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NATIONAL SENIOR CERTIFICATE EXAMINATION
NOVEMBER 2019
MATHEMATICAL LITERACY: PAPER I
MARKING GUIDELINES
Time: 3 hours 150 marks
These marking guidelines are prepared for use by examiners and sub-examiners,
all of whom are required to attend a standardisation meeting to ensure that the
guidelines are consistently interpreted and applied in the marking of candidates'
scripts.
The IEB will not enter into any discussions or correspondence about any marking
guidelines. It is acknowledged that there may be different views about some
matters of emphasis or detail in the guidelines. It is also recognised that,
without the benefit of attendance at a standardisation meeting, there may be
different interpretations of the application of the marking guidelines.
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Mathematical Literacy Grade 12 IEB Paper 1 2019 Memo
IEB Grade 12 Mathematical Literacy Paper 1 memorandum from the 2019, 10 pages. Read online or get the free PDF download, question paper linked when available.
Publisher: IEB
Mathematical Literacy · Grade 12 · 2019. Memorandum, 10 pages. Read online or download the PDF.
- Subject
- Mathematical Literacy
- Grade
- Grade 12
- Document type
- Memorandum
- Year
- 2019
- Paper
- 1
- Publisher
- IEB
- Curriculum
- IEB
- Pages
- 10
- File size
- 771.4 KB
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NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER I – MARKING GUIDELINES Page 2 of 10
QUESTION 1
QUESTION ANSWER SKILLS ASSESSED
1.1.1 (a) 1 May 2016 1 May 2016
1.1.1 (b) Sunday Sunday
1.1.2 R38 – R20 Subtraction of correct values
= R18 R18
18
1.1.3
20
100 Correct numerator
Correct denominator
= 90%
90%
1.1.4 33 26 29 25 20 23 24
Sum of data
7 Dividing by 7
= 180 ÷ 7 R25,71
= R25,71
1.1.5 (a) 5,27% 5,27%
1.1.5 (b) 2016 – 2017 Increase by 5,27%
R26,00 × 1,0527 R27,3702
= R27,3702 Increasing R27,3702 by %
R28,68
2017 – 2018
R27,3702 × 1,0478
= R28,68
1.2.1 Labour OR $1,70 Labour OR $1,70
1.2.2 35c:30c Ratio (correct values in correct
7:6 order)
Simplified ratio
1.2.3 0,35
× 100
3
= 11,67%
OR Fraction values correct
35 11,67%
× 100
300
= 11,67%
12%; 11,7% accepted
1.2.4 0,45c × 1 200 Multiply by 1 200
= $540 $540
OR
45 × 1 200
= 54 000 c
IF
$54 000, award unit penalty
1.2.5 540 ÷ 0,13301 Division by exchange rate
= R4 059,85 (money rounding penalty) R4 059,85
1.3 $3 ÷ $0,50 Division by correct values
= 6 times 6
1.4.1 Clicks Clicks
1.4.2 R1 299 R1 299
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NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER I – MARKING GUIDELINES Page 3 of 10
1.4.3 1 299 Division
1,15 1,15
= 1 129,57 R1 129,57
1.4.4 0,25 × 1 299 25% of 1 299
= R324,75 Subtraction of 25% of 1 299
1 299 – 324,75 R974,25
= R974,25
OR
OR Subtraction from 100% = 75%
0,75 × 1 299 75% of 1 299
= R974,25 R974,25
1.5.1 180 ÷ 2 Division by 2
= R90/bag R90
1.5.2 1 000 g ÷ 250 g Number of bags
=4 Cost per bag multiplied by number
of bags
R90 × 4
= R360
1.5.3 (a) 1 pound = 16 ounces Division by 0,454
1 pound = 0,454 kg Multiplication by 16
35 ounces
Therefore
16 ounces = 0,454 kg
1 ÷ 0,454 × 16
= 35,24
= 35 ounces
OR
16 ÷ 0,454
= 35,24
= 35 ounces
1.5.3 (b) 0,08 × 35 CA from 1.5.3. (a)
= US$2,80 Cost ($/ounce) multiplied by 35
US$2,80
OR
= US$2,82 if they used previous
unrounded value on their calculator.
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NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER I – MARKING GUIDELINES Page 4 of 10
QUESTION 2
QUESTION ANSWER SKILLS ASSESSED
2.1.1 10:15 10:15
IF
10:15 pm
2.1.2 10:41 – 10:15 26 minutes
= 26 minutes
2.1.3 2 047,2 + 3 669,5 Addition of 2 distances
= 5 716,7 5 716,7
2.1.4 1 270 406 × 2 2 540 812
= 2 540 812 Two million five hundred and forty
Two million five hundred and forty thousand eight hundred and twelve
thousand eight hundred and twelve
IF
Have a different large number and
correctly written in words
2.2.1 10 050 + 6 000 Addition of values
= 16 050 m Conversion of 6 km
16 050 m
OR
10,05 + 6
= 16,05 km
= 16 050 m
2.2.2 9 843 × 0,3048 Multiplication by 0,3048
= 3 000,15 m 3 000 m
A accurately illustrated on graph
OR
1 m = 3,28 feet
9 843 ÷ 3,28
= 3 000,914 m
A
2.3.1 East East
(accept North East)
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NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER I – MARKING GUIDELINES Page 5 of 10
2.3.2 1 : 5 000 Correct use of scale
5,4 × 5 000 Conversion
= 27 000 cm
= 270 m (÷100)
OR
54 × 5 000
= 270 000 mm
= 270 m (÷1 000)
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NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER I – MARKING GUIDELINES Page 6 of 10
QUESTION 3
QUESTION ANSWER SKILLS ASSESSED
3.1.1 80 minutes 80 minutes
(accept 1h20)
3.1.2 20 min + 1 hour + 25 min + 1 min + Addition of the correct times
3 min + 12 min Correct time to add
= 1 hour + 61 min OR 121 min 11:31
= 2 hours 1 min
09:30 + 2 hrs 1 min
= 11:31
IF
1 hr 44 min = 11:14 accept
OR
2 hrs 4 min = 11:34 accept
3.1.3 100° 100°
3.1.4 5 176,667
°C = (350 – 32) Rounding 180 °C
9
°C = 176,667
°C = 180 °C
3.1.5 (a) 1ℓ 1ℓ
3.1.5 (b) 360 × 2,36 ml Multiplying correct values
= 849,6 850 ml
= 850 ml B correctly marked on measuring
jug
OR
3
2 4 × 250 ml
= 687,5ml
= 690 ml
Check B on the measuring jug
B
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NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER I – MARKING GUIDELINES Page 7 of 10
3.2.1 20 cm ÷ 2,54 Division by 2,54
= 7,87 7,87 or 8 inch
= 8 inch A or B
A or B
OR Multiplication by 2,54
8 inch × 2,54 20,32 or 20 cm
= 20,32 cm A or B
A or B
3.2.2 d = 20 Radius
r = 10 Substitution of correct values
1 885,2 cm³ or 2 493,18 cm³
3,142 × 10² × 6
= 1 885,2 cm³
OR
d = 23
r = 11,5
3,142 × 11,5² × 6
= 2 493,18 cm³
3.2.3 L² × H = 1 885,2 Substitution
L² × 6 = 1 885,2 Division by 6
L² = 1 885,2 ÷ 6 Square rooting
L² = 314,2 18 cm or 20 cm
L = 314,2
L = 17,7 cm
L ≈ 18 cm
OR
L² × H = 2 492,85
L² × 6 = 2 492,85
L² = 2 492,85 ÷ 6
L² = 415,475
L = √415,475
L = 20,38 cm
L ≈ 20 cm
3.3.1 Length: Addition
10 + 22 + 10 + 22 + 20 74 cm
= 74 cm 42 cm
Width:
10 + 22 + 10
= 42 cm
3.3.2 74 × 42 Multiplication
= 3 108 cm² (unit penalty) 3 108 cm²
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NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER I – MARKING GUIDELINES Page 8 of 10
QUESTION 4
QUESTION ANSWER SKILLS ASSESSED
4.1.1 Shakespeare's works accurate plotting
gaps for bar graph
Comedies
Long Poems
Histories Tragedies Sonnets
4.1.2 154 + 11 + 17 + 10 + 4 Addition
= 196 196
OR
154 +38 + 4
= 196
4.1.3 154 ÷ 196 × 100 Division by correct values
= 78,6 78,6
= 80% 80%
4.1.4 17 ÷ 196 × 360 Multiplication by 360
= 31,22 ° 31,22 °
4.2 6 Numerator
27 Denominator
2 2
=
9 9
4.3.1 1 361 1 361
4.3.2 1 361 – 605 Subtraction
= 756 756
4.3.3 1 380 – 1 221 Subtraction
= 159 159
4.3.4 (a) 2 950 ÷ 10 Sum of all data
= 295 Division by 10
295
4.3.4 (b) Hamlet, Duke of Gloucester, Hamlet, Duke of Gloucester, Othello,
Othello, Iago, Anthony, Richard III, Iago, Anthony, Richard III, Timon,
Timon, Cleopatra Cleopatra
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NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER I – MARKING GUIDELINES Page 9 of 10
QUESTION 5
QUESTION ANSWER SKILLS ASSESSED
5.1 2,9 cm : 100 km 2,9 cm
11,3 cm ÷ 2,9 × 100 Calculating distance
= 389,655 km 389,665 km
Accept range 2,8 to 3 cm
OR
1,45 cm : 50 km
11 m 3 cm ÷ 1,45 × 100
= 389,655 km
5.2.1 Avengers: Infinity War Avengers
5.2.2 100 + 94 + 93 + 69 + 55 + 45 + 36 + Estimating correct values
35 + 34 + 31 (realistic estimation) Addition of values
= 592 Rounding
= 600
5.2.3 January 29 to March 31 62 days
= 62 days Division by number of days
$16 129 032,26
$1 000 000 000 ÷ 62
= $16 129 032,26
OR
= $0,01612903226 billion/day
= $0,02 billion/day
OR for Afrikaans students
$16 129 032 260
5.3.1 F9 F9
5.3.2 22 × 76 Multiplication by
= R1 672 76
R1 672
5.3.3 14 × 12 + 12 method
= 180 180
186 accepted if 6 shaded-out seats
included
5.4 R76 × 3 3
= R228 Multiplication by 3
R228
5.5.1 1 1
4 4
1 1
𝑂𝑅 12 accepted due to varieties
8
given on image
5.5.2 1 1
3 3
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NATIONAL SENIOR CERTIFICATE: MATHEMATICAL LITERACY: PAPER I – MARKING GUIDELINES Page 10 of 10
5.5.3 1 1 Multiplication of 2 probabilities
4 3 1
1 12
=
12
Variations of answers accepted if
students multiply answers to Q 5.5.1
and Q 5.5.2
1 1
OR
24 36
5.5.4 25 1,85 Difference between cost & selling
× 100 price
1,85
Division by cost
= 1 251,35%
1 251,35%
Total: 150 marks
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