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NATIONAL SENIOR CERTIFICATE EXAMINATION
NOVEMBER 2018
MATHEMATICAL LITERACY: PAPER II
MARKING GUIDELINES
Time: 3 hours 150 marks
These marking guidelines are prepared for use by examiners and sub-examiners,
all of whom are required to attend a standardisation meeting to ensure that the
guidelines are consistently interpreted and applied in the marking of candidates'
scripts.
The IEB will not enter into any discussions or correspondence about any marking
guidelines. It is acknowledged that there may be different views about some
matters of emphasis or detail in the guidelines. It is also recognised that,
without the benefit of attendance at a standardisation meeting, there may be
different interpretations of the application of the marking guidelines.
IEB Copyright © 2018 PLEASE TURN OVER
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Mathematical Literacy Grade 12 IEB Paper 2 2018 Memo
IEB Grade 12 Mathematical Literacy Paper 2 memorandum from the 2018, 6 pages. Read online or get the free PDF download, question paper linked when available.
Publisher: IEB
Mathematical Literacy · Grade 12 · 2018. Memorandum, 6 pages. Read online or download the PDF.
- Subject
- Mathematical Literacy
- Grade
- Grade 12
- Document type
- Memorandum
- Year
- 2018
- Paper
- 2
- Publisher
- IEB
- Curriculum
- IEB
- Pages
- 6
- File size
- 216.6 KB
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NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER II – MARKING GUIDELINES Page 2 of 6
QUESTION 1
450 000 000
1.1 1.1.1 = 0,1323
3 400 000 000
1 ZAR = 0,13 USD
1.1.2 (3 × 60) + (1 × 30) + (1 × 55) = R265
1.1.3 265 × 0,08 = $21,20
1.1.4 2006: 1 ZAR = 0,13 USD
2018: 1 ZAR = 0,08 USD
0,13 − 0,08
× 100 = 38,46%
0,13
1
1.2 × 85 000 = 21 250
4
21 250 × 90 = R1 912 500
OR
3
× 85 000 63
= 750
4
85 000 – 63 750 = 21 250 × R90 = R 1 912 500
1.3 1.3.1 (a) 0,7
(b) 0,4
(c) 0,2 OR (c) 0,8
(d) 0,8 (d) 0,2
(e) rain (e) no rain
(f) no rain (f) rain
1.3.2 0,7 × 0,8 × 100 = 56%
1.4 320 ÷ 40 = 8
280 ÷ 25 = 11,2 ≈ 11
11 × 8 = 88 fields
OR
320 ÷ 25 = 12,8 ≈ 12
280 ÷ 40 = 7
12 × 7 = 84 fields
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NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER II – MARKING GUIDELINES Page 3 of 6
QUESTION 2
2.1 Anchovies, because there is no bag limit.
2.2 2.2.1 C = 500 + (n – 1) 250
2.2.2 Fines for galjoen caught over the limit
2400
2300
2200
2100
2000
1900
1800
1700
1600
1500
Cost in Rands
1400
1300
1200
1100
1000
900
800
700
600
500
400
300
200
100
0
0 1 2 3 4 5 6 7 8 9 10 11
Number of galjoen caught over the limit
2.2.3 1 500
2.2.4 7 × 240 = R1 680
He will have R180 left over.
2.3 2.3.1 QUANTITY OF FISH CAUGHT ANNUALLY
OFFICIAL ACTUAL
1996 86 000 000 130 000 000
1997 84 800 000 129 620 000
1998 83 600 000 129 240 000
1999 82 400 000 128 860 000
2000 81 200 000 128 480 000
Official versus Actual number of fish caught
140
FISH CAUGHT (MILLIONS OF TONS)
120
100
80
60
40
20
0
1996 1997 1998 1999 2000
YEARS
Official Actual
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NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER II – MARKING GUIDELINES Page 4 of 6
2.3.2 (a) Range = 95 – 87 = 8 million tons
(b) Median = 90 million tons
(c) Mode = 90 million tons
999
(d) Mean = = 90,8 ≈ 91 million tons
11
OR 90 800 000 OR 91 000 000
2.4.1 1,5 cm = 100 km (accept 1,4 – 1,6 cm)
1,5 cm = 10 000 000 cm
1 : 6 666 666 (accept 7 142 857 – 6 250 000)
2.4.2 4,2 cm (accept 4 – 4,3 cm)
4,2 × 6 666 666 = 27 999 997cm
(accept 250 – 287)
2.4.3 (a) 279,99 – 170 = 109,99 km
(b) Table more accurate – Map small scale or table includes
actual distance on roads. OR inaccurate measurement using
bar scale.
170 km
(c) = 14,16 ℓ
12 km/
1
50 × = 12,5 ℓ
4
No he will not make it.
OR
1
50 × = 12,5 ℓ
4
12,5 × 12 km/ ℓ = 150 km
No he will not make it.
d 170
(d) t= = = 2,125 hours
s 80
= 2:07
OR
2:08
OR
2hrs:7,5 min
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NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER II – MARKING GUIDELINES Page 5 of 6
QUESTION 3
1
3.1 Area triangle = (2,5)(3) = 3,75 m2
2
Area rectangle = 5,5 × 3 = 16,5 m2
Area circle = (3,14)(0,15)2 = 0,07068 m2
Total Area = 3,75 + 16,5 – 0,07068 = 20,18 m2
0,99
3.2 d= = 0,315 m
3,14
= 315 mm
Hole will be too small.
OR
Circumference of hole = 2 × 3,14 × (0,3 ÷ 2 = 0,94 m
Circumference of tree = 0,99m
∴ Hole is too small
7×3
3.3 = 116,67 = 117 strips
0,15 × 1,2
OR
7 3
× = 117 strips
0,15 1,2
OR
7 3
× = 117 strips
1,2 0,15
117
3.4 = 14,6 ≈ 15 packs
8
15 × 159,95 = R2 398,50 ≈ R2 400
3.5 Perimeter = 3,9+ 5,5 + 3 + 5,5 + 2,5 = 20,4 m Yes that will be enough.
1 000
3.6 = 4,34
230
so 4 bricks in the top and the bottom of the length = 8 bricks
1 000
= 9 so 9 bricks in the middle of the length
110
(9 + 4 + 4) × 2 = 34 bricks
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NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER II – MARKING GUIDELINES Page 6 of 6
QUESTION 4
1 1
4.1 oz × 0,0625 = lbs or 0,00625
10 160
1
÷ 0,0022 = 2,84 g
160
4.2 1 : 10 weight
3 800 : 31 600 cost
1 : 8,315
Therefore not the same.
OR
1/10 oz = R3 800 so 1 oz = R38 000
1 oz = R31 600 so No
375
4.3 4.3.1 × 100 = 7,5%
5 000
4.3.2 (a) (i) 5 575 × 0,115 = R641,12/13
(ii) 5 575 + 641,12 = R6 216,12/13
(iii) R6 216,12/13
(iv) 6 216,12 × 0,115 = R714,85
(v) 6 216,12 + 714,85 = R6930,97/98
(b) 7 900 – 6 930,97/98 = R 969,03/02 Short
31 600
4.4 = R27 478,261 ≈ R27 478,26
1,15
Total: 150 marks
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