MLIT P1 GR11 NOV2013 MEMO (Engl)_hlayiso.com_.pdf

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 11 NOVEMBER 2013 MATHEMATICAL LITERACY P1 MEMORANDUM MARKS: 100 SYMBOL EXPLANATION A Accuracy CA Consistent Accuracy C Conversion J Justification (Reason/Opinion) M Method MA Method with accuracy P Penalty for no units, incorrect rounding off, etc. R Rounding off RT/RG Reading from tabl e/graph S Simplification SF Correct substitution in a formula O Own opinion This memorandum consists of 7 pages.

Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P1 (NOVEMBER 2013) QUESTION 1 (30 MARKS) Question Solution Explanation Level + Topic 1.1 Fixed Expenses 1M Method Finance = 6000 + 1500 + 465 + 250 + 1 750 + 500 used √M√SF 1SF Correct L1 = R 10 465, 00 √A values substituted 1A Correct answer (3) 1.2 Cost of ingredients 1M Method Finance = 15,50 + 0,25 + 11,50 + 9,50 + 12,75 + used 8,00 + 12,50 1SF Correct L1 √M√SF values = R70,00 √A substituted 1A Correct answer (3) 1.3 Cost for Ingredients for one Giant Muffin 1SF Correct = 70, 00 50 √SF substitution Finance = R1,40 √MA 1MA Method and accuracy L1 (2) 1.4 Cost of Electricity for one Muffin 1SF Correct Finance = (6 x 1,09) 50√SF substitution = 0,1308 1MA Method L2 = R0,13 √MA and accuracy (2) 1.5 Cost of one Giant Muffin 1SF Correct Finance = 1,40 + 0,13 √SF substitution = R1,53 √MA 1MA Method L1 and accuracy (2) 1.6.1 Profit = 5,00 – 1,53 √SF√SF 2SF Correct Finance = R3,47 √MA substitutions 1MA Method L1 and accuracy (3) 1.6.2 3,47 1SF Correct Finance % Profit = x 100 1,53 values used √SF 1A Accuracy L1 = 226,7973856 √A 1C Conversion = 226,80% √C to 2 decimal places (3)

Downloaded from hlayiso.com (NOVEMBER 2013) MATHEMATICAL LITERACY P1 3 . Question Solution Explanation Level + Topic 1.7 , 1SF Correct Finance Number of muffins = √SF , values used = 3015,850144 √A 1A Accuracy L2 = 3016 Muffins √C 1C Conversion up to whole muffin (3) 1.8.1 A = 12 500 + 12 500 x 12,5% x 5 √SF 1SF Correct Finance = 12 500 + 7 812,50 √CA substitution = R20 312,50 √A 1CA Accurate L2 calculation 1A Correct answer (3) 1.8.2 Monthly Payment = 20 312, 50 60 √M √C 1M Correct Finance = R 338,5416667 method used ( = R 338,54 √C 1C using 60 L2 1C Correct answer to 2 decimal places (3) 1.8.3 Extra muffins needed = 338, 54 3,47 √M√SF 1M Correct Finance = 97,56195965 method used = 98 muffins more √C 1SF Correct L2 values used 1C Correct answer round up (3) [30]

Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P1 (NOVEMBER 2013) QUESTION 2 (22 MARKS) Question Solution Explanation Level + Topic 2.1.1 Surface Area = 2 x 15 x 1,5 + 2 x 8 x 1,5 √SF 1SF Correct Measure = 45 + 24 √MA values substituted = 69 √CA 1MA Correct L1 method and accuracy 1CA Correct answer (3) 2.1.2 20 cm 100 = 0,2 m √C 1C Correct Measure Tile area = 0,2 x 0,2 conversion L2 = 0,04 each √CA 1CA Accurate answer No. of Tiles needed = 69 0,04 √M 1M Correct = 1725 tiles √CA method 1CA Correct answer (4) 2.2 Volume = 15 x 8 x 1,5 √SF 1Sf Correct Measure = 180 √A substitution = 180 kilolitres √C 1A Accurate L2 answer 1C Correct conversion (3) 2.3 Cost = 180 x 5, 55 √SF √SF 2SF Correct Finance = R 999,00 √CA values used 1CA Consistent L1 accuracy (3) 2.4 Water evaporated = 180 x 1,5% √SF √M 1SF Correct Measure = 2,7 kilolitres √CA values used 1M Correct L2 method (x 1,5%) 1CA Consistent accuracy (3)

Downloaded from hlayiso.com (NOVEMBER 2013) MATHEMATICAL LITERACY P1 5 Question Solution Explanation Level + Topic 2.5.1 Width of paving = 17 – 15 or 10 – 8 1M Correct Measure 2 2 √M method used = 1m √CA 1CA Correct L1 answer (2) 2.5.2 50 100 = 0,5 2 pavers per metre √C 1C Correct Measure concept No. pavers for length = 17 x 2 x 2 1M correct = 68 pavers √M method L3 No. pavers for width = 8 x 2 x 2 1M Correct = 32 pavers √M method Total No. of Pavers = 68 + 32 1CA Correct L2 = 100 pavers √CA Answer (4) Width and length with 2 m short can be swapped around [22] QUESTION 3 (20 MARKS) Question Solution Explanation Level + Topic 3.1.1 North √A 1A Correct Maps answer (1) etc. L1 3.1.2 Go through the passage from the front door 2 CI correct Maps onto the veranda. directions given etc. Turn right and walk on the veranda until you Give 1 mark for get to a classroom every 2 correct L1 Turn left along the veranda and enter the instructions (2) third door on your right. √√CI 3.1.3 Double door √A 1A correct Maps Reason = 2 arcs and a line – allows more answer etc. children to go through in one go √J 1J Correct justification (2) L1 3.2.1 Length = 3 cm √A 1A Correct Maps answer etc. Breadth = 2,2 cm √A 1A correct answer (2) L1

Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY P1 (NOVEMBER 2013) Question Solution Explanation Level + Topic 3.2.2 Real life length = 3 x 400 √M 1M correct Maps etc. = 1 200 cm / 12 m √CA method used 1CA L1 Real life breadth = 2,2 x 400 √M Consistent accuracy = 880 cm / 8,8 m √CA 1M correct method used 1CA Consistent accuracy (4) As indicated Maps etc. 3.3 with drawing L1 . 1 mark for correct 1 door 1 mark for correct number of windows (can vary in size) 1 mark for roof (roof may have angled sides) (3) 3.4 No, they are not all the same size. √A 1A Correct Maps etc. answer Not all classes need the same amount of 1J L1 space. Justification/ Some classes less learners etc. Accept any Opinion reasonable answer here. √J (2) 3.5.1 Annual School fees = 10 x 950 √M 1M Correct Finance = R 9 500 √CA method 1CA Correct L1 answer (2) 3.5.2 Discount = 9 500 x 15% √M 1M Correct Finance = R1 425 √CA method Accept x by 0,15 instead of 15% 1CA Correct L2 answer (2) [20]

Downloaded from hlayiso.com (NOVEMBER 2013) MATHEMATICAL LITERACY P1 7 QUESTION 4 (28 MARKS) Question Solution Explanation Level + Topic 4.1.1 16 √RG 1RG Correct Data reading from graph (1) L1 4.1.2 5 √RG 1RG Correct Data reading from graph (1) L1 4.1.3 4 Overs √RG√RG 2RG Correct Data etc. adding and reading from L1 graph (2) 4.1.4 6 Overs √RG√RG 2RG Correct Data etc. adding and reading from L1 graph (2) 4.1.5 1SF Correct Probability P(9 runs SA) = √SF = 20%√C values Substituted L1 or 1C Correct 1 conversion 5 (2) 4.1.6 Total number of runs SA 1MA Correct Data etc. = 5 + 10 + 15 + 9 + 0 + 6 + 15 + 12 + 8+ method and 9 + 4 + 11 + 16 + 1 + 9 + 24 + 12 + 18 + accuracy L1 13 + 9 √MA 1CA Correct = 206 runs √CA answer (2) 4.1.7 Average = 194 20 √M 1M Correct Data etc. = 10,3 runs per over √CA method 1CA Consistent L2 accuracy (2) 4.1.8 Total number of runs New Zealand 1MA Correct Data etc. = 6 +12 + 12 + 7 + 2 + 8 + 12 + 10 + 10 + method and 12 + 2 + 5 + accuracy L1 12 + 2 + 7 + 18 + 6 + 12 + 15 + 2 √MA 1CA Correct = 172 runs √CA answer 1J Correct SA won because they made more justification (3) runs √J

Downloaded from hlayiso.com 8 MATHEMATICAL LITERACY P1 (NOVEMBER 2013) Question Solution Explanation Level + Topic 4.2.1 Social Networking √RG 1Rg Correct Data etc. reading from graph (1) L1 4.2.2 % usage = 72 x 100 √√SF 2SF Correct Data etc. 400 values substituted = 18% √CA 1CA Correct L1 answer (3) 4.2.3 400 x 8% √M 1M Correct Data etc. = 32 learners √A method used 8% = SMSs √CA 1A Accuracy L3 1CA Correct answer (3) 4.2.4 No. Degrees Social Networking 1M Correct Data etc. = 80 x 360 method used 400 √M√SF 1SF correct values L2 substituted = 72° √CA 1CA Correct answer (3) 4.2.5 P( games) = 45 √SF = 11,25 % √CA 1SF Correct Probability 400 √SF numerator 1SF correct L1 denominator 1CA Correct percentage (3) [28] TOTAL: 100