Physical Sciences Grade 12 P2 Eastern Cape Mock 2025 Memo

NATIONAL SENIOR CERTIFICATE/ NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 12 SEPTEMBER 2025 PHYSICAL SCIENCES P2: CHEMISTRY/ FISIESE WETENSKAPPE V2: CHEMIE MARKING GUIDELINE / NASIENRIGLYN MARKS/PUNTE: 150 This marking guideline consists of 17 pages./ Hierdie nasienriglyn bestaan uit 17 bladsye.

2 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/SEPTEMBER 2025) QUESTION/VRAAG 1 1.1 B  (2) 1.2 C  (2) 1.3 D  (2) 1.4 C  (2) 1.5 B  (2) 1.6 C  (2) 1.7 A  (2) 1.8 C  (2) 1.9 D  (2) 1.10 D  (2) [20] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

(EC/SEPTEMBER 2025) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 3 QUESTION/VRAAG 2 2.1 A series of organic compounds that can be described by the same general formula.  ʼn Reeks organiese verbindings wat deur dieselfde algemene formule beskryf kan word. OR / OF A series of organic compounds in which one member differs from the next with a CH2 group.  ʼn Reeks organiese verbindings waarin een lid van die volgende met ʼn CH2- groep verskil. (2) 2.2 2.2.1 C (1) 2.2.2 E (1) 2.2.3 D and/en E  (2) 2.3 2.3.1 4-chloro-2-methylhexane  4-chloro-2-metielheksaan Marking criteria/Nasienkriteria: • hexane / heksaan  • chloro and methyl / en metiel  • Whole name correct / Hele naam korrek  (3) 2.3.2 4-methylpent-2-yne  Marking criteria/Nasienkriteria: 4-metielpent-2-yn • Pentyne / Pentyn  OR / OF • Whole name correct / Hele naam 4-methyl-2-pentyne  korrek  4-metiel-2-pentyn (2) 2.4 H Marking criteria/Nasienkriteria: │ • Correct functional group.  H ― C― H H │ • Whole structure correct  H H  O H • Korrek functionele groep │ │ │ │ • Hele struktuur korrek H ― C ― C ― C― C― C―H  │ │ │ │ H H │ H H H ― C―H │ H (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

4 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/SEPTEMBER 2025) 2.5 2.5.1 Marking criteria/ Nasienkriteria If any of the underlined key words/phrases in the correct context are omitted: - 1 mark per word/phrase. Indien enige van onderstreepte die sleutelwoorde/frases in die korrekte konteks weggelaat word: - 1 punt per woord/frase. Compounds with the same molecular formula but different positions of the side chain, substituents or functional group on the parent chain.  Verbindings met dieselfde molekulêre formule, maar verskillende posisies van die syketting, substituente of funksionele groepe op die stamketting. (2) 2.5.2 Marking criteria/Nasienkriteria: H H H O │ │ │ ‖ • Position of the methyl group H ― C ― C ―C― C―H  moved to carbon 2  │ │ • Whole structure correct  H H │ • Posisie van metiel groep verskuif na koolstof 2 H ― C―H • Hele struktuur korrek │ H NOTE: If position of functional group is changed then 0/2 LET WEL: As die posisie van die funksionele groep verander dan 0/2 (2) 2.6 2.6.1 Using oxygen/gebruik suurstof Using hydrogen/gebruik waterstof P (2) + 6(1) = 8(2)  6 x 2 = 12 CxH12  ∴ C5H12 P= 5 P=5 (2) 2.6.2 CH3CH2CH2CH2CH3  (2) [21] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

(EC/SEPTEMBER 2025) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 5 QUESTION/VRAAG 3 Marking criteria/ Nasienkriteria If any of the underlined key words/phrases in the correct context are omitted: - 1 mark per word/phrase. Indien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks weggelaat word: - 1 punt per woord/frase. 3.1 The pressure exerted by a vapour at equilibrium with its liquid in a closed system.  Die druk wat deur damp uitgeoefen word by ewewig met sy vloeistof in ʼn geslote sisteem. (2) 3.2 LIQUID  The boiling points of the substances are above room temperature.  OR The vapour pressure of the substances at 25 oC are below the atmospheric pressure.  VLOEISTOF Die kookpunt van die stowwe is hoër as kamertemperatuur. OF Die dampdruk van die stowwe by 25 C is laer as die atmosferiese druk. o (2) 3.3 DECREASES / LAER AS.  (1) 3.4 The longer the chainlength / stronger the intermolecular forces the lower the vapour pressure.  Hoe langer die kettinglengte / sterker die intermolekulêrekragte hoe laer die dampdruk. (2) 3.5 3.5.1 Marking criteria/ Nasienkriteria If any of the underlined key words/phrases in the correct context are omitted: - 1 mark per word/phrase. Indien enige van die onderstrerepte sleutelwoorde/frases in die korrekte konteks weggelaat word: - 1 punt per woord/frase. The temperature at which the vapour pressure of a substance equals the atmospheric pressure.  Die temperatuur waarteen die dampdruk van ʼn stof gelyk is aan die atmosferiese duk. (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

6 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/SEPTEMBER 2025) 3.5.2 Marking criteria • Identify the number of sites of hydrogen bonds in propan-1-ol • Identify the number of sites of hydrogen bonds in propanoic acid • Compare the strength of the hydrogen bonds / intermolecular forces • Relate the strength of intermolecular to energy involved. Nasienkriteria • Identifiseer die aantal waterstofbindings in propan-1-ol • Identifiseer die aantal waterstofbindings in propanoësuur • Vergelyk die sterkte van die waterstofbindings / intermolekulêrekragte • Vergelyk die energie van die intermolekulêrekragte • One site of hydrogen bonds in propan-1-ol/A  • Two sites of hydrogen bonds in propanoic acid/B  • Hydrogen bonds / intermolecular forces in propanoic acid/B are stronger than that of propan-1-ol/A  • More energy is needed to overcome the intermolecular forces is propanoic acid/B  OR • One site of hydrogen bonds in propan-1-ol/A  • Two sites of hydrogen bonds in propanoic acid/B  • Hydrogen bonds/ intermolecular forces in propan-1-ol/A is weaker than that of propanoic acid/B  • Less energy is needed to overcome the intermolecular forces is propan-1-ol/A  • Een plek vir waterstofbindings in propan-1-ol/A • Twee plekke vir waterstofbindins in propanoësuur/B • Waterstofbinding/ intermolekulêrekragte in propanoësuur/B is sterker as dié van propan-1-ol/A • Meer energie word benodig om die intermolekulêrekragte in propanoësuur/B te oorkom OF • Een plek vir waterstofbindings in propan-1-ol/A • Twee plekke vir waterstofbindins in propanoësuur/B • Waterstofbinding / intermolekulêrekragte in propan-1-ol/A is swakker as dié van propanoësuur/B • Minder energie word benodig om die intermolekulêrekragte in propan-1-ol/A te oorkom (4) [13] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

(EC/SEPTEMBER 2025) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 7 QUESTION/VRAAG 4 4.1 4.1.1 Esterification/Condensation/Esterifikasie/Versteuring  (1) 4.1.2 H O Marking criteria/Nasienkriteria │ ││  • Correct functional group  H– C–C–O–H  Funksionele groep korrek │ • Whole structure correct  H Hele struktuur korrek (2) 4.2 4.2.1 H2SO4 / Sulphuric acid / Swawelsuur  (1) 4.2.2 But-1-ene/ 1-Butene/ But-1-een /1-Buteen  (2) 4.3 4.3.1 Hydrohalogenation/Hidrohalogenering  (1) 4.3.2 Secondary Halolalkane  The halogen/Cℓ is bonded to a secondary carbon. /The halogen/Cℓ is bonded to a carbon that is bonded to two other carbon atoms. /The halogen/Cℓ is bonded to a carbon that contains one hydrogen atom.  Sekondêre haloalkaan Die halogeen/Cℓ is aan ʼn sekondêre koolstof verbind. /Die halogeen/ Cℓ is verbind aan ʼn koolstof wat verbind is aan twee ander koolstofatome./ Die halogeen/ Cℓ is verbind aan ʼn koolstof wat een waterstof atoom bevat. (2) 4.4 4.4.1 Elimination/dehydrohalogenation/ Eliminasie/dehidrohalogenering  (1) 4.4.2 H H H H H H H H │ │ │ │ │ │ │ │  H─C─C─C─C─ H  + NaOH→ H ─C─ C ═ C ─ C ─ H  │ │ │ │ │ │ H H Cℓ H H H + NaCℓ + H2O Marking criteria for organic compounds/ Nasienkriteria vir organiese verbindings • Correct functional group  Funksionele groep korrek • Whole structure correct  Hele struktuur korrek Inorganic reagent / Anorganiese reagense • NaOH,  NaBr and H2O  (6) [16] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

8 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/SEPTEMBER 2025) QUESTION/VRAAG 5 5.1 Marking criteria/ Nasienkriteria If any of the underlined key words/phrases in the correct context are omitted: - 1 mark per word/phrase. Indien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks weggelaat word: - 1 punt per woord/frase. ANY ONE Change in concentration ✓ of reactant or product per (unit) time. ✓ Change in amount/ number of moles/ volume/ mass of products or reactants per (unit) time. ✓✓ Change in amount/ number of moles/ volume/ mass of products formed or reactants used reactants per (unit) time. ✓✓ ENIGE EEN Verandering in konsentrasie van reaktanse of produkte per (eenheid) tyd. Verandering in hoeveelheid/ getal mol/ volume /massa van produkte of reaktanse per (eenheid) tyd. Verandering in hoeveelheid/ getal mol/ volume/ massa van produkte gevorm/ reaktanse gebruik per (eenheid) tyd. OR/OF The rate of change in concentration/amount of moles/number of moles/volume /mass. ✓✓ (2 or 0) Die tempo van verandering in konsentrasie/hoeveelheid mol/getal mo/volume/ massa. (2 of 0) (2) 5.2 Volume of carbon dioxide (CO2) gas produced remains constant/No CO2 gas bubbles produced ✓ Volume koolstof dioksied (CO2) wat geproduseer word bly konstant/Geen CO2 gasborrels word geproduseer. (1) 5.3 5.3.1 Reaction rate ∆V = Reaksietempo ∆t 147 – 0  = 50  = 2,94 (cm·s-1)  (3) 5.3.2 Marking criteria/ Nasienkriteria (a) Substitution into/ Vervanging in n = V/ Vm (b) Use of mole ratio/ Gebruik van mol verhouding CaCO3 : CO2 (c) Substitution into/ Vervanging in m = nM (d) Substitution into percentage purity equation/ Vervanging in persentasie suiwerheid vergelyking (e) Final answer/ Finale Antwoord Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

(EC/SEPTEMBER 2025) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 9 V n = Vm 147 = (a)  24 000 n = 6,125 x 10-3 mol n (CaCO3) = n (CO2) = 6,125 x 10-3 mol (b)  m = nM m(CaCO3) = (6,125 x 10-3)(100) (c)  m (CaCO3) = 0,6125 g % purity/ suiwerheid 0,6125 = x 100 (d)  2,5 % purity/ suiwerheid = 24,5 % (e)  (5) 5.4 5.4.1 INCREASES / TOENEEM  (1) 5.4.2 • Powdered CaCO3 will increase the surface area/contact area/ increases the state of division of CaCO3.  • More particles will collide with the correct orientation.  • More effective collisions per unit time / Frequency of the effective collisions increase  • Gepoeierde CaCO3 sal die oppervlakte/kontakarea vergroot/vergroot die toestand van verdeling van CaCO3. • Meer deeltjies sal met die korrekte oriëntasie bots • Meer effektiewe botsings per eenheidstyd/ Frekwensie van die effektiewe botsings neem toe (3) 5.5 5.5.1 Particles with sufficient kinetic energy for effective collisions.  Deeltjies met genoeg kinetiese energie vir effektiewe botsings. (1) 5.5.2 INCREASE/ TOENEEM  An increase in temperature increases the average kinetic energy of the particles.  ʼn Toename in temperatuur verhoog die gemiddelde kinetiese energie van die deeltjies. (2) [18] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

10 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/SEPTEMBER 2025) QUESTION/VRAAG 6 6.1 Marking criteria/ Nasienkriteria If any of the underlined key words/phrases in the correct context are omitted: - 1 mark per word/phrase. Indien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks weggelaat word: - 1 punt per word/frase. When the equilibrium in a closed system is disturbed, the system will re- instate a new equilibrium by favouring the reaction that will oppose/cancel the disturbance.  Wanneer die ewewig in ʼn geslote sisteem versteur word, sal die sisteem ʼn nuwe ewewig herstel deur die reaksie wat die versteuring sal teenwerk/ kanselleer, te bevoordeel. (2) 6.2 6.2.1 Blue/Blou  (1) 6.2.2 Green/Groen  (1) 6.3 • The addition of saturated sodium chloride solution increases the concentration of the chloride ions (Cℓ-).  • According to Le Chatelier’s principle the system will respond by consuming the Cu(H2O)62+ and Cℓ--  • The forward reaction will be favoured / the equilibrium position shifts towards right  • Die byvoeging van versadigde natriumchloriedoplossing verhoog die konsentrasie van die chloriedione (Cℓ-). • Volgens Le Chatelier se beginsel sal die sisteem reageer deur die Cu(H2O)62+ en Cℓ- op te gebruik • Die voortwaartse reaksie word bevoordeel/Die ewewigsposisie verskuif na regs (3) 6.4 6.4.1 INCREASES / TOENEEM  • According to Le Chatelier’s principle an increase in temperature favours the endothermic reaction.  • The forward reaction is favoured / the equilibrium position shifts towards right.  • More CO2 is produced. • Volgens Le Chatelier se beginsel ʼn toename in temperatuur bevoordeel die endotermiese reaksie. • Die voortwaartse reaksie word bevoordeel/ die ewewigsposisie verskuif regs. • Meer CO2 word geproduseer. (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

(EC/SEPTEMBER 2025) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 11 6.4.2 OPTION 1 / OPSIE 1 Marking criteria: (a) Correct Kc expression ✓ (b) Substitution into correct Kc expression ✓ (c) Calculation of moles of CO2 by substitution into n = cV ✓ (d) The use of molar ratio to calculate reacted moles of CaCO3 ✓ (e) Calculating the mol of CaCO3 that is unreacted ✓ (f) Substituting molar mass and unreacted moles of CaCO3 in m = nM ✓ (g) Final answer ✓ Nasienkriteria: (a) Korrekte Kc-uitdrukking (b) Vervanging in korrekte Kc-uitdrukking (c) Bereken die mol van CO2 deur in n = cV te vervang (d) Die gebruik van mol verhouding om die aantal mol te bereken van CaCO3 wat reageer het (e) Bereken die aantal onreageerde mol van CaCO3 (f) Vervanging van molêre massa en onreageerde mole van CaCO3 in m = nM (g) Finale antwoord ✓ Kc = [CO2] (a) ✓ [CO2] = 0,0385 mol.dm-3 (b) ✓ n(CO2) = cV = 0,0385 x 2 (c) ✓ = 0,077 mol n(CO2) = n(CaCO3) n(CaCO3) = 0,077mol CaCO3 reacted/reageer (d) ✓ n(unreacted / = n(Initial) – n(reacted/reageer) onreageerde CaCO3) = 0,24 – 0,077 ✓ (e) = 0,163 mol m(unreacted/onreageerde) = nM = 0,163 x 100 ✓ (f) = 16,3 g ✓ (g) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

12 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/SEPTEMBER 2025) OPTION 2 / OPSIE 2 Marking criteria: (a) Correct mol ratio (b) Divide the equilibrium mol of CO2 by 2 (c) Correct Kc expression ✓ (d) Substitution into correct Kc expression ✓ (e) Calculating the mol of CaCO3 that is unreacted ✓ (f) Substituting molar mass and unreacted moles of CaCO3 in m = nM ✓ (g) Final answer ✓ Nasienkriteria: (a) Korrekte mol verhouding (b) Deel ewewigs mol van CO2 deur 2 (c) Korrekte Kc-uitdrukking (d) Vervanging in korrekte Kc-uitdrukking (e) Bereken die aantal onreageerde mol van CaCO3 (f) Vervanging van molêre massa en onreageerde mole van CaCO3 in m = nM (g) Finale antwoord ✓ CaCO3 (s) CaO (s) CO2 (g) Initial mol 0,24 Aanvangsmol Change in mol Verandering in - 𝑥 +𝑥 ✓ (a) mol Equilibrium mol 0,24 - 𝑥 𝑥 Ewewigsmol 𝑥 Concentration ✓ (b) 2 Kc = [CO] ✓ (c) 𝑥 0,038 = 2 ✓ (d) 𝑥 = 0,077 ne = 0,24 – 0,077 ✓ (e) ne = 0,163 mol m (CaCO3) = nM m(CaCO3) = (0,163)(100) ✓ (f) (CaCO3) = 16,3 g ✓ (g) (7) [17] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

(EC/SEPTEMBER 2025) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 13 QUESTION/VRAAG 7 7.1 7.1.1 Bases produce hydroxide ions (OH–) in aqueous solution.  (2 or 0) Basisse produseer hidroksiedione (OH–) in waterige oplossing. (2 of 0) (2) 7.1.2 A (1) 7.1.3 SO42–  (1) 7.2 7.2.1 It ionises incompletely in water  to form low concentration of H3O+ ions.  Dit ioniseer onvolledig in water om lae konsentrasie H3O+-ione te vorm. (2) 7.2.2 Alkaline salt/Alkaliese sout  (1) 7.2.3 CH3COO – + H2O → CH3COOH + OH–  (reactants / reaktanse and / en products / produkte) Excess OH– is produced/Produseer oormaat OH–.  (3) 7.3 7.3.1 Bromothymol blue/Broomtimol blou  (1) 7.3.2 Marking criteria (a) Substitution in caVa (b) Substitution in cbVb (c) Subsitution in na/ nb (d) Use of mole ratio H2SO4 : H3O+ (e) Formula pH = - log [H3O+] (f) Substitution in pH = - log [H3O+] (g) Final answer Nasienkriteria (a) Vervanging in caVa (b) Vervanging in cbVb (c) Vervanging in na/ nb (d) Gebruik van mol verhouding H2SO4 : H3O+ (e) Formule pH = - log [H3O+] (f) Vervanging in pH = - log [H3O+] (g) Finale antwoord Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

14 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/SEPTEMBER 2025) OPTION 1 / OPSIE 1 OPTION 2 / OPSIE 2 caVa na = cbVb nb n(NaOH) = cV Ca x 25 (a)  1 (c) n(NaOH) = (0,2)(12,5 x 10-3) (a)  = 0,2 x 12,5(b)  2  n (NaOH) = 2,5 x 10-3 mol ca = 0,05 mol·dm-3 n (H2SO4) = 2 x n (NaOH) n (H2SO4) = ½ x (2,5 x 10-3) (b)  n (H2SO4) = 1,25 x 10-3 mol c = n/V c = 1,25 x 10-3 / 25 x 10-3 (c)  ca = 0,05 mol·dm-3 H2SO4 + H2O → 2 H3O+ + SO42- c (H3O+) = 2 c (H2SO4) c (H3O+) = 2(0,05) (d)  [H3O+] = 0,1 mol·dm-3 pH = - log [H3O+] (e)  = - log 0,1 (f)  = 1 (g)  (7) [18] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

(EC/SEPTEMBER 2025) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 15 QUESTION 8/VRAAG 8 8.1 8.1.1 Chemical energy to electrical energy.  Chemiese energie na elektriese energie. (2) 8.1.2 Metal M  The substance with the lower standard electrode potential is more easily oxidized. / Metal M is a stronger reducing agent than silver.  Metal M will be oxidised  Metaal M Die stof met die laer standaard elektrodepotensiaal word makliker geoksideer / Metaal M is ʼn sterker reduseermiddel as silwer. Metaal M sal geoksideer word (3) 8.2 8.2.1 Eθcell = Eθcathode/reduction/oxidising agent –Eθanode/oxidation/reducing agent ✓ Eθsel = Eθkatode/reduksie/oksidaseermiddel–Eθanode/oksidasie/reduseermiddel 1,54 ✓= (0,8) – Eθanode/oxidation/reducing agent / Eθanode/oksidasie/reduseermiddel ✓ Eθanode/oxidation/reducing agent / Eθanode/oksidasie/reduseermiddel = 0,74 V ✓ Marking criteria/Nasienkriteria Metal is chromium (Cr)  • Any other formula using unconventional abbreviation , e.g. / Metaal is chroom (Cr) Eθcell = EθOA –Eθ RA followed by the correct substitution Max ¾ Enige ander formule wat onkonvensionele afkorting gebruik bv. Eθsel = EθOM –Eθ RM gevolg deur korrekte vervanging Maks ¾ (5) 8.2.2 Cr│Cr3+ ││ Ag+│Ag  (3) 8.3 8.3.1 REMAINS THE SAME/BLY DIESELFDE  (1) 8.3.2 INCREASES/TOENEEM  (1) [15] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

16 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/SEPTEMBER 2025) QUESTION/VRAAG 9 9.1 A substance of which aqueous solutions contains ions  (2 or 0) ʼn Stof waarvan die oplossing in water ione bevat (2 of 0) OR / OF A substance that dissolves in water to give a solution that conducts electricity. (2 or 0)  ʼn Stof wat in water oplos om ʼn oplossing te vorm wat elektrisiteit gelei. (2 of 0) (2) 9.2 ENDOTHERMIC/ENDOTERMIES  (1) 9.3 X  (1) 9.4 Cu2+(aq) + 2e- → Cu (s)  (2) Ignore phases/ Ignoreer fase Marking criteria / Nasienkriteria • Cu (s) ← Cu2+(aq) + 2e− 2/2 • Cu (aq) + 2e ⇌ Cu(s) 2+ - 1/2 • Cu (s) ⇌ Cu (aq) + 2e 2+ − 0/2 • Cu (aq) + 2e ← Cu(s) 2+ − 0/2 Ignore if the charge omitted on electron/ Ignoreer indien lading weggelaat op elektron 9.5 Silver (Ag) is a weaker reducing agent than copper (Cu) and Zinc (Zn).  Silver (Ag) will not be oxidized. Silwer (Ag) is ʼn swakker reduseermiddel as koper (Cu) en sink (Zn). Silwer (Ag) word nie geoksideer nie. (1) 9.6 Marking criteria / Nasienkriteria (a) Substitution in/ Vervang in n = N/NA (b) Use of mole ratio/ Gerbuik van mol verhouding M : e- (c) Formula/ Formule n = m/M (d) Substitution into/ Vervang in n = m/M (e) Formula/ Formule CaCℓ2 N n= NA 1,806 x 1022 n= (a)  6,02 x 1023 n= 0,03 mol Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

(EC/SEPTEMBER 2025) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 17 n (M)= 0,03 x ½ (b)  n (M)= 0,015 mol m M= (c)  n 0,6 M= (d)  0,015 M= 40 g·mol-1 M= CaCℓ2 (e)  (5) [12] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief