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education
Department:
Education
North West Provincial Government
REPUBLIC OF SOUTH AFRICA
PROVINCIAL ASSESSMENT ]
GRADE 12
OSS SUSSSEER ERTS COMM ESSSESR SSS OSS ee UTES EEE EES,
PHYSICAL SCIENCES: CHEMISTRY (P2)
JUNE 2024
2
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a
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0
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: 150
TIME: 3 hours
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Physical Sciences Grade 12 P2 North West Prelim 2024 QP
Grade 12 Physical Sciences Paper 2 question paper from the North West Prelim Exam 2024, 18 pages. Read online or download the free PDF.
Physical Sciences · Grade 12 · North West Prelim Exam · 2024. Question paper, 18 pages. Read online or download the PDF.
- Subject
- Physical Sciences
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- Grade 12
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- Year
- 2024
- Exam period
- North West Prelim Exam
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- 2
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- CAPS
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- 18
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This exam
North West Prelim Exam 2024
- Paper 1Question paper
- Paper 2Question paper
Questions in this paper
- Question 1Rate and Extent of Reactions20 marks
- Question 2Organic Compounds and Macromolecules22 marks
- Question 3Organic Compounds and Macromolecules15 marks
- Question 4Organic Compounds and Macromolecules18 marks
- Question 5Rate and Extent of Reactions22 marks
- Question 6Rate and Extent of Reactions11 marks
Show all 8 questions
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Physica! Sciences/P2 2 NW/June 2024
Grade 12
INSTRUCTIONS AND INFORMATION
1.
Zi
10.
411.
12,
Write your name in the appropriate space on the ANSWER BOOK.
This question paper consists of EIGHT questions. Answer ALL the questions in
the ANSWER BOOK.
Start EACH question on a NEW page in the ANSWER BOOK.
Number the answers correctly according to the numbering system used in this
question paper,
Leave ONE line between two sub-questions, e.g. between QUESTION 2.1 and
QUESTION 2.2,
You may use a non-programmable calculator.
You may use appropriate mathematical instruments.
Show ALL formulae and substitutions in ALL calculations.
Round off your FINAL numerical answers to a minimum of TWO decimal places.
Give brief motivations, discussions, etc. where required.
You are advised to use the attached DATA SHEETS.
Write neatly and legibly.
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Physical Sciences/P2 3 NW/June 2024
Grade 12
QUESTION 1: MULTIPLE CHOICE QUESTIONS
Various options are provided as possible answers to the following questions, Each
question has only ONE correct answer. Write the letter (A-D) next to the question
numbers (1.1 to 1.10) in the ANSWER BOOK, for example 1.11 E.
1.1 Which ONE of the following compounds belongs to the same homologous
series as an ester?
A CHsCOCHs
B CHsCH2CH20H
c CHsCOOCH3
D CH3CH2CHO (2)
1.2. Molecules with the same molecular formulae, but different types of chains
are called ...
A positional isomers.
B chain isomers.
Cc structural isomers.
D functional isomers. (2)
1.3 Consider the reaction represented below.
CHsCH2CHBrCHs + HzO —-»CHaCH2zCHOHCHs + HBr
Which ONE of the following CORRECTLY gives the type of reaction that
takes place and its reaction conditions?
TYPE OF REACTION REACTION CONDITIONS
A Addition Excess H20 + acid as catalyst
B Addition Pt, Pd or Ni as catalyst
Cc Substitution Dilute strong base + mild heat
D Substitution Excess H2O + mild heat (2)
1.4 The activation energy for a certain reaction is 70 kJ.mot, Energy is released
when this reaction takes place.
Which ONE of the following is correct for the reverse reaction?
ACTIVATION ENERGY | HEAT OF REACTION
(Ea) (AH)
A Ea < 70 kJ.mof" AH > 0
B Ea< 70 kJ.mof! AH <0
C | Ea>70kJ.mott AH <0
D Ea > 70 kJ.mott AH>0 (2)
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Physical Sclences/P2 4 NWiJune 2024
Grade 12
1.5. The following reaction has reached equilibrium in a closed container at a
temperature of 359 K:
ANH3(g) + 502(g) + 4NO(g) + BH2O(g) + energy
Which ONE of the following will increase the equilibrium concentration of NH3?
A Add a catalyst.
B Remove NO(g) from the container.
Cc Increase the volume of the container.
D The temperature is increased to 400 K. (2)
1.6 Which ONE of the following graphs shows the mass of a catalyst against time
at the end of the chemical reaction?
wo
A
Mass (g)
Mass (g)
Time (s) Time (s)
Mass (g)
Mass (g)
Time (s) Time (s)
(2)
1.7 Ata temperature of 150°C substances A(g) and B(s) are placed in a closed
container. The concentration of A(g) is 0,0002 mol.dm* at equilibrium.
Equal amounts of P(g) and Q(g) are formed.
The Ke value = 0,123
The equilibrium concenirations of P and Q will be ...
1,57 x 10 @mol.dm3
2,46 x 10 4mol.dm%
1,23 x 10 “mol.dm?
4,92 x 10 “mol.dm? (2)
o0Omu,r
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Physical Sciences/P2
5
Grade 12
NW/June 2024
1,8 Which ONE of the following is a conjugate acid-base pair in the following
reaction?
CHsCOOH + NHs ——» CH3COO- + NH«*
ACID CONJUGATE BASE
A NH3 NHa*
|B CHsCOO- NHa"
¢c CH3sCOOH NHa
ie) CHsCOOH CHsCOO-
1.9 Aweak acid HA dissociates in aqueous solution as shown below.
HA (aq) % H*(aq) + A‘ag)
Which ONE of the followin
the solution?
A
B
c
D
1.10 Which ONE of the following solutions has the HIGHEST pH value?
VUOU>D
Addition of a little aqueous sodium hydroxide solution
Raising the temperature of the solution
Dissolving a little of the sodium salt,NaA, in the solution.
Adding a catalyst to the solution
0,1 mol-dm? Mg(OH)2
0,1 mol-cdm NH
0,1 mol-dm? HCE
0,1 mol-dm* H2SOx
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AH=+20 kJmoft
(2)
g changes will result in an increase in the [H*] of
(2)
(2)
[20]
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Physical Sciences/P2 6
Grade 12
QUESTION 2 (Start on a new page)
NW/June 2024
Study the following organic compounds, represented by the letters A to I in the
table below:
fe}
A 2-methylpropane F CHs — CH2— —_
CHs —C = CH —CHs
B Butane G |
CHs
c C2HsBr H |} HC——=CGH
H #H f
D Butan-1-ol 1} H— f- fot H
H H
i= Butan-2-ol
2.1 Write down the letter(s) that represent(s) the following:
2.2
2.1.1 Two compounds that are CHAIN ISOMERS.
2.1.2 APRIMARY alcohol,
2.1.3 Aweak MONOPROTIC ACID
Compound G is a hydrocarbon.
2.2.1 Define the term hydrocarbon.
2.2.2 Is compound G SATURATED or UNSATURATED?
Give a reason for your answer,
2.2.3 Write down the IUPAC name of compound G.
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(1)
(1)
(1)
(2)
(3)
(2)
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Physical Sciences/P2 7 NW/June 2024
Grade 12
2.3 Write down the NAME of the homologous series to which compound G
belongs. (2)
2.4 Compound | is the product of an esterification reaction.
Write down the:
2.4.1. IUPAC name for compound | (2)
2.4.2 STRUCTURAL FORMULA of the alcohol from which
compound I is synthesized (2)
2.4.3 IUPAC name of the carboxylic acid from which il is synthesized (2)
2.5 The table contains compounds which are functional isomers.
2.5.1 Define the term functional isomers. (2)
2.5.2 Write down the LETTERS that represent two compounds that are
functional isomers. (2)
[22]
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Physical Sciences/P2 3 NWiJune 2024
Grade 12
QUESTION 3 (Start on a new page.)
A student performs an experiment to compare the boiling points of organic
compounds belonging to different homologous series.
Butan-1-ol, butanoic acid and butanal are used.
He then recorded the results on the table given below.
Name Boiling point (° C)
Compound A 76
Compound B 118
Compound C 164
3.1 Define the term vapour pressure (2)
3.2 For this experiment give the:
3.2.1 Independent variable (1)
3.2.2 Dependent variable (1)
3,3 Is the boiling point of butan-1-ol HIGHER or LOWER than the
boiling point of propan-1-ol? Explain the answer by referring to the
INTERMOLECULAR FORCES. (3)
3.4 Write down the STRUCTURAL FORMULA for the FUNCTIONAL group of:
3.4.1 Compound A (2)
3.4.2 Compound C (2)
3.5 Is the vapour pressure of butanal be LOWER or HIGHER than the vapour
pressure of butan-1-ol? Explain your answer by referring to the type of
INTERMOLECULAR FORCES present and ENERGY. (4)
[15]
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Physical Sciences/P2 i] NW/June 2024
Grade 12
QUESTION 4 (Start on a new page)
Consider the following organic reactions | to IV involving organic compounds
AtoE.
| |A+Bre —Ulight B+ HBr
tl B + concentrated alcoholic KOH — C + KBr + H20
Dilute H H H H H H H
HPO; i tt £ YT kh
ee Perr TTT
i
H ? AH & 8 H
H D
600 (°C)
A ——— Cio + E
4.1 For the above reactions, write down the type of:
4.2
4.3
44
4.5
46
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4.1.1 Reaction!
(1)
4.1.2 Reaction Ill (1)
4.1.3 Reaction IV (1)
Write down the IUPAC name for compound D. (2)
Write the molecular formula for each of the following:
4.3.1. Compound A (2)
4.3.2 Compound E (2)
Draw the structural formula of compound B. (2)
Write down the balanced chemical equation for complete COMBUSTION
of CaHio using MOLECULAR FORMULAE. (3)
For Reaction I
4.6.1 Draw the STRUCTURAL FORMULA of compound C (2)
4.6.2 State TWO reaction conditions. (2)
[18]
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Physical Sciences/P2 10 NWi/June 2024
Grade 12
QUESTION 5 (Start on a new page.)
5.1 Agroup of learners uses the reaction of hydrochloric acid with magnesium ribbon
to investigate the factors that influence rate of reaction.
The balanced equation for the reaction is given below:
Mg(s) + 2HC% (ag) —> MgCho(ag) + H2(g)
The hydrochloric acid is in EXCESS, and the same mass of magnesium is used
in ALL the experiments.
REACTION CONDITIONS
Feperinaat Concentration of Temperature es -—
3 0; ”
HC&(ag)(mol.dm*) (°C) Magnesium
Before | After
1 35 57 Powder
2 30 48 Ribbon
3 20 33 Ribbon
4 1,5 30 45 Ribbon
5.1.1 Define the term rate of reaction. (2)
5.1.2 In which experiment is the reaction rate HIGHEST? Explain your answer. (3)
5.2 The reaction in Experiment 2 is compared to the reaction in Experiment 4.
5.2.1 Write down ONE control variable for this comparison. (1)
5.2.2 How does the amount of hydrogen gas produced in Experiment 2
compare to the amount produced in Experiment 4 if the same volume of
acid is used in both experiments?
Write down only HIGHER THAN, SMALLER THAN or EQUAL TO.
Give a reason for your answer. (2)
5,3 Give a reason why it is not a fair test to compare the rate of reaction of
Experiment 1 with that of Experiment 3. (1)
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Physical Sciences/P2 a NW/June 2024
Grade 12
5.4 Calculate the mass of hydrochloric acid that remains in the flask at the
completion of the reaction in Experiment 4 if the initial volume of the hydrochloric
acid is 80 cm, (7)
5.5 The Maxwell-Boltzman distribution curves labelled P, Q and R for the reactions
in experiments 1, 2 and 3 in random order are shown below.
a
5 |
~
“oS R
ey ~ —-—
—
Kinetic energy
5.5.1 Write down the name of the label, Y, on the vertical axis. (1)
5.5.2 Which curve (Q, P or R) represents the results of Experiment 3? (1)
5.5.3 With the aid of the collision theory explain the effect of TEMPERATURE
on reaction rate, (4)
[22]
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Physical Sciences/P2 12 NWiJune 2024
Grade 12
QUESTION 6 (Start on a new page)
Consider the following balanced chemical equation:
CHa(g) + 202(g) = CO2(g) + 2H20(0) 4H =-216,7 kJ-mot?
The graph below shows the potential energy against the course of this reaction.
7 2 670}-------------7---------
3
2 400 Reactants |p
3 Products
5 Re
: X ee
Course of reaction
8.1 Define the term activation energy. (2)
6.2 Is the reaction Endothermic or Exothermic? Give a reason for the answer, (3)
6.3 What do the following sections of the graph represents?
6.3.1 RP (1)
63.2 QP (1)
6.4 Determine BY CALCULATION the value of X. (3)
6.5 What effect will the addition of suitable catalyst to the reaction mixture have on
the activation energy of the reaction? Choose from INCREASES, DECREASES
or NO EFFECT. (1)
[11]
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Physical Sciences/P2 13 NWiJune 2024
Grade 12
QUESTION 7 (Start on a new page.)
Consider the reaction represented by the balance equation below.
4HCL(g) + O2(g) = ZH2O(g) + 2Ck(g) AH <0
Initially 1,5 mole of HC&(g) and 2 mole of O2(g) were mixed in a sealed 5 dm?
container which had 18g of H2O(g). The reaction reached equilibrium after 20
minutes at 600°C and 0,6 mole of C&(g) was present in the container,
vA Define the term chemical equilibrium. (2)
Tee How does the rate of forward reaction compare to the rate of the reverse
reaction after 10 minutes? Choose from HIGHER THAN, LOWER THAN
or EQUAL TO. (1)
7.3. Calculate the value of Ke at 600°C (8)
7A State Le Chatelier’s principle {2)
7.5 The volume of the container is now decreased to 2,5 dm® while the
temperature is kept constant.
How will each of the following be affected? Choose from INCREASES,
DECREASES or REMAINS THE SAME.
7.5.1 The value of Ke (1)
7.5.2 The mass of Cf2(g) in the container. (1)
7.6 Explain your answer ta QUESTION 7.5.2 by referring to Le Chatelier’s
Principle (2)
7.7 ‘The temperature of the container is now increased, and equilibrium is re-
established
7.7.1 How does the new value of Ke at this temperature compare to the
one obtained at 600°C? Choose from HIGHER THAN, LOWER
THAN or EQUAL TO (1)
7.7.2 Explain the answer to QUESTION 7.7.1 by referring to Le
Chatelier's Principle (2)
[20]
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Physical Sciences/P2 14 NW/June 2024
Grade 12
QUESTION 68 (Start on a new page.)
A group of learners use 35 cm? standard solution of 0,1 mol.dm* sodium
hydroxide solution to standardize an oxalic acid solution of volume 40 cm3,
At the endpoint, 12 cm? of the sodium hydroxide remains unreacted,
8.1 Define a standard solution (2)
The net ionic equation is given below:
CeH204 + 20H- = C2022 + 2400
8.2 Identify the conjugate acid-base pairs. (4)
8.3 Is oxalic acid a weak or a strong acid? Explain the answer (3)
8.4 COs undergoes ionisation in a TWO step process as shown below:
| HeCOs+H2O = HCOs +H30+
Il HCOs+H20 = X+HsO+
8.4.1 Identify a substance in the above reactions that can act as an
ampholyte. (2)
8.4.2 Write down the formula of the substance(s) that is represented by
X in reaction Il. (2)
8.5 A sulphuric acid solution is Prepared by dissolving 5,25 g of H2SO« in
250 cm*of water.
Calculate the following:
8.5.1 The number of moles of sulphuric acid in the original standard
solution. (4)
8.5.2 pH of the solution. (5)
[22]
TOTAL: 150
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Physical Sclences/P2 1 NWiJune 2024
Grade 12
DATA FOR PHYSICAL SCIENCES GRADE 12
PAPER 2 (CHEMISTRY)
GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 12
VRAESTEL 2 (CHEMIE)
TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES
NAME/NAAM SYMBOL/SIMBOOL VALUE/WAARDE
a p? 4,013 x 10° Pa
Molar gas volume at STP ae
Molére gasvolume by STD Vim 22,4 dm*-mot
Standard temperature j
Standaardtemperatuur T 273 K
Charge on electron yy 19
Lading op electron i TEXTES
Avogadro's constant 23 4
Avogadro-konstante Ns Bo2a 10° mar
TABLE 2: FORMULAE/TABEL 2: FORMULES
m aM
easy 2
eat or/of pa fin.
i MV V,
GaVs a -aagnaO a
ChVy Ny pH = -log[H30*]
Kw = [H3sO*][OH] = 1 x 104 at/by 298 K
or/of
orlof
Fea = Beste =F (Ely = Eh — Es
Bei = Eeariin ~ Eas, 7 =a a
| Ea = Eat eont — Enucry age (Ew = ESnamcas — E Samanta
=@ i
=2 =2
q = IlAt -
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Physical Sciences/P2 3 NW/June 2024
Grade 12
TABLE 4A: STANDARD REDUCTION POTENTIALS
TABEL 4A: STANDAARD-REDUKSIEPOTENSIALE
Half-reactions/Haifreaksies E 8 ”)
Fi(g)+2e = 2F + 2,87
Co*+e = Co* + 1,81
HO2 + 2H*+#2e- = 2H:0 +177
MnO, +8H*+5e = Mn*+4H,0 + 1,51
Cb(g)+2e- = 2Cr + 1,36
CrO 27 +14Ht+6e- = 2CP*+7HO | + 1,33
O.(g) + 4H" +4e- = 2H:0 + 1,23
MnO,+4H*+2e- = Mn%+2H,0 | +1,23
| Pt+2e = Pt + 1,20
Bro(t)+2e° = 2Br + 1,07 '
3 NO, +4H*+3e- = NO(g)+2H,0 | +0,96 s
3 Hg? +2e- = Hoa(t) +085 3
3 Ag’t+e = Ag +0,80 5
$ NO} +2H*+e- = NO2(g)+H20 | +0,80 8
g Fe*+e- = Fe* +0,77 2
Ps Og) + 2H" +2e° = H202 +0,68 5
g k+2e = 2F + 0,54 >
g Cu’+e = Cu +0,52
. $02+4H*+4e 4 $+2H0 + 0,45
o 2H20+O24+4e + 4OH- + 0,40
2 Cu +2e- = Cu + 0,34 3
2 S027 +4H*+2e- = SOxg)+2H0 | +0,17 &
2 Cur +e = Cut +0,16 FS
g Sn*+2e- = Sn* #015 Rs
E §$+2H"+2e = H:S(g) +0,14 r
F 2H*+2e = Hig) 0,00 ra
s Fe*+3e- = Fe —0,06 S
ll Pb?*+2e- = Pb ~0,13 a
£ Sn*+2e = Sn -0,14 <
3 NP +2e- = Ni -0,27 2
¥ Co*+2e = Co 0,28 £
= Cd*+2e = Cd —0,40 oS
s Cr++e° = Cr —0,41 €
2 Fe**+2e- = Fe | —0,44 ma
g Cr+ 3e- = Cr -0,74 &
@ Zn*+2e- = Zn 0,76 <A
2 2H,0+2e- = He(g)+20H- | —0,83 &
s Cr-+2e = Cr | -0,91 EY
5 Mn®*+2e = Mn | —1,18 5
= AC +3e- = AL | —1,66 =
Mg? +2e- = Mg — 2,36
Nate = Na —2,71
Ca +2e = Ca — 2,87
S+2e = Sr ~2,89
Ba**+2e- = Ba | —2,90
Cst+e = Cs | 2,92
K'+e = K —2,93
litte = Li — 3.05
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Physical Sciences/P2
Increasing strength of oxidising agents/Toenemende sterkte van oksideermiddels
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4
Grade 12
TABLE 4B: STANDARD REDUCTION POTENTIALS
TABEL 4B: STANDAARD-REDUKSIEPOTENSIALE
Half-reactions/Halfreaksies 59 Ww)
tee = L ~ 3,05
Kite = K -2,93
Cst+e = Cs = 2,92
Bat*+2e° = Ba -2,90
SPt+2e- = Sr — 2,89
Ca*+2e- = Ca - 2,87
Nat+e- = Na -2.74
Mg**+2e- = Mg - 2,38
Agt+3e = At - 1,66
Mn*+2e- = Mn -1,18
Cr++2e = Cr —0,91
2H20 + 2e- = Ha(g)+2O0H- | -0,83
Zn*+2e = Zn -0,76
Chet+3e = Cr -0,74
Fe*+2e = Fe —0,44
Csit+e = Cre | -0,41
Cd? +2e- = Cd —0,40
Co*+2e = Co —0,28
Ni +2e- = Ni —0,27
Sn*+2e = Sn -0,14
Pb? +2e- = Pb —0,13
Fe*+3e = Fe —0,06
2H'+2e- = Hig) 0,00
$+2H*+20- = HS(g) +0,14
Sn +2e° = Sn? +015
Cut+e- = Cut +0,16
SO; #4H*+2e- = SOx(g) +2140 | + 0,17
Cu*+2e° = Cu + 0,34
2H20+O2+4e° = 4OH- +040
SOz+4H'+4e- = S+2H20 +045
Cute = Cu + 0,52
hb+2e = 2b +0,54
Ox{g) +2H*+2e- = H2O2 + 0,68
Fe*¥ +e = Fett +077
NO4 +2H*+e> = NOx(g)+H20 | +0,80
Agi+e = Ag +0,80
Hg*+2e = Hg() + 0,85
NO; +4H*+3e- = NO(g)+2H20 | +0,96
Br()+2e 2 2Br | +4,07
Pe+2e 2S Pt | + 1,20
MnOz+4H*+2e° = Mn+ 2H3:0 +41,23
Oa(g) + 4H*+4e = 2H:O +1,23
Cho} +14H'+6e- = 208+ 70 | + 1,33
Chk(g)+#2e = 20h + 1,36
MnO, + 8H*+5e~ = Mn*+4H20 | + 1,51
H202+ 2H 426" = 2120 +177
Co*+e = Cor + 1,81
Fo(g)+ 207 = 2F- +2,87
NW/June 2024
Increasing strength of reducing agents/Toenemende sterkte van reduseermiddels
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