a series of future dated regular deductions  O OR  O Stop order: Future dated regular monthly deductions (2) 2.1.2  M/A F Difference = R940 465,89 – R536 523,25 1M/A subtraction of L1 correct value = R403 942,64  C/A 1CA simplification AO (2) 2.1.3 F Number of years (2017 – 2029) = 12  M/A 1M/A calculating years L2 Number of months in 12 years = 12 × 12 1C converting years to = 144  C  A months Number of months from 10 May to 1 November = 6 1A additional months Total number of contributions = 144 + 6 1CA total number of = 150  CA months. AO (4) 2.1.4 1M/A multiplying (5 and F Total contribution value 12) L2  M/A 1RT reading monthly = (5 × 12) × R740,22  RT contribution = R44 413,20 CA 1CA total contribution AO NPR (3) 2.1.5 A F a greater / an increased/ a higher / more/ bigger/ larger/ 2A correct missing L1 inflated / better words (2) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 5 DBE/Feb.–Mar. 2018 Marking Guidelines Ques Solution Explanation Topic/L 2.1.6 MA R740,22 + R740,22 × 8,5% 1MA percentage F = R740,22 + R62,9187 M L1 = R803,14 1M adding two values OR M OR R740,22 × 108,5% MA 1M multiplying = R803,14 1MA 108,5% OR OR 740,22 × 8,5% = 62,9187 MA 1MA percentage ∴ 803,14 − 62,9187 = 740,22 M 1M subtracting values (2) 2.2.1 F Hourly overtime rate = R17,76 ×1 MA 1 3 1MA hours L1 = R23,68 CA 1CA rate AO (2) 2.2.2 MA A F 2017 Sunday wage rate = 19,39 × 150% = R29,09 1MA increasing by 150% L2 1A Sunday hourly rate A Total wage = 3 × 9 × R29,09 M 1A hours per day = R785,43 CA 1M multiplying 1CA wage OR AO MA A 2016 Sunday wage rate = R17,90 × 150% = R26.85 A 1MA increasing by 150% Total wage = 3 × 9 × R26,85 M 1ASunday hourly rate = R724,95 CA 1A hours per day 1M multiplying 1CA wage NPR (5) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 6 DBE/Feb.–Mar. 2018 Marking Guidelines Ques Solution Explanation Topic/L 2.2.3 A F (a) 17,76  16,40 1M percentage L1 % increase  × 100% M 16,40 1A correct values used = 8,29268….% ≈ 8,3% OR OR A 19,39  17,90 M 1M percentage % increase = × 100% 1A correct values used 17,90 = 8,324…% ≈ 8,3% OR OR A R16,40 × 1,083 = R17,76 M 1M percentage 1A correct values used OR A OR R17,90× 1,083 = R19,39 M 1M percentage 1A correct values used OR A OR R17,76 ÷ 1,083 = R16,40 M 1M percentage 1A correct values used OR OR A R19,39 ÷ 1,083 = R17,90 M 1M percentage 1A correct values used (2) 2.2.3 F (b) A × 108,3% = 21,93 RT 1RT reading values L2 A= 21,93 1M dividing by 108,3% 108,3% M 1CA amount = R20,25 CA OR OR RT 21,93 A= 1RT reading values 1,083 M 1M dividing by 108,3% = R20,25 CA 1CA amount AO (3) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 7 DBE/Feb.–Mar. 2018 Marking Guidelines Ques Solution Explanation Topic/L 2.2.4 2017 F Total Weekly Wage MA RT 1RT reading value from the L2 = (6 × 9 × R17,76) + (9 × 150% × R17,76) table 1MA multiply with = R959,04 + R239,76 no. of days and hours = R1 198,80 CA 1CA simplification OR OR 2016 1RT reading value from the Total weekly wage MA RT table = (6 × 9 ×R16,40) + (9 × 150% × R16,40) 1MA multiply with no. of days and hours =R1 107,00 CA 1CA simplification (3) 2.3 F Total Income for the day 2RT correct values L1 = 7 × R70 + 35 × R50 + 4 × R75 RT M 1M multiply price by vehicle type = R490 + R1 750 + R300 1CA total income = R2 540 CA OR OR Income from bakkies = 7 × R70 = R490 A 1A bakkies Income from Cars = 35 × R50 = R1 750 A 1A cars Income from minibus = 4 × R75 = R300 A 1A minibus Total Income = R2 540 CA 1CA total income AO (4) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 8 DBE/Feb.–Mar. 2018 Marking Guidelines Ques Solution Explanation Topic/L 2.4.1 Employer provides people job/work for pay F O L1 OR Employer is the company/individual who offers work opportunities for pay. O 2O explanation OR Employer owner of the company O (2) 2.4.2 O O F Get a few months reduced income after termination of L1 work. OR O To give employee a short-term financial relief should 2O reason he/she become unemployed. O O OR O Make provision for some income when a person becomes (2) unemployed or retrenched or retired from work. 2.4.3 RT M 1RT amounts (a) B = R6 272,16 – (R1 184,40 + R350,88) 1M subtracting F = R4 736,88CA 1CA value of B L1 M OR OR RT 1RT amounts B = 9 × 6 × 4 × 21,93 1M multiplying all = R4 736,88CA values 1CA value of B Accept B = (R5 131,62 If 26 days used) (3) 2.4.3 1% of gross salary = R6 272,16 – R6 209,44 MA 1MA subtracting F (b) = R62,72 A correct values L2 1A simplification Total UIF amount = 2 × R62,72 = R125,44 CA 1CA total amount payable OR OR A Total UIF amount = 2 × (1% of R6 272,16) 1A calculating 1% = 2 × R62,7216 MA = R125,44 CA 1MA 2 contributions OR 1CA amount Total UIF amount = 2% of R6 272,16  MA OR = R125,44 CA 2MA Calculating 2% of salary 1CA amount AO (3) [44] Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 9 DBE/Feb.–Mar. 2018 Marking Guidelines QUESTION 3 [25 MARKS] Ques Solution Explanation Topic/L RT RT RT RT M 3.1.1 6 months to 2 years. OR ( ½ year to 2 years) 2RT age L1 OR 6 months to 24 months Accept 23-24 months RT RT (2) 3.1.2 8 kg RT 2RT mass/weight M (2) L1 3.1.3 12 months to 15 months  RT 2RT (one age in this range) M (2) L1 3.1.4 February A 2Acorrect month M (2) L1 3.1.5 weight (in kg) M BMI = L2 (height in m) 2 1SF correct values 11,2  SF 19,5 kg/m2 = 2 (height in m) 1M new subject M 1M finding sq. root 11,2 Height = M 19,5 1CA simplification = 0,758 m  CA AO (4) 3.2.1 55 litre 1MA multiply by M Distance = × 100 km  MA 7,6 litre  MA 100 L2 1MA divide by 7,6 = 723,68 ≈ 724 km  R 1R distance AO (3) 3.2.2  SF 1C to hours M 189 189 1SF correct values L2 Average speed = = 01h45 1,75  C = 108 km/h  CA 1CA Average speed AO (3) 3.3.1  SF M Volume = 53,34cm × 17,78cm × 42,32 cm 1SF correct substitution L3 1CA volume = 40 135,66 cm3  CA 1MA dividing by 1 000 40 135,66 = litres 1000 MA = 40 litres  R 1R volume in litres (4) 12  A 3.3.2 P 3 1A numerator P(U)= or L2 12 48  A 1A denominator = 0,25  CA 1CA decimal AO (3) [25] Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 10 DBE/Feb.–Mar. 2018 Marking Guidelines QUESTION 4 [19 MARKS] Ques Solution Explanation Topic/L A A MP 4.1.1 N10 and N2 1A N10 L1 1A N2 (2)  RT MP 4.1.2 Mountain Zebra N.P 2RTcorrect name L1 (2) 4.1.3 Kirkwood A 2A correct hometown MP (2) L2 4.1.4  RT M Distance = 25 km + (207 km – 22 km ) + 24 km 1RT correct distances MP 1M adding L2 = 234 km  CA 1CA difference OR OR  RT M 1RT correct distances Distance = 24 km + ( 380 km – 195 km ) + 25 km 1M adding = 234 km  CA 1CA difference AO (3) MP 4.2.1 3750 mm  A 2A distance L1 (2) Total exterior length of western wall MP 4.2.2 = 3 550 mm + 3750 mmA 1A adding 3 correct distances L1 = 7 300 mm = 7,3 m C 1C conversion to m OR OR 1A adding correct distances of Total exterior length of western wall Eastern wall (opp. Side //) = 3, 55 m + 1, 7 m + 2, 05 m A = 7, 3 m C 1C conversion to m AO (2) 2A MP 4.2.3 Living room.  A (Passage and/or Kitchen L1 maximum 1 mark) (2) MP 4.2.4 Bedroom 2  A 2A room L1 (2)  A MP 4.2.5 Wash basin/sink/water basin OR Shower OR 2A any item L1 Cupboard (2) [19] Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 11 DBE/Feb.–Mar. 2018 Marking Guidelines QUESTION 5 [32MARKS] Ques Solution Explanation Topic/L D 5.1.1 Numerical A 2A answer L1 (2) D 5.1.2 50% A 2A answer L1 (2) Range = Maximum - minimum M 1M range concept (can be implied) D 5.1.3 L2 34 = 90 – F RT 1RT correct values 1CA simplification F = 90 – 34 = 56 CA AO (3) 5.1.4 67  69 Median % = M 1M concept of median D 2 1A median L2 = 68 A AO (2) Inter-quartile range = Q3 - Q1 M 1M IQR concept(implied) D 5.1.5 L2 Inter-quartile range = 70 – 20 RT 1RT correct values = 50  CA 1CA simplification AO (3) D 5.1.6 66 A 2A mode L1 (2) D 5.1.7 sum of the marks L3 Mean = total number of learners 1MA mean concept (implied) A 1 741  H 1A adding values 70 = MA 26 1 820 = 1 741 + H 1CA value of H H = 79 CA AO (3) P 13 P (equal marks) = A 5.1.8 1A numerator L3 26  A 1A denominator 1 = 1CA simplification 2 CA AO (3) Copyright reserved Please turn over

Downloaded from hlayiso.com Mathematical Literacy/P1 12 DBE/Feb.–Mar. 2018 Marking Guidelines Ques Solution Explanation Topic/L 5.2.1 MA D Q = 288 912 + 393 954 + 94 552 + 192 933 + 650 033 + 1MA adding all Non- L1 299 994 + 575 371 + 312 273 + 372 090 literate adults = 3 180 118 CA 1CA Simplification OR OR MA 1MA subtracting Literate Q = 15 353 036 – 12 172 919 = 3180 118 CA from Total 1CA simplification AO (2) 5.2.2  RT D 1 2 172 919 1RT numerator and L2 % literate = × 100 M 15 353 036 denominator 1M multiply by 100 ≈ 79,3  CA 1CA answer AO OR  RT 1RT numerator and 3 180 118 denominator % literate = 100 - (15 353 036 × 100) M 1M multiply by 100 ≈ 100 - 20,71 ≈ 79,3  CA 1CA answer NPR (3) 5.2.3 D Non Literate: Literacy L2 = 650 033:1 956 497  RT 1RT both values 650 033 1 956 497 = : MA 1MA ratio in correct order 650 033 650 033 = 1 : 3,009842577 ≈1 : 3 or 1 : 3,01 or 1 : 3,0099  CA CA unit ratio NPR (3) 5.2.4 MA 2MA arranging D 244 282; 609 029; 760 029;784 347; 922 171; 1 120 567; L1 1 762 494; 1 956 497; 4 013 463 (2) (Descending 1 Mark; Omitting 1 value 1 mark) 5.2.5 D Northern Cape (NC) A 2A correct province L1 (2) [32] TOTAL: 150 Copyright reserved