Physical Sciences Grade 12 Paper 2 NSC June 2017 Memo

Downloaded from hlayiso.com SENIOR CERTIFICATE EXAMINATIONS SENIORSERTIFIKAAT-EKSAMEN PHYSICAL SCIENCES: CHEMISTRY (P2) FISIESE WETENSKAPPE: CHEMIE (V2) 2017 MARKING GUIDELINES/NASIENRIGLYNE MARKS/PUNTE: 150 These marking guidelines consist of 14 pages. Hierdie nasienriglyne bestaan uit 14 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 2 DBE/2017 SCE/SSE – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 1 1.1 D  (2) 1.2 D  (2) 1.3 B  (2) 1.4 A  (2) 1.5 C  (2) 1.6 A  (2) 1.7 B  (2) 1.8 D  (2) 1.9 C  (2) 1.10 C  (2) [20] QUESTION/VRAAG 2 2.1 A bond / an atom / a group of atoms  that determine(s) the (physical and chemical) properties of a group of organic compounds.  'n Binding / 'n atoom / 'n groep atome wat die (fisiese en chemiese) eienskappe van 'n groep organiese verbindings bepaal. (2) 2.2 2.2.1 O C H  (1) 2.2.2 Carboxyl (group) / karboksiel(groep)  (1) 2.3 2.3.1 Ketones / Ketone  (1) H H  H H H Marking criteria/Nasienriglyne: 2.3.2 O  • Functional group/ H C C C C C C H Funksionele groep korrek  • Two methyl substituents/ H H H Twee metielsubstituente  H C H H C H • Whole structure correct/  Hele struktuur korrek: 3 H H 3 (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 3 DBE/2017 SCE/SSE – Marking Guidelines/Nasienriglyne 2.4 2.4.1 5-bromo-4-ethyl-2,2-dimethylhexane 5-bromo-4-etiel-2,2-dimetielheksaan Marking criteria/Nasienriglyne: • Correct stem i.e. hexane./Korrekte stam d.i. heksaan.  • All substituents (bromo, ethyl and dimethyl) correctly identified./Alle substituente (bromo, etiel en dimetiel) korrek geïdentifiseer.  • IUPAC name completely correct including numbering, sequence, hyphens and commas./IUPAC-naam heeltemal korrek insluitende volgorde, koppeltekens en kommas .  (3)  2.4.2 4-methylpent-2-yne  4-metielpent-2-yn OR/OF 4-methyl-2-pentyne / 4-metiel-2-pentyn NOTE/LET WEL 4-methyl / 4-metiel  pent-2-yne / pent-2-yn  IUPAC name correct but hyphens omitted / IUPAC naam korrek maar koppeltekens uitgelaat: 1 2 (2) [13] QUESTION/VRAAG 3 3.1 3.1.1 H Marking criteria/Nasienriglyne:  • Functional group H C H Funksionele groep korrek  • Methyl substituent on C-2 H H Metielsubstituent op C-2 • Whole structure correct H C C C O H  Hele struktuur korrek: 3 3 H H H Accept/Aanvaar: -OH as condensed -OH as gekondenseerd (3) 3.1.2 D Accept/Aanvaar: butan-1-ol (1) 3.1.3 G Accept/Aanvaar 2-methylpropan-2-ol / 2-metielpropan-2-ol (1) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 4 DBE/2017 SCE/SSE – Marking Guidelines/Nasienriglyne 3.2 3.2.1 (Increase in) chain length / molecular size / molecular mass/ number of C- atoms/ surface area / contact area / number of electrons (Toename in) kettinglengte / molekulêre grootte / molekulêremassa / aantal C- atome (reaksie)oppervlakte / kontakopperlakte /aantal elektrone (1) 3.2.2 London forces / dispersion forces / induced dipole forces  Londonkragte / dispersiekragte / geïnduseerde dipoolkragte (1) 3.3 3.3.1 108 (°C)  (1) 3.3.2 Compare compound F with compounds C and D: Vergelyk verbinding F met verbindings C en D: • Compound F has a larger molecular mass / molecular size / surface area/contact area / number of C-atoms / number of electrons / than compound C.  Verbinding F het 'n groter molekulêre massa/molekulêre grootte / (reaksie)oppervlakte /kontak area / aantal C-atome / aantal elektrone as verbinding C. • Compound F is more branched than compound D.  Verbinding F is meer vertak as verbinding D. • Intermolecular forces in compound F are stronger than in compound C and weaker than in compound D.  Intermolekulêre kragte in verbinding F is sterker as in verbinding C en swakker as in verbinding D. • More energy needed to overcome intermolecular forces in compound F than in compound C and less energy needed to overcome (break) intermolecular forces in compound F than in compound D.  Meer energie word benodig om intermolekulêre kragte in verbinding F te oorkom as in verbinding C, en minder energie word benodig om intermolekulêre kragte in verbinding F te oorkom / breek as in verbinding D. (4) 3.4 H H H O C H H C O H H H Marking criteria/Nasienriglyne: At least one structural formula of methanol as shown.  Ten minste een struktuurformule van metanol soos aangetoon. Dotted line drawn from O atom on one molecule to H atom bonded to an O atom in the second molecule. (H atom should be between two O atoms.) Stippellyn getrek van O-atoom op een molekuul na die H-atoom gebind aan 'n O-atoom in die tweede molekuul. (H-atoom moet tussen twee  O-atome wees.) Accept/Aanvaar: -OH as condensed / -OH as gekondenseerd (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 5 DBE/2017 SCE/SSE – Marking Guidelines/Nasienriglyne 3.5 3.5.1 Esterification / Condensation  Verestering / Esterifikasie / Kondensasie (1) 3.5.2 Marking criteria/Nasienriglyne: H H  H H • Functional group/ O Funksionele groep korrek   • Whole structure correct/ H C C O C C C H Hele struktuur korrek: 2 2 (2) H H H H [17] QUESTION/VRAAG 4 4.1 4.1.1 Addition / hydrogenation  Addisie / hidrogenering / hidrogenasie (1) 4.1.2 Substitution / halogenation / chlorination  Substitusie / halogenering / halogenasie / chlorinering / chlorinasie (1) 4.1.3 Elimination / dehydration  (1) Eliminasie / dehidrasie / dehidrering  4.2 2-bromopropane  Note/Aantekening: 2-bromopropaan IF/INDIEN: Bromopropane/bromopropaan 1 2 2-bromo propane (2) 4.3 4.3.1 Dehydrohalogenation / Dehydrobromination  Dehidrohalogenering / dehidrohalogenasie / dehidrobrominering / dehidrobrominasie (1) 4.3.2 Hot ethanolic strong base • Concentrated strong base / NaOH / KOH Gekonsentreerde sterk basis / NaOH / KOH OR/OF Strong base with no water / Sterk basis met geen water nie. OR/OF Strong base in (pure) ethanol as solvent. / Sterk basis in (suiwer) etanol as oplosmiddel. • Strongly heated or hot base / Sterk verhitte of warm basis OR/OF High temperature/heat strongly / Hoë temperatuur/sterk verhit (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 6 DBE/2017 SCE/SSE – Marking Guidelines/Nasienriglyne 4.4 4.4.1 H 2 O / NaOH / KOH  (1) 4.4.2 H H H  H H H    H C C C H + H−Cℓ H C C C H +H O H O H H Cℓ H H H Notes/Aantekeninge: • Ignore/Ignoreer ⇌ • Accept HCℓ and H 2 O as condensed./Aanvaar HCℓ en H 2 O as gekondenseerd. • Any additional reactants and/or products Enige addisionele reaktanse en/of produkte: Max./Maks. 3 4 • Accept coefficients that are multiples. Aanvaar koëffisiënte wat veelvoude is. • Incorrect balancing/Verkeerde balansering: Max./Maks. 3 4 • Molecular/condensed formulae Molekulêre/gekondenseerde formule: Max./Maks. 2 4 Accept/Aanvaar: -OH as condensed / -OH as gekondenseerd (4) [13] QUESTION/VRAAG 5 5.1 5.1.1 To measure volume / amount  of gas/oxygen produced. Om die volume van die gas / suurstof berei te meet. (1) 5.1.2 Catalyst / Speeds up the reaction. / Increases reaction rate.  Katalisator / Versnel die reaksie. / Verhoog die reaksietempo. (1) 5.2 No gas / bubbles produced. / Geen gas / borrels word gevorm nie.  OR/OF Volume of gas in syringe remains constant. / The plunger stops moving. Volume van gas in spuit bly konstant. / Die suier hou op beweeg. (1) 5.3 CuO / Copper(II) oxide / catalyst  CuO / koper(II)oksied / katalisator (1) 5.4 • A catalyst provides an alternative pathway of lower activation energy.  'n Katalisator verskaf 'n pad van laer aktiveringsenergie. • More molecules have sufficient / enough kinetic energy. / Meer molekule het voldoende/genoeg kinetiese energie.  OR/OF More molecules have kinetic energy equal to or greater than the activation energy./ Meer molekule het kinetiese energie gelyk aan of groter as die aktiveringsenergie. • More effective collisions per unit time. / Frequency of effective collisions increases.  Meer effektiewe botsings per eenheidtyd. / Frekwensie van effektiewe botsings neem toe. (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 7 DBE/2017 SCE/SSE – Marking Guidelines/Nasienriglyne 5.5 5.5.1 Released / Vrygestel  - Products at lower (potential) energy than reactant. / Reaction is exothermic / ∆H < 0  Produkte by laer (potensiële) energie as reaktans. / Reaksie is eksotermies. / ∆H < 0 (2) 5.5.2 B (1) 5.6 V Marking criteria/Nasienriglyne: n(O 2 ) produced = • Use 0,4 dm3 and 25 dm3 to calculate n(O 2 ). Vm  0,4 Gebruik 0,4 dm3 en 25 dm3 om n(O 2 ) te =  25 bereken. • Use/Gebruik n(H 2 O 2 ) = 2n(O 2 ).  = 0,016 mol • Substitute/Vervang 0,05 dm3 in a/’n relevant formula /relevante formula  • Substitute ∆c/∆n in rate formula.  Vervang ∆c/∆n in tempoformule. • Substitute ∆t in rate formula  Vervang ∆t in tempoformule. • Final answer/Finale antwoord: 0,11 mol∙dm-3∙min-1 Range/Gebied: 0,11 to 0,14 mol∙dm-3∙min-1 OPTION/OPSIE 1 OPTION/OPSIE 2 Rate at which O 2 is formed: n(H 2 O 2 ) used/gebruik = 2(0,016)  Tempo waarteen O 2 vorm: = 0,032 mol ∆n n rate = [H 2 O 2 ] = ∆t V 0,016 − 0  0,032 = = 5,8 − 0  0,05  = 2,76 x 10-3 mol∙min-1 = 0,64 mol∙dm-3 Rate/tempo H 2 O 2 used = 2(rate O 2formed ) ∆c = 2(2,76 x 10-3)  Rate/tempo = − = 5,52 x 10-3 mol∙min-1 ∆t 0 − 0,64  = − 5,52 × 10 −3 5,8 − 0  Rate/tempo = 0,05  = 0,11 (mol∙dm-3∙min- 1 ) = 0,11 (mol∙dm-3∙min-1)   0,64 Accept /Aanvaar: and 5,8 − 0,64 5,8 (6) [16] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 8 DBE/2017 SCE/SSE – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 6 6.1 6.1.1 Products can be converted back to reactants.  Produkte kan omgeskakel word na reaktanse. OR/OF Both forward and reverse reactions can take place. Beide voor-en terugwaartse reaksies kan plaasvind. (1) 6.1.2 Endothermic/Endotermies  (1) - 6.1.3 • K c increases with increase in temperature.  K c neem toe met toename in temperatuur. • Forward reaction is favoured. / Concentration of products increases. / Concentration of reactants decreases.  Voorwaartse reaksie word bevoordeel. / Konsentrasie van produkte neem toe. / Konsentrasie van reaktanse neem af. • Increase in temperature favours an endothermic reaction.  Toename in temperatuur bevoordeel 'n endotermiese reaksie. (3) 6.1.4 Increases / Vermeerder  (1) 6.1.5 Remains the same / Bly dieselfde  (1) 6.2 6.2.1 Marking criteria/Nasienriglyne: (a) Use 48 g·mol-1 to calculate n(Ti).  Gebruik 48 g·mol-1 om n(Ti) te bereken. (b) Use 71 g·mol-1 to calculate n(Cℓ 2 ).  Gebruik 71 g·mol-1 om n(Cℓ 2 ) te bereken. (c) Use mole ratio/Gebruik molverhouding: n(Cℓ 2 ) = 2n(Ti).  (d) n(Cℓ 2 ) equilibrium/ewewig = n(Cℓ 2 ) initial/aanvanklik – n(Cℓ 2 ) reacted/reageer .  (e) Divide by volume/Deel deur volume.  (f) K c expression/K c uitdrukking.  (g) Substitution of c(Cℓ 2 ) in K c /Vervanging van c(Cℓ 2 ) in K c .  (h) Final answer/Finale antwoord: 0,25  Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 9 DBE/2017 SCE/SSE – Marking Guidelines/Nasienriglyne OPTION/OPSIE 1 Cℓ 2 Ti Initial quantity (mol) 6 (b) 7 (a) Aanvangshoeveelheid (mol) Use mole ratio(c) Change (mol)/Verandering (mol) 2 1 Gebruik Quantity at equilibrium (mol) molverhouding 4 (d) 6 (a) Hoeveelheid by ewewig (mol) Equilibrium concentration (mol∙dm-3) Divide by 2(e) 2 Ewewigskonsentrasie (mol∙dm-3) Deel deur 2 No KC expression/Verkeerde Kc-uitdrukking: 1 Kc = (f) Max./Maks. 7 [Cl2 ] 2 8 1 Wrong KC expression/Verkeerde Kc-uitdrukking: = (g) (2)2 Max./Maks. 5 = 0,25 (h) 8 OPTION/OPSIE 2 m 336 − 288 n(Ti) reacted/reageer = = = 1 mol M 48  n(Cℓ 2 ) reacted/reageer = 2n(Ti) = 2(1)  = 2 mol m 426 n(Cℓ 2 ) initial/aanvanklik = = = 6 mol M 71 n(Cℓ 2 ) equilibrium/ewewig = 6 – 2  = 4 mol n 4 c= =  V 2 No KC expression/Verkeerde Kc-uitdrukking: = 2 mol·dm-3 1 Max./Maks. 7 Kc =  8 [Cl2 ] 2 Wrong KC expression/Verkeerde Kc-uitdrukking: 1 =  Max./Maks. 5 (2)2 8 = 0,25  (8) 6.2.2 Remains the same / Bly dieselfde  (1) [16] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 10 DBE/2017 SCE/SSE – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 7 7.1 7.1.1 Weak (acid) / Swak (suur)  (1) 7.1.2 pH = -log[H 3 O+]  4  = -log[H 3 O+] [H 3 O+] = 1 x 10-4 mol∙dm-3  (3) 7.2 7.2.1 A substance that produces hydroxide ions / OH- in water.  'n Stof wat hidroksiedione / OH- in water vorm. NOTE/LET WEL: If water is omitted/Indien water weggelaat is: 1 2 (2) 7.2.2 Marking guidelines/Nasienriglyne: n c × Va na • Formula/Formule: c = /n = cV/ a =  V c b × Vb nb • Use mol ratio/Gebruik molverhouding: 1:1  • Substitution of/Vervanging van: 0,16 x 25 /0,16 x 0,025  • Use/Gebruik V b = 12,5 cm3/0,0125 dm3  • Use/Gebruik 56 g·mol-1  • Substitute/Vervang V = 0,25 dm3  • Final answer/Finale antwoord: 4,48 g  OPTION/OPSIE 1 OPTION/OPSIE 2 OPTION/OPSIE 3 c a × Va na c a × Va na n(acid) used = cV  =  =  = (0,16)(0,025)  c b × Vb nb c b × Vb nb = 4 x 10-3 mol 0,16 × 25 1 0,16 × 25 1 =  =  c b × 12,5 1 c b × 12,5 1 n(KOH) = 4 x 10-3 mol  c b = 0,32 mol·dm-3 c b = 0,32 mol·dm-3 In 12,5 cm3: m n n(KOH) = 4 x 10-3 mol c= c= MV V m n In 250 cm3 0,32 = 0,32 = 250 56× 0,25  0,25  n(KOH) = × 4 × 10 −3  n = 0,08 mol 12,5 m = 4,48 g  m = 0,08 mol n= M m(KOH) = nM m 0,08 = = 0,08 x 56  56 = 4,48 g  m = 4,48 g  Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 11 DBE/2017 SCE/SSE – Marking Guidelines/Nasienriglyne OPTION/OPSIE 4 OPTION/OPSIE 5 n(CH 3 COOH) used = cV  n(CH 3 COOH) used = cV  = (0,16)(0,025)  = (0,16)(0,025)  = 4 x 10-3 mol = 4 x 10-3 mol n(KOH) = 4 x 10-3 mol  n(KOH) = 4 x 10-3 mol  n n c= c= V V 4 × 10 −3 4 × 10 −3 = = 0,0125  0,0125  c b = 0,32 mol·dm-3 c b = 0,32 mol·dm-3 m n c= c= MV V m n 0,32 = 0,32 = 56× 0,25  0,25  m = 4,48 g  n = 0,08 mol m n= M m 0,08 = 56 m = 4,48 g  (7) 7.2.3 Greater than 7 / Groter as 7  (1) 7.2.4 CH 3 COO-(aq) + H 2 O(ℓ)  ⇌ CH 3 COOH(aq) + OH-(aq)  Due to formation of (OH-), the solution is basic / alkaline As gevolg van die vorming van (OH-) is die oplossing basies / alkalies Notes/Aantekeninge • Reactants  Products  Ignore balancing Reaktanse Produkte Ignoreer balansering • Ignore/Ignoreer  and phases/en fases. • Marking rule 6.3.10/Nasienreël 6.3.10 (3) [17] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 12 DBE/2017 SCE/SSE – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 8 8.1 8.1.1 Emf / Emk  (1) 8.1.2 Voltmeter / Multimeter  (1) 8.1.3 Salt bridge / Soutbrug  (1) 8.1.4 Temperature / Temperatuur: 25 °C / 298 K  Concentration / Konsentrasie: 1 mol·dm-3  (2) 8.2 Marking criteria/Nasienriglyne: Dependent and independent variables correctly identified.  - Afhanklike en onafhanklike veranderlikes korrek geïdentifiseer. Relationship between the independent and dependent variables correctly stated./Verwantskap tussen die afhanklike en onafhanklike veranderlikes korrek  genoem. Examples/Voorbeelde: Emf increases as concentration (of oxidising agent) increases. Emk neem toe soos wat konsentrasie (van die oksideermiddel) toeneem. NOTE/LET WEL: IF/INDIEN: Emf is directly proportional to concentration. Emk is direk eweredig aan konsentrasie. .1 2 (2) 8.3 OPTION/OPSIE 1 Notes/Aantekeninge θ E cell θ = E reduction θ − E oxidation  • Accept any other correct formula from the data sheet./Aanvaar enige ander korrekte 1,11  = EθX / X2+ - (- 0,76)  formule vanaf gegewensblad. EθX / X2+ = 0,35 (V)  • Any other formula using unconventional abbreviations, e.g. E° cell = E° OA - E° RA followed by correct substitutions:/Enige X = Copper / Cu / koper  ander formule wat onkonvensionele afkortings gebruik bv. Accept/Aanvaar: E° sel = E° OM - E° RM gevolg deur korrekte Cu/Cu2+ half reaction / half-reaksie vervangings: Max/Maks: 3 4 OPTION/OPSIE 2 X2+(aq) + 2e-  X(s) 0,35 (V)   Zn(s)  Zn2+(aq) + 2e- 0,76 (V)  X2+(aq) + Zn(s)  X(s) +Zn2+(aq) 1,11 (V)  X = Copper/Cu/koper  Accept/Aanvaar: Cu/Cu2+ half reaction / half-reaksie (5) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 13 DBE/2017 SCE/SSE – Marking Guidelines/Nasienriglyne 8.4 Cu2+(aq) + Zn(s)  → Zn2+(aq) + Cu(s)  Bal.  Accept/Aanvaar: • X2+(aq) + Zn(s) → Zn2+(aq) + X(s) • Any metal identified in QUESTION 8.3 of which the ion has a +2 charge. Enige metaal geïdentifiseer in VRAAG 8.3 waarvan die ioon 'n +2-lading het. Notes/Aantekeninge • Reactants  Products  Balancing  Reaktanse Produkte Balansering • Ignore phases./Ignoreer fases. • Ignore double arrows./Ignoreer dubbelpyle. • Marking rule 6.3.10/Nasienreël 6.3.10. (3) [15] QUESTION/VRAAG 9 9.1 Electrolytic (cell) / Elektrolitiese (sel)  (1) 9.2 P (1) 9.3 9.3.1 Au(s) → Au3+(aq) + 3e-  Ignore phases / Ignoreer fases Notes/Aantekeninge Au3+ + 3e- ← Au (2 ) Au3+ + 3e- ⇌ Au (0 ) 2 2 Au ⇌ Au + 3e 3+ - ( 1 ) Au3+ + 3e → Au ( 0 ) 2 2 (2) 9.3.2 (+)3  (1) 9.3.3 Electrical energy (is converted) to chemical energy.  Elektriese energie (omgeskakel) na chemiese energie. (1) 9.3.4 Becomes smaller / thinner / eroded / decrease in mass.  (1) Word kleiner / dunner / weggevreet / afname in massa. 9.4 ANY ONE/ENIGE EEN: • Increase in value. / Neem toe in waarde.  • Protection against rust. / Beskerming teen roes. (1) 9.5 ANY ONE/ENIGE EEN: • Replace Au3+(aq) / electrolyte with Ag+(aq) / silver(I) solution / use a silver solution Vervang Au3+(aq) / elektroliet met Ag+(aq) / silwer(I)-oplossing / gebruik 'n silwer oplossing • Replace P / anode / gold with Ag(s) / silver Vervang P / anode / goud met Ag(s) / silwer. (1) [9] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 14 DBE/2017 SCE/SSE – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 10 10.1 10.1.1 B/air/lug  & C/methane/metaan  (2) 10.1.2 Nitric acid / HNO 3 / salpetersuur  (1) 10.1.3 A / Sulphur / Swael / S  (1) 10.1.4 2NH 3 (g) + H 2 SO 4  → (NH 4 ) 2 SO 4  Bal.  Notes/Aantekeninge • Reactants  Products  Balancing  Reaktanse Produkte Balansering • Ignore/Ignoreer ⇌ and phases/en fases. • Marking rule 6.3.10/Nasienreël 6.3.10 (3) 10.1.5 D / potassium chloride / kalium chloried (1) 10.2 10.2.1 OPTION/OPSIE 1: OPTION/OPSIE 2: 3 3 22 %P = x 22% ∴ m(P) = (0,44) ( x 2 = 0,44) 7 7 100 = 9,43% = 0,19 kg  9,43 ∴m(P) = × 2 kg  100 = 0,19 kg  (3) 10.2.2 OPTION/OPSIE 1 OPTION/OPSIE 2 22 %filler/bindstof = 100 – 22  m(fertiliser/kunsmis) = x2  = 78% 100 = 0,44 kg 78 m(filler/bindstof) = x2  m(filler/bindstof) = 2 – 0,44  100 = 1,56 kg  = 1,56 kg  (3) [14] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou