Physical Sciences Grade 12 Paper 1 North West June 2025 Memo

education Department: Education North West Provincial Government REPUBLIC OF SOUTH AFRICA PROVINCIAL ASSESSMENT/ PROVINSIALE ASSESSERING [ GRADE/GRAAD 12 } PHYSICAL SCIENCES: PHYSICS (P1) FISIESE WETENSKAPPE: FISIKA (V1) JUNE/JUNIE 2025 FINAL MARKING GUIDELINES/NASIENRIGLYNE SERB RRR TR RR RETEST RRR TTR Re « e . . . . . . . ’ °¢ ETT TTT bd MARKS/PUNTE: 144 These marking guidelines consist of 15 pages. Hierdie nasienrigyne bestaan uit 15 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

QUESTION 1/VRAAG 1 110 By 12) Dv 13° CW 14 AVY 15° AVY Te ¢ A 17 CW 18 AVY 19 Dw 110 A VW Copyright reserved/Kopiereg voorbehou NW/June/Junie 2025 (2) (2) (2) (2) (2) (2) (2) (2) (2) (2) [20] Please turn over/Blaai om asseblief

QUESTION 2/VRAAG 2 2a 2.2 Marking criteria If any of the underlined key words/phrases in the correct context is omitted deduct 1 mark. /Indien enige van die onderstreepte word/frases nie in die korrekte konteks is When a net force acts on an object, the object will accelerate in the direction of the force /and the acceleration is directly proportional to the force and inversely proportional to the mass of the object. / /Wanneer ‘n netto krag op ‘n voorwerp inwerk, sal die voorwerp versnel in die rigting van die krag en die versnelling is direk eweredig aan die krag en omgekeerd eweredig aan die massa van die voorwerp. Fa Fu Fy NOTE/NOTA If force — diagram/ Indien ‘n kragtediagram (5/5) Accept the following symbols: Aanvaar die volgende simbole | Fu vo | Fx/ N/Normal force/Normaalkrag TV) ~~ Frit ension/Spanning Fg Vv w /mg/weight/gravitational force/gravitasiekrag fv Fk/f/Ff /Force of friction/kinetic frictional force/kinetiese wrywingskrag Fav FE/FA/F/Applied force/Toegepaste krag NOTES/NOTA Mark awarded for label and arrow. / Punte toegeken vir benoemimg en pyltjie. Do not penalise for the length of arrows. / Moet nie penaliseer vir die lengte van die pyltjies nie. Any other additional force(s)/ Enige ekstra kragte: Max 4/5 If everything is correct, but no arrows. / Alles korrek maar geen pyle: Max 4/5 (2) (5)

2.3 NW/June/Junie 2025 oat Fnet = ma} (Direction of motio Car / Kar -T - fk + Fe = ma} -T— 1800 + 8000 = 900a v -T = 900a - 6200 Trailer T - fk = ma} T -300 = 150a Substituting (1) and (2) T - 300 = 150a -(900a - 6200) - 300 = 150a v a=56ms* left v +/Rigting van beweging as +) ¥ Any one/ enige een (5) 2.4 Increase Vv ¥ Copyright reserved/Kopiereg voorbehou (2) [14] Please turn over/Blaai om asseblief

NW/June/Junie 2025 QUESTION 3/VRAAG 3 3.4 Marking criteria lf any of the underlined key words/phrases in the correct context is omitted deduct 1 mark. /Indien enige van die onderstreepte word/frases nie in die korrekte konteks is. The force that opposes the motion of an object and which acts parallel to the surface. / / / Die krag wat die geneigdheid vir beweging van ‘n stielstaande voorwerp reletief / paraliel tot die opperviak teenstaan. (2) 3.2 Fu tt Fo NOTE/NOTA Freebody — diagram / vryliggamdiagram (3/3) Accept the following symbols: Aanvaar die volgende simbole Fu Vv Fy/ N/Normal force/Normaalkrag fv F,/f/Ff /Force of friction/kinetic frictional force/kinetiese wrywingskrag Fg V w /mg/weight/gravitational force/gravitasiekrag NOTES/NOTA e Mark awarded for label and arrow. / Punte toegeken vir benoemimg en pyltjie. e Do not penalise for the length of arrows. / Moet nie penaliseer vir die lengte van die pyltjies nie. e Any other additional force(s)/ Enige ekstra kragte: Max 2/3 e If everything is correct, but no arrows. / Alles korrek maar geen pyle. Max 2/3 (3) 3.3 Fai = Fg sin 6 v =mgsin8 | any onefenige een = (25) (9,8) sin 30°V Fgi = 122,5 NV (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

NW/June/Junie 2025 3.4 | OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 tan @ = ps Fgu=f =0,6 mg sin@ = ps N @ = tan'(0,6) v Us =mg sin 8/mg cos 8 8 = 30,96°” 6 = tan” (0,6) v 9 = 30,96°v (2) 3.5 Frictional force decreases v “. Frictional force is directly proportional the normal force/ As the normal force decreases with an increase in the angle of inclination frictional force will also decrease, “/ Wrywingskrag neem af. Wrywingskrag is direk eweredig aan normaalkrag/indien die hoek van die helling groter word, sal normaalkrag en wrywingskrag verminder. (3) [13] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

NW/June/Junie 2025 QUESTION 4 /VRAAG 4 41 4.2 Marking criteria lf any of the underlined key words/phrases in the correct context is omitted deduct 1 mark. /Indien enige van die onderstreepte word/frases nie in die korrekte konteks is. tn an isolated/ closed system the total (linear) momentum is conserved/ remains constant. v v/ In ‘n gesiote sisteem bly die totale momentum behoue/konstant. 4.2.1 Zpi = Ipf Any one V/Enige een mvic + mvit = mvfc + mvft (650) (16,67) V_+(1000) (8,33) V = (650) (vfc)+(1000) (10) V Vic= 14,10 m.s" to the right V / na regs 4.2.2 POSITIVE MARKING FROM QUESTION 4.2.1. POSITIEWE NASIEN VANAF VRAAG 4.2.1. If system approched is used (vamvie? +%”m vic = Yamvie? + Yami) NOTE: Award marks for only the formula and conclusion. (2/6) Before collision/Voor botsing Yamvic. + Yarnvie’ ¥ % (650) (16.67) + ¥ (1000) (8,33). ¥ 90313,89+34694,45 125008,34 J ¥ After collision/Na botsing Yernvec + Yarovee Y%, (650) (14,10)" + % (1000) (10) ¥ 64613,25+50 000 114 613,25 Jv 12500,34 J # 114 613,25 J «. Inelastic v/Onelasies 4.3 Newton's third law. //Newton se derde wet Copyright reserved/Kopiereg voorbehou When the car and the truck collide, the force that the car exerts on the truck is equal in magnitude V but opposite in direction to the force that the car exerts on the truck. V/Wanneer die kar en die trok bots, sal die krag wat die kar op die trok uitoefen net so groot wees as die krag wat die trok op die kar uitoefen, maar in teenoorgestelde rigting. (6) (3) [16] Please turn over/Blaai om asseblief

NW/June/Junie 2025 QUESTION 5 /VRAAG 5 5.1 The product of the resultant/ net force acting on an object and the time the net force act on an object. / // Die produk van die resultant/netto krag op die voorwerp en die tyd wat die netto krag op die voorwerp uitgeoefen is. (2) 5.2 Magnitude of net force Frye: (N) 01 02 03 04 At(s) Marking criteria/ Nasienkriteria Shape. ¥/ Vorm Both axis with S.| units. “// Beide asse met SI eenhede. (2) 5.3 5.3.1 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 Fnet-At = Area under graph Fret-At = 22 x 0.4 W /Area onder die grafiek = 8,8/2 ¥ =%xbxhv Fnet-At = 4,4 N.s ¥ =%x0,4x22v Fret-At = 4,4 N.s v (3) 5.3.2 |bosiTIVE MARKING FROM QUESTION 5.3.1/POSITIEWE NASIEN FnetAt = Ap } FnetAt = m (vf - vi) J any one V/enige een 4.4 V = 0,65 (vf-0) V Vf = 6,77 m.st V (4) 5.4 Increase. V/ Toeneem (1) 5.5 There must be an increase in change of velocity, to maintain a constant impulse when mass decreases. V //Daar moet ‘n toename in die verandering van snelheid wees om 'n konstante impuls te behou as die massa afneem (2) [14] QUESTION 6 /VRAAG 6 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

6.1 6.2 6.3 6.4 Copyright reserved/Kopiereg voorbehou Negative. V/ Negatief 6.2.1 Gradient= vo- vi ¥ te-t = 0=(-9,8) ¥ 3-2 = 9,8 (m.s7) ¥ 6.2.2 (Gravitational) acceleration. “/ (Gravitasie)versnelling. 6.3.1 OPTION 1 Gradient= v2- vi ¥ te-t 9,8= 14.7-vi ¥ 2-0 vi=-4,9 ms" «V1 = 4,9 m.s upwards V /opwaarts OPTION 2 vi = vi + aAtY 14,7 = vi + (9,8) (2) ¥ vi=-4,9 m.s* * Vi = 4,9 m.s upwardsY /opwaarts 6.3.2 14,7 m.s‘v downwards. V/ afwaarts 6.3.3 9,8 m.s* V upwards. “/ opwaarts 64.1 Remeved 6.4.2 Remove 6.4.3. Maximum height after the first bounce. ” Removed NW/June/Junie 2025 (1) (3) (2) (3) (2) (2) (1) (1) (1) (4) [14] Please turn over/Blaai om asseblief

QUESTION 7 /VRAAG 7 eA 7.2 7.3 NW/June/Junie 2025 An object which has been given an initial velocity and moves under the influence of gravitational force only. /V/‘n Voorwerp wat ‘n beginsnelhei gegee is en dan beweeg slegs onder die invioed van gravitasiekrag Oms!¥ (2) (1) OPTION 1/OPSIE 1 (Upwards as positive)/ Opwaarts as positief OPTION 2/OPSIE 2 (Downwards as positive)/ Af as positief v2 = vi2 + 2aAy ¥ (0)? = (vi)? + 2(-9,8) (30) ¥ vi = 24,25 m.s'“upwards”/ opwaarts OPTION 3 /OPSIE 3 (Upwards as positive)/ Opwaarts as positief v2 = vi? + 2ahy ¥ ve = (0)? + 2(9,8) (30) V Vi = 24,25 m.s! Vv downwardsv/ afwaarts OPTION 4/OPSIE 4 (Downwards as positive)/ Af as positief Ay = vidt + “at? -30 = (0) At+ % (-9,8) At? -30 = 0-4,9 At? At=2,47s Both v/Albei Vr = vi + at vr = (0) + (-9,8) (2,47) v vr = 24,21 m.s downwardsv/ Afwaarts Ay = viAt + “at? 30 =0+4,9 At? At=2,47s Both v/ Albei ve=vit at (0) = vi + (9,8) (2,47) ¥ Vi = -24,21 m.st vi= 24,21 m.s-1 upwards v/ opwaarts Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

74 Ball/Bal X Ayx = yt - yi =yi-0 Ayx= yt Ball/Bal X Ayx = viAt+ Yadt? / = (24,25) (At) + % (-9,8) At Vv = 24,25 At-4,9 At... nT Yfx = Yfy 24,25 At-4,9 Av=-4,9 AP + 30/ 24,25 At = 30 At=1,24sV Position m us) NW/June/Junie 2025 POSITIVE MARKING FROM QUESTION 7.3./POSITIEWE NASIEN Ball/Bal Y Ayy = yt- yi = yr- 30 Ayy = yr- 30 Ayy + 30 = yyy Ball/Bal Y Ayy = viAt + %aAt? = (0) (At) + % (-9,8) AB V =-4,9 At. - (7) Posisie {m) Gk hl ts} Marking criteria/Nasienkriteria Note: 1 shape labelled (3/3) and No shape labelled (1/3) Shape for ball X/Vorm van bal X v Shape for ball Y/Vorm van bal Y v Both axis with S.| units /Beide asse met S.l eenhede v (3) Copyright reserved/Kopiereg voorbehou [17] Please turn over/Blaai om asseblief

NW/June/Junie 2025 QUESTION 8 /VRAAG 8 8.1 8.2 The mechanical energy in an isolated system remains constant. /V /Die totale meganiese energie bly konstant in 'n geisoleerde sisteem. Emecha = Emechc (mghc+Ymvc*)= (mghc+Ymvc2) | Any one // Enige een (120)(9,8)(8) + % (120)(0)? V= (120)(9.8)(2) — % (120)vc2V 9408 = 2352 + 60 vc? Ve = 10,84 m.s'/ 8.3 POSITIVE MARKING FROM QUESTION 8.2. / POSITIEWE NASIEN Option 1/Opsie 1 Ware = AEk + AEp Ws = (amv? - Ymv2) + (mghf - mghi)} Any one V/Enige een Wr = (A(120)(1,1 2-% (120)(10 84)2) V+((120)(9 8)(5) — (120)(9,8)(2)) V IW; = - 6977,74 + 3528 IW: = -3449,74 J V (Accept range/Aanvaar:between/tussen (3449 J — 3456 J) Option 2/Opsie 2 Emecha = Ep + Ek =mgh +¥%mv 2 | Any one // Enige een = (120)(9,8)(5) + %(120)(1,1)2 V = § 952,6 J mecha = Mgh = (120)(9,8)(8) =9408 JV Heat generated/Hitte gegenereer = 9408 — 5952,6 = 3455.4 JV Accept range/Aanvaar: between/tussen (3449 J — 3456 J) QUESTION 9 /VRAAG 9 Copyright reserved/Kopiereg voorbehou (2) (4) (4) [10] Please turn over/Blaai om asseblief

NW/June/Junie 2025 9.1 | Marking criteria lf any of the underlined key words/phrases in the correct context is omitted deduct 1 mark. //ndien enige van die onderstreepte word/frases nie in die korrekte konteks is nie, trek 1 punt af A force for which the work done in moving an object between two points depends on the path taken. ~~/n krag waarvoor die arbeid verrig om 'n voorwerk tussen twee punte te beweeg, afhanklik is van die roete wat gevolg word. (2) = Option 1/ Opsie 1 Whe = AEk + AEp Wa + Wr = (Yamve - Yam) + (mghr- mghi) FAny one v / Enige Wa + (- 5,85 x 108) = (0) + (1750)(9,8)(55) v Wa= 943250 + 5,84 x 108 Wa = 6 783 250 J Wa = Fa Ax cos 8 ¥ 6 783 250 = Fa (570) cos (0) ¥ Fa= 11 900,44 N v Accept range: between (11 900,42 N - 11 900,45 N) Option 2 Wr = f Ax cos 8 ¥ -5,84 x 10° = f (570) cos (180) v f = 10245,61 J Faet= ma Fra =0 -f—Foi+ Fa=0) Anyone “/Enige een - f-— (1750) (9,8) sin 6+ FA =0 - (10245,61)— (1750) (9,8) (=)+ Fa= 0 v Fa= 11900, 43Nv Accept range: between (11 900,42 N - 11 900,45 N) (5) 9.3 Fret = ON v (1) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

9.4 NW/June/Junie 2025 OPTION 1 / OPSIE 1 Whe = AE + AEp Wa + Wt = (Yamve? - Yamvi7) + (mghr- mghi)F Any one ¥ Wa + (6,44 x 10°) (570) cos (180) v = % (1 100)(25? — 202) v + (4. 100)(9,8)(0 — 55)v” Wa= 3 670 800 — 592 900 + 123 750 Wa = 3 201 650 J OPTION 2/ OPSIE 2 Whet = AE Wa + Wy + Wegi= (Amve - Zmv2) Any one v Wa + f Ax cos 6 = mg sin @ Ax cos 9 = (Yemve? - “mvi?) Wa + (6,44 x 10°) (570) cos (180) v’ + (1100) (9,8) (+) 570 cos (0) v = Ye (1 100)(25? — 202) v Wa - 3 660 451,95 + 592 900 = 123 750 Wa = 3 201 650 J v (5) [13] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

QUESTION 10 /VRAAG 10 10.1 Doppler effect. //Doppler effek 10.2 fis VEVL fast vivs = 340 V (458) v 340-30 fL = 502,32 HzV 10.3 Decrease V/ Afneem 10.4 Equal to V/Gelyk aan (1) (4) (1) 10.5 10.6 The velocity of the fire engine driver relative to the fire engine siren is zero.’ OR /Die snefheid van de brandweerman relatief tot die brandweerwa is nul The fire engine driver has the same velocity as the fire engine. V OR/ Die brandweerman beweeg teen dieselfde snelheid as die brandweema. There is no relative motion between the fire engine driver and the (2) fire engine. // Daar is geen relatiewe beweging tussen die brandweerwa en die brandweerman nie. Use of ultrasound for measuring the rate of blood flow. //Gebruik ultraklank om bloedvioei te meet Use of ultrasound to measure the heartbeat of a foetus.V/Gebruik ultrank om die hartklop van die fetus te meet To detect weather by analysing doppler shift of radar waves. (3) v¥/Weervoorspelling deur die annalise van die dopplerskuif van radargolwe. (Any other correct answers). When light from a distant star or galaxy is observed to have shifted towards (2) the red end of the spectrum. V //Wanneer lig van ‘n verafgeleé ster of sterrestelsel waargeneem word en daar vind rooiverskuiwing van die spektrum plaas. [13] TOTAL/ TOTAAL: 150 Copyright reserved/Kopiereg voorbehou