Mathematical Literacy Grade 12 P2 2022 Memo (Eng)

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 12 JUNE 2022 MATHEMATICAL LITERACY P2 MARKING GUIDELINE MARKS: 100 Symbol Explanation M Method M/A Method with Accuracy MCA Method with Consistent Accuracy CA Consistent Accuracy A Accuracy C Conversion S Simplification RT/RG/RM Reading from a table OR Reading from a graph OR Read from map F Choosing the correct formula SF Substitution in a formula J Justification P Penalty, e.g. for no units, incorrect rounding off etc. R Rounding Off OR Reason AO Answer only NPR No penalty for rounding This marking guideline consists of 7 pages.

Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P2 (E/CJUNE2022) QUESTION 1 [20] Ques. Solutions Explanations Level 1.1.1 Mozambique ✓✓ 2RT correct L1 country (2) Maps 1.1.2 3 ✓✓ 2A no of tented camps L1 (2) Maps 1.1.3 9 ✓✓ 2A correct number LI (2) Maps 1.1.4 Main camp ✓✓ 2A type of camp L1 (2) Maps 1.2.1 260 ÷ 10 ✓ 1C dividing by 10 L1 Meas. 26 cm ✓ 1A answer (2) 1.2.2 150 – 40 ✓ 1MA subtraction LI Meas. 110 mm ÷ 1 000 ✓ 1C dividing by 1 000 0,11 m ✓ 1A answer (3) 1.2.3 100 : 150 ✓✓ 1RT correct values LI 1M ratio concept Meas. 2:3✓ 1S simplification (3) 1.3.1 14 x 2 + 3 ✓ 1MA multiplication L1 and addition Meas 31✓ 1A answer (2) 1.3.2 6 ✓✓ 2A L1 (2) Probl. [20] Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/JUNE 2022) MATHEMATICAL LITERACY P2 3 QUESTION 2 [32] Ques. Solutions Explanations Level 2.1.1 Distance = 1 029 km ✓ 1RT correct distance L2 Maps 1 029 x 1 000 ✓ 1C conversion 1 029 000 m ✓ 1CA answer (3) 2.1.2 Cape Town to Johannesburg = 1 402 km ✓ 1RT distance CT to L4 Johannesburg Maps Johannesburg to Bloemfontein = 417 km ✓ 1RT distance to Bloem 1CA total distance Total = 1 402 + 417 1RT Nelspruit 1CA difference = 1 819 km ✓ 1O valid Cape Town to Nelspruit = 1 779 km ✓ Difference = 1 819 – 1 779 = 40 km ✓ Valid ✓ (6) 2.1.3 Distance = 1 393 km ✓ 1RT correct distance L3 Maps Distance = Speed x Time 1A substitution 1 393 = 105 x T ✓ 1S simplification T = 1 393/105 ✓ 1C hours to minutes T = 13,2666 hrs 1M adding times = 0,2666 x 60 ✓ 1CA answer = 16 min T = 13hrs 16 min + 2 hrs 30min ✓ = 15hrs 46min ✓ (6) 2.2.1 Bar scale ✓✓ 1A type of scale L1 (2) Maps 2.2.2 Scale 1,2 cm = 5 km ✓ 1A measuring the L3 scale Maps 4,3 cm = 5 x 4,3 ✓ Accept 1,1 cm–1,3 cm 21,5 1A measuring the map = 1,2 ✓ Accept 4,1 cm–4,4 cm = 17,916666 x 1 000 1S simplification = 1 7 917 m ✓ 1CA distance in metres (4) Copyright reserved Please turn over

Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P2 (E/CJUNE2022) 2.2.3 South East ✓✓ 2A direction (2) L2 Maps 2.2.4 2 850 = 870 1MA dividing by 2 850 L2 Maps 870 ✓ 2 850 1C to cm 0,30526 x 100 ✓ 1CA answer 30,526 ✓ 1R rounding to two = 30,53 cm ✓ decimals (4) 2.2.5 Fuel consumed: L3 Maps 10 km = 1litre 1 1 km = 10 litre 1 Therefore 929 km will require: 929 × 10 litre ✓M 1M Determine litres = 929 ÷ 10 = 92,9 litre ✓ A 1A correct answer Cost of return journey = 2 (92,9 × R16,98) ✓ M 1M using 929 km = 2 (R1 577,442) = R3 154, 884 ✓ S 1S simplifying = R3 154, 88 ✓ CA CA correct answer (5) [32] Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/JUNE 2022) MATHEMATICAL LITERACY P2 5 QUESTION 3 [29] Ques. Solutions Explanations Level 3.1.1 274 +15,25 + 15,25 ✓✓ 1RT all values correct L1 1MA adding overhang Meas. = 304,5 cm ✓ 1CA answer OR 274 + 2(15,25) ✓ 274 + 30,5 ✓ = 304,5 cm ✓ (3) 3.1.2 274 – 152,5 ✓ 1MA subtraction L2 Meas. 121,5 x 10 ✓ 1C to mm 1 215 mm ✓ 1CA answer OR (274 x 10) – (152,5 x 10) ✓ = 2 740 – 1 525 ✓ = 1 215 mm ✓ (3) 3.1.3 10:08 + 1:58 ✓ 1MA adding time L2 Meas. 11:66 ✓ 1S simplification 12:06 ✓ 1A correct time (3) 3.1.4 76 + 15,25 ✓ 1MA addition L4 Meas. = 91,25 1MA subtraction 1A answer 152,5 – 91,25 ✓ 1O not valid = 61,25 ✓ Not valid ✓ (4) 3.2.1 100 +40 + 40 + 60 + 20 + 60 + 60 +120+20 +40 ✓✓ 1A all values correct L1 1MA adding all values Meas. = 560 cm ✓ 1A answer (3) Copyright reserved Please turn over

Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY P2 (E/CJUNE2022) 3.2.2 Area = Length x Width 1A area 1 L2 1A area 2 Meas. FIGURE 1 = 100 x 40 1A area 3 = 4 000 cm2 ✓ 1MA total area FIGURE 2 = 20 x 60 = 1 200 cm2 ✓ 1CA area in square FIGURE 3 = 120 x 40 metres = 4 800 cm2 ✓ Total area = 4 000 + 1 200 + 4 800 = 10 000 / 10 000 ✓ = 1 m2 ✓ (5) 3.2.3 Area to paint = 1 x 2 x 2 ✓ 1 MA multiplying by L3 coats and no. of shapes Meas. = 4 m2 ✓ 1 CA area to be painted 4 Litres needed = 6,2 ✓ 1 S simplification = 0,645 ✓ 1 CA no of litres = 0,65 m2 ✓ 1 R rounding (5) 3.2.4 0,65 x 1 000 ✓ 1 MCA multiplying by L4 1 000 Meas. = 650 mℓ ✓ 1 CA simplification Valid ✓ 1 O verification (3) [29] Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/JUNE 2022) MATHEMATICAL LITERACY P2 7 QUESTION 4 [19] Ques. Solutions Explanations Level 4.1.1 17 1A numerator L2 x 100 ✓✓ 255 1A denominator Prob 1CA percentage = 6,67% ✓ NPR (3) 4.1.2 D44 ✓✓ 1A letter LI 1A number (2) Maps 4.1.3 D = 29 ✓ 3A all rows 1 mark for L2 each row Maps E = 32 ✓ 1A correct total H = 41 ✓ Total = 29 + 32 +41 = 102 ✓ (4) 4.2.1 29,9 ✓✓ 2RT correct amount L1 (2) Meas. 4.2.2 (height)2 x BMI = Weight 1SF substitution L4 Meas. 1,7 x 1,7 x BMI = 95 ✓ 1S simplification 2,89 x BMI = 95 1CA BMI = 95/2,89 ✓ 1O verification = 32,87 ✓ Obese / High health risk. Not valid ✓ (4) 4.2.3 Exercise ✓✓ 2A L4 2A Meas. Eat healthy food ✓✓ 2 for each suggestion OR Any other relevant answer. (4) [19] TOTAL: 100 Copyright reserved Please turn over