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Mathematical Literacy Grade 12 IEB Paper 2 2018 Memo

IEB Grade 12 Mathematical Literacy Paper 2 memorandum from the 2018, 6 pages. Read online or get the free PDF download, question paper linked when available.

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Subject: Mathematical LiteracyGrade 1220186 pages
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Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE EXAMINATION NOVEMBER 2018 MATHEMATICAL LITERACY: PAPER II MARKING GUIDELINES Time: 3 hours 150 marks These marking guidelines are prepared for use by examiners and sub-examiners, all of whom are required to attend a standardisation meeting to ensure that the guidelines are consistently interpreted and applied in the marking of candidates' scripts. The IEB will not enter into any discussions or correspondence about any marking guidelines. It is acknowledged that there may be different views about some matters of emphasis or detail in the guidelines. It is also recognised that, without the benefit of attendance at a standardisation meeting, there may be different interpretations of the application of the marking guidelines. IEB Copyright © 2018 PLEASE TURN OVER
Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER II – MARKING GUIDELINES Page 2 of 6 QUESTION 1 450 000 000 1.1 1.1.1 = 0,1323 3 400 000 000 1 ZAR = 0,13 USD 1.1.2 (3 × 60) + (1 × 30) + (1 × 55) = R265 1.1.3 265 × 0,08 = $21,20 1.1.4 2006: 1 ZAR = 0,13 USD 2018: 1 ZAR = 0,08 USD 0,13 − 0,08 × 100 = 38,46% 0,13 1 1.2 × 85 000 = 21 250 4 21 250 × 90 = R1 912 500 OR 3 × 85 000 63 = 750 4 85 000 – 63 750 = 21 250 × R90 = R 1 912 500 1.3 1.3.1 (a) 0,7 (b) 0,4 (c) 0,2 OR (c) 0,8 (d) 0,8 (d) 0,2 (e) rain (e) no rain (f) no rain (f) rain 1.3.2 0,7 × 0,8 × 100 = 56% 1.4 320 ÷ 40 = 8 280 ÷ 25 = 11,2 ≈ 11 11 × 8 = 88 fields OR 320 ÷ 25 = 12,8 ≈ 12 280 ÷ 40 = 7 12 × 7 = 84 fields IEB Copyright © 2018 PLEASE TURN OVER
Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER II – MARKING GUIDELINES Page 3 of 6 QUESTION 2 2.1 Anchovies, because there is no bag limit. 2.2 2.2.1 C = 500 + (n – 1) 250 2.2.2 Fines for galjoen caught over the limit 2400 2300 2200 2100 2000 1900 1800 1700 1600 1500 Cost in Rands 1400 1300 1200 1100 1000 900 800 700 600 500 400 300 200 100 0 0 1 2 3 4 5 6 7 8 9 10 11 Number of galjoen caught over the limit 2.2.3 1 500 2.2.4 7 × 240 = R1 680 He will have R180 left over. 2.3 2.3.1 QUANTITY OF FISH CAUGHT ANNUALLY OFFICIAL ACTUAL 1996 86 000 000 130 000 000 1997 84 800 000 129 620 000 1998 83 600 000 129 240 000 1999 82 400 000 128 860 000 2000 81 200 000 128 480 000 Official versus Actual number of fish caught 140 FISH CAUGHT (MILLIONS OF TONS) 120 100 80 60 40 20 0 1996 1997 1998 1999 2000 YEARS Official Actual IEB Copyright © 2018 PLEASE TURN OVER
Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER II – MARKING GUIDELINES Page 4 of 6 2.3.2 (a) Range = 95 – 87 = 8 million tons (b) Median = 90 million tons (c) Mode = 90 million tons 999 (d) Mean = = 90,8 ≈ 91 million tons 11 OR 90 800 000 OR 91 000 000 2.4.1 1,5 cm = 100 km (accept 1,4 – 1,6 cm) 1,5 cm = 10 000 000 cm 1 : 6 666 666 (accept 7 142 857 – 6 250 000) 2.4.2 4,2 cm (accept 4 – 4,3 cm) 4,2 × 6 666 666 = 27 999 997cm (accept 250 – 287) 2.4.3 (a) 279,99 – 170 = 109,99 km (b) Table more accurate – Map small scale or table includes actual distance on roads. OR inaccurate measurement using bar scale. 170 km (c) = 14,16 ℓ 12 km/ 1 50 × = 12,5 ℓ 4 No he will not make it. OR 1 50 × = 12,5 ℓ 4 12,5 × 12 km/ ℓ = 150 km No he will not make it. d 170 (d) t= = = 2,125 hours s 80 = 2:07 OR 2:08 OR 2hrs:7,5 min IEB Copyright © 2018 PLEASE TURN OVER
Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER II – MARKING GUIDELINES Page 5 of 6 QUESTION 3 1 3.1 Area triangle = (2,5)(3) = 3,75 m2 2 Area rectangle = 5,5 × 3 = 16,5 m2 Area circle = (3,14)(0,15)2 = 0,07068 m2 Total Area = 3,75 + 16,5 – 0,07068 = 20,18 m2 0,99 3.2 d= = 0,315 m 3,14 = 315 mm Hole will be too small. OR Circumference of hole = 2 × 3,14 × (0,3 ÷ 2 = 0,94 m Circumference of tree = 0,99m ∴ Hole is too small 7×3 3.3 = 116,67 = 117 strips 0,15 × 1,2 OR 7 3 × = 117 strips 0,15 1,2 OR 7 3 × = 117 strips 1,2 0,15 117 3.4 = 14,6 ≈ 15 packs 8 15 × 159,95 = R2 398,50 ≈ R2 400 3.5 Perimeter = 3,9+ 5,5 + 3 + 5,5 + 2,5 = 20,4 m Yes that will be enough. 1 000 3.6 = 4,34 230 so 4 bricks in the top and the bottom of the length = 8 bricks 1 000 = 9 so 9 bricks in the middle of the length 110 (9 + 4 + 4) × 2 = 34 bricks IEB Copyright © 2018 PLEASE TURN OVER
Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER II – MARKING GUIDELINES Page 6 of 6 QUESTION 4 1 1 4.1 oz × 0,0625 = lbs or 0,00625 10 160 1 ÷ 0,0022 = 2,84 g 160 4.2 1 : 10 weight 3 800 : 31 600 cost 1 : 8,315 Therefore not the same. OR 1/10 oz = R3 800 so 1 oz = R38 000 1 oz = R31 600 so No 375 4.3 4.3.1 × 100 = 7,5% 5 000 4.3.2 (a) (i) 5 575 × 0,115 = R641,12/13 (ii) 5 575 + 641,12 = R6 216,12/13 (iii) R6 216,12/13 (iv) 6 216,12 × 0,115 = R714,85 (v) 6 216,12 + 714,85 = R6930,97/98 (b) 7 900 – 6 930,97/98 = R 969,03/02 Short 31 600 4.4 = R27 478,261 ≈ R27 478,26 1,15 Total: 150 marks IEB Copyright © 2018

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