Physical Sciences Grade 12 Paper 1 North West Mock 2025 Memo

education Department: Education North West Provincial Government REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE NASIONALE SENIOR SERTIFIKAAT [ GRADE 12/GRAAD 12 PHYSICAL SCIENCES: PHYSICS (P1} FISIESE WETENSKAPPE: FISIKA (V1) SEPTEMBER 2025 MARKING GUIDELINES/NAS/ENRIGL YNE MARKS/PUNTE: 150 These marking guidelines consist of 15 pages. Hierdie nasienriglyne bestaan uit 15 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

QUESTION/VRAAG 1 1.1 le 1.3 1.4 1.5 1.6 1.7 1.8 1.9 Copyright reserved/Kopiereg voorbehou Cc on DO > Qo 0 FO WO > vv vv vv vv vv vv Vv Vv vv vv NW/September 2025 (2) (2) (2) (2) (2) (2) (2) (2) (2) (2) [20] Please turn over/Blaai om asseblief

NW/September 2025 QUESTION/VRAAG 2 2.1. The force that opposes the motion of a moving object relative to the surface.” “/Die krag wat die beweging van ‘n bewegende voorwerp relatief tot ‘n opperviak teenwerk. (2 orlof 0) (2) Fr v¥ Fgo¥ Accepted labels/Aanvaarde bendemings Fn_| N/Normal force/Normaatkrag _ Fr_| T/Tension force/Spanningskrag Fy | Fw/w/gravitational force/weight/gravitasiekrag/gewig Fr_| f/fk/(kinetic) friction/(kinetiese) wrywing Notes/Aantekeninge: e Mark awarded for label and arrow./Punt toegeken vir benoeming en pylijie. e Do not penalise for length of arrows since drawing is not to scale./Moenie vir die lengte van die pyltjies penaliseer nie aangesien die tekening nie volgens skaal is nie. e Any other additional force(s)/Enige ander addisionele krag(te): Max/Maks 3/4 e If everything correct, but no arrows/Indien alles korrek, maar geen pyltjies: Max/Maks 3/4 e If force(s) do not make contact with the dot /Indien krag(te) nie met die kolletjie kontak maak nie: Max/Maks 3/4 e If components drawn for Fg/Indien komponente van F, geteken: Max/Maks 3/4 (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

NW/September 2025 2.3.1 | Fnet = ma P v Toft For=ma_{ Any onev/Enige een T= 4,3 — (3 x 9,8 sin 30°) V= 3 x 2V T=25NV (4) POSITIVE MARKING FROM 2.3.1/POSITIEWE NASIEN VANAF 2.3.1 2.3.2 | Fnet = ma p v, 5 Tn heome ib Any onev/Enige een F-25-7,2=6x2v F=44,2NV (3) 2.4 Increasev/Toeneem (1) [14] QUESTION/VRAAG 3 3.1 Marking criteria/Nasienkriteria: If any of the underlined key words/phrases in the correct context is omitted deduct 1 mark/ Indien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af. If gravity/gravitation without force is used 1/2 Indien gravitasie sonder krag gebruik word 1/2 An object which has been given an initial velocity” and then moves under the influence of the gravitational force only.~/’n Voorwerp waaraan ‘n beginsnelheid_gegee word, wat daarna slegs onder die invloed van gravitasiekrag beweeg. (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

NW/September 2025 3.2.1 Upwards as positive (note: vr and vi can be switched except for OPTION 1)/Opwaarts as positief (nota: vr en vi kan omgeruil word behalwe virOPSIE 1) —__ So — OPTION/OPSIE 1 OPTION/OPSIE 2 OPTION/OPSIE 3 Ay =viAt+ Zad?tY | w=wtadt w= vit adt =0+ %(-9,8)(1,5)?Y | O= vit (-9,8)(1,5) 0 = vi+ (-9.8)(1,5) = 11,025 m vi= 14,7 ms? w= 14,7 m-s? h=11,025+100Y |ve=vit 2ady ¥ Ay = viAt + % aAt? ¥ h= 111,03 mv 0 = 14,72 + (-9,8)Ay ¥ | =14,7(1,5)+ % (9,8)(1,5)2¥ OPTION/OPSIE 4 iAy = 11,025 Ay = 11,025 m vi = vi t+ aAt _ O= wit (-9,8)(1,5) h=11,025+100“ | h=11,025 + 100 v vi=14,7 ms? h= 111,03 m ¥ h= 111,03 m ¥ = VVE Ay = — At v Ay= SET isv Ay = 11,025 h = 11,025 + 100 v h= 111,03 m ¥ Downwards as positive (note: vr and vi can be switched except for OPTION 5)/Afwaarts as positief (nota: vt en vi kan omgeruil word behalwe vir OPSIE 5) OPTION/OPSIE 5 OPTION/OPSIE 6 OPTION/OPSIE 7 Ay = viAt + % adt? ¥ Vi=vi+ adt VW= vit adt =0+%(9,8)(1,5)% | 0 =vi+ (9,8)(1,5) 0 = vit (9,8)(1,5) = 11,025 m vi= -14,7 ms? vi= -14,7 ms? h = 11,025 + 100 v vi? = vi2+ 2ady ¥ Ay = viAt + % aAt? V h= 111,03 mV O= -14,72 + (9,8)Ay v | = -14,7(1,5)+%(9,8)(1,5)2” OPTION/OPSIE 8 Ay =-11,025 Ay = 11,025 m ve = vi + aAt h=11,025+100Y | h=11,025 + 100 ¥ 0 = vit (-9,8)(1,5) h=111,03 mv h= 111,03 mv vi= 14,7 ms? Ay = oat 0+14,7 v z 15 Ay= Ay = 11,025 h = 11,025 +100 v h= 111,03 mV (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

NW/September 2025 3.2.2 Upwards as positive/Opwaarts as positief OPTION/OPSIE 1 OPTION/OPSIE 2 Vi=vitadt POSITIVE MARKING FROM 3.2.1/ O=vit (-9,8)(1,5) POSITIEWE NASIEN VANAF 3.2.1 im vest w= 14,7 ms iPmupe Banya ve = viet Zady ¥ ve = 02+ 2(-9,8)(-111,03) ¥ = 14,7? + 2(-9,8)(-100) v vi = 46,65 m:s! ¥ downwards¥/ ve = 46,65 ms Ydownwardsv/ afwaarts afwaarts Downwards as positive/Afwaarts as positief OPTION/OPSIE 3 OPTION/OPSIE 4 Vi = vi + adt POSITIVE MARKING FROM 3.2.1 0 = vit (9,8)(1,5) POSITIEWE NASIEN VANAF 3.2.1 = eel vi= -14,7 ms Weare pany ve = vit+ 2ady ¥ ve = 02+ 2(9,8)(111,03) ¥ = -14,72 + 2(9,8)(100) “” vs = 46,65 m:s! ¥ downwardsv/ vi = 46,65 m:s"! ~ downwardsy / afwaarts afwaarts (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

NW/September 2025 3.2.3 Positive marking from/Positiewe nasien vanaf 3.2.1 and/en 3.2.2 Upwards as positive/Opwaarts as positief OPTION/OPSIE 1 ve= vit adt 0 = vit (-9,8)(1,5) vi= 14,7 ms" Ay = viAt + % adt? ¥ OPTION/OPSIE 2 vi = vi + aAt = vit (-9,8)(1,5) vi= 14,7 ms" Vr = vit adt Y 100 = 14,7At + % (-9,8)(At ¥ | 46,65 = 14,7 + (-9,8)At ¥ At = 6,26 s V At=6,26 sv OPTION/OPSIE 3 ve? = vit+ 2aAy vie = 14,72+ 2(-9,8)(-100) vi = 46,65 m-s" v= vit adt ¥ -46,65 = 14,7 + (-9,8)At ¥ At=6,26s Vv Downwards as positive/Afwaarts as positief Ve = vit adt ¥ 46,65 = -14,7 + (9,8)At ¥ At=6,26 s Vv OPTION/OPSIE 4 OPTION/OPSIE 5 Ay = viAt + % aAt? ¥ VWe= vit adt 100 = -14,7At + % (9,8)(At)? ¥ 0 = vit (9,8)(1,5) At=6,26s Vv vi= 14,7 ms vi = vit adt ¥ 46,65 = -14.7+ 9. 8At ¥ At= 6,26 s ¥ OPTION/OPSIE 6 ve = vi2+ 2aAy ve = -14,72+ 2(9,8)(100) vi = 46,65 m-st (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

3.3 Copyright reserved/Kopiereg voorbehou NW/September 2025 POSITIVE MARKING FROM QUESTION 3.2.1 AND QUESTION 3.2.3/ POSITIEWE NASIEN VANAF VRAE 3.2.1 EN 3.2.3 OPTION 1: UPWARDS AS POSITIVE/OPSIE 1: OPWAARTS AS POSITIEF Velocity vs time graph/Snelheid teenoor tyd grafiek < = a my © Velocity/Snetheid (m-s') * Ball/Bal B 7,76 time/tyd (s) Batl/Bal A 46,6 OPTION 2: DOWNWARDS AS POSITIVE/OPSIE 2: AFWAARTS AS POSITIEF Velocity vs time graph/Snetheid teenoor tyd grafiek 46,65 fF £ 2 Ball/Bal A o s 2 Z > s 7,76 time/tyd (s) 3 > v 14,7 Ball/Bal B Criteria/Kriteria: e Same initial velocity for both ball A and B.~/Dieselfde aanvanklike snelheid vir beide bal A en bal B. e Graph of ball B starts at 1,5 s.~/Grafiek van bal B begin by 1,5 s. e Both graphs end with the same final velocity.~/Beide grafieke eindig met dieselfde eindsnelheid. ¢ Graph of ball B stops at 7,76 s.~/Grafiek van bal B eindig by 7,76 s. e Correct shape and equal sizes for both graphs.“ /Korrekte vorm en gelyke groottes vir beide grafieke. (5) [18] Please turn over/Blaai om asseblief

QUESTION/VRAAG 4 41 4.2 4.3 4.4 NW/September 2025 mva + mvs = mva + mvs ¥ (m x 12) + (3m x 0) Y= mva + (3m x 4,68) ¥ v=-0,86 ms* v = 0,86 m:s" leftv/links Ex=%mv?v Before collision/Voor botsing Ex = %4(m)(12)? + %(3m)(0)* ¥ Ex = 72m J After collision/Na botsing Ex = %4(m)(0,86)* + %4(3m)(4,68)? ¥ Ex = 14,83m J Ex before is not equal to Ex afier¥ /Ek voor is nie gelyk aan Ex na Thus, an inelastic collision./Dus ‘n onelastiese botsing. Marking criteria/Nasienkriteria: If any of the underlined key words/phrases in the correct context is omitted deduct 1 mark/ indien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks uitgelaai is, trek 1 punt af. The product of the resultant/net force acting on an object “and the time the net force acts on the object.“/Die produk van die resulterende/netto_krag wat op ‘n voorwerp inwerk en die tyd wat die netto krag op die voorwerp inwerk. OPTION/OPSIE 1 OPTION/OPSIE 2 Fret x 0,03 = 0,05 (-0,86 — 12) v Fret X 0,03 = 0,15(4,68 — 0) ¥ Fret = 21,43 N ¥ Fret = 23,4 N ¥ Copyright reserved/Kopiereg voorbehou (4) (4) (2) (3) [13] Please turn over/Blaai om asseblief

NW/September 2025 QUESTION/VRAAG 5 5.1 (Kinetic) frictional force.”/(Kinetiese) wrywingskrag 5.2.1] mhgr+ %mve =mhgi + %mvi2 ¥ 0+ % 4(w*) = (4 x 9,8 x 15) + % 4(32) v vi = 17,41 mst v¥ 522 FnetAx = Ye mv? - % mvi? Y fk x 18cos 180° Y = 0 - % 4(17,417) v fk = 33,68 N ¥ 5.3 POSITIVE MARKING FROM 5.2.1/POSITIEWE NASIEN VANAF 5.2.1 fk = uxmg ¥ 33,68 = pkx4x9,8 vw Uk = 0,86 ¥ QUESTION/VRAAG 6 6.1 Marking criteria/Nasienkriteria: If any of the underlined key words/phrases in the correct context is omitted deduct 1 mark/ Indien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af. The change in frequency (or pitch) of the sound detected by the listenery, because the sound source and the listener have different velocities relative to the medium of sound propagation.~/Die verandering in frekwensie (of toonhoogte) van die klank waargeneem deur _'n luisteraar omdat die klankbron en die luisteraar verskillende snelhede relatief tot die medium waarin die klank voortgeplant word, het. OR/OF An (apparent) change in (observed/detected) frequency (pitch),“ as a result of the relative motion between a source and an observer Vv (listener). 'n (Skynbare) verandering in (waargenome) frekwensie (toonhoogte), as gevolg van die relatiewe beweging tussen die bron en 'n waarnemer (luisteraar). 6.2.1 veMfv 343 = 350 x 10° f ¥ f =980 Hz v Copyright reserved/Kopiereg voorbehou (1) (3) (4) (3) [11] (2) (3) Please turn over/Blaai om asseblief

NW/September 2025 6.2.2 POSITVE MARKING FROM 6.2.1/POSITIEWE NASIEN VANAF 6.2.1 viv f= - fs v ViVs _ 343 980 v = 343-30 fv fs = 894,29 Hz veh 343 =A x 894,29 v A= 0,39 m¥ (5) 6.3.1 TOWARDSYV/NA 6.3.2 (1) The curve shows a blue shift~/Die kurwe toon ‘n blou verskuiwing , the star moves towards the side of a higher frequency/lower wavelength.” /die ster beweeg na die kant met 'n hoér frekwensie/korter golflengte. QUESTION/VRAAG 7 FA (2) [13] Criteria for sketch/Kriteria vir skets Marks/ Punte Correct direction of field lines./Korrekte rigting van veldlyne. Correct shape of te electric field lines between the charges and on the outside of the charges./Korrekte vorm van elektriese veldlyne tussen ladings en aan die buitekant van die ladings. No field lines crossing each other. Field lines must touch the charge, but not go inside the charge./Geen veldlyne wat mekaar kruis nie. Veldlyne moet die lading raak, maar nie die lading binnegaan nie. Note: If learner draws field pattern of two like charges: 0/3 If only one charge is drawn: 0/3 Nota: Indien leerder elektriese veld van twee gelyke ladings teken: 0/3 Indien slegs een lading geteken is: 0/3 (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

NW/September 2025 7.2 | Marking criteria/Nasienkriteria If any of the underlined key words/phrases in the correct context is omitted deduct 1 mark./Indien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af. If mass is used//ndien massa gebruik is: 0/2 If force is ommited/Indien krag weggelaat is: 0/2 The magnitude of the electrostatic force exerted by one point charge on another point charge is directly proportional to the product of the magnitudes of the charges” and inversely proportional to the square of the distance between themv Die grootte van die elektrostatiese_krag wat een puntlading op 'n ander puntlading uitoefen, is direk eweredig aan die produk van die groottes van die _ladings en omgekeerd eweredig aan die kwadraat van die_afstand tussen hulle. (2) 73 | pu kay, r2 9 -19 -19 peed x 1,6 x 10 ae VY (3x 1071?) (3) F=2,56x10°Nv 74.1| =x? + y? v (or any suitable equation/of enige geskikte formule) r2 = (2,56 x 10°)? + (2,56 x 10°5)2 ¥ Fret = 3,62 x 10°°.N ¥ 45° north west/west of north/north of west /noordwes/wes van noord/noord van wes ORIOF 315° (4) 7.4.2 | OPTION/OPSIE 1 ACCEPT/IAANVAAR: POSITIVE MARKING FROM 7.4.1/ B= kKQ Vv POSITIEWE NASIEN VANAF 7.4.1 r E=fv 5 = 2% 10x 1,6x 10° Ie 5 (3x 10712) 3,62 x 10” Sr rer E=1,6 x 10% N-C* ves, HAWARITAER Ene? = (1,6 x 10")? + (1,6 x 10")? v = 2,26 x 10! NC ¥ Enet = 2,26 x 104#N-C v (3) [15] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

NW/September 2025 QUESTION/VRAAG 8 8.1 To measure the total current of the circuit.“~/ Om die totale stroomsterkte in die stroombaan te meet. (If only current: 0/1/Indien slegs stroomsterkte: 0/1) (1) Zl aa 821 Sv xiv =3,33AV (3) 8.2.2 | EmffEmk = I(R +r) ¥ 26 = 5(R + 0,6) ¥ Re =4,60 1 1.1 eos gees qos Re 2R R lt, v= zl. + i v 4,6 2R_ R R=69QV¥ (5) 8.2.3 | OPTION/OPSIE 1 OPTION/OPSIE 2 POSITIVE MARKING FROM Velr 8.2.2/POSITIEWE NASIEN =5x06 VANAF 8.2.2 =3V V=IRV = Emf = Vext + Vint/Emk =Vekstem + Vinten ¥ =5x4,6v = 26=V+3V =23VVv V=23VVY (3) 8.2.4 POSITIVE MARKING FROM 8.2.1; 8.2.2 AND 8.2.3/ POSITIEWE NASIEN VANAF 8.2.1; 8.2.2 EN 8.2.3 OPTION/OPSIE 1 OPTION/OPSIE 2 OPTION/OPSIE 3 W = PRAt ¥ W = V7/RAt ¥ W = VIAt ¥ = 3,33? x 6,9 x 120 ¥ = 237/6,9 x 120 v = 23 x 3,33 x 120 V = 9181,61 Jv = 9200 J ¥ = 9190,8 J ¥ (3) 8.3.1 DECREASEY/AFNEEM (1) 8.3.2 Total external resistance increase, current decreases. ¥ Vint decreases as current decreases/Vint is directly proportional to current ¥ Emf remains constant v’, thus Viost decreases. Totale eksterne weerstand vermeerder, stroom verminder. Vint verminder soos stroom verminder/Vint is direk eweredig aan die stroom Emk bly konstant, dus neem Vvertore af. (3) [19] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

NW/September 2025 QUESTION/VRAAG 9 9.1 9.2 9.3 9.4 9.5.1 9.5.2 Copyright reserved/Kopiereg voorbehou Mechanical to electrical energyY V/Meganiese na elektriese energie. BtoAYvV/BnaA « Use stronger magnets./Gebruik sterkter magnete. ¥ e Increase frequency of the rotationY/Verhoog die frekwensie van die rotasie e Increase the number of coils/surface area/Meer windings/vergroot oppervlak (any two/enige twee) Marking criteria/Nasienkriteria: If any of the underlined key words/phrases in the correct context is omitted deduct 1 mark/ Indien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af. The AC current which dissipates/produces the same amount of energy/heatY as an equivalent direct current (DC).~ Die wgk-stroom is die wisselstroom wat dieselfde hoeveelheid energie verbruik/oordra as 'n ekwivalente gelykstroom (GS). Imax imaks lms =—— ¥ / I, ete rms Va / wgk Vo 23 ==Vv v2 = 16,26A Vv OPTION/OPSIE 74 OPTION/OPSIE 2 V=IRV POSITIVE MARKING FROM 9.5.1/ =23x13Vv POSITIEWE NASIEN VANAF 9.5.1 = 299 V v V=IR = 16,26 x 13 Vimsiugk = 211,38 V ¥ v, v, Vims = 2 / Vucok = mais v2 v2 = Vmaximats 211,38 = = v | Viaximans = 298,94 V ¥ (2) (2) (2) (2) (3) (3) [14] Please turn over/Blaai om asseblief

NW/September 2025 QUESTION 10/VRAAG 10 10.1 10.2 10.3 10.4 10.5 10.6 Photon” /Foton Marking criteria/Nasienkriteria: if any of the underlined key words/phrases in the correct context is omitted deduct 1 mark/ Indien enige van die onderstreepte >lwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af. minimum frequency requiredY to eject an electron from a metal surface.~/Die minimum _frekwensie benodig om ‘n elektron uit ‘n metaalopperviak vry te stel. OPTION/OPSIE 1 OPTION/OPSIE 2 NOvV/NEE NOv/NEE Wo = hfo ¥ E=hfv = 6,63 x 10% x8,1x10%Y | 4,8 x 1079 =6,63 x 10™4f v =5,37x 10% Jv f=7,24 x 104 Hz ¥ Wo>E fo > f POSITIVE MARKING FROM 10.3/POSITIEWE NASIEN VANAF 10.3 E = Wot % mvVmawmaks? ¥ 7,68 x 10-19 = 5,37 x 10°19 V+ % 9,11 X 10°! Vmaximaks* Y Vmaximaks = 712 134,13 ms? ¥ REMAIN THE SAMEv/BLY DIESELFDE e Intensity does not affect the maximum speed.v e Only achange in frequency affects the maximum speed. e Intensiteit het geen effek op die maksimum spoed nie. e Slegs ‘n verandering in die frekwensie sal die maksimum spoed beinvloed. (any one/enige een) TOTAL/TOTAAL: Copyright reserved/Kopiereg voorbehou (1) (2) (4) (4) (1) (1) [13] 150